Which one of the following changes would cause the pressure of a gas to double assuming volume and moles were held constant?
A) Increasing the temperature from 20.0 °C to 40.0 °C.
B) Decreasing the temperature from 400 K to 200 K.
C) Increasing the temperature from 200K to 400K.
D) Decreasing the temperature from 40.0 °C to 20.0 °C.

H2 is the unknown gas if a gas mixture is made by combining 5.5 g each of Ar, Ne, and an unknown diatomic gas and at STP, the mixture occupies a volume of 70.31 L.

Why is there volume in gas?

Because their molecules are very loosely packed, contain wide intermolecular gaps, and move about, gases lack a distinct shape or volume. Because there is little to no attraction between molecules, gases can take on any shape or volume.

One mole of gas will take up 22.4 litres at typical conditions (0 °C and 1 atm). No matter what kind of petrol is being used, this is true. Since the relationship between volume and the number of moles of a gas is linear, two moles of any gas at STP should have twice the volume of one mole.

The total number of moles of Ar, Ne, and unknown gas, each with a mass of 7g, in the gas mixture is

= (5.5/40 + 5.5/20 + 5.5/m) mol

Total volume of all gases at STP:

(5.5/40 + 5.5/20 + 5.5/m) mol * 22.4 L/(mol) = 70.31L

(5.5/40 + 5.5/20)+ 5.5/m = 70.31L/ 22.4L

5.5/m  = 3.19 -0.4125

m  = 1.98 ≈ 2g/mol i.e. H2

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Answer: 2

Explanation: Greenhouse gases are very important in keeping our planet just right. If we have too many Greenhouse gases it would be too hot, but we can't eliminate all of them or it will be too cold

Based on the given pH scale, we can only conclude that baking soda is a weak base (option A).

According to the given pH scale, we can determine the strengths of various substances as acids or bases. Let's analyze each option:

A) Baking soda is listed with a pH of 9, which indicates it is a weak base. Bleach is not specifically mentioned in the given pH scale, so we cannot determine its classification based on the information provided. Therefore, option A cannot be concluded.

B) Coffee is listed with a pH of 4, indicating it is a weak acid. Drain cleaner is listed with a pH of 14, which suggests it is a strong base. Thus, option B is incorrect.

C) Oven cleaner is not specifically mentioned in the given pH scale, so we cannot determine its classification. Battery acid, on the other hand, is listed with a pH of 0, which indicates it is a strong acid. Therefore, option C cannot be concluded.

D) Soft drinking water is listed with a pH of 5, indicating it is a weak acid. Soapy water is not specifically mentioned, so we cannot determine its classification based on the information provided. Hence, option D is incorrect.

In summary, based on the given pH scale, we can only conclude that baking soda is a weak base (option A). The information provided does not allow us to determine the strengths of bleach, oven cleaner, or soapy water.

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Note- The question seems to be incomplete and the complete question isn't available in the search engine.

The ranking of the given fatty acids according to their melting point is Stearic acid > Palmitic acid > Lauric acid > Myristic acid > Oleic acid > Linoleic acid.

1. Stearic acid: Stearic acid has a long chain of 18 carbon atoms with no double bonds, resulting in a tightly packed structure. It has the highest melting point among the given fatty acids.

2. Palmitic acid: Palmitic acid also has a long chain of 16 carbon atoms with no double bonds. While it is slightly shorter than stearic acid, it still has a high melting point.

3. Lauric acid: Lauric acid contains 12 carbon atoms and no double bonds. It has a slightly lower melting point compared to palmitic acid and stearic acid.

4. Myristic acid: Myristic acid consists of 14 carbon atoms and no double bonds. It has a slightly lower melting point compared to lauric acid.

5. Oleic acid: Oleic acid is an unsaturated fatty acid with one double bond, located at the 9th carbon atom. It has a lower melting point compared to the saturated fatty acids listed above.

6. Linoleic acid: Linoleic acid is a polyunsaturated fatty acid with two double bonds, located at the 9th and 12th carbon atoms. It has the lowest melting point among the given fatty acids due to the presence of multiple double bonds, which disrupt the packing of the fatty acid chains.

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Answer:

what is cocococococo?

Explanation:

isnt it like a plant for choclate?

Answer:

hhhhhhhh

Explanation:

Answer:

20 km/h

Explanation:

Speed = distance ÷ time

Speed = 10 ÷ 0.5 hours

Speed = 20 km/hr

To calculate the standard reaction free energy (ΔG°) for the given redox reaction, we need to use the standard reduction potentials from the ALEKS data tab.

To calculate the standard reaction free energy (ΔG°) for the given redox reaction, we need to utilize the standard reduction potentials (E°) of the involved species. The ΔG° is related to the standard reduction potentials through the equation: ΔG° = -nFΔE°, where n represents the number of electrons transferred and F is the Faraday constant.

Let's analyze the reaction and identify the half-reactions to determine the number of electrons transferred.

Half-reaction 1: I2(s) + 2e- → 2I- (aq)

Half-reaction 2: Br2(l) + 2e- → 2Br- (aq)

Half-reaction 3: 6H2O (l) → 12H+ (aq) + 6e-

Half-reaction 4: 2IO3- (aq) + 12H+ (aq) + 10e- → I2 (s) + 6H2O (l)

By comparing the half-reactions, we can see that 5 electrons are transferred in the reaction.

For the oxidation reactions:

   2IO3- (aq) + 12H+ (aq) + 10Br- (aq) → I2 (s) + 6H2O (l) + 5Br2 (l): coefficient = 1

Now we can calculate ΔGᴰ:

ΔGᴰ = (1 * E°(I2/I-)) + (5 * E°(Br2/Br-)) + (3 * E°(H2O/O2)) - (1 * E°(IO3-/H2O/Br2))

Substituting the values:

ΔGᴰ = (1 * 0.536 V) + (5 * 1.087 V) + (3 * 1.229 V

ΔE° = E°(half-reaction 4) - [E°(half-reaction 1) + E°(half-reaction 2) + E°(half-reaction 3)]

After obtaining ΔE°, we can calculate the standard reaction free energy (ΔG°) using the equation ΔG° = -nFΔE°. Since we know n = 5 and F is a constant, we can substitute these values into the equation to calculate ΔG°.

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The correct option is A. Because Cl is more b electronegative than I.

Both ICH2COOH and ClCH2COOH are members of the carboxylic acid family. The acidity of carboxylic acids is generated by their carboxyl group (-COOH). When it comes to acidity, there are numerous factors to consider. The acidity of a carboxylic acid is determined by its carboxyl group and the substituents on the carbon atom adjacent to the carboxyl group. In the case of carboxylic acids, the strength of the acid increases as the substituents on the carbon atom adjacent to the carboxyl group become increasingly electron-withdrawing or electronegative.

A carboxylic acid with a strong electron-withdrawing substituent on the adjacent carbon atom is more acidic than a carboxylic acid with a weak electron-withdrawing substituent on the adjacent carbon atom. When we look at the two molecules, ICH2COOH and ClCH2COOH, we see that they have the same chemical structure except for the halogen substituent. The electronegativity of Cl is more than that of I, which means that Cl is more electron-withdrawing than I. As a result, ClCH2COOH has a stronger electron-withdrawing group attached to it, making it a stronger acid than ICH2COOH. Therefore, the correct option is A. Because Cl is more electronegative than I.

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Answer:

A is the symbol of mass number.

Explanation:

→ Mass number (A) = Protons + Neutrons

It is the required formula. The symbol of the mass number is A.

Answer:

The letter A

Explanation:

Explanation:

Na2CO3+Ca(No3)2---> CaCO3+2NaNo3

Answer:

Every Chlorine atom has an atomic mass of 35.45u and 17 protons and electrons.

Explanation:

this can all be figured out looking at the atomic number in the top left corner and the mass is found at the bottom.

The statement "Hydrogen can be prepared by suitable electrolysis of aqueous zinc salts" is false.

Electrolysis is the process of using an electric current to drive a non-spontaneous chemical reaction. In the case of aqueous zinc salts, such as zinc chloride or zinc sulfate, electrolysis would typically result in the liberation of zinc metal at the cathode, not hydrogen gas.

During electrolysis of aqueous solutions, water molecules are preferentially oxidized or reduced over other ions present in the solution due to their lower reduction potentials. Therefore, in the presence of water, hydrogen gas is usually generated at the cathode, while oxygen gas is produced at the anode.

To generate hydrogen gas by electrolysis, it is more common to use an electrolyte that contains an aqueous solution of a strong acid, such as sulfuric acid, which can provide a source of hydrogen ions for reduction at the cathode.

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Answer:

physical change occured

Explanation:

it is still juice

(a) The frequency of electromagnetic radiation required to observe features around the size of atoms is approximately 4.6 × 10⁻¹⁹ Hz, (b) This type of electromagnetic radiation might be X-rays.

The relationship between the wavelength is (λ), frequency is (ν), and the speed of light is (c) is given by the equation c = λν. The atom size and the size of the wavelength should be same. Therefore, λ ≈ 6.5 × 10⁻¹⁰ m. Now, rearranging and solving,

ν = c/λ

ν = (3×10⁸m/s)/(6.5×10⁻¹⁰m)

ν ≈ 4.6 × 10¹⁹ Hz

Hence, the frequency of electromagnetic radiation required to observe features around the size of atoms is approximately 4.6 × 10¹⁹ Hz. This is X-rays.

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The molar mass of the acid is 82.0 g/mol. The Ka of the unknown acid is  1.69 × 10⁻⁶.

Molar mass of the acid:

The molar mass of the acid can be calculated using the following equation:

Molar mass = mass / moles

The mass of the acid is 0.2140 g and the moles of the acid can be calculated using the following equation:

moles = volume × concentration

The volume of NaOH used to reach the equivalence point is 27.4 mL and the concentration of NaOH is 0.0950 M.

moles of NaOH = 27.4 mL × 0.0950 M = 2.613 mmol

Since the acid and NaOH react in a 1:1 ratio, the moles of the acid is also 2.613 mmol.

Substituting these values into the first equation:

Molar mass = 0.2140 g / 2.613 mmol = 82.0 g/mol

Ka for the unknown acid:

The Ka for the unknown acid can be calculated using the following equation:

Ka = [H⁺][A⁻] / [HA]

where:

Ka is the acid dissociation constant

[H⁺] is the concentration of hydrogen ions

[A⁻] is the concentration of the conjugate base

[HA] is the concentration of the acid

The concentration of hydrogen ions can be calculated using the pH. The pH of the solution after 15.0 mL of base had been added is 6.50.

pH = -log[H⁺]

6.50 = -log[H⁺]

[H⁺] = 10^-6.50

[H⁺] = 3.162 × 10⁻⁷ M

The concentration of the conjugate base can be calculated using the following equation:

[A-] = moles of A- / volume of solution

The moles of A⁻ = the moles of NaOH added after 15.0 mL, which is 1.438 mmol. The volume of the solution is 25.0 mL + 15.0 mL = 40.0 mL.

[A⁻] = 1.438 mmol / 40.0 mL

[A⁻] = 3.595 × 10⁻³ M

The concentration of the acid can be calculated using the following equation:

[HA] = moles of HA / volume of solution

The moles of HA = the moles of acid, which is 2.613 mmol. The volume of the solution is 40.0 mL.

[HA] = 2.613 mmol / 40.0 mL

[HA] = 6.532 × 10⁻³ M

Substituting these values into the Ka equation:

Ka = (3.162 × 10⁻⁷ M)(3.595 × 10⁻³ M) / (6.532 × 10⁻³ M)

Ka = 1.69 × 10⁻⁶

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Answer:

i think so

Explanation:

just eat them anyways

Answer: Yes they are

Explanation: Where's the picture?

Answer:

Attached picture

Ka = [?] x 10

1.02 x 10^-11 = [?] x 10

[?] = 1.02 (I'm assuming you're asking this)

(If not then divide the 10)

Answer:

The answer is 1.02x10^-11

Explanation:

Fill in the box 1.02 and then -11

At point A on the titration curve for the titration of HF with NaOH, the primary species in the solution is HF.

This is because at the beginning of the titration before any NaOH is added, the solution consists primarily of the acid being titrated, which in this case is HF.

As NaOH is slowly added, it reacts with HF in a 1:1 stoichiometric ratio to form water and the conjugate base of HF, F-. However, at point A, the amount of NaOH added is still very small, so the majority of the original HF remains unreacted.

The presence of OH- ions from NaOH is not significant enough at this point to affect the overall pH of the solution. Therefore, the primary species at point A is HF.

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Yes, steam distillation of ethanol can be done. Steam distillation is a technique used to separate volatile compounds from non-volatile or less volatile substances. Ethanol is a volatile compound with a boiling point of approximately 78.4 °C.

In steam distillation, the mixture containing the volatile compound (in this case, ethanol) is heated, and steam is passed through the mixture. The steam carries the volatile compound along with it, and the mixture is then condensed to separate the volatile compound from the non-volatile components.

Ethanol forms an azeotropic mixture with water, meaning that the boiling point of the mixture is lower than the boiling points of the individual components. In the case of ethanol-water mixture, the boiling point of the azeotropic mixture is around 78.2 °C, slightly lower than pure ethanol. This azeotropic behavior actually facilitates the steam distillation process of ethanol because the steam carries along the ethanol vapor more effectively.

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Molecular compounds of low molecular weight tend to be gases at room temperature. LiCl is most likely to not be a gas at room temperature. The correct answer is C.

LiCl is a salt, which is an ionic compound. Ionic compounds are held together by strong electrostatic forces between the oppositely charged ions.

These forces are much stronger than the forces that hold together molecular compounds, which are held together by covalent bonds. As a result, ionic compounds have much higher melting and boiling points than molecular compounds.

At room temperature, LiCl is a solid. It has a melting point of 613 degrees Celsius and a boiling point of 1360 degrees Celsius.

The other compounds listed in the question are all molecular compounds. They have much lower melting and boiling points than LiCl. At room temperature, they are all gases.

Cl₂ has a melting point of -101 degrees Celsius and a boiling point of -34 degrees Celsius.

HCl has a melting point of -85 degrees Celsius and a boiling point of -85 degrees Celsius.

H₂ has a melting point of -259 degrees Celsius and a boiling point of -253 degrees Celsius.

CH₄ has a melting point of -182 degrees Celsius and a boiling point of -164 degrees Celsius.

Therefore, the correct option is C, LiCl.

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Answer:

(C)

the tendency of a cell to maintain a stable internal environment.

Answer:

Homeostasis refers to C. the tendency of a cell to maintain a stable internal environment.

Answer:  (1.5 M) V1 = (3.40 M) (500mL)

            (multiply 3.40M x 500mL)    V1 = 1700 mL

1700 mL of the 1.5 M NaCl + 1200mL of water.

Explanation:

Answer:

[tex]T_{EQ}=37\°C[/tex]

Explanation:

¡Hola!

En este caso, para los problemas de equilibrio térmico, consideramos que la energía liberada por la sustancia que inicialmente está caliente (agua), es absorbida por la sustancia que inicialmente está fría (alcohol); thus, we can write:

[tex]Q_{agua}=-Q_{alcohol}[/tex]

La cual puede ser escrita en términos de masa, calor specifico y temperaturas:

[tex]m_{agua}C_{agua}(T_{EQ}-T_{agua})=-m_{alcohol}C_{alcohol}(T_{EQ}-T_{alcohol})[/tex]

De este modo, al resolver para la temperature de equilibrio térmico, obtenemos la siguiente expresión:

[tex]T_{EQ}=\frac{m_{agua}C_{agua}T_{agua}+m_{alcohol}C_{alcohol}T_{alcohol}}{m_{agua}C_{agua}+m_{alcohol}C_{alcohol}}[/tex]

Así, al reemplazar los valores en esta, obtenemos:

[tex]T_{EQ}=\frac{(20g)(1cal/g\°C)(40\°C)+(15g)(0.58cal/g\°C)(30\°C)}{(20g)*(1cal/g\°C)+(15g)(0.58cal/g\°C)} \\\\T_{EQ}=37\°C[/tex]

¡Saludos!

Answer:

Mutation

Explanation:

Mutation refers to the change in the structure of a gene. This change occurs when changes are made in the base/nucleotide sequence on a gene.

An example of such error made during DNA replication are incorrectly paired nucleotides or insertion/deletion of nucleotides during replication.

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

The equilibrium reactions for an aqueous solution of [tex]Ag_{2}CO_{3}[/tex] involve the dissociation of silver carbonate, carbonic acid, bicarbonate ion, and water, resulting in the formation of silver ions, carbonate ions, hydrogen ions, bicarbonate ions, hydronium ions, and hydroxide ions.

The dissociation reactions pertinent to an aqueous solution of [tex]Ag_{2}CO_{3}[/tex](silver carbonate) can be represented as follows:

1. Dissociation of [tex]Ag_{2}CO_{3}[/tex]:

[tex]Ag_{2}CO_{3}[/tex](s) ⇌ [tex]2Ag[/tex]⁺(aq) + [tex]CO_{3}[/tex]²⁻(aq)

In this reaction, solid silver carbonate dissociates into silver ions ([tex]Ag[/tex]⁺) and carbonate ions ([tex]CO_{3}[/tex]²⁻) in the aqueous solution.

2. Dissociation of [tex]H_{2}CO_{3}[/tex](carbonic acid):

[tex]H_{2}CO_{3}[/tex](aq) ⇌ [tex]H[/tex]⁺(aq) + [tex]HCO_{3}[/tex]⁻(aq)

Carbonic acid, when dissolved in water, forms hydrogen ions ([tex]H[/tex]⁺) and bicarbonate ions ([tex]HCO_{3}[/tex]⁻).

3. Dissociation of [tex]HCO_{3}[/tex]⁻ (bicarbonate ion):

[tex]HCO_{3}[/tex]⁻(aq) ⇌[tex]H[/tex]⁺(aq) + [tex]CO_{3}[/tex]²⁻(aq)

The bicarbonate ion further dissociates into hydrogen ions (H⁺) and carbonate ions (CO₃²⁻).

4. Dissociation of [tex]H_{2}O[/tex](water):

[tex]2H_{2}O[/tex](l) ⇌ [tex]H_{3}O[/tex]⁺(aq) + [tex]OH[/tex]⁻(aq)

Water undergoes self-ionization to form hydronium ions ([tex]H_{3}O[/tex]⁺) and hydroxide ions ([tex]OH[/tex]⁻).

These equilibrium reactions describe the dissociation processes occurring in an aqueous solution of silver carbonate.

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Answer:

5

Explanation:

Na, N, O, O, O