Answer:
6.5
Step-by-step explanation:
you take the sides all added up (which was 13in) and divided it by two
Answer: the answer is 18. Trust me. I know what I’m doing lol
Step-by-step explanation:
Find the distance between the two points (-4,1) (4,5)
Joanne has a health insurance plan with a $1000 calendar-year deductible, 80% coinsurance, and a $5,000 out-of-pocket cap. Joanne incurs $1,000 in covered medical expenses in March, $3,000 in covered expenses in July, and $30,000 in covered expenses in December. How much does Joanne's plan pay for her July losses? (Do not use comma, decimal, or $ sign in answer)
Joanne's plan pays $2400 for her July losses, as she is responsible for 20% of the covered expenses during that month.
Joanne's health insurance plan with a $1000 deductible, 80% coinsurance, and a $5000 out-of-pocket cap requires her to pay for her medical expenses until she reaches the deductible.
After reaching the deductible, she is responsible for 20% of the covered expenses, up to the out-of-pocket cap. The plan pays the remaining percentage of covered expenses.
To calculate how much the plan pays for Joanne's July losses, we need to consider her deductible, coinsurance, and out-of-pocket cap.
In March, Joanne incurs $1000 in covered medical expenses.
Since this amount is equal to her deductible, she is responsible for paying the full amount out of pocket.
In July, Joanne incurs $3000 in covered expenses. Since she has already met her deductible, the coinsurance comes into play.
According to the plan's coinsurance rate of 80%,
Joanne is responsible for 20% of the covered expenses.
Therefore, Joanne is responsible for paying 20% of $3000, which is $600.
The plan will pay the remaining 80% of the covered expenses, which is $2400.
In December, Joanne incurs $30,000 in covered expenses. Since she has already met her deductible and reached her out-of-pocket cap, the plan pays 100% of the covered expenses.
Therefore, the plan will pay the full $30,000 for her December losses.
To summarize, Joanne's plan pays $2400 for her July losses, as she is responsible for 20% of the covered expenses during that month.
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Find the probability P(not E) if P(E)=0.39.
The probability P(not E) is _______ (Simplify your answer.)
The probability that the event E does not happen is:
P(not E) = 0.61
How to find the probability?First, remember that for any experiment with N outcomes, the sum of the N probabilities for these outcomes must be 1.
Then if we have two outcomes, E happens or E does not happen, we have:
P(E) + P(not E) = 1
Replace the value that we know:
0.39 + p(not E) = 1
Solve for the probability we want:
P(not E) = 1 - 0.39
P(not E) = 0.61
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Assuming that P ? 0, a population is modeled by the differential equation
dP/dt = 1.1P(1-P/4100)
1. For what values of P is the population increasing? Answer (in interval notation):
2. For what values of P is the population decreasing? Answer (in interval notation):
3. What are the equilibrium solutions? Answer (separate by commas): P =
1. The population is increasing for 0 < P < 4100. The answer in interval notation is (0, 4100).
2. The population is decreasing for P > 4100. The answer in interval notation is (4100, ∞).
3. The equilibrium solutions are P = 0 and P = 4100.
To determine when the population is increasing or decreasing, we need to examine the sign of the derivative dP/dt.
1. For what values of P is the population increasing?
The population is increasing when dP/dt > 0.
In this case, we have dP/dt = 1.1P(1 - P/4100).
To find the values of P for which the population is increasing, we need to solve the inequality 1.1P(1 - P/4100) > 0.
To do this, we can consider the sign of each factor:
1.1 is positive.
P is the variable.
(1 - P/4100) is positive when P < 4100 and negative when P > 4100.
From this, we can determine the intervals where the population is increasing:
When P < 0 (since P cannot be negative in a population context), the term 1.1P is negative, so the entire expression is negative. The population is not increasing in this interval.
When 0 < P < 4100, both 1.1P and (1 - P/4100) are positive, so the entire expression is positive. The population is increasing in this interval.
When P > 4100, 1.1P is positive, but (1 - P/4100) is negative. The entire expression is negative. The population is not increasing in this interval.
Therefore, the population is increasing for 0 < P < 4100. The answer in interval notation is (0, 4100).
2. For what values of P is the population decreasing?
The population is decreasing when dP/dt < 0.
In this case, we have dP/dt = 1.1P(1 - P/4100).
To find the values of P for which the population is decreasing, we need to solve the inequality 1.1P(1 - P/4100) < 0.
Using the same analysis as in the previous part, we can determine the intervals where the population is decreasing:
When P < 0, the population is not decreasing.
When 0 < P < 4100, the population is not decreasing.
When P > 4100, the population is decreasing.
Therefore, the population is decreasing for P > 4100. The answer in interval notation is (4100, ∞).
3. What are the equilibrium solutions?
Equilibrium solutions occur when the population remains constant, meaning dP/dt = 0.
In this case, we have dP/dt = 1.1P(1 - P/4100)
= 0.
To find the equilibrium solutions, we solve the equation 1.1P(1 - P/4100) = 0.
This equation is satisfied when either 1.1P = 0 or (1 - P/4100) = 0.
From 1.1P = 0, we have P = 0.
From (1 - P/4100) = 0, we have P = 4100.
Therefore, the equilibrium solutions are P = 0 and P = 4100.
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if the rate of change of f at x = c is twice its rate of change at x =1
The function f(x) is more steeply increasing at all points x than it is at x=1.
If the rate of change of f at x=c is twice its rate of change at x=1, then f(x) is said to be more steeply increasing at x=c than at x=1.
The rate of change of a function f(x) at any point x can be calculated by differentiating the function f(x).
That is, the derivative of the function f(x) gives the rate of change of the function at any point x.
If the rate of change of f(x) at x=1 is f'(1), and its rate of change at x=c is f'(c), then we have f'(c) = 2f'(1)
We can see that f(x) is more steeply increasing at x=c than at x=1 if and only if f'(c) > f'(1).
Since f(x) is twice as steep at x=c than at x=1, we can conclude that f'(c) > f'(1) for all c.
That is, the rate of change of f(x) is greater at any point x=c than at x=1.
Therefore, the function f(x) is more steeply increasing at all points x than it is at x=1.
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Let AA and BB be two mutually exclusive events, such that P(A)=0.2272P(A)=0.2272 and P(B)=0.4506P(B)=0.4506. Find the following probability:
The probability that the events do not occur is 0.6778`.
The probability that the events do not occur is given by `P(Ac)=1-P(A)` and `P(Bc)=1-P(B)`.
The given probabilities are `P(A)=0.2272` and `P(B)=0.4506`.
Using the formula `P(A∪B)=P(A)+P(B)-P(A∩B)`, we have `P(A∩B) = P(A) + P(B) - P(A∪B)`
Using the fact that the two events are mutually exclusive, we get `P(A∩B) = 0`.
Thus, `P(A∪B) = P(A) + P(B) = 0.2272 + 0.4506 = 0.6778`.
The probability that either A or B but not both occurs is given by `P(AΔB) = P(A∪B) - P(A∩B) = 0.6778 - 0 = 0.6778`.
Hence, the required probability is `P(AΔB) = 0.6778`.
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suppose the superhero had flown 150 m at an 120 degree angle with respect to the positive x axis find the component of displacemnet vector
The component of the displacement vector are: Horizontal component = -75 m Vertical component = 129.9 m (approx)
Given that the superhero flew 150 m at an angle of 120° with respect to the positive x-axis. We need to find the components of displacement vector.
Let's consider the given figure: Here, AB represents the displacement vector. AC represents the horizontal component of displacement vector and BC represents the vertical component of displacement vector.
The horizontal component can be calculated as: AC = AB cos θ
Here, θ = 120° and AB = 150 mAC = 150 cos 120°AC = -75 m (Negative sign indicates that the displacement is in the negative direction of the x-axis)
The vertical component can be calculated as: BC = AB sin θHere, θ = 120° and AB = 150 mBC = 150 sin 120°BC = 129.9 m (Approx)
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Given information: A superhero flew 150 m at a 120-degree angle with respect to the positive x-axis. The x-component of the displacement vector is 75 m and the y-component of the displacement vector is 129.9 m.
Components of displacement vector: The component of displacement vector with respect to the x-axis is called the x-component of displacement vector.
Similarly, the component of displacement vector with respect to the y-axis is called the y-component of displacement vector.
As per the given information, the angle of displacement vector is 120 degrees with respect to the positive x-axis.
So, the angle of the vector with respect to the negative x-axis is 180 - 120 = 60 degrees (supplementary angles).
Now, the horizontal component (x-component) of the vector is given by the product of the magnitude and the cosine of the angle with respect to the x-axis.
Let the x-component of displacement vector be x.
Then, x = 150 cos 60°
x = 75 m.
The vertical component (y-component) of the vector is given by the product of the magnitude and the sine of the angle with respect to the x-axis.
Let the y-component of displacement vector be y.
Then, y = 150 sin 60°
y = 129.9 m.
Therefore, the x-component of the displacement vector is 75 m and the y-component of the displacement vector is 129.9 m.
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A variable X has a probability density function:
F(x) = k x² for -1
Calculate:
(a) The value of the constant K;
(b) The mean and variance of X;
(c) The cumulative distribution function of
To find the value of the constant k, we need to integrate the probability density function (PDF) over its entire range and set it equal to 1, since the total area under the PDF should be 1.
(a) Calculating the value of the constant K:
∫[from -1 to 1] kx² dx = 1
Integrating, we get:
(k/3) [x³] from -1 to 1 = 1
(k/3)(1³ - (-1)³) = 1
(k/3)(1 + 1) = 1
(2k/3) = 1
2k = 3
k = 3/2
Therefore, the value of the constant k is 3/2.
(b) Calculating the mean and variance of X:
To find the mean (μ), we need to calculate the expected value of X. Since the PDF is symmetric around x = 0, the mean will be 0.
μ = 0
To find the variance (σ²), we need to calculate the second moment of X around its mean.
σ² = ∫[from -1 to 1] x² * f(x) dx
Substituting the PDF f(x) = (3/2)x²:
σ² = ∫[from -1 to 1] x² * (3/2)x² dx
σ² = (3/2) ∫[from -1 to 1] x^4 dx
σ² = (3/2) * (1/5) [x^5] from -1 to 1
σ² = (3/2) * (1/5) * (1^5 - (-1)^5)
σ² = (3/2) * (1/5) * (1 - (-1))
σ² = (3/2) * (1/5) * 2
σ² = 3/5
Therefore, the mean of X is 0, and the variance is 3/5.
(c) The cumulative distribution function (CDF) of X is found by integrating the PDF from negative infinity to x:
F(x) = ∫[from -∞ to x] f(t) dt
For the given PDF f(x) = (3/2)x², the cumulative distribution function can be calculated as follows:
F(x) = ∫[from -∞ to x] (3/2)t² dt
F(x) = (3/2) ∫[from -∞ to x] t² dt
F(x) = (3/2) * (1/3) [t³] from -∞ to x
F(x) = (1/2) x³
Therefore, the cumulative distribution function (CDF) of X is F(x) = (1/2) x³.
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Find critical value t*n−1 depends on the confidence level, C, and the number of degrees of freedom, n−1.
Find The confidence interval for the population mean, μ is y±t*n−1sn, where y is the sample mean, s is the sample standard deviation, and n is the sample size. The critical value t*n−1
The confidence interval for the population mean, μ is y ± t*n-1sn, where y is the sample mean, s is the sample standard deviation, and n is the sample size.
The critical value t*n-1 depends on the confidence level, C, and the number of degrees of freedom, n-1.Critical value t*n−1:The critical value t*n-1 refers to the value of t that separates the middle 100C% of the t distribution from the extreme (tail) regions, where C is the specified confidence level.
The number of degrees of freedom is n - 1. A t-value can be used to determine the confidence interval for a population mean with unknown standard deviation if the sample size is less than 30 or the population is not normally distributed.
Confidence interval:If y is the sample mean and s is the sample standard deviation, the confidence interval for the population mean μ is y ± t*n-1sn, where n is the sample size. The confidence interval is a range of values around the sample statistic that is likely to contain the true population parameter. The confidence interval is used to estimate the value of an unknown parameter, such as a population mean or proportion, and to quantify the level of uncertainty surrounding that estimate.
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Thank you in advance.
PLEASE HELP ME PUT THEM IN ORDER
Answer
picture below of order. Not entirely
Step-by-step explanation:
if square root of x = -7 does x= -49
Answer:
x does not equal - 49.
x = 49
Step-by-step explanation:
To find the square you multiply the square root.
- 7 × - 7 = 49
x ≠ - 49
x = 49
Which of the following expressions results in 0 when evaluated at x = 3?
(x + 3)(x + 12)
(x + 20)(x - 3)
-20x(x + 3)
(x + 8)(x - 5)
Find Sn for the following arithmetic sequences described.
a1 = 132, d = -4, an = 52
Answer:
We can use the formula for the nth term of an arithmetic sequence to find n:
an = a1 + (n - 1)d
Substituting the given values, we get:
52 = 132 + (n - 1)(-4)
Simplifying and solving for n, we get:
n = 21
So, the sequence has 21 terms.
We can use the formula for the sum of the first n terms of an arithmetic sequence to find Sn:
Sn = n/2(2a1 + (n - 1)d)
Substituting the given values, we get:
Sn = 21/2(2(132) + (21 - 1)(-4))
Simplifying, we get:
Sn = 21/2(264 - 80)
Sn = 21/2(184)
Sn = 1932
Therefore, the sum of the first 21 terms of the arithmetic sequence is 1932.
The mathematical sentence that describes the inequality 5n - 10 > 26 is: Ten subtracted from 5 times n is greater than 26. I hope this mathematical sentence is what you are looking for,
Write the inequality in words.
5n – 10 > 26
A. Ten less than a number is less than or equal to twenty-six.
B. Ten less than five times a number is greater than twenty-six.
C. Five times n less than ten is twenty-six.
D. Ten plus five times n is less than or equal to twenty-six.
Answer:
Write the inequality in words.
5n – 10 > 26
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
n > 36/5
Interval Notation:
(36/5, ∞)
THANKS
0
Answer:
B. Ten less than five times a number is greater than twenty-six.
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Inequality Form:
n > 36 /5
Interval Notation:
( 36 /5 , ∞ )
Given the definitions of f(x) and g(x) below, find the value of f(g(-1)).
f(x) = x^2+ x + 10
g(x) -5x-3
Answer:
16
Step-by-step explanation:
Given the definitions of f(x) and g(x) below,
f(x) = x^2+ x + 10
g(x) = -5x-3
f(g(x)) = f(-5x-3)
f(-5x-3) = (-5x-3)²+((-5x-3)+10
f(-5x-3) = 25x²+30x+9-5x-3+10
f(-5x-3) = 25x² +25x+16
f(g(x)) = 25x² +25x+16
f(g(-1)) = 25(-1)² +25(-1)+16
f(g(-1)) = 25-25 + 16
f(g(-1)) = 16
Hence f(g(-1)) is 16
Triangle EFG is dilated by a scale factor of 1/4 to form triangle E'F'G'. Side E'F' measures 12.512.5. What is the measure of side EF?
Answer: 3.125
Step-by-step explanation:
Given
Triangle is dilated by a factor of [tex]\frac{1}{4}[/tex] i.e. each side multiplies to 0.25.
Side E'F' becomes 0.25 times the original length
[tex]\Rightarrow E'F'=\dfrac{1}{4}\times 12.5=3.125[/tex]
Find the inverse of the function and state its domain and range. {(-3, 4), (-1,5), (0, 2), (2, 6), (5, 7)} a. {(4, -3), (5, -1), (2.0), (6,2), (7,5)} D = {2, 4, 5, 6, 7); R = {-3, 1,0, 2, 5) b. {(3, 4), (1,5), (0, 2), (-2, 6), (-5, 7)); D = (3, 1,0.-2. -5); R = {2, 4, 5, 6, 7} O (3.-4), (1,-5), (0, -2), (-2, -6). (-5, -7)}; D = (3, 1, 0, -2. -5); R = (-7 -6, -5, -4.-2} c. [(-3.-4), (-1, 5), (0.2). (2. -6), (5,-2)}; D = (-3, 1.0, 2.5); R = (-7 -6, 5, 4-2)
The inverse function is obtained by interchanging the x and y values of each point. The correct option is b: {(3, 4), (1, 5), (0, 2), (-2, 6), (-5, 7)}; D = {3, 1, 0, -2, -5}; R = {4, 5, 2, 6, 7}.
The domain of the inverse function consists of the x-values from the original function, and the range consists of the y-values from the original function
To compute the inverse of the function, we interchange the x and y values of each point. The inverse function is {(4, 3), (5, 1), (2, 0), (6, -2), (7, -5)}.
The domain of the inverse function is D = {3, 1, 0, -2, -5} which consists of the x-values from the original function. The range of the inverse function is R = {4, 5, 2, 6, 7} which corresponds to the y-values from the original function.
It's important to note that in the inverse function, the roles of the domain and range are swapped. The x-values of the original function become the y-values of the inverse function, and vice versa.
Therefore, the correct answer is option b: {(3, 4), (1, 5), (0, 2), (-2, 6), (-5, 7)}; D = {3, 1, 0, -2, -5}; R = {4, 5, 2, 6, 7}.
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for the variable A type the word lambda, fory type the word gamma, otherwise treat these as you would any other variable We will solve the heat equation -6, 0
The required heat equation is u(x, t) = (A×cos(λx) + B×sin(λx)) × exp(-λ²t)
To solve the heat equation in the given interval [-6, 0], we can use the separation of variables method. Let's denote the dependent variable as u(x, t), where x represents the spatial variable and t represents the temporal variable.
The heat equation in one dimension is given by:
∂u/∂t = α ∂²u/∂x²,
where α is the thermal diffusivity constant.
To solve this equation, we assume that the solution can be represented as a product of two functions, each depending on a single variable:
u(x, t) = X(x)T(t).
Substituting this into the heat equation, we have:
X(x)T'(t) = αX''(x)T(t),
where prime (') denotes differentiation with respect to the variable.
Dividing both sides by αX(x)T(t), we get:
T'(t)/T(t) = αX''(x)/X(x).
Since the left side depends only on t and the right side depends only on x, both sides must be equal to a constant, which we'll denote as -λ²:
T'(t)/T(t) = -λ² = αX''(x)/X(x).
Now, let's solve the temporal part of the equation:
T'(t)/T(t) = -λ²
This is a separable ordinary differential equation (ODE), and its general solution is given by:
T(t) = exp(-λ²t).
Next, let's solve the spatial part of the equation:
αX''(x)/X(x) = -λ².
This is also a separable ODE, and its general solution is given by:
X(x) = A×cos(λx) + B×sin(λx),
where A and B are arbitrary constants.
Therefore, the general solution to the heat equation is:
u(x, t) = (A×cos(λx) + B×sin(λx)) × exp(-λ²t).
Since we have the given interval [-6, 0], we can apply appropriate boundary conditions to determine the values of A, B, and λ that satisfy the problem.
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4.40 divided by 0.08
Answer:
55
Step-by-step explanation:
Find the slope of the line
Answer:
m = 3/4
Step-by-step explanation:
slope of a line equation:
[tex]m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
m = (3-0)/(2-(-2))
m = 3/4
12. What is the equation of the following parabola?
A y = 2(x + 1)2 - 4
B y = 3(x - 1)2 - 4
C y = 3(x + 1)2 - 4
Dy=2(x - 1)2 - 4
Answer:
c
Step-by-step explanation:
4) A store donated 4 72 dozen cookies for a
fundraiser. Another store donated 3 14 dozen
cookies. How many dozen cookies did they
donate altogether?
Both the stores together donated 65.5 dozen cookies.
Solve the equation for a.
3a+13.61=−9.43
Answer: a = -7.68
STEPS:
- Subtract 13.61 from both sides
- Simplify
- Divide both sides by 3
Arthur has a balance of $2330 on his credit card, which he plans to pay off by
making a payment of the same amount each month. Which of these monthly
amounts will allow Arthur to pay off his balance the fastest?
Answer:
C. $80
Step-by-step explanation:
A. $70
B. $65
C. $80
D. $75
When he pays $70 monthly
Number of months = $2330 / $70
= 33.3 months
When he pays $65 monthly
Number of months = $2330 / $65
= 35.9 months
When he pays $80 monthly
Number of months = $2330 / $80
= 29.1 months
When he pays $75 monthly
Number of months = $2330 / $75
= 31.1 months
The monthly amounts that will allow Arthur to pay off his balance the fastest is $80 per month
answer this for 15 and branlyist
Answer:
Financial Literacy = 25
Model with mathematics:
a) cranes = 40 panthers = 40
b) yes, finding the mean is a good way of determining which team has the better record, because "finding the mean" is just finding the average.
Step-by-step explanation:
Financial Literacy:
24 = [tex]\frac{x+15+20+10+12+20+16+80+18}{9}[/tex] → [tex]24 = \frac{191}{9}[/tex]
24×9=x · 191
→ 216 = x · 191
→ 216-191=x
x = 25
Model with Mathematics:
Add all six wins and divide by how many seasons there are. (do it for both sides. Also, I'm too lazy to type it out.)
Part B
What percentage of Americans would you predict wear glasses?
Answer: 64%
75% of adults use some sort of vision correction. About 64% of them wear eyeglasses, and about 11% wear contact lenses, either exclusively, or with glasses. Over half of all women and about 42% of men wear glasses.
63.8% of Americans are predicted to wear glasses
How to determine the percentage?The given parameters are:
Glasses = 638Sample size = 1000The percentage of Americans that wear glasses is calculated as:
Percentage = Glasses/Sample size
This gives
Percentage = 638/1000
Evaluate the quotient
Percentage = 0.638
Express as percentage
Percentage = 63.8%
Hence, 63.8% of Americans would wear glasses
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what is the range of the following data set ? 16, 19, 24, 27, 29, 32, , 33, 34
HELP!! :'(
An exponential function does not have a constant rate of change, but it has ____.
A. a slope
B. a parabolic shape
C. None of these
D. constant ratios
I am confused about this equation; 5x+2y=6, 7x+8y=-2 Does anyone think they can help me out?
Answer:
I cannot solve it step-by-step because like I'm helping other people cuz I'm busy with my homework so just I'm going to direct you the question you're supposed to solve simultaneous equation by any method example elimination method substitution method then you get the answer if you get stuck you can inform me