Which of the diagrams represent a chromosome or chromosome pair in a cell at the end of prophase II? Multiple Choice Ο diagram 1 Ο diagram 2 Ο diagram 3 Ο diagram 4 Ο diagram 5
Answers
Diagram 2 represents a chromosome or chromosome pair at the end of prophase II in a cell.
Let's delve into more detail about what happens during this stage of meiosis.
Prophase II is the second phase of meiosis II, which follows the first division of meiosis known as meiosis I. During meiosis I, the homologous chromosomes pair up and separate, resulting in two daughter cells with half the number of chromosomes as the parent cell.
In prophase II, the two daughter cells from meiosis I enter a brief interphase, where DNA replication does not occur. This means that the chromosomes in each daughter cell still consist of two identical chromatids held together by a centromere, just as they were at the end of meiosis I.
At the onset of prophase II, the nuclear envelope, if it had reformed during interphase, breaks down once again. The chromosomes, already duplicated during the previous interphase, condense and become visible under a microscope.
In the diagram, you will likely observe two chromosomes or chromosome pairs, depending on whether it represents a haploid or diploid cell. Each chromosome appears as two sister chromatids connected by a centromere. These chromatids are identical because they resulted from the DNA replication that occurred in the previous S phase.
Towards the end of prophase II, the microtubules of the spindle apparatus attach to the kinetochores on each sister chromatid. This attachment prepares the chromosomes for separation during the subsequent stages of meiosis II.
It's important to note that prophase II is followed by metaphase II, anaphase II, and telophase II, which together complete the second division of meiosis and eventually result in the formation of four haploid daughter cells (gametes) with a single set of chromosomes.
The complete question is:
Which of the diagrams represent a chromosome or chromosome pair in a cell at the end of prophase II? Multiple Choice - diagram 1 , diagram 2 ,diagram 3 ,diagram 4 , diagram 5
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Related Questions
why is sexual reproduction a necessity for sharks
Answers
Answer:
cause they can't asexually reproduce
Explanation:
a shark has to reproduce and is too big of an organism to use asexual reproduction, so there's only one left
In the bacterial transformation experiment, what is the primary purpose of using an ampicillin-containing medium?
to select for transformed cells
to select for wildtype cells
to prevent contamination
to stimulate a color change
Answers
The primary purpose of using an ampicillin-containing medium in a bacterial transformation experiment is a. to select for transformed cells
In a bacterial transformation experiment, the main goal of employing an ampicillin-containing media is to select for transformed cells. Ampicillin is an antibiotic that prevents bacteria from growing by disrupting the formation of their cell walls. Researchers frequently insert a plasmid harbouring an ampicillin resistance gene into the bacterium as part of a transformation experiment.
The only bacteria that can live and thrive in the presence of ampicillin are those that successfully take up the plasmid and transform. As a result, the ampicillin-containing media functions as a selective agent, enabling the separation of the altered cells from the population and their identification.
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Complete Question:
In the bacterial transformation experiment, what is the primary purpose of using an ampicillin-containing medium?
a. to select for transformed cells
b. to select for wildtype cells
c. to prevent contamination
d. to stimulate a color change
Which of the following is an example of a phenotype (select all that apply)?
Group of answer choices
Brown Hair
GG
RR'
Physical trait
Answers
Answer:
brown hair and physical trait
An example of phenotypes are brown hair and physical trait. Therefore, option A and D are correct.
What is phenotype ?A set of an organism's observable qualities or characteristics is known as its phenotype. The phrase refers to an organism's morphology, or its physical form and structure, as well as its physiological and biochemical characteristics, behavior, and the outcomes of that behavior.
We examine the alleles of the parent organisms and predict how frequently the offspring will exhibit those genes to determine a phenotypic ratio. Most of the time, we are aware of the alleles' expression and appearance.
An observable characteristic is simply referred to as a "phenotype." Pheno, which has the same root as the term "phenomenon," simply means "observe." It can therefore relate to anything from a common characteristic, like height or hair color, to a visible type of organism.
Thus, option D is correct.
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which data regarding a client with a diagnosis of colon cancer are subjective?
Answers
A subjective data is defined as information that is based on personal interpretation, opinion, judgment, or belief. It is data that cannot be observed by another person, and it is based on personal feelings or experiences.
A subjective data is defined as information that is based on personal interpretation, opinion, judgment, or belief. It is data that cannot be observed by another person, and it is based on personal feelings or experiences. In a patient with colon cancer, there are different data that are subjective. For instance, a patient may report feeling fatigued and not able to carry out daily activities due to the condition. This is a subjective data as it is based on the patient's personal interpretation of their condition. Other examples of subjective data regarding a client with a diagnosis of colon cancer include the following: Changes in bowel habits such as diarrhea or constipation, abdominal pain, nausea, and vomiting Blood in stool Difficulty in passing stool Unintentional weight loss Anemia Fatigue, weakness, and malaise Depression, anxiety, and stress. There are a lot of subjective data regarding a client with a diagnosis of colon cancer, and these subjective data are important in the overall assessment of the patient. As subjective data is reported by the patient, the healthcare professional has to be empathetic and pay attention to the patient's concerns in order to make an accurate diagnosis and provide proper treatment.
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What are some skills that scientists must have to be successful?
Answers
Answer:
they have to be smart
Explanation:
...........
Answer:
They need to be creative, logical, analytical, and good at communication.
Explanation:
hope this helps!
What process adds carbon dioxide to the air
teven cycle
water evele
respation
photosynthesis
Answers
Answer:
Respation
Explanation:
Though it is spelled respiration.
normal skin microbiota are able to grow on the skin because they can thrive in the presence of
Answers
Normal skin microbiota are able to grow on the skin because they can thrive in the presence of appropriate pH, temperature, moisture, and nutrients.
Normal skin microbiota are able to grow on the skin because they can thrive in the presence of appropriate pH, temperature, moisture, and nutrients. They are referred to as commensals because they form a mutually beneficial relationship with the host. When it comes to the human skin, the skin microbiota is diverse and distinct between different body regions. These microbiota are considered an important component of skin health and play a crucial role in protecting the skin from invading pathogens. In addition, the skin microbiota also helps to maintain the skin’s barrier function and homeostasis by producing antimicrobial substances that can inhibit the growth of harmful microorganisms and support the growth of beneficial bacteria. In summary, the growth of normal skin microbiota is supported by a variety of factors that create an environment conducive to their survival and proliferation.
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How does the large intestine help the body excrete wastes?
It reabsorbs water from filtrate.
It forms urine.
It removes urea from the body.
It processes undigested food into feces.
Answers
Answer:
It processes undigested food into feces.
Explanation:
Answer:
D. It processes undigested food into feces.
Explanation:
Correct on EDGE 2021!
6. When does the DNA in a cell replicate?
a. before cell division (mitosis or meiosis)
b. during cell division (mitosis or meiosis)
after cell division (mitosis or meiosis)
d. at random times throughout the cell's life cycle
Answers
Answer:
the answer is A before cell division (mitosis or meiosis)
Explanation:
The S phase of a cell cycle occurs during interphase, before mitosis or meiosis, and is responsible for the synthesis or replication of DNA. In this way, the genetic material of a cell is doubled before it enters mitosis or meiosis, allowing there to be enough DNA to be split into daughter cells.
Select three ways the United States could use resources more sustainably.
A. using non-renewable energy sources
B. increasing access to technologies
C. using clean and renewable energy sources
D. decreasing overconsumption
E. increasing overconsumption
F. decreasing access to technologies
Answers
Answer:
IT IS B
Explanation:
If yellow skin (Y) exhibits incomplete dominance with red skin (y), what color of skin would result from the genotype Yy?
Answers
Answer:
Orange skin
Explanation:
Incomplete dominance with the genotype Yy results in a combination of the dominant and recessive traits. In this case the combination of yellow and red skin would be orange skin.
When you were born you were 22 inches long now you were about 60+ inches long how do you account for this 40+ inches of growth?
Answers
Which of the following statements best summarizes the metabolic results of photorespiration? • ATP is hydrolyzed, oxygen is produced, and carbon dioxide is consumed ATP, oxygen and carbon dioxide are all produced
• ATP and oxygen are produced and carbon dioxide is consumed • ATP is hydrolyzed, carbon dioxide is produced, and oxygen is consumed • ATP is produced, oxygen and carbon dioxide are consumed
Answers
The following statement best summarizes the metabolic results of photorespiration: ATP is hydrolyzed, carbon dioxide is produced, and oxygen is consumed, option C is correct.
Photorespiration is a metabolic process that occurs in plants under certain conditions, such as high temperatures or low carbon dioxide levels. During photorespiration, ATP is indeed hydrolyzed as energy is required for the process. Carbon dioxide is produced through the breakdown of organic compounds, releasing carbon dioxide as a byproduct. Furthermore, oxygen is consumed during photorespiration due to its involvement in the chemical reactions that take place.
This process is considered wasteful for plants as it consumes energy and can lead to a decrease in photosynthetic efficiency. Therefore, this accurately summarizes the metabolic results of photorespiration, option C is correct.
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The complete question is:
"Which of the following statements best summarizes the metabolic results of photorespiration? •
A. ATP is hydrolyzed, oxygen is produced, and carbon dioxide is consumed ATP, oxygen and carbon dioxide are all produced•
B. ATP and oxygen are produced and carbon dioxide is consumed
C. ATP is hydrolyzed, carbon dioxide is produced, and oxygen is consumed
D. ATP is produced, oxygen and carbon dioxide are consumed"
Cytochrome C is a protein that functions in cellular respiration as part of the electron transport chain. It is frequently used to determine evolutionary relationships between different organisms because it is highly conserved (only differs slightly) between different organisms. A student researching evolutionary relationships between different organisms came across the following information about the differences between cytochrome C proteins in different organisms when compared to humans. Number of different amino acids compared to humansChimpanzee0Rhesus Monkey1Cow10Yeast42 The student plans to use an antibody to the human cytochrome C protein in an ELISA test on cytochrome C samples from these four organisms. What should she use as a positive control
Answers
Answer:
Human cytochrome C
Explanation:
The enzyme-linked immunosorbent assay (ELISA) is a technique widely used to detect and measure antibodies and antigens in biological samples. This technique can be used to diagnose different diseases by detecting antigens that bind to antibodies. The ELISA test consists of a plate with a capture antibody against the antigen of interest coating the plate. Subsequently, the target antigen is detected by adding a detection antibody labeled with an enzyme (e.g., alkaline phosphatase) that binds to this antigen. Finally, a particular substrate (e.g. ABTS) is added to the plate and the subsequent reaction converts it into a colored product which can be easily detected using microplate readers. In this case, the positive control will be human cytochrome C which will bind to specific antigens in order to evidence the presence of this molecule in the sample.
In response to a decrease in tissue metabolic activity, tissue oxygen concentrations ________, which causes a(n) ________. In response to a decrease in tissue metabolic activity, tissue oxygen concentrations ________, which causes a(n) ________. increase : active hyperemic response decrease : dilation of the arterioles decrease : increase in tissue ischemia decrease : active hyperemic response increase : constriction of the arterioles
Answers
Answer:
The correct answer is - increase: constriction of the arterioles.
Explanation:
When the physical activity is decreased by the tissues of the muscle, the oxygen concentration in the tissue increases which leads to the constriction of the arterioles.
It takes place in order to decrease blood flow and blood pressure as oxygen requirement is less in the tissue in decreased physical metabolic activity. The constriction of arterioles results in more resistance to decrease the blood flow in capillaries.
Compared to freshwater fishes, marine fishes: drink seawater and produce a large volume of urine. do not drink seawater in an effort to conserve as much water as possible. produce a large volume of dilute urine in an effort to rid their bodies of excess water. tend to gain water by osmosis since their internal salt concentration is higher than that of seawater. tend to lose water by osmosis since their internal salt concentration is lower than that of seawater.
Answers
Answer:
The correct answer is - tend to lose water by osmosis since their internal salt concentration is lower than that of seawater.
Explanation:
In freshwater fishes, the body of fishes has a higher salt concentration inside their body than the surrounding water, water enters through the osmosis process. Without any active regulation of this process, fishes would swell and get bigger and bigger. They have specialized cells called chloride cells in gills to take ions from water as they do not have kidneys.
In contrast, the marine fishes have a lower salt concentration in their body than surrounding water of sea or ocean and they lose water continuously and to compensate for this they need to drink water regularly.
This is currently assigned to you. Try some challenge questions to turn in this assignment
= Steroid
Hormone
Diffusion: Getting Stuff into your
Cells!
= H20 = glucose
Key
= Na
Extracellular Space
Several types of molecules are sitting outside your cell. Only some
of them can diffuse into your cell without help.
• Use the red or orange points to drag each substance through
the cell membrane to find out which ones can and can't enter
• What is unique about the molecules that can enter the cell?
OOOOOOOOOOOOOOOOOOOO
CHALLENGE ME
Intracellular Space
Learn More
Answers
Answer:
What is the name of this website
or the book?
In your own words, describe how the time required for digestion can be used to determine the time of death.
Answers
Answer: Backdating the time required for food found in the stomach of the deceased to digest. Since digestion can't continue after death.
Explanation: The time taken for food to get digested can be employed to depicts time of death. This process involves understanding the period of time that usually takes the food found in the gastric of the deceased to calculate the time of death.
Different foods has varying time of digestion, so therefore, the gastric content is a good indicator to determine time of death by the doctor who is carrying out autopsy, since digestion does not continue after death.
However, it is established by scientist that food takes up to 4-6hours in the stomach depending on the size and type of food. Hence, if the status of the food found in the deceased stomach is noted accordingly and the time taken requires for digestion is also noted، the doctor can deduce the time of death accordingly from this two points.
Provide two reasons why it is important to isolate undigested plant cells.
I need this asap
Answers
Answer:
It helps to support growth and helps producing energy to do vital functions.
Hope this helps!
A reliable DNA analysis is based on the DNA conditions. The importance of using undigested cells is that DNA is well-preserved, not affected by external factors, and can be used to compare it to database sequences.
------------------------------------------
Dr. Pringle studies niche partitioning and competition reduction among coexistent species in Africa.
He is interested in knowing the exact source of food of different herbivorous species. To do so, he is using the technique of DNA metabarcoding.
He collects fresh animals' dung and gets the indigested plant cells.
DNA is isolated, sequenced, and compared with the DNI of known species, which are a potential source of food for these animals.
Once he matches the cells' DNA with the corresponding plant species from the database, he can use this information to detail the animal's source of food.
The importance of getting fresh, undigested cells from the dung, is that
The animal's digestive enzymes have not broken the cell walls and digested the cell content. The dung environmental conditions such as pH, temperature, or microbiota have not affected the cell's DNA. Undigested cells' DNA is well-preserved and can be used to compare it with the plant species database.------------------------------------------------------
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Where does absorption of ALL the small molecules such as glucose and amino acids occur?
Answers
Answer:
The absorption process also occurs in the small intestine. Food has been broken down into particles small enough to pass into the small intestine. Sugars and amino acids go into the bloodstream via capillaries in each villus.
Explanation:
Pls help, due today, would be really appreciated.
Answers
for some reason I can't submit my typed answer but here's the screenshot
You measure the initial rate of an enzyme reaction as a function of substrate concentration in the presence and absence of an inhibitor. The following data are obtained: a) What is the V_max in the absence of inhibitor? b) What is the K_m in the absence of inhibitor? c) When [S] = 0.0004, what will V_0 be in the absence of inhibitor? d) When [S] = 0.0004, what will V_0 be in the presence of inhibitor? e) What kind of inhibitor is it likely to be?
Answers
a)[tex]V_{max[/tex] in the absence of inhibitor cannot be determined without the specific data.
b) [tex]K_m[/tex] in the absence of inhibitor cannot be determined without the specific data.
c)[tex]V_0[/tex] in the absence of inhibitor at [S] = 0.0004 cannot be determined without the specific data.
d) [tex]V_0[/tex] in the presence of inhibitor at [S] = 0.0004 cannot be determined without the specific data.
e) The type of inhibitor cannot be determined without the specific data and further analysis.
The [tex]V_{max[/tex] and [tex]K_m[/tex] values, as well as the impact of the inhibitor, not set in stone through examination of the information utilizing compound energy conditions.
[tex]V_{max[/tex] addresses the most extreme speed of the compound response, which is accomplished when the chemical is soaked with substrate. It tends not set in stone by finding the most elevated starting rate saw without the inhibitor.
[tex]K_m[/tex] addresses the substrate focus at which the compound response rate is half of the most extreme speed. It very well not entirely settled by distinguishing the substrate focus at which the underlying rate is half of the [tex]V_{max[/tex].
To work out the particular qualities for [tex]V_0[/tex] (introductory rate) at a given substrate focus ([S]), the catalyst energy condition (e.g., Michaelis-Menten condition) can be utilized.
The idea of the inhibitor (e.g., cutthroat, non-serious, uncompetitive) can be resolved in view of its impact on the [tex]V_{max[/tex] and [tex]K_m[/tex] values. A cutthroat inhibitor normally expands the clear [tex]K_m[/tex] esteem, while a non-serious or uncompetitive inhibitor influences the [tex]V_{max[/tex] without essentially modifying the [tex]K_m[/tex] esteem.
Without the particular information, giving exact responses to the questions is absurd.
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During one year, seven coyotes in a population die. Eight immigrate into the population, but none emigrate. If the overall population growth is 13 coyotes, what was the birth rate of coyotes during the year? Use this formula: population growth = (birth rate + immigration) – (death rate + emigration) 7 11 12 15
Answers
Answer:
Death rate= 7 coyotes
Immigration= 8
Emigration= 0
Population growth= 13
Let’s suppose that the birth rate for the given population is x.
Population growth = (birth rate+immigration) - (death rate+emigration)
13=(x+8)-(7+0)
13=x+1
Move the variable to the left side and change its sign.
-x+13=1
Move the constant to the right side and change its sign
-x=1-13
-x=-12
x=12
Answer: x=12
Explanation:
edge2021
Answer:
Death rate= 7 coyotes
Immigration= 8
Emigration= 0
Population growth= 13
Let’s suppose that the birth rate for the given population is x.
Population growth = (birth rate+immigration) - (death rate+emigration)
13=(x+8)-(7+0)
13=x+1
Move the variable to the left side and change its sign.
-x+13=1
Move the constant to the right side and change its sign
-x=1-13
-x=-12
x=12
Answer: x=12
Explanation:
edge 2021
At what position in the amplicon is there a difference specifically between the taster and non- taster alleles ? What is that change?
Answers
There is a specific position within the amplicon where a difference exists between the taster and non-taster alleles. The nature of this change will be explained in the subsequent paragraph.
Without specific information about the amplicon or the specific taster/non-taster alleles in question, it is not possible to provide an exact position or change. The difference between taster and non-taster alleles could be due to a single nucleotide polymorphism (SNP) or a variation in the length of a repeat sequence. To determine the specific position and change, the DNA sequence of both alleles would need to be compared. This comparison would involve identifying any differences in nucleotide sequence, such as substitutions, insertions, or deletions, at specific positions within the amplicon.
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Which substance is a compound?
water
gold
oxygen
hydrogen
Answers
ITS WATER I SWEAR
H20 has multiple elements in it so its a compound the others are just single elements
PLEASE giv brainliest
Which of the following sentences is the best example of formal language?
A. I've gotten totally into theater lately, but opera is too much for me; I
don't know why.
B. When I see one of my acting idols on the screen, I'm like wow,
how'd he do that?
C. I wanted to ask if you wanna come to this thing I'm in on Saturday
night?
D. I would like to extend to you an invitation to my recital, which takes
place this weekend.
SUBMIT
Answers
Answer:
b
Explanation:
......am like wow can be used to someone u are used to
Answer:
The answer is D
Explanation:
just did the test :)
I need help figuring this out. Please
Answers
Answer:
1) G C G U A U G (C C C) (U U U) (A A C) (C G C)
2) U U A U G (C G U) (U A G) (G C G) (U U U) (A U U)
3) U A U G (G C U) (U A G) (A A U) (A A C) (C C G) (U A A)
4) U U A U G (C A A) (A G G) (G C G) (U A U) (C U U) (U A G)
5) represent codons which are groupings of 3 consecutive nucletides
Explanation:
Opposites for REGULAR mDNA base pairings are T= A and G = C, however, since it is mRNA, your base pairings change a little. G is still to C BUT Thymine (T) becomes Uracil (U) so A= U instead of A= T. So big difference between mRNA and mDNA is that Thymine changes to Uracil and vice versa depending on how the code is being translated.
Hope this helps some, please let me know if there's anything that doesn't make sense
How does E. Coli disrupt homeostasis
Answers
Identify 3 biotic factors that affect the weather. Identify 3 abiotic factors that affect the weather. Explain how for each.
Answers
Answer:
volcanoes, hurricanes, and earthquakes
Explanation:
Natural selection leads to adaptations to __________ in an organism's environment. View Available Hint(s) Hint 1.opened hint Consider the features of the environment that affect organisms' existence. Natural selection leads to adaptations to __________ in an organism's environment. nonliving factors such as temperature and chemicals other living organisms abiotic and biotic factors water for aquatic organisms and the atmosphere for terrestrial organisms
Answers
Answer:
abiotic and biotic factors
Explanation:
According to the evolutionary theory proposed by Darwin, natural selection can be defined as the mechanism by which evolution occurs (i.e., the mechanism by which species change over time). An organism´s environment is comprised of abiotic (e.g., temperature, light, water, etc) and biotic (e.g., microbes, food availability, etc) factors. Adaptations refer to the phenotypic traits that increase the chance of survival and reproduction of an organism in its environment. Organisms better adapted to their environment are selected by natural selection to reproduce and thus perpetuate their genes across generations.