To check on the strength of certain large steel castings, a small test piece is produced at the same time as each casting, and its strength is taken as a measure of the strength of the large casting. To examine whether this procedure is satisfactory, i.e., the test piece is giving a reliable indication of the strength of the castings, 11 castings were chosen at random, and both they, and their associated test pieces were broken. The following were the breaking stresses: 61 71 51 62 36 Test piece (): Casting (y) : 45 67 3986 97 77 102 45 62 58 69 48 80 74 53 53 48 (a) Calculate the correlation coefficient, and test for significance. (b) Calculate the regression line for predicting y from x'. (c) Compute and interpret the coefficient of determination. (d) Find 90% prediction limits for the strength of a casting when x = 60.

Answer:

2 + 1 = 3

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Berverly already has = 2 pens

Berverly bought = 1 pen

Then to show this situation in numerical expression, we have to add both values, then

= 2 + 1 = 3

Hence, this shows that the total number of pens Berverly has after buying is 3.

Answer:

8 cups of potatoes are needed

Step-by-step explanation:

One way of doing this work is to write out

1/4 cup                                             1 cup

------------- , which is equivalent to  ------------ (a unit rate)

 1 bowl                                              4 bowl

and then multiply this unit rate by 32 bowls:

(1/4)(32 bowls) = 8 cups of potatoes are needed

Answer:

586.76

Step-by-step explanation:

Take the area of the rectangular prism = 348

Find the area of the cylinder = 477.52

Divide the cylinder by 2 = 238.76

Add both together = 586.76

Answer:

995.26

Step-by-step explanation:

I'm not sure but this is what I got

The given parabola is a downward-opening parabola, its directrix is y = -1/2, and its focus is located at (0, -1/2).

The parabola represented by the equation [tex]-2y^2 = 4x[/tex] is a downward-opening parabola.

To understand the direction of the parabola, we can look at the coefficient of the [tex]y^2[/tex] term in the equation. Since it is negative (-2), the parabola opens downwards. If the coefficient were positive, the parabola would open upwards.

The equation of the directrix of a parabola can be determined by rearranging the given equation to the standard form, which is [tex](y - k)^2 = 4p(x - h)[/tex], where (h, k) represents the vertex of the parabola and p represents the distance between the vertex and the focus.

In the given equation, [tex]-2y^2 = 4x[/tex], we can divide both sides by -2 to obtain [tex]y^2 = -2x[/tex]. Comparing this to the standard form, we can see that the vertex is at (0, 0) since h = 0 and k = 0.

The coefficient of x in the standard form equation is 4p. Therefore, in our equation, 4p = -2, which implies p = -1/2.

Since p is negative, the directrix will be a horizontal line parallel to the x-axis and situated below the vertex. The equation of the directrix can be written as y = -1/2.

The focus of the parabola can be found by adding p to the y-coordinate of the vertex. In this case, since the vertex is at (0, 0) and p = -1/2, the focus will be at (0, -1/2).

In summary, the parabola represented by [tex]-2y^2 = 4x[/tex] is a downward-opening parabola. The equation of the directrix is y = -1/2, and the focus is located at (0, -1/2).

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Answer:

I would expect Emmy to get 8 hits in her next 16 tosses.

Emmy is to get 8 hits in her next 16 tosses.

Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Probability = Number of favourable outcomes / Number of samples

Given that Emmy is tossing bean bags at a target. She hit the target on 9 out of her last 18 tries. Considering this data.

The probability is,

P = 9 / 18

P = 0.5

The expected number of the hits on the target in 16 tosses will be;-

Number = 16 x 0.5

Number = 8

Therefore, Emmy is to get 8 hits in her next 16 tosses.

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A Möbius transformation is a transformation of the form f(z) = (az+b)/(cz+d), where a, b, c, and d are complex numbers and ad-bc ≠ 0. The complex number z maps to f(z).

To find the Möbius transformation f such that f(0) = 0, f(1) = 1, f([infinity]) = 2, we follow these steps:

Step 1: Map 0 to 0 We need to map 0 to 0, so we set f(0) = 0. So, we get 0 = (a(0) + b) / (c(0) + d). This gives us b = 0. Step 2: Map infinity to 2We need to map [infinity] to 2, so we set f([infinity]) = 2. So, we get 2 = (a[infinity] + b) / (c[infinity] + d). This gives us a/c = 2/d. Cross-multiplying the terms, we get ad = 2c.

Let us assume that d = 1, then we have a = 2c.

We can substitute this value of a in the Möbius transformation, and we get f(z) = (2cz) / (cz + 1).Step 3: Map 1 to 1To map 1 to 1, we evaluate the Möbius transformation at z = 1. We get f(1) = (2c) / (c + 1) = 1.

Solving this, we get c = -1/2. Therefore, the Möbius transformation is f(z) = (2z) / (z - 2).

Hence, we have found the required Möbius transformation f(z) = (2z) / (z - 2) such that f(0) = 0, f(1) = 1, and f([infinity]) = 2.

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Answer:

c

Step-by-step explanation:

it passes vertical line test and is linear

Answer:

C

Step-by-step explanation:

The answer is C. Hoped it helped.

In the drawing a graph is there with labeling of vertices A,B,C,D with matrix [tex]\begin{bmatrix}2 &1 & 1&0\\1 & 0 & 0&1\\1&0&0&1\\0&1&1&0\end{bmatrix}[/tex].

Given that,

a. We have to draw a graph which has the following adjacency matrix

[tex]\begin{bmatrix}2 &1 & 1&0\\1 & 0 & 0&1\\1&0&0&1\\0&1&1&0\end{bmatrix}[/tex]

Taking the matrix rows and column as A,B,C,D.

Therefore, In the drawing the graph is with matrix.

(b) We have to label the vertices of your graph A,B,C,D.

The drawing can be seen with the label of vertices A,B,C,D.

(c) We have to find how many different paths of length are there from the vertex you labelled A to D

A →A →B →A→A→B→A→C→D

A→A→A→A→A→C→D

A→A→A→A→A→B→D

Therefore, In the drawing a graph is there with labeling of vertices A,B,C,D with matrix [tex]\begin{bmatrix}2 &1 & 1&0\\1 & 0 & 0&1\\1&0&0&1\\0&1&1&0\end{bmatrix}[/tex].

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Answer:

y=3x^2-6x+3

Step-by-step explanation:

Answer:

51

Step-by-step explanation:

mode is the value which appears the most than other values. In this case 51 will appear 3 times.

Answer:

5.1

Step-by-step explanation:

dont forget the decimal

Answer:

area of triangle =1/2 p×b=1/2×4×3=6unit²

There is insufficient evidence to support the claim that the training technique is effective in raising the gymnasts scores.

In hypothesis testing, we often use significance levels such as 0.01 to determine whether or not there is enough evidence to support the hypothesis.

Here is the solution to the given problem.

The null hypothesis is that the training technique is not effective in raising the gymnasts' scores.

It is expressed as

H0: µd = 0.

The alternative hypothesis is that the technique is effective in raising the gymnasts' scores.

It is expressed as

Ha: µd > 0.

The significance level α = 0.01 is given.

Therefore, the given problem can be tested using a one-tailed t-test.

This is because the alternative hypothesis states that the mean difference between the two populations is greater than zero.

A t-test is appropriate because the sample sizes are less than 30.

The difference between the before and after competition scores of each gymnast should be calculated.

This gives us the difference scores, which are as follows:

0.1, 0.2, -0.02, -0.1, 0.1, 0.3, -0.2.

Next, we compute the mean and standard deviation of the differences. We have:

n = 7d

= 0.0714Sd

= 0.1466

Then we compute the t-statistic:

t = (d - µd) / (Sd / √n)

t = (0.0714 - 0) / (0.1466 / √7)

t = 1.5184

The degrees of freedom for this test are (n - 1) = 6.

Using a t-distribution table with 6 degrees of freedom and a significance level of 0.01 for a one-tailed test, we find that the critical t-value is 2.998.

For the given problem, the test statistic t = 1.5184 is less than the critical value of 2.998.

Therefore, we do not reject the null hypothesis.

There is insufficient evidence to support the claim that the training technique is effective in raising the gymnast scores.

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Given that (xn) and (yn) are Cauchy sequences, then for any ε > 0, there exist N1 and N2 such that |xn - xm| < ε/2, for all n, m ≥ N1 and |yn - ym| < ε/2, for all n, m ≥ N2. Then, for all n, m ≥ max{N1, N2},

we have: |xnyn - xmym| = |xnym - xmym + xmym - xnym| ≤ |xn - xm||ym| + |ym - yn||xm| ≤ |xn - xm|ε/2 + |ym - yn|ε/2 < εThis shows that (xnyn) is a Cauchy sequence.

Moreover, for any ε > 0, there exists N such that |xn - xm| < ε/2 and |yn - ym| < ε/(2max{|x1|, |x2|, . . . , |y1|, |y2|, . . . , |yn|}) for all n, m ≥ N. Then, for all n, m ≥ N,

we have: |xnyn - xmym| = |xnym - xmym + xmym - xnym| ≤ |xn - xm||ym| + |ym - yn||xm| + |ym - yn||yn| ≤ |xn - xm|ε/(2max{|x1|, |x2|, . . . , |yn|}) + |ym - yn|ε/(2max{|x1|, |x2|, . . . , |yn|}) + |yn|ε/(2max{|x1|, |x2|, . . . , |yn|}) < ε.

This shows that (xn)(yn) is also a Cauchy sequence.

Therefore, from the given definition, it has been shown that if (xn) and (yn) are Cauchy sequences, then (xn) (yn) and (xnyn) are Cauchy sequences.

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Answer:

I can't able to understand this question plz check this question if it is right or not

Answer:

The question needs more information but you can see that all the numbers in the 1st column are multiplied by 6 to equal the number in column 2

Step-by-step explanation:

3 x6 =18

6 x 6= 36

9 x6= 54

12 x6 =72

Answer:

96730322328

Step-by-step explanation:

I hope this helps

The third-degree Maclaurin polynomial for f(x) = sin(x) is P3(x) = x - (x^3) / 6.

To find the nth Maclaurin polynomial for the function f(x) = sin(x) when n = 3, we need to compute the polynomial up to the third-degree term.

The Maclaurin polynomial for a function f(x) centered at x = 0 is given by the formula:

Pn(x) = f(0) + f'(0)x + (f''(0)x^2) / 2! + (f'''(0)x^3) / 3! + ...

Let's calculate the nth Maclaurin polynomial for f(x) = sin(x) when n = 3:

First, we find the values of the function and its derivatives at x = 0:

f(0) = sin(0) = 0

f'(x) = cos(x), so f'(0) = cos(0) = 1

f''(x) = -sin(x), so f''(0) = -sin(0) = 0

f'''(x) = -cos(x), so f'''(0) = -cos(0) = -1

Using these values, we can write the Maclaurin polynomial:

P3(x) = 0 + 1x + (0x^2) / 2! + (-1x^3) / 3!

Simplifying further, we have:

P3(x) = x - (x^3) / 6.

Therefore, the third-degree Maclaurin polynomial for f(x) = sin(x) is:

P3(x) = x - (x^3) / 6.

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To approximate the sum of the series [infinity] (−1)n−1n^2/(8n), we can use a numerical method such as the partial sum method.

Let's calculate the partial sums of the series and add up terms until the sum converges to a desired level of accuracy. We will stop adding terms once the absolute difference between two consecutive partial sums is less than the desired accuracy.

Let's start by calculating the partial sums:

S_1 = (-1)^1-1(1^2)/(81) = 1/8

S_2 = (-1)^2-1(1^2)/(82) + (-1)^1-1(2^2)/(82) = 1/8 - 1/16 = 1/16

S_3 = (-1)^3-1(1^2)/(83) + (-1)^2-1(2^2)/(83) + (-1)^1-1(3^2)/(83) = 1/8 - 1/16 - 1/24 = -1/24

We can observe that the partial sums alternate between positive and negative values. This indicates that the series does not converge to a specific value but oscillates between two values.

To approximate the sum, we will calculate partial sums until the difference between two consecutive partial sums is less than the desired accuracy. Let's say we want the accuracy to be 0.0001.

Let's continue calculating partial sums:

S_4 = (-1)^4-1(1^2)/(84) + (-1)^3-1(2^2)/(84) + (-1)^2-1(3^2)/(84) + (-1)^1-1(4^2)/(84) = 1/8 - 1/16 - 1/24 + 1/32 = -1/48

S_5 = (-1)^5-1(1^2)/(85) + (-1)^4-1(2^2)/(85) + (-1)^3-1(3^2)/(85) + (-1)^2-1(4^2)/(85) + (-1)^1-1(5^2)/(8*5) = 1/8 - 1/16 - 1/24 + 1/32 + 1/40 = 1/120

The difference between S_4 and S_5 is 1/120 - (-1/48) = 1/120 + 1/48 = 1/80, which is greater than 0.0001.

Therefore, we can approximate the sum of the series as -1/48, correct to four decimal places.

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Answer:

(1.5, -4)

Step-by-step explanation:

( -1, -5) and (4, -3)

[tex](\frac{-1+4}{2} ,\frac{-5-3}{2} )\\\\(\frac{3}{2} ,\frac{-8}{2} )\\\\(1.5,-4)[/tex]

The answer is the test statistic (13.765) is greater than the critical value (5.991), we reject the null hypothesis. Therefore, we can conclude that there is a significant relationship between political party affiliation and support for the referendum on gay rights.

To represent the data in a table, we can create a contingency table:

                             For      Against

Republican            16        54

Democrat              72        28

Other                     27         3

Null hypothesis (H₀): There is no relationship between political party affiliation and support for the referendum on gay rights.

Alternative hypothesis (H₁): There is a relationship between political party affiliation and support for the referendum on gay rights.

To analyze the data, we can perform a chi-square test of independence. This test will determine if there is a significant association between political party affiliation and support for the referendum.

Applying the chi-square test at a significance level (α) of 0.05, we can calculate the test statistic and compare it to the critical value from the chi-square distribution with (rows - 1) × (columns - 1) degrees of freedom.

Let's calculate the expected frequencies for each cell assuming the null hypothesis is true:

                          For      Against    Total

Republican          27        43            70

Democrat            48        52           100

Other                   12        18             30

Total                    87       113            200

Now, we can calculate the chi-square statistic:

χ² = Σ[(O - E)² / E]

where O is the observed frequency and E is the expected frequency.

Performing the calculations, we find:

χ² ≈ 13.765

To determine the critical value, we need to find the degrees of freedom, which is equal to (rows - 1) × (columns - 1) = (3 - 1) × (2 - 1) = 2.

Using a chi-square distribution table or a statistical software, we find that the critical value for a significance level of 0.05 and 2 degrees of freedom is approximately 5.991.

Since the test statistic (13.765) is greater than the critical value (5.991), we reject the null hypothesis. Therefore, we can conclude that there is a significant relationship between political party affiliation and support for the referendum on gay rights.

In Michael's survey data, political party affiliation is related to the support for the referendum. Further analysis and interpretation of the results are needed to understand the nature and strength of this relationship.

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Answer:

53.8 gallons

Step-by-step explanation:

5.4*3=16.2

5.4 (gallons used per shower) * 3 (number of showers) = 16.2 (gallons used in 3 showers)

70-16.2=53.8

70 (Water in tank) - 16.2 (gallons used in 3 showers) = 53.8 (gallons of water left)

Hope this helps! Please brainliest!!!

Answer:

A(3) = 53.8 gallons left after 3 showers

Step-by-step explanation:

A(x) = volume of water left in tank = 70 gallons - (5.4 gallons)x, where x is the number of showers already taken.  

After  3 showers, the volume of water left is A(3) = 70 gal - (5.4 gallons)(3), or

A(3) = 53.8 gallons left after 3 showers

Answer:

Q2. angle 5 +angle 6=90°

angle 5+ 6°=90°

angle 5=90°-6°

angle 5=84°

Q.3 angle 8+angle 9=90°

angle 8 + 11°=90°

angle 8=90°-11°

angle 8=79°

Answer:

6, 8 and 10  and  -2, 0, 2

There are two roots x = -2 and 6,    

but the since I don't believe 0 is an even number the answer is 6, 8 and 10

I was incorrect according to G0ggle zero is an even number so another answer is  -2, 0, 2

Step-by-step explanation:

read the question and convert the English to mathematics

x, y and z    even consecutive number

y = x+2

z = y+2 = x+4

and

xyz = x³ + y² + 2z²                                   substitiute x terms  in for y and z

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²           solve for x by graphing on DEMOS

                                                                 x = -2, 6  solved algebraically below

x = -2   y=0   z=2

x = 6    y=8   z=10

Checked both answers

xyz = x³ + y² + 2z²

-2(0)2 = -8 + 0 + 8                  when x = -2

   0   =  0

and

6(8)(10)  =  6³ + 8² +2(10)²      when x = 6

   480   =  216+64+200

             =  480

x(x+2)(x+4)  = x³ + (x+2)² + 2(x+4)²                           solved algebraically

(x²+2x)(x+4)   = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + x² +4x +4 + 2x² + 16x + 32

x³ + 6x² + 8x = x³ + 3x² + 20x + 36

      3x² - 12x - 36 = 0         factor out the 3

      3[x² - 4x - 12] = 0

       3(x+2)(x-6) = 0     x = -2 and -12

Answer:

(2x+7)(x+7)

Step-by-step explanation:

Answer:

I don't think so .... :(((

Complete Question

Find the circumference of the pizza to the nearest hundredth.

When Diameter = 18 in.

Answer:

56.55 inches

Step-by-step explanation:

A pizza is circular in shape.

The formula for the circumference of a circle is given as:

πD

Where D = Diameter

From the above question,

Diameter = 18 inches

Hence,

Circumference of the circular pizza = π × 18 inches

= 56.548667765 inches

Approximately = 56.55 inches

Answer:

35

Step-by-step explanation:

subtract highest and lowest numbers