Answer:
Its cost about 1.5625
if you rounded its 1.56 :)
Step-by-step explanation:
Yoshi is a basketball player who likes to practice by attempting the same three-point shot until he makes the shot. His past performance indicates that he has a 30 % 30%30, percent chance of making one of these shots. Let X XX represent the number of attempts it takes Yoshi to make the shot, and assume the results of each attempt are independent. Is X XX a binomial variable? Why or why not?
Answer:
There is no fixed number of trials, so X is not a binomial variable
Step-by-step explanation:
mama
There is no fixed number of trials, so X is not a binomial variable.
What is a binomial variable in statistics?
This is a specific kind of discrete random variable. A binomial random variable counts how regularly a specific event occurs in a fixed variety of attempts or trials.
What is a binomial data example?The binomial is a form of distribution that has possible effects (the prefix “bi” method two, or twice). as an example, a coin toss has only viable effects: heads or tails, and taking a check may want to have viable outcomes: pass or fail. A Binomial Distribution indicates both success and failure.
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i need help please thanks
Answer:
33
Step-by-step explanation:
6 * 3 = 18
8-3 = h
h = 5
A = 5 * 3 = 15
Combined:
15 + 18
33
Which correctly describes this rotation?
A. a counterclockwise rotation of 30° about point A
B. a counterclockwise rotation of 45° about point A
c. a counterclockwise rotation of 90° about point A
D. a counterclockwise rotation of 180° about point A
Put all equations into y= and see which have matching graphs.
Answer:
I don't see any equations.
Describe how to find the sale price of an item that has been discounted 15%.
Multiply the original price by
% to find the sale price.
Multiply the discount percent to the marked price and subtract from the marked price.
What will be the selling price?As we know that the discount is always given on the marked price of the product.
We will take one example to understand it supposes the marked price of any object is MP= 100 and the discount =15% so to find the SP
First, find the discount amount
[tex]MP\times Discout \ percent =100\times \dfrac{15}{100} =15[/tex]
Now to find the SP subtract the discount from the MP
[tex]SP=MP-Discount[/tex]
[tex]SP=100-15=75[/tex]
So for finding SP multiply the discount percent to the marked price and subtract from the marked price.
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help-
1. half a number, less 3, is 8
2. the area decreased by 7 is 14
Answer:
. the area decreased by 7 is 14
plzzzz help me plzzzzz z z z zz z !!!!!!!!!
Answer:
circle: ( 1, 0.5 )
square: ( 4.5, 3.5 )
triangle: ( 0, 2.5 )
Step-by-step explanation:
The table shows the scores of students recent test. Find the mean of the scores and round to the nearest hundredth
Answer:
Answer and work is in the pdf
Step-by-step explanation:
75+75+80+80+80+80+80+80+85+85+90+90+90+90+90+90+95+95+95+100+100+100+100+100+100
=2,425
2+6+2+6+3+8
=27
2,425/27=89.81
The mean is 89.81
You have an order for an 8-gallon aquarium that is 20 in long and 10.5 in wide. How deep should the aquarium be?
Answer:
8.8
Step-by-step explanation:
Find the equation in slope-intercept form for the line with a slope of 5/4 and passes through the point (8, 2)
Answer:
92/37
Step-by-step explanation:
Tossing of a fair coin infinitely many times. Define (1, if head shows, X(t)= for nT
Tossing of a fair coin infinitely many times. The process X(t) can be defined as follows:
- X(t) = 1 if a head shows up at time t, where t = nT for some positive integer n.
- X(t) = 0 if a tail shows up at time t.
In the given scenario, we are considering the tossing of a fair coin infinitely many times. We want to define a process X(t) that represents the outcome of each toss at different time points.
The process X(t) is defined as 1 when a head shows up at time t, where t is a multiple of T (the fixed time interval between tosses). In other words, X(t) takes the value 1 when t is of the form nT, where n is a positive integer.
Conversely, X(t) is defined as 0 when a tail shows up at time t. This includes all time points that are not of the form nT.
The process X(t) is a representation of the outcome of the coin tosses over time. It takes the value 1 when a head shows up at time t = nT for some positive integer n, and 0 when a tail shows up. This process allows us to track the occurrences of heads at specific time intervals in the infinite sequence of coin tosses.
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Compare lengths. Select >, <, or = .
900 cm _ 9 m
Answer:
900 cm = 9 m
Step-by-step explanation:
9 m = 900 cm
Therefore, 9 m equals 900 cm.
Point E is located at (-8,7). Point F is located at (9,7).
What is the distance, in units, between point E and point F?
Answer:
18 units to the right.
Step-by-step explanation:
Hope this helps!
At a birthday party pizzas and sodas were purchased for the kids. The number of sodas bought was two more than three times the number of pizzas. Pizzas cost $9.50 each and sodas cost $1.25 each. (ANSWER A AND B PLEASEEEEEEE I REALLY NEED HELP!!!!)
A). If 8 pizzas were bought, how many sodas were bought?
B). How much was the total money would be spent on the pizza and sodas from (A)?
THANK YOU SOOOOO MUCH!!!! :))))))
Answer:
61
Step-by-step explanation:
Givens
Let the pizzas = x
Let the sodas = y
Equation
y = 3x + 2
Part A
y = 3*8 + 2
y = 24 + 2
y = 26
Part B
Sodas = 26* 1.25 = 32.50
Pizzas =9.50 * 3 = 28.50
Total for both = 32.50 + 28.50 = 61
Find the total amount owed, to the nearest cent, for the following simple interest loans.
(Step-by-step explanation)
a. $525 loan at 9.9% interest for 6 months
b. $12,460 loan at 5.6% interest for 30 months
a. The total amount owed for the $525 loan at 9.9% interest for 6 months is approximately $556.19 when rounded to the nearest cent.
b. The total amount owed for the $12,460 loan at 5.6% interest for 30 months is approximately $33,504.80 when rounded to the nearest cent.
a. To calculate the total amount owed for the $525 loan at 9.9% interest for 6 months, we can use the formula for simple interest:
Total amount owed = Principal + (Principal × Interest Rate × Time)
Given:
Principal (P) = $525
Interest Rate (R) = 9.9% = 0.099 (converted to decimal)
Time (T) = 6 months
Plugging these values into the formula, we get:
Total amount owed = $525 + ($525 × 0.099 × 6)
Simplifying the equation:
Total amount owed = $525 + ($31.185)
Total amount owed = $556.185
Therefore, the total amount owed for the $525 loan at 9.9% interest for 6 months is approximately $556.19 when rounded to the nearest cent.
b. To calculate the total amount owed for the $12,460 loan at 5.6% interest for 30 months, we'll follow the same formula for simple interest:
Total amount owed = Principal + (Principal * Interest Rate * Time)
Given:
Principal (P) = $12,460
Interest Rate (R) = 5.6% = 0.056 (converted to decimal)
Time (T) = 30 months
Plugging these values into the formula, we get:
Total amount owed = $12,460 + ($12,460 * 0.056 * 30)
Simplifying the equation:
Total amount owed = $12,460 + ($21,044.8)
Total amount owed = $33,504.8
Therefore, the total amount owed for the $12,460 loan at 5.6% interest for 30 months is approximately $33,504.80 when rounded to the nearest cent.
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Show explicitly that the following functions: (a) (x+at)², (b) 2e-(x-at) ², 7 satisfy the wave equation J²u(x, t) Ət² = (c) 5 sin[3 (x - at)] + (x + at). ₂d²u(x, t) dx²
Each satisfies the wave equation.
We are given the functions as follows:
(a) (x+at)², (b) 2e-(x-at) ², 7 satisfy the wave equation J²u(x, t) Ət² = (c) 5 sin[3 (x - at)] + (x + at).
₂d²u(x, t) dx²
Let us prove that they satisfy the wave equation using the formula of the wave equation. Wave equation is given by;
J²u(x, t) Ət² = ₂d²u(x, t) dx²
Applying the partial derivative to
(a) with respect to time, t, we obtain:
2a(x+at)
The second partial derivative with respect to x is as follows:
2a
By substituting these results into the wave equation, we have:
J²u(x, t) Ət² = ₂d²u(x, t) dx²
(2a(x+at)) = 2aJ²u(x, t) Ət² = 2a
Ət² = 1/J².
Thus, (a) satisfies the wave equation.
For part (b), let us begin by taking the partial derivative of the function with respect to time, t. This is given by:
-4a e^-(x-at) ²
By taking the second partial derivative with respect to x, we get:4a e^-(x-at) ²
Similar to above, we substitute these results into the wave equation as follows:
J²u(x, t) Ət² = ₂d²u(x, t) dx²
-4a e^-(x-at) ² = 4aJ²u(x, t) Ət² = -4a e^-(x-at) ²/J²
Ət² = -1/J²e^-(x-at) ².
Thus, (b) satisfies the wave equation.
For part (c), let us calculate the partial derivative with respect to t as follows:
5a cos[3(x-at)] + a
The second partial derivative with respect to x is given by:-
15a sin[3(x-at)]
By substituting these results into the wave equation, we have:
J²u(x, t) Ət² = ₂d²u(x, t) dx²
(5a cos[3(x-at)] + a) = -15a
sin[3(x-at)]J²u(x, t) Ət² = -15a
sin[3(x-at)]/(5a cos[3(x-at)] + a)
Ət² = -3 sin[3(x-at)]/(cos[3(x-at)] + 1/5).
Thus, (c) satisfies the wave equation.
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Integrate the function y = f(x) between x = 2.0 to x = 2.8, using Simpson's 1/3 rule with 6 strips. Assume a = 1.2, b = -0.587
y = ax2/(b+ x2)
Using Simpson's [tex]\frac{1}{3}[/tex] rule with 6 strips, the approximate value of the integral ∫[2.0, 2.8] f(x) dx is -3.8492.
To integrate the function [tex]\begin{equation}y = f(x) = \frac{ax^2}{b + x^2}[/tex] using Simpson's 1/3 rule, we need to divide the interval [2.0, 2.8] into an even number of strips (in this case, 6 strips). The formula for approximating the integral using Simpson's 1/3 rule is as follows:
[tex]\begin{equation}\int_a^b f(x) dx \approx \frac{h}{3} \left[ f(x_0) + 4f(x_1) + 2f(x_2) + 4f(x_3) + ... + 2f(x_{n-2}) + 4f(x_{n-1}) + f(x_n) \right][/tex]
Where:
h is the width of each strip ([tex]\begin{equation}h = \frac{b - a}{n}[/tex], where n is the number of strips)
[tex]x_0[/tex] is the lower limit (2.0)
[tex]x_n[/tex] is the upper limit (2.8)
f(xi) represents the function evaluated at each strip's midpoint
Given the values of a = 1.2 and b = -0.587, we can proceed with the calculations.
Step 1: Calculate the width of each strip (h):
[tex]\begin{equation}h = \frac{b - a}{n} = \frac{-0.587 - 1.2}{6} = \frac{-1.787}{6} \approx -0.2978[/tex]
Step 2: Calculate the function values at each strip's midpoint:
x₀ = 2.0
x₁ = x₀ + h = 2.0 + (-0.2978) = 1.7022
x₂ = x₁ + h = 1.7022 + (-0.2978) = 1.4044
x₃ = x₂ + h = 1.4044 + (-0.2978) = 1.1066
x₄ = x₃ + h = 1.1066 + (-0.2978) = 0.8088
x₅ = x₄ + h = 0.8088 + (-0.2978) = 0.511
x₆ = x₅ + h = 0.511 + (-0.2978) = 0.2132
xₙ = 2.8
Step 3: Evaluate the function at each midpoint:
[tex]f(x_0) = \frac{1.2 \times 2^2}{-0.587 + 2^2} = \frac{4.8}{3.413} \approx 1.406 \\\\f(x_1) = \frac{1.2 \times 1.7022^2}{-0.587 + 1.7022^2} \approx 2.445 \\\\f(x_2) = \frac{1.2 \times 1.4044^2}{-0.587 + 1.4044^2} \approx 2.784 \\\\f(x_3) = \frac{1.2 \times 1.1066^2}{-0.587 + 1.1066^2} \approx 2.853 \\\\[/tex]
[tex]f(x_4) = \frac{1.2 \times 0.8088^2}{-0.587 + 0.8088^2} \approx 2.455 \\f(x_5) = \frac{1.2 \times 0.511^2}{-0.587 + 0.511^2} \approx 1.316 \\f(x_6) = \frac{1.2 \times 0.2132^2}{-0.587 + 0.2132^2} \approx 0.29[/tex]
Step 4: Apply Simpson's 1/3 rule formula:
[tex]\begin{equation}\int_{2.0}^{2.8} f(x) dx \approx \frac{h}{3} \left[ f(x_0) + 4f(x_1) + 2f(x_2) + 4f(x_3) + 2f(x_4) + 4f(x_5) + f(x_6) \right][/tex]
[tex]\begin{equation}\approx \frac{-0.2978}{3} \left[ 1.406 + 4(2.445) + 2(2.784) + 4(2.853) + 2(2.455) + 4(1.316) + 0.29 \right][/tex]
[tex]\begin{equation}= \frac{-0.2978}{3} \left[ 1.406 + 9.78 + 5.568 + 11.412 + 4.91 + 5.264 + 0.29 \right][/tex]
≈ (-0.09926) * 38.63
≈ -3.8492
Therefore, the approximate value of the integral ∫[2.0, 2.8] f(x) dx using Simpson's 1/3 rule with 6 strips is approximately -3.8492.
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30 POINTS!!! HELP!!!!
Please help and explain, please no links, thank you
Answer:
The two triangles are related by angles, so the triangles are similar but not proven to be congruent.
Step-by-step explanation:
Because the triangles have the same angles, they are congruent. The definition of congruence is if you take a shape and scale it up or down (or keep it the same) therefore, they are congruent.
Hope this helped, have a nice day
EDIT: I screwed up, I thought it was supposed to be similar. These triangles are SIMILAR not congruent. The actual answer is they are related by AAA similarity but they are similar, but they are not proven to be congruent. Hope this clears it up, and sorry.
~cloud
Reagan rides on a playground roundabout with a radius of2.5 feet. To the nearest foot, how far does Reagan travel over an angle of 4π/3 radians?
Answer:
10 feets
Step-by-step explanation:
Given that:
Angle, θ = 4π/3
Radius, r = 2.5 feets
To obtain how Far Reagan traveled, we calculate the Length of the arc, s
s = r*θ
s = 2.5 feets * 4π/3
s = 10π/3
s = 10.4719
To the nearest foot ; distance traveled by Reagan is 10 feets
What is the answer to this question?
Answer:
what should i answer?
Step-by-step explanation:
sound travels at 320.29 meters per second at sea level. how many miles will sound travel at sea level in 7 seconds?
round off the answer to the nearest thousandths
thx in advance
Answer:
1.393 milesExplanation:
320.29 × 7 = 2,242.03 m = 1.39313285413187 miles ≈ 1.393
A horse runs three races. The first is 2 miles, the second is 1,300 yards, and the last is 850 yards. How many yards does the horse run in all
Answer:
5670 yards
Step-by-step explanation:
Length of first race = 2 miles
Since, 1 mile = 1760 yards
Therefore, 2 miles = 1760 × 2
= 3520 yards
Length of second race = 1300 yards
Length of third race = 850 yards
Total distance to be run by the horse = 3520 + 1300 + 850
= 5670 yards
A system of linear equations is graphed.
Which ordered pair is the best estimate for the solution to the system?
(−4, 2 1/2)
(0, −2)
(−4 1/2, 2 1/2)
(0, 7)
The best estimate for the solution to the system of linear equations among the given ordered pairs is (-4, 2 1/2).
In the context of a system of linear equations, the solution represents the values of the variables that satisfy all the equations simultaneously. To determine the best estimate for the solution, we need to evaluate each ordered pair and see which one satisfies the given system.
By substituting the values of the ordered pairs into the equations of the system, we can determine if they satisfy the equations or not. Among the given options, when substituting (-4, 2 1/2) into the system of linear equations, it is likely to result in a solution that satisfies all the equations. Therefore, it is important to consider the specific equations and the context of the problem to determine the best estimate for the solution.
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T=21and u =4 what is \sqrt(t+U)
Answer: 5
Step-by-step explanation: 21 + 4 = 25
square root of 25 = 5
Answer and Step-by-step explanation:
T = 21
U = 4
[tex]\sqrt{ 21 + 4} \\\\\\\sqrt{25} \\\\\\5[/tex]
5 is the answer to the expression.
#teamtrees #PAW (Plant And Water)
If Θˆ 1 and Θˆ 2 are unbiased estimators of the same parameter θ, what condition must be imposed on the constants k1 and k2 so that k1Θˆ 1 + k2Θˆ 2 is also an unbiased estimator of θ?
The condition imposed on the constants k₁ and k₂ for k₁Θ⁻₁ + k₂Θ⁻₂ to be an unbiased estimator of θ is that their sum must equal 1.
For k₁Θ⁻₁ + k₂Θ⁻₂ to be an unbiased estimator of θ, its expected value should be equal to θ. In other words, we want to find the conditions on k₁ and k₂ such that E(k₁Θ⁻₁ + k₂Θ⁻₂) = θ.
Given that Θ⁻₁ and Θ⁻₂ are unbiased estimators of θ, we have:
E(Θ⁻₁) = θ
E(Θ⁻₂) = θ
Now, let's calculate the expected value of k₁Θ⁻₁ + k₂Θ⁻₂:
E(k₁Θ⁻₁ + k₂Θ⁻₂) = k₁E(Θ⁻₁) + k₂E(Θ⁻₂)
Since E(Θ⁻₁) = θ and E(Θ⁻₂) = θ, we can substitute these values into the equation:
E(k₁Θ⁻₁ + k₂Θ⁻₂) = k₁θ + k₂θ
To make sure this expression is equal to θ, we need:
k₁θ + k₂θ = θ
This implies that k₁ + k₂ = 1. Therefore, the condition imposed on the constants k₁ and k₂ for k₁Θ⁻₁+ k₂Θ⁻₂ to be an unbiased estimator of θ is that their sum must equal 1.
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Which of the following is true?
Answer:
option B should be correct
Pre-image ABCD was dilated to produce image A'B'C'D' What is the scale factor from the pre-image to the image?
Answer:
The answer is 3/4
Step-by-step explanation:
What is the difference between 3/4 and one
Answer:
3/4 is 0.75 and 1 is 1
Step-by-step explanation:
:\
Which of the following are among the five basic postulates of Euclidean geometry? Check all that apply.
A. All circles have 360 degrees
B. A straight line segment can be drawn between any two points.
C. A straightedge and compass can be used to create a triangle.
D. Any straight line segment can be extended indefinitely.
Answer:
B and D.
Step-by-step explanation:
A p e x
The following are among the five basic postulates of Euclidean geometry
A straight line segment can be drawn between any two points.Any straight line segment can be extended indefinitely.The five basic postulates of Euclidean geometry
The five (5) basic postulates are:
Any segment of a straight line connecting any two points can be drawn.You can draw and stretch any straight line to any finite length.Given a centre and radius, circles are drawn.Congruent angles are always right angles.There is a line that is parallel to the given line if a given point is not on the supplied line.Learn more about Euclidean Geometry here:
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