When choosing a respirator for your job, you must conduct a _____ test.

A) Fit B) Practice C) Breathing D) Weight?

Answer:

The answer is below

Explanation:

a) Density is the ratio mass of a substance to the total volume it occupies. The SI unit of density is kg/m³. The formula for density is:

Density = mass / volume

1 ounce =  0.0283495 kg

1 inch = 0.0254 m

The mass of liquid = 1617 ounces = [tex]1617\ ounce * 0.0283495\frac{kg}{ounce} =45.84\ kg[/tex]

diameter of container (d) = 26 inches = [tex]26\ inches*0.0254\frac{m}{inch}=0.66\ m[/tex]

Radius = d/2 = 0.66/2 = 0.33 m

The volume of a hemisphere = (2/3)πr³

Volume = [tex]\frac{2}{3}*\pi*(0.33)^3 =0.075\ m^3[/tex]

Density = mass / volume = 45.84 kg / 0.075 m³ = 609.04 kg/m³

b) Specific weight = density × acceleration due to gravity = 609.04 kg/m³ × 9.807 m/s² = 5972.83 N/m³

Answer:

I would say that the hardest part about learning Thermodynamics is the generality and abstractness of it all.

Explanation:

Answer:

Explanation:

In mechanics of materials, the bending stress of a beam in bending can be determined by the equation

Answer:

A. True

Explanation:

MATLAB may be defined as a programming platform that is designed specifically for the engineers as well as the scientists to carry out different analysis and researches.

MATLAB makes use of a desktop environment which is tuned for certain iterative analysis and the design processes with a programming language which expresses matrix as well as array mathematics directly.

Thus the answer is true.

Answer:

2.187 inches

hope it would be helpful

Answer:

2.187 in.

Explanation:

Answer

TL/TH- TL

Because we know that power coefficient is. = QL/QH-QL

=so using this for performance we have

=>Perf= TL/(TH-TL)

Answer:

I wrote this on my own so hope I helps!

Explanation:

The most basic calculations are addition, subtraction, multiplication, and division. The more transistors an integrated circuit has, the more advanced mathematical functions it can perform. ... Thus, when you input numbers into a calculator, the integrated circuit converts those numbers to binary strings of 0s and 1s.

this is what I know :)

hope it helps

Answer:

Technicians A is  correct

Explanation:

According to ASE ( Automotive service excellence) "Certification credentials are valid for five years. If it has been five years or more since you took a test, it’s time to register for the corresponding Recertification Test. The five-year requirement ensures certified professionals are current in this rapidly changing industry."

This counters the claim of technician B who say the programs must be reviewed every three years  , and ASE sends you reminders before your credentials expire.

Answer:

8 for dual-op-amp package, and 14 for quad-op-amp

Explanation;

This is because every op-amp has 2 input terminal 4 pns

So one output terminal that is 2 pins which are required for power

and the same for a minumum number of pins required by quad op amp which is 14

Answer:

a) 0.489

b) 54.42 kg/s

c) 247.36 kW/s

Explanation:

Note that all the initial enthalpy and entropy values were gotten from the tables.

See the attachment for calculations

Answer: metal inert gas (MIG) welding

Explanation:

Gas metal arc welding (GMAW), also called metal inert gas (MIG) welding, is an arc welding process in which the heat for melting the metal is generated by an electric arc between a consumable electrode and the metal (Fig.

Answer:

some connecting rods have spit holes

Some connecting rods have crankshaft to help lubricate the cylinder wall or piston pin.

A crankshaft is a mechanical component that converts reciprocating motion in a piston engine into rotational motion.

The crankshaft is a rotating shaft with one or more crankpins that drive the pistons via the connecting rods.

Reduced fuel economy is one issue you'll face if your car's crankshaft isn't working properly. The reason for this is that your vehicle's fuel injectors will not efficiently direct gas to the engine.

The connecting rods' big ends are lubricated with oil that travels up an oilway drilled through the crankshaft.

From the main bearings to the big end bearings, oil is pushed. It will lubricate the cylinder walls in some engines by passing through a passage drilled in the connecting rod.

Thus, the answer is crankshaft.

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Answer:

machine guarding

Explanation:

Machine guarding protects an operator from the point of operation.

Explanation:

1. Both a and b only

2. A only

3. B only

4.Neither a or b

Answer:

a

Explanation:

because it a year yea yea

Answer:

Explanation:

Given that:

From process 1 → 2

[tex]P_1 = 10 bar \\ \\ V_1 = 1 m^3 \\ \\ V_2 = 4 m^3[/tex]

[tex]PV^{1.5} = \ constant[/tex]

[tex]\gamma = 1.5[/tex]

Process 2 → 3

The volume is constant i.e [tex]V_2 =V_3 = 4m^3[/tex]

[tex]P_3 = 10 \ bar[/tex]

Process 3 → 1

P = constant  i.e the compression from state 1

Now, to start with 1 → 2

[tex]P_1V_1^{1.5} = P_2V_2^{1.5}[/tex]

[tex]P_2 = P_1 (\dfrac{V_1}{V_2})^{1.5}[/tex]

[tex]P_2 = 10 \times (\dfrac{1}{4})^{1.5}[/tex]

[tex]P_2 =1.25[/tex]

The work-done for the process  1 → 2 through adiabatic expansion is:

[tex]W = \dfrac{1}{1-\gamma}[P_2V_2-P_1V_1][/tex]

We know that 1 bar = [tex]10^5 \ N/m^2[/tex]

∴

[tex]W = \dfrac{1}{1-1.5}[1.25 \times 10^5 \times 4- 10 \times 10^5 \times 1][/tex]

[tex]W =1000000 \ J[/tex]

[tex]W_{1 \to 2} = 1000 kJ[/tex]

For process 2 → 3

Since V is constant

Thus:

W = PΔV = 0

[tex]W_{2 \to 3} = 0[/tex]

For process 3 → 1

W = PΔV

[tex]W _{3 \to 1} = P_3(V_1-V_3)[/tex]

[tex]W _{3 \to 1} = 10 \times 10^5 (1-4)[/tex]

[tex]W _{3 \to 1} = 10 \times 10^5 (-3)[/tex]

[tex]W _{3 \to 1} = -3 \times 10^6 \ J[/tex]

[tex]W _{3 \to 1} = -3000 \ kJ[/tex]

The net work-done now  for the entire system is :

[tex]W_{net} = W_{1 \to 2} + W_{2 \to 3 } + W_{ 3 \to 1 }[/tex]

[tex]W_{net} = (1000 + 0 + (-3000)) \ kJ[/tex]

[tex]W_{net} =-2000 \ kJ[/tex]

The sketch of the processes on p -V coordinates can be found in the image attached below.

A) The work done for each process are :

B) The net work for the cycle = -2000 kJ

Given Data :

For process (1 -2)      For process ( 2 - 3 )       process ( 3 - 1 )

P₁ = 10 bar                   P₃ = 10 bar                  constant pressure compression

V₁ = 1 m³                  constant volume heating

V₂ = 4 m³

PV[tex]^{1.5}[/tex] = constant

A) Determine work done for each process

Calculate work done for process (1 - 2)

W₁ ₋ ₂ = [tex]\frac{P_{1}V_{1} - P_{2}V_{2} }{n -1 }[/tex] * 100

         = [ ( 10*1 ) - ( 1.25 * 4 ) ] / 1.5 - 1

         = [ 10 - 5 ] / 0.5

         = 10 * 100 = 1000 kJ

Calculate work done for process ( 2-3 )

given that there is constant volume heating

W₂₋₃ = 0 kJ

Calculate work done for process ( 3-1)

W₃₋₁ = P ( Δ V )     given that p = constant

       = 10 * 100 ( -3 )

       = - 3000 kJ

B) The net work for the cycle

W₁ ₋ ₂  +  W₂₋₃  + W₃₋₁

= 1000 kJ  + 0 kJ  +  - 3000 kJ

= - 2000 kJ

Hence we can conclude that the ) The work done for each process are :

and The net work for the cycle = -2000 kJ

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Attached below is the P-V sketch of the process

Answer:

true

Explanation:

The statement "Safety and environmental training are important in keeping employees safe and free from injuries and illness" is definitely true.

Injury may be characterized as a circumstance of being damaged or injured due to any physical means. This activity impacts the overall health and fitness of an individual.

Employees are working in their respective fields on the basis of their educational background, skills, and interests. But the fact that is common to all forms of employees is safety and security.

This safety prevents the employees from being injured and ill with the help of some crucial safety and environmental training in their respective trades. This approach by their company is beneficial for maintaining the health of their employees as well as the growth of the company.

Therefore, the statement "Safety and environmental training are important in keeping employees safe and free from injuries and illness" is definitely true.

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Answer:

According to the National Electric Code Paragraph 404 section 2, the cables entering into the 2-gang wall must be 4 in number and it must be fitted with a neutral conductor terminal as well.

Cheers

Answer:

The major systems of an automobile are the engine, fuel system, exhaust system, cooling system, lubrication system, electrical system, transmission, and the chassis. The chassis includes the wheels and tires, the brakes, the suspension system, and the body.

Explanation:

Answer:

[tex]\frac{To - T}{To - T_{infinity} } = 1 - e^{\frac{-bast}{mc} }[/tex]

Explanation:

Attached below is the detailed expression

Given function : T(x,y)

assuming surface of the lake is in (x,y) plane

path across the lake surface = (x(t), y(t)) = ( bi(t), b2(t))

In other to find an expression we have to make some assumptions

Active Filters:

Active filters are made by using the active components i.e operational amplifiers.

Passive Filters:

Passive filters are made by using passive components i.e capacitor, resistor, and inductor.

Active High Pass Filter:

An active high pass filter is shown in attachment. When the input with the high frequency is applied then the capacitive reactance will be low and signal will pass. When input frequency will be low capacitive reactance will be high. So, It will not allow to pass the Signal.

Designing:

The cuttoff frequency of this filter is given below:  

                                      [tex]f = 1/2\pi RC[/tex]

It is always known the cutoff frequency of the required filter. Hence, by supposing R we can find the C for this active high pass filter.

Gain:

As this is non-inverting amplifier so, its gain will be

                                       [tex]A = 1+ Ri/Rf[/tex]    

Answer:

c. 96.676 sq. Inches and 0.671 sq. Feet

Explanation:

From the list of the given option, we are told to chose the correct area in sq. inches that correspond to sq. Feet.

If we recall from the knowledge of our conversion  table that,

1 sq feet = 144 sq inches

Then, let's confirm if the option were true.

a.  966.76 sq. Inches and 8.056 sq. Feet

Assuming

if 1 sq feet = 8.056

in sq inches, we have ( 8.056 × 144 ) sq inches

= 1160.064 sq. inches

So, 1160.064 sq. inches is equal to 8.056 sq. Feet. Then option 1 is wrong

b. 96.676 sq. Inches and 8.056 sq. Feet

if 1 sq feet = 8.056

in sq inches, we have ( 8.056 × 144 ) sq inches

= 1160.064 sq. inches

So, 1160.064 sq. inches is equal to 8.056 sq. Feet. Then option 2 is wrong/

c. 96.676 sq. Inches and 0.671 sq. Feet

if 1 sq feet = 0.671

in sq inches, we have ( 0.671 × 144 ) sq inches

=  96.624 sq. Inches which is closely equal to 96.676 sq. Inches

Therefore, this is the correct answer as it proves that 96.676 sq. Inches = 0.671 sq. Feet

Answer:

DeMorgan equivalent :

F = B + C

F' = ⁻B⁻+⁻C⁻ = ⁻BC⁻

Explanation:

Attached below is the logic gate implementation diagram and the DeMorgan equivalent Boolean statement as requested in part A and B

Answer:

599.7 m

approximately 600 m

Explanation:

initial speed of the rocket = 0

net acceleration upwards = 7 m/s^2

the engine cuts out 10 sec after take off

maximum height reached = ?

we neglect air resistance

To get the velocity of the rocket at the point where the engine cuts off, we use the equation

v = u + at

where

v is the velocity at this point where the engine stops = ?

u is the initial velocity of the rocket from rest = 0 m/s

a is the net acceleration upwards = 7 m/s^2

t is the time the engine runs = 10 s

substituting, we have

v = 0 + (7 x 10)

v = 70 m/s

to get the distance from the ground to this point, we use the equation

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as

where

v is the final velocity at the the height where the engine is cut out = 70 m/s

u is the initial speed at the ground = 0 m/s

a is the net acceleration on the rocket = 7 m/s^2

s is the distance from the ground to this point

substituting, we have

[tex]70^{2}[/tex] = [tex]0^{2}[/tex] + 2(7 x s)

4900 = 14s

s = 4900/14 = 350 m

After this point when the engine cuts out, the rocket experiences an acceleration proportional to the acceleration due to gravity 9.81 m/s^2 downwards, and slows down gradually before coming to a stop at the maximum height.

To get this height, we use the equation

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] - 2gs   (the negative sign is due to the downward direction of the acceleration g)

where

v is the final velocity at the maximum height = 0 m/s (it comes to a stop)

u is the speed at the instance that the engine is cut out = 70 m/s

g is the acceleration due to gravity = 9.81 m/s^2

s is the distance from this point to the maximum height

substituting values, we have

[tex]0^{2}[/tex] = [tex]70^{2}[/tex] - 2(9.81 x s)

0 = 4900 - 19.62s

4900 = 19.62s

s = 4900/19.62 = 249.7 m

The maximum height that will be reached = 350 m + 249.7 m = 599.7 m

approximately 600 m

Answer: C

Both A and B are correct

Explanation:

Latent heat is the hidden heat.

Latent heat is the heat energy required to change one state of matter to another state of matter without change in temperature. For example, solid state to liquid state, or liquid state to gaseous state.

Thermometer can not detect the latent heat. That is why it is called hidden heat.

If Technician A says that latent heat is hidden heat and cannot be measured on a thermometer. And Technician B says that latent heat is hidden heat that is required for a change of state of matter, then we can therefore conclude that both Technician A and Technician B are correct.

Answer:

645 lb/ft

Explanation:

The height of the wall = 15 ft

For the 2 x 4 in. studs:

The minimum dead load for a 2 x 4 in. studs (from table 1-3) = 4 psf = 4 lb/ft²

Therefore for a 15 ft tall wall, the dead load for a 2 x 4 in. studs = 15 ft × 4 lb/ft² = 60 lb/ft

For the 4 in. clay brick:

The minimum dead load for a 4 in. clay brick (from table 1-3) = 39 psf = 39 lb/ft²

Therefore for a 15 ft tall wall, the dead load for a 4 in. clay brick = 15 ft × 39 lb/ft² = 585 lb/ft

Therefore the average load = load for the 4 in. clay brick + load for the 2 x 4 in. studs = 585 lb/ft + 60 lb/ft = 645 lb/ft

Answer:

Technician A is correct.

Two technicians are discussing a starter that clicks once when turning the key to the crank position. Technician A is correct. The correct option is A.

An electromagnet known as a starter solenoid is activated to turn on an internal combustion engine's starter motor. The starter solenoid then connects two contacts or metal points as the key is turned.

The starter motor receives electrical currents from the ignition through the solenoid in this way. This sets off a series of electrical reactions that ultimately start the combustion engine. The multifunctional crankshaft position sensor regulates ignition timing, measures RPM, and determines relative engine speed.

The solenoid is likely defective, and the starter may sustain serious damage as a result, if the starter engages but does not disengage when you release the key.

Therefore, the correct option is A. Technician A.

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Answer:

True ! Unsafe sites may use our personal information for criminal activities .

True ! Unsafe sites may use our personal information for criminal activities .

"Criminal Activities" should be required pre-"The Hateful Eight" viewing for anyone who's either forgotten or taken for granted Quentin Tarantino's gifts as a filmmaker.

Director Jackie Earle Haley's "Criminal Activities" is the worst kind of Tarantino clone, one with no gas in the tank, and no clue about how to pull off Tarantino's swagger.

So much of "Criminal Activities," a dizzyingly convoluted hostage drama, feels like a grim hang-out comedy as scripted by undergrad college film students.

Therefore, True ! Unsafe sites may use our personal information for criminal activities.

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Answer:

Casual workers

Explanation:

Casual workers are workers on a short-term employment contract that unlike non-permanent workers have restricted entitlement to benefits, little employment security, with the primary distinction of there being a lack of a stable connection or relationship between them and their employers for the to be referred to as employees.