The statements that are TRUE with regard to a data set's measures of Central Tendency, Dispersion, and Paired Observations are the following:In a very small set of data, i.e. small n, the Sample Standard Deviation is generally smaller than its Population Standard Deviation.
It is possible for the value of the Correlation between a set of paired observations to be greater than 1.In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction.In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range.Why these statements are true?In a very small set of data, the Sample Standard Deviation is generally smaller than its Population Standard Deviation because when the sample size is smaller, there is less dispersion and thus the value of the sample standard deviation is generally smaller than that of the population standard deviation.It is possible for the value of the Correlation between a set of paired observations to be greater than 1 because the correlation coefficient r ranges from -1 to 1, inclusive of both endpoints.
However, it is practically impossible to get a value of r outside this range in a real dataset.In a set of paired observations of X and Y, if the Correlation is 0.75, then as the values of X increases (decreases), the values of Y also generally increases (decreases) in the same direction. This is because 0.75 is a strong positive correlation indicating that as the value of one variable increases, the value of the other variable also increases.In a very large set of data, i.e. large n, the Standard Deviation is a better measurement than Range because the standard deviation takes into account all values in the dataset and is less sensitive to outliers as compared to the range. On the other hand, the range only considers the minimum and maximum values of the dataset and thus is less informative.
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When solving the equation x/5 - 12 = 10, what is your last step?
A. Multiply by 5 on each side.
B. Add 12 to each side.
C. Divide by 5 on each side.
D. Subtract 12 from each side.
+10 points!
Answer:
c
Step-by-step explanation:
Cynthia bought a shirt for $35 that was originally $55. What was the percent change in the price of the shirt? Round to the nearest hundredths place.
NO LINKS OR I WILL REPORT YOU
Answer:36.36%
Step-by-step explanation:
%change=100 X (final-inital value) divided by initial
Joses his yearly wages were $50 more than marks, so he earned 16,815.43. Yet he said his taxes are the same as marks. Is he right? How can you tell?
Answer:
No
Step-by-step explanation:
This depends on many other things but in a basic tax bracket, both Joses and Mark both fall under the 12% tax bracket. This is for individuals who make a yearly salary between $9,876 to $40,125, in which the taxes would be 12% of the yearly salary. Since this is percent based, their taxes would not be the same, they would be close but Mark would still end up paying a little bit more since he made more money.
The function C(x) = -2x2 + 38x + 40 models the sales, in hundreds of
millions of dollars, of compact discs for years since 1990.
Question:
Rewrite the function to reveal when sales of compact discs and $0.
Answer:
The cost in 2010 is $0
Step-by-step explanation:
Given
[tex]C(x) = -2x^2 + 38x + 40[/tex]
Required
Find x when [tex]C(x) = 0[/tex]
This gives:
[tex]C(x) = -2x^2 + 38x + 40[/tex]
[tex]-2x^2 + 38x + 40=0[/tex]
Expand
[tex]-2x^2 + 40x -2x+ 40=0[/tex]
Factorize:
[tex]-2x(x - 20) -2(x- 20)=0[/tex]
[tex](-2x - 2)(x- 20)=0[/tex]
Solve for x
[tex]-2x-2=0\ or\ x - 20 = 0[/tex]
[tex]x = -1\ or\ x = 20[/tex]
x represents time. So, it cannot be negative.
[tex]x = 20[/tex]
20 years after 1990 is: 2010. Hence, the cost in 2010 is $0
For the following linear operators T: R2→R2
T(x, y)=(3x+3y, x+5y)
Find:
Subtask (1). All eigenvalues and a basis for each eigenspace.
Subtask (2). A basis for each eigenspace.
Subtask (3). Find a maximum set S of linearly independent eigenvectors of T.
Subtask (4). Is T diagonalizable? If yes, find P such that D=P-1[T]P is diagonal the diagonal representation of a matrix representation of T. Here [T] is the matrix representation of T in usual basis.
T is diagonalizable, and the matrix P = [(1, -3), (1, 1)] is the transformation matrix that diagonalizes T. The diagonal matrix D is D = [(7.5, 22.5), (2.5, 7.5)].
To find the eigenvalues and eigenvectors of the linear operator T: R2 → R2 given by T(x, y) = (3x + 3y, x + 5y), we can follow the steps outlined in the subtasks.
Subtask (1): Finding Eigenvalues and Eigenvectors
To find the eigenvalues, we need to solve the equation (T - λI)v = 0, where λ is the eigenvalue, I is the identity matrix, and v is the eigenvector.
Let's set up the equation:
(T - λI)v = 0
[(3x + 3y) - λx, (x + 5y) - λy] = [0, 0]
Expanding the equations, we get:
(3 - λ)x + 3y = 0 ...(1)
x + (5 - λ)y = 0 ...(2)
For nontrivial solutions (v ≠ 0), the determinant of the coefficient matrix must be zero. So we have:
[tex](3 - \lambda)(5 - \lambda) - 3 = 0\\(15 - 8 \lambda + \lambda^2) - 3 = 0\\ \lambda^2 - 8 \lambda+ 12 = 0\\( \lambda - 6)( \lambda - 2) = 0[/tex]
Solving for λ, we find two eigenvalues:
λ1 = 6 and λ2 = 2
For each eigenvalue, we need to find the corresponding eigenvectors by substituting back into equations (1) and (2).
For λ1 = 6:
From equation (1): (3 - 6)x + 3y = 0
-3x + 3y = 0
x = y
So, the eigenvector corresponding to λ1 = 6 is v1 = (1, 1).
For λ2 = 2:
From equation (1): (3 - 2)x + 3y = 0
x + 3y = 0
x = -3y
So, the eigenvector corresponding to λ2 = 2 is v2 = (-3, 1).
Subtask (2): Basis for Each Eigenspace
The eigenspace corresponding to an eigenvalue λ is the set of all eigenvectors associated with that eigenvalue. To find a basis for each eigenspace, we can take linearly independent eigenvectors.
For λ1 = 6, the eigenspace is spanned by the eigenvector v1 = (1, 1).
For λ2 = 2, the eigenspace is spanned by the eigenvector v2 = (-3, 1).
Subtask (3): Maximum Set of Linearly Independent Eigenvectors
The maximum set S of linearly independent eigenvectors can be formed by taking one eigenvector from each distinct eigenvalue. In this case, S = {v1, v2} = {(1, 1), (-3, 1)}.
Subtask (4): Diagonalizability
To check if T is diagonalizable, we need to determine if there exists a basis for R2 consisting of eigenvectors of T. If we can find a basis consisting of eigenvectors, then T is diagonalizable.
Since we have a maximum set of linearly independent eigenvectors, S = {(1, 1), (-3, 1)}, we can form a matrix P with these eigenvectors as columns:
P = [(1, -3), (1, 1)]
To find the diagonal matrix D, we use the formula D = P^(-1)[T]P, where [T] is the matrix representation of T in the usual basis.
Calculating P^(-1):
P^(-1) = 1/4 [(1, 3), (-1, 1)]
Now, calculating D:
D = P^(-1)[T]P
= 1/4 [(1, 3), (-1, 1)][(3, 3), (1, 5)][(1, -3), (1, 1)]
= 1/4 [(1, 3), (-1, 1)][(6, 18), (8, 28)]
= 1/4 [(1, 3), (-1, 1)][(6, 18), (8, 28)]
= 1/4 [(30, 90), (10, 30)]
= [(7.5, 22.5), (2.5, 7.5)]
So, the matrix representation of T, [T], in the basis of eigenvectors is D = [(7.5, 22.5), (2.5, 7.5)].
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With the values of sin 30°, cos 30°, sin 60° and cos 60°
What is the solution to the system of equations?
-6x-2y = 8
1
X+ 3y = 29
O (10,-2)
O (10, 2)
O (2, 10)
O (-2, 10)
Step-by-step explanation:
-2,10 is the answer according to my working
I'm stuck. plz help I dont know how
Answer:
1) regular price ⇒ $X
Sale price:75,24
Regular price: 100, X
2) The Ratio of the numbers in the first column equals the to ratio
of numbers in the second one
so.. [tex]\frac{75}{124}=\frac{100}{x} \\[/tex]
X=100 ×24/75
X=$32
Regular price-sale price=32-24=$8
hope it helps...
What will be the 50th term in the sequence defined by an = -11 +5(n − 1)?
Answer:
234
Step-by-step explanation:
Simplify the expression. an=5n-16. Substitute 50 for n. 5(50)-16= 250-16=234
For problems like this, simplifying the equation helps.
A formula of order 4 for approximating the first derivative of a function f gives: f'(0) -4.50557 for h = 1 f'(0) 2.09702 for h = 0.5 By using Richardson's extrapolation on the above values, a better
Using Richardson's extrapolation the improved approximation of the first derivative at x = 0 is -4.94543.
A formula of order 4 for approximating the first derivative of a function f gives two values: f'(0) = -4.50557 for h = 1 and f'(0) = 2.09702 for h = 0.5.
To obtain a better approximation using Richardson's extrapolation, we can use these two values and apply the following formula:
f'(0) = f'(0) + (f'(0) - f'(0)) / (h^p - 1)
where p is the order of the formula (in this case, p = 4).
Using the given values, we have:
f'(0) = 2.09702 + (2.09702 - (-4.50557)) / ((0.5/1)^4 - 1)
Simplifying the expression:
f'(0) = 2.09702 + 6.60259 / (0.0625 - 1)
f'(0) = 2.09702 + 6.60259 / (-0.9375)
f'(0) = 2.09702 - 7.04245
f'(0) ≈ -4.94543
Therefore, the improved approximation of the first derivative at x = 0 using Richardson's extrapolation is f'(0) ≈ -4.94543.
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Please help me
If you spin the spinner shown, what is probability of landing on red?
favorableoutcomes
——————————-
possibleoutcomes
Write your response...
Answer:
1/4 or 25%
Step-by-step explanation:
Theres a 1/4 chance of it landing on red.
Answer:
they be correct
Step-by-step explanation:
In Problems 10 and 11, a sequence is defined recursively. Write down the first five terms.
10. a1=3; an=4-an-1
11. a1=1; a2=2; an=-1 *an-2
Step-by-step explanation:
10. a1=3, a2=1, a3=3, a4=1, a5=3
11. a3=2x1=2, a4=2x2=4, a5=4x2=8
hope that helps :)
Find the distance between the points (–2,8) and (–2,3).
Answer:
I think it's 5
Step-by-step explanation:
I am not really sure but I tried I guess
I need help I’ll appreciate if you help thank you
Answer:
b
Step-by-step explanation:
u start at (0,9.5) and with every increasing x value the y value is decreasing by .5 units
A sample of 110 one-year-old spotted flounder had a mean length of 120.18 millimeters with a sample standard deviation of 18.08 millimeters, and a sample of 138 two-year-old spotted flounder had a mean length of 134.96 millimeters with a sample standard deviation of 27.41 millimeters. Construct a 95% confidence interval for the mean length difference between two-year-old flounder and one-year-old flounder. Let μ_1, denote the mean length of two-year-old flounder and round the answers to at least two decimal places.
A 95% confidence interval for the mean length difference, in millimeters, between two- year-old flounder and one-year-old flounder is ____ <μ_1 - μ_2 < _____
The 95% confidence interval for the mean length difference between two-year-old flounder and one-year-old flounder is (8.03 mm, 21.53 mm).
How to calculate the valueUsing a t-table or calculator, we can find the t-value corresponding to a 95% confidence level and 109 degrees of freedom. The t-value is approximately 1.984.
Substituting the values into the formula:
CI = (134.96 - 120.18) ± 1.984 * √[(18.08² / 110) + (27.41² / 138)]
CI = 14.78 ± 1.984 * √[(327.2064 / 110) + (752.6681 / 138)]
CI = 14.78 ± 1.984 * √[2.9746 + 5.4557]
CI = 14.78 ± 1.984 * √8.4303
CI = 14.78 ± 1.984 * 2.9015
CI = 14.78 ± 5.7519
CI = (8.0281, 21.5319)
The 95% confidence interval for the mean length difference between two-year-old flounder and one-year-old flounder is (8.03 mm, 21.53 mm).
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Find the volume of a right circular cone that has a height of 18.5 in and a base with a diameter of 17.5 in. Round your answer to the nearest tenth of a cubic inch.
Answer:
Step-by-step explanation:
volume of cone formula: V = 1/3 πr²h
r = 1/2 d
r = 1/2 (17.5)
r = 8.75 in
V = 1/3 (π8.75²)(18.5)
V = 1483.26 in²
HELLP ASAP PLEASE!!!
Answer: 18) (9x)° + 45° = 180°-45°= 135° then we isolate the variable and the answer is 9x/9 which is equal to x = 15°.
Step-by-step explanation: 18) supplementary angles add up to 180 degrees. So a supplementary angle lies on a single, straight line
Help plssssss I need it I’m failing life like uhhhhhh
Answer:
164
Step-by-step explanation:
15(5)
2(7)
15(5)
add em up
75 plus 14 plus 75
Write down the expression that results when the change of base formula is applied to log4(x+2).
The expression that results when the change of base formula is applied to log4(x+2) is log(x+2) / log(4).
1- Apply the change of base formula to log(x + 2):
log(x + 2) = log(x + 2) / log(10)
2- Apply the change of base formula to log(4):
log(4) = log(4) / log(10)
3- Rewrite the original expression, substituting the step 1 and step 2 results:
log(x + 2) / log(4) = (log(x + 2) / log(10)) / (log(4) / log(10))
4- Simplify by multiplying the numerator and denominator by the reciprocal of log(10):
log(x + 2) / log(4) = (log(x + 2) / log(10)) * (log(10) / log(4))
5- Cancel out log(10) in the numerator and denominator so we get:
= log(x + 2) / log(4)
Therefore, the expression resulting from applying the change of base formula to log4(x + 2) is log(x + 2) / log(4).
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Meteorologists are interested in the relationship between minimum pressure and maximum wind speed of hurricanes. The minimum pressure, in millibars, and maximum wind speed, in knots, were collected for a random sample of 100 hurricanes from the year 1995 to the year 2012. A regression analysis of maximum wind speed on minimum wind pressure produced a 95 percent confidence interval of (-1.42, -1.20) for the slope of the least-squares regression line. Which statement is a correct interpretation of the interval?
Answer:
We can be 95% confident that wind speed decreases, on average, between 1.20 knots and 1.42 knots for each millibar increase in minimum pressure.
Step-by-step explanation:
The computed confidence interval for a certain statistical parameter gives a range of value represented by a minimum value and a maximum value. The α value upon which the value was calculated represents the probability of the estimated value containing the true value of the parameter in question.
The minimum and maximum values represents the range of possible slope parameters, the true value falls in between two negative values, thus we have a negative slope, depicting a decline in one variable and the as the other increases.
From the options above, the most appropriate option is ;
We can be 95% confident that wind speed decreases, on average, between 1.20 knots and 1.42 knots for each millibar increase in minimum pressure.
If the diameter of a men’s basketball is 10 inches and a women’s is 9 inches, what is the approximate difference of their volumes? 133.9 in.3 137.6 in.3 141.9 in.3 145.6 in.3
Answer:
Its c
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
A random sample of size 25 is to be taken from a population that is normally distributed with mean 60 and standard deviation 10. The average of the observations in our sample is to be computed. The sampling distribution is
A. Normal with mean 60 and a standard deviation of 10.
B. Normal with mean 12 and a standard deviation of 2.
C. Normal with mean 60 and a standard deviation of 0.4.
D. Normal with mean 60 and a standard deviation of 2.
The correct option is D. Normal with mean 60 and a standard deviation of 2.
A sampling distribution is a probability distribution derived from taking numerous samples of a specific size from a population. The characteristics of the sampling distribution are determined by the sample size and how the samples are collected.
Standard deviation is the amount by which the observations in a dataset deviate from the mean. It is a measure of variability that reflects the degree to which data is spread around the mean.
The higher the standard deviation, the more spread out the data is.What is the formula for the standard deviation of a sampling distribution?σ_x = σ/√nWhere,σ_x is the standard deviation of the sampling distribution σ is the population standard deviationn is the sample size
To calculate the standard deviation of the sampling distribution, we must first identify the population standard deviation, which is 10 in this case, and the sample size, which is 25.σ_x = σ/√nσ_x = 10/√25σ_x = 2Therefore, the standard deviation of the sampling distribution is 2.
The mean of the sampling distribution is equal to the population mean, which is 60. Thus, the sampling distribution is normal with a mean of 60 and a standard deviation of 2.
Therefore, option D is correct.Normal distribution has a shape that is symmetrical and bell-shaped with a mean of 0 and a standard deviation of 1. The curve's tail will continue indefinitely in both directions.
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The correct answer is option D. Normal with mean 60 and a standard deviation of 2.
A random sample of size 25 is to be taken from a population that is normally distributed with a mean 60 and a standard deviation 10.
The average of the observations in our sample is to be computed.
The sampling distribution is Normal with a mean 60 and a standard deviation of 2.
What is the sampling distribution? When we take the average of a large number of samples drawn from a normally distributed population, the resulting distribution is referred to as a sampling distribution.
Because the population is normally distributed, the mean of the sampling distribution will be the same as the population mean, which is 60.
The standard deviation of the sampling distribution is determined by dividing the population standard deviation by the square root of the sample size, therefore the standard deviation of the sampling distribution is 2.
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Charlie’s Wholesale Fruit Company, located in McAllen, Texas, is considering the purchase of a new fleet of trucks to be used in the delivery of fruits and vegetables grown in the Rio Grande Valley of Texas. If the company goes through with the purchase, it will spend $350,000 on eight rigs and $50,000 on the shipping cost. The new trucks will be kept for five years, during which time they will be depreciated toward a $40,000 salvage value using straight-line depreciation. The rigs are expected to have a market value in five years equal to $30,000. The new trucks will be used to replace the company’s older fleet of eight trucks, which are fully depreciated without any salvage value but can be sold for an estimated $20,000 today. The existing truck fleet is expected to be usable for five more years, after which time the rigs will have market value of $1,000. The existing fleet of trucks uses $250,000 per year in diesel fuel, whereas the new, more efficient fleet will use only $150,000. In addition, the new fleet will be covered under warranty, so the maintenance cost per year are expected to be only $10,000 compared to $35,000 for the existing fleet. Those changes in operating activities will have decrease the company’s requirement on net operating working capital as much as $20,000. The company’s current revenue is $800,000 and projected to grow at 10% per annum for the next five years. Cost of goods sold is always 50% of the company’s revenue. A $50,000 annual fixed operating expense (excluding fleet related costs) will remain the same for the next five years. The company has none fixed assets except for the fleet. The company faces a marginal tax rate of 30%. a. Calculate the replacement free cash flows generated by this proposed project! b. Calculate the Payback Period of this proposed project! c. If Charlie requires a 15% discount rate for the new investments, calculate the NPV and Profitability Index of this proposed project! d. Calculate the IRR of this proposed project! e. Based on your answer on b, c, and d, should the fleet be replaced? Why?
a. The replacement free cash flows is $255,000
b. The Payback Period time required to recover the initial investment is 2.7778 years.
d. By calculating the NPV at various discount rates, we can determine the rate at which NPV is closest to zero.
a. To calculate the replacement free cash flows, we need to consider the cash flows associated with the new fleet of trucks. Here's the calculation:
Initial cash outflow: Purchase cost of new trucks + Shipping cost
= $350,000 + $50,000
= $400,000
Annual cash flows:
Operating cost savings:
Diesel fuel savings: $250,000 - $150,000 = $100,000
Maintenance cost savings: $35,000 - $10,000 = $25,000
Net operating working capital reduction: $20,000
Total operating cost savings per year: $100,000 + $25,000 + $20,000 = $145,000
Revenue increase:
Revenue growth rate: 10%
Year 1 revenue increase: $800,000 * 10% = $80,000
Year 2 revenue increase: $800,000 * 10% = $80,000
Year 3 revenue increase: $800,000 * 10% = $80,000
Year 4 revenue increase: $800,000 * 10% = $80,000
Year 5 revenue increase: $800,000 * 10% = $80,000
Salvage value: Market value of the new trucks at the end of 5 years = $30,000
Free cash flows:
Year 0: Initial cash outflow = -$400,000
Year 1: Cash flow = Operating cost savings + Revenue increase = $145,000 + $80,000 = $225,000
Year 2: Cash flow = Operating cost savings + Revenue increase = $145,000 + $80,000 = $225,000
Year 3: Cash flow = Operating cost savings + Revenue increase = $145,000 + $80,000 = $225,000
Year 4: Cash flow = Operating cost savings + Revenue increase = $145,000 + $80,000 = $225,000
Year 5: Cash flow = Operating cost savings + Revenue increase + Salvage value = $145,000 + $80,000 + $30,000 = $255,000
b. The Payback Period is the time required to recover the initial investment. To calculate it, we sum the cash flows until they equal or exceed the initial investment. Here's the calculation:
Payback Period = Number of years to recover initial investment
= 2 years (Year 1 cash flow + Year 2 cash flow)
+ (Remaining investment / Year 3 cash flow)
= 2 years + ($400,000 - $225,000) / $225,000
= 2 years + 0.7778 years
= 2.7778 years
c. To calculate the Net Present Value (NPV) and Profitability Index (PI), we need to discount the cash flows using the given discount rate of 15%. Here's the calculation:
Discount rate: 15%
Present value factor for each year:
Year 0: 1 / (1 + Discount rate)^0 = 1
Year 1: 1 / (1 + Discount rate)^1 = 0.8696
Year 2: 1 / (1 + Discount rate)^2 = 0.7561
Year 3: 1 / (1 + Discount rate)^3 = 0.6575
Year 4: 1 / (1 + Discount rate)^4 = 0.5718
Year 5: 1 / (1 + Discount rate)^5 = 0.4972
NPV calculation:
NPV = (Year 0 cash flow) + (Year 1 cash flow * Present value factor) + (Year 2 cash flow * Present value factor) + ...
= -$400,000 + ($225,000 * 0.8696) + ($225,000 * 0.7561) + ($225,000 * 0.6575) + ($225,000 * 0.5718) + ($255,000 * 0.4972)
Profitability Index calculation:
PI = NPV / Initial investment
= NPV / $400,000
d. To calculate the Internal Rate of Return (IRR), we find the discount rate that makes the NPV equal to zero. Here's the calculation:
IRR = Discount rate that makes NPV equal to zero
By calculating the NPV at various discount rates, we can determine the rate at which NPV is closest to zero.
e. Based on the information provided, we can determine if the fleet should be replaced by considering the Payback Period, NPV, Profitability Index, and IRR.
If the Payback Period is within the company's acceptable timeframe and the NPV is positive, or the Profitability Index is greater than 1, and the IRR exceeds the company's required rate of return, then replacing the fleet would be financially favorable. If any of these criteria are not met, it would indicate that the replacement may not be the best option.
Please note that the calculation of IRR requires further information, and the final decision should consider additional factors such as qualitative aspects, operational requirements, and strategic considerations.
Without the specific values for cash flows in each year, it is not possible to provide a definitive answer to whether the fleet should be replaced based on the given information.
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A homologous series of centrifugal pumps has a specific speed of 1.1 and are driven by 2400-rpm motors. For a 400-mm size within this series, the manufacturer claims that the best efficiency of 85% occurs when the flow rate is 500 L/s and the head added by the pump is 895 m. What would be the best-efficiency operating point for a 300-mm size within this homologous series, and estimate the cor- responding efficiency
For centrifugal, the best-efficiency operating point for a 300-mm size within this homologous series, and estimate the corresponding efficiency can be calculated as follows:
Given data: Specific speed (Ns) = 1.1Speed of motor (N) = 2400 rpm Best efficiency of 400 mm size pump within this series is 85%The flow rate (Q) at best efficiency is 500 L/s The head added (H) by the pump at best efficiency is 895 m We are required to find the best efficiency and operating point of a 300-mm size within this homologous series.
As per affinity laws of pump, the performance of pumps that are geometrically similar but of different sizes can be compared by the equation:N1/Q1 = N2/Q2 (speed and flowrate relationship)H1/H2 = (D1/D2)² (head and diameter relationship)P1/P2 = (D1/D2)³ (power and diameter relationship)Where,N1 and N2 are speeds of the pumpsQ1 and Q2 are the flowrates of the pumpsH1 and H2 are the heads added by the pumpsD1 and D2 are the diameters of the pumpsP1 and P2 are the power input of the pumps
This information can be used to estimate the best efficiency operating point of the 300-mm pump. Let's assume that the efficiency of the 300-mm pump at the best efficiency operating point is η.We can use the pump affinity laws to estimate the efficiency of the 300-mm pump as follows:η1/η2 = (D1/D2)³ (efficiency and diameter relationship)η1 = 85% (best efficiency of 400-mm pump)η2 = η (efficiency of 300-mm pump)D1 = 400 mmD2 = 300 mm∴ η1/η2 = (D1/D2)³η2 = η1 / (D1/D2)³= 85% / (400/300)³= 69.7%
Therefore, the best efficiency of the 300-mm pump is 69.7%.Answer: The best-efficiency operating point for a 300-mm size within this homologous series is a flow rate of 500 L/s and a head of 677 m. The corresponding efficiency is 69.7%.
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Find the total cost if the price of a netbook is 375.00.
Answer:
387.50.
Step-by-step explanation:
Need asap please help
Answer:
(3)
Step-by-step explanation:
Lynn is trying to determine how far away Student B is from the balloon. He decides to use the
equation shown below. Is his equation correct? Why or why not?
5
cos 60º =
BIV x
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete as the image that illustrates the scenario is not given.
However, I can deduce that the question is about a right-angled triangle.
So, I will give a general explanation on how to find each of the side of the triangle, given a side and an angle.
For triangle A (solve for b)
Using cosine formula.
[tex]\cos \theta = \frac{Adjacent}{Hypotenuse}[/tex]
[tex]\cos 60= \frac{5}{b}[/tex]
Make b the subject
[tex]b= \frac{5}{\cos 60}[/tex]
For triangle B (solve for b)
Using cosine formula.
[tex]\sin \theta = \frac{Opposite}{Hypotenuse}[/tex]
[tex]\sin 60= \frac{b}{5}[/tex]
Make b the subject
[tex]b = 5\sin 60[/tex]
For triangle C (solve for b)
Using cosine formula.
[tex]\tan \theta = \frac{Opposite}{Adjacent}[/tex]
[tex]\tan 60= \frac{b}{5}[/tex]
Make b the subject
[tex]b = 5\tan 60[/tex]
Answer:
Did you get the answer If so please give it to me.
Step-by-step explanation:
Can you help me solve this?
Y-intercept= 4, goes through the point (2, 3)
Please solve using y=Mx+b
Answer:
y=-1/2x+4 Is your answer
Step-by-step explanation:
y=mx+b
3=2x+4
-1=2x
x=-1/2
You already know y is 4 so y=-1/2x+4
QUICK! WHOEVER GIVES CORRECT ANSWER GETS BRAINLIEST
Answer:
15
Step-by-step explanation:
Answer:
15 cookies
Step-by-step explanation:
10 cookies is equivalent to 2 scoops of flour.
You need to find how many cookies they can make with just 1 scoop of flour.
So, to do that, you'd need to do 10/2, which is 5.
10 represents the number of cookies, and 2 represents the scoops of flour. (5 represents the number of cookies you can make with 1 scoop of flour.)
This will work with any certain amount of flour, just use the equation 5 times X, where X is the amount of flour.
In this certain problem, they gave us the scoops of flour.
Replace X with 3.
3 times 5 = 15.
15 cookies.
In a particular chi-square goodness-of-fit test, there are six categories and 575 observations. Use the 0.02 significance level. a. How many degrees of freedom are there? Degrees of freedom 5 es b. What is the critical value of chi-square? (Round your answer to 3 decimal places.) Critical value 9.837
a. There are 5 degrees of freedom in the data
b. The critical value represents the value beyond which the test statistic must exceed to reject the null hypothesis.
How many degrees of freedom are there?In a chi-square test, the degrees of freedom (df) can be calculated as (number of categories - 1). In this case, there are six categories, so the degrees of freedom would be:
df = 6 - 1
df = 5
Therefore, there are 5 degrees of freedom.
To find the critical value of chi-square at a significance level of 0.02 and 5 degrees of freedom, you can refer to a chi-square distribution table or use a statistical calculator. The critical value represents the value beyond which the test statistic must exceed to reject the null hypothesis.
For a significance level of 0.02 and 5 degrees of freedom, the critical value of chi-square is approximately 9.837 (rounded to 3 decimal places).
Learn more on chi-square test here;
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