The critical value for the 40% level of significance is 1.96. Therefore, we can reject the Null hypothesis at the 40% level of significance.
In hypothesis testing, the critical value is used to determine the threshold for rejecting or not rejecting the Null hypothesis. The critical value depends on the desired level of significance and the distribution being used. In this scenario, we are conducting a one-sample t-test with a known population standard deviation.
To determine the critical value, we need to consider the level of significance. In this case, the level of significance is 40%, which corresponds to an alpha value of 0.40. Since the test is a one-tailed test (we want to test whether the mean waiting time is significantly more than 3 minutes), we divide the alpha value by 2, resulting in 0.20.
Using a t-distribution table or a statistical calculator, we find that the critical value for an alpha of 0.20 with degrees of freedom equal to the sample size minus 1 (99) is approximately 1.96.
Therefore, if the test statistic falls beyond the critical value of 1.96, we can reject the Null hypothesis at the 40% level of significance.
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Mrs. Avery is going to randomly select one student from her class to read a poem out loud. There are 15 boys and 13 girls in her class
The probability of selecting a girl to read the poem out loud in her class is 46.4% .
To calculate the probability of selecting a girl to read a poem out loud in a class of 28 students, we can use the formula:
Probability = Number of Desirable Outcomes / Total Number of Outcomes
Here, the desirable outcome is selecting a girl to read the poem, and the total outcomes are all the students in the class.
Number of Desirable Outcomes:
Mrs. Avery has 13 girls in her class, so there are 13 desirable outcomes.
Total Number of Outcomes:
Mrs. Avery has 28 students in her class, so there are 28 total outcomes.
Probability = Number of Desirable Outcomes / Total Number of Outcomes
Probability = 13 / 28
Probability = 0.464 or 46.4%
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Note: The complete question is -Mrs. Avery is planning to have one student read a poem out loud in class. She has a class of 28 students, consisting of 15 boys and 13 girls. What is the probability that she will select a girl to read the poem out loud?
Can someone help me with this. Will Mark brainliest.
Answer:
[tex]\sqrt{53}[/tex]
Step-by-step explanation:
Use the distance formula:
[tex]\sqrt{(x1-x2)^2+(y1-y2)^2}[/tex]
plug in (-5,6) for (x1,y1) and (-3,-1) for (x2,y2)
[tex]\sqrt{(-5-(-3))^2+(6-(-1))^2}[/tex]
[tex]\sqrt{4+49}[/tex]
[tex]\sqrt{53}[/tex]
Hope that helps :)
Plz help been stuck for a while now
Ay benefit concert, twelve bands have volunteered to perform but there is only enough time for eight of the bands to play. How many lineups are possible?
The requried, there are 495 possible combination lineups with eight bands out of twelve for the benefit concert.
To determine the number of possible lineups with eight out of twelve bands performing, we need to calculate the combination.
The number of ways to choose eight bands out of twelve without considering the order is given by the combination formula:
[tex]C(n, r) = \dfrac{n!}{ (r! * (n-r)!)}[/tex]
where n is the total number of bands (12 in this case) and r is the number of bands to be chosen (8 in this case).
Let's calculate it:
[tex]C(12, 8) =\dfrac {12!}{(8! * (12-8)!)}[/tex]
[tex]= \dfrac{12!} {(8! * 4!)}[/tex]
= (12 * 11 * 10 * 9) / (4 * 3 * 2 * 1)
= 495
Thus, there are 495 possible combination lineups with eight bands out of twelve for the benefit concert.
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Consider the function y = 4x + 5 between the limits of z = 1 and 2 = 5. a) Find the arclength L of this curve: L= Round your answer to 3 significant figures. b) Find the area of the surface of revolution, A, that is obtained when the curve is rotated by 2 radians about the a-axis. Do not include the surface areas of the disks that are formed at z = 1 and a = 5. A Round your answer to 3 significant figures.
Answer: 84π √(17) (rounded to 3 significant figures)
a) To find the arc length of the given curve we need to first evaluate the derivative of y w.r.t. x:dy/dx = 4. The arclength of the curve is given by L = ∫√(1+(dy/dx)^2) dx The value of dy/dx is already given and hence we can substitute the value and integrate .L = ∫√(1+(4)^2) dx = ∫√(17) dx Between the limits z = 1 and 2, x varies from 9 to 13. We need to substitute these values in the integral. L = ∫√(17) dx = √(17) * [x]9^13= √(17) * [13 - 9]= 4 √(17)Answer: 4√17 (rounded to 3 significant figures)
b) The area of the surface of revolution, A, that is obtained when the curve is rotated by 2 radians about the a-axis is given by:A = ∫2π * y √(1+(dy/dx)^2) dx We know that dy/dx = 4 and the value of y is given by 4x+5.A = ∫2π * (4x+5) √(1+(4)^2) dx= ∫2π * (4x+5) √(17) dx Between the limits z = 1 and 2, x varies from 9 to 13. We need to substitute these values in the integral. A = ∫2π * (4x+5) √(17) dx = 2π * √(17) * ∫(4x+5) dx= 2π * √(17) * [2x^2/2 + 5x]9^13= 2π * √(17) * [(26 + 60) - (18 + 20)]= 84π √(17)
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I just need the answer
Question: what’s the volume?
Write a negative integer and a positive integer whose sum is –5.
Answer:
-18+ 13
-6 + 1
-20 + 15
-7 + 2
Step-by-step explanation:
7
not using theorem in book. prove statement:
Let n be an integer. If a and b are integers such that a is
divisible by n and b is divisible by a, then a − b is divisible by
n
To prove the statement, let's assume that a and b are integers such that a is divisible by n and b is divisible by a.
Since a is divisible by n, we can write a = kn for some integer k.
Similarly, since b is divisible by a, we can write b = am for some integer m.Now, let's find the difference a - b:
a - b = kn - am
Factoring out common terms, we get:
a - b = n(k - m)
Since k and m are integers, their difference (k - m) is also an integer.
Therefore, we have expressed a - b as the product of n and an integer (k - m), which means that a - b is divisible by n.
Hence, we have proved that if a and b are integers such that a is divisible by n and b is divisible by a, then a - b is divisible by n, without using any specific theorem from a book.
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Steves pattern: 4, 25, 130, 665. what is steves pattern?
Answer: (4+1)*5=25; (25+1)*5=130; (130+1)*5=655.
Step-by-step explanation:
a toy rocket is fired into the air from the top of a barn its height H above the ground in yards after T seconds is given by the function h of T is equal to -5 t^2 + 10t + 20
1.what is the maximum height of the rocket
2. how long was the rocket in the air before hitting the ground
3.at what time(s) will the rocket be at a height of 22 yards
Answer:
45
Step-by-step explanation:
x = -30/2(-5)
x = -30/(-10)
x = 3 sec
.
Plug above into equation to find height:
h=-5t^2 + 30t
h=-5*3^2 + 30(3)
h=-5*9 + 30(3)
h=-45 + 90
h=45
You estimate that there are 56 marbles in a jar. The actual amount is 70 marbles. Find the percent error.
Answer:
80 percent of 70 is 56, so you were 20% wrong?
The percent error is 20%
let me know if you need anything else :)
There are some hens and some sheeps are in a farm,total number of animals are 10 and total number of their legs are 32 1.Find number of hens? 2. Find number of sheeps?
Answer: The number of hens are 4 and number of sheeps are 6
Step-by-step explanation:
Given : Total animals = 10
Total number of legs = 32
Let number of hens = h and number of sheep = s
Thus h+s = 10 (1)
Now each hen has two legs and each sheep has 4 legs :[tex]2\times h+4\times s=32[/tex] (2)
Solving for h and s we get:
s = 6 , h =4
Thus number of hens are 4 and number of sheeps are 6
WILL GIVE BRAINLIEST identify the domain of the function
Answer: The horizontal extent of the graph is -3 to 1, so the domain of f is (-3,1]
Step-by-step explanation:
The range is [-4,0]
A half-century ago, the mean height of women in a particular country in their 20s was 62.9 inches. Assume that the heights of today's women in their 20s are approximately normally distributed with a standard deviation of 2.87 inches.
If the mean height today is the same as that of a half-century ago, what percentage of all samples of 21 of today's women in their 20s have mean heights of at least 64.76 inches?
About _____ % of all samples have mean heights of at least 64.76 inches.
Approximately 0.11 percent of all samples have mean heights of at least 64.76 inches.
Given: 50 years prior, the mean level of ladies in a specific country in their 20s was 62.9 inches. With a standard deviation of 2.87 inches, women in their 20s today have heights that are roughly typical. We must determine the proportion of all 21 samples that have mean heights of at least 64.76 inches among today's women in their 20s. Bit by bit clarification:
Let μ be the mean level of ladies in this day and age and allow n to be the example size. We can find the likelihood of an example mean being more prominent than or equivalent to 64.76 inches utilizing the z-score recipe, as follows: z = (x - μ)/(σ/√n) = (64.76 - 62.9)/(2.87/√21) = 3.06The likelihood that an example of 21 ladies will have a mean level more noteworthy than or equivalent to 64.76 inches is equivalent to the likelihood that a typical irregular variable Z is more noteworthy than or equivalent to 3.06.
This probability is approximately 0.0011, or 0.11 percent, according to a typical normal table or calculator. This means that approximately 0.11 percent of all samples have mean heights of at least 64.76 inches.
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Q2 Solve the following initial value problem 1 y" + 4y = r - sin 3x y(0) = 1, (0) by using method of undetermined coefficients. (10 marks)
The given initial value problem using the method of undetermined coefficients. The final solution to the initial value problem is y = cos(2x) + x - (1/9)*sin(3x).
To solve the given initial value problem, we begin by finding the general solution to the associated homogeneous equation. The homogeneous equation is given by y'' + 4y = 0. The characteristic equation is obtained by substituting y = e^(mx) into the equation, resulting in the quadratic equation m^2 + 4 = 0. Solving this equation yields two distinct roots: m_1 = 2i and m_2 = -2i. Thus, the general solution to the homogeneous equation is y_h = c_1cos(2x) + c_2sin(2x), where c_1 and c_2 are arbitrary constants.
Next, we assume a particular solution in the form of y_p = Ax + B + Csin(3x) + Dcos(3x), where A, B, C, and D are undetermined coefficients. We substitute this particular solution into the given differential equation and solve for the coefficients. Comparing the coefficients of like terms, we find A = 0, B = 1, C = -1/9, and D = 0.
The particular solution is y_p = x - (1/9)*sin(3x), and the complete solution is obtained by adding the particular solution to the homogeneous solution: y = y_h + y_p. Applying the initial condition y(0) = 1, we find that c_1 = 1 and c_2 = 0. Therefore, the final solution to the initial value problem is y = cos(2x) + x - (1/9)*sin(3x).
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Please help 6th grade math please please help
Step-by-step explanation:
the beginning number is the beginning of your range the last number is the end of your range
hey what's the answer ?
[tex] \sqrt{36 \times 2 \times 2 \times 3 \times 3} [/tex]
Step-by-step explanation:
36 is your answer
I hope.it helps mate
have a nice day
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For which values of n does K, the complete graph on n vertices, have an Euler cycle? (b) Are there any K, 's that have Euler trails but not Euler cycles? (c) For which values of rand s does the bipartite graph Khave an Euler cycle?
(a) The complete graph [tex]K_n[/tex] has an Euler cycle if and only if n is an even number greater than or equal to 2.
(b) There are no complete graphs [tex]K_n[/tex] that have Euler trails but not Euler cycles. A complete graph always has an Euler cycle if it has an Euler trail.
(c) The bipartite graph [tex]K_r[/tex],s has an Euler cycle if and only if both r and s are even numbers greater than or equal to 2.
(a) To determine the values of n for which the complete graph [tex]K_n[/tex] has an Euler cycle, we need to understand the conditions for an Euler cycle to exist in a graph.
An Euler cycle is a closed walk in a graph that visits every edge exactly once and starts and ends at the same vertex. In order for a graph to have an Euler cycle, it must satisfy the following conditions:
All vertices in the graph have even degrees (an even number of edges incident to them).
The graph is connected, meaning there is a path between any two vertices.
Now let's apply these conditions to the complete graph [tex]K_n[/tex].
Degree of Vertices: In a complete graph [tex]K_n[/tex], each vertex is connected to every other vertex. Therefore, each vertex has a degree of n-1, as it is connected to n-1 other vertices. Since n-1 is always an odd number, it means that all vertices in [tex]K_n[/tex] have odd degrees. Hence, [tex]K_n[/tex] does not have an Euler cycle for any value of n.
Connectivity: A complete graph [tex]K_n[/tex] is always fully connected, meaning there is a direct edge between every pair of vertices. Therefore, the connectivity condition is satisfied for any value of n.
Based on these conditions, we can conclude that the complete graph [tex]K_n[/tex] does not have an Euler cycle for any value of n.
(b) since [tex]K_n[/tex] does not have an Euler cycle for any value of n, it also implies that there are no [tex]K_n[/tex] graphs that have Euler trails but not Euler cycles.
(c) The bipartite graph [tex]K_r[/tex],s is a complete bipartite graph with two sets of vertices, one with r vertices and the other with s vertices. To have an Euler cycle in this bipartite graph, the following conditions must be met:
All vertices in each set have even degrees.
The number of vertices in each set must be equal.
Since the complete bipartite graph [tex]K_r[/tex],s has all vertices with degree s in one set and degree r in the other set, it means that both r and s must be even numbers for all vertices to have even degrees. Additionally, the number of vertices in each set must be equal for the graph to be bipartite. Therefore, an Euler cycle exists in the bipartite graph [tex]K_r[/tex],s if and only if both r and s are even numbers.
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A five-year project that will require $3,200,000 for new fixed assets will be depreciated straight-line to a zero book value over six years. At the end of the project, the fixed assets can be sold for $640,000. The tax rate is 32% and the required rate of return is 13.30%. What is the amount of the aftertax salvage value?
As per the given values, the after-tax salvage value is $435,200.
Amount required = $3,200,000
Time = 6 years
Calculating the accumulated depreciation -
Amount/ Number of years
= $3,200,000 / 6
= $533,333.3.
Calculating the accumulated depreciation at project end -
= 6 x $533,333.33
= $3,200,000.
Calculating the book value of the fixed assets -
Book value = Cost of fixed assets - Accumulated depreciation
= $3,200,000 - $3,200,000
= $0
Calculating the taxable gain or loss on the sale of the fixed assets -
Taxable gain/loss = Selling price - Book value
= $640,000 - $0
= $640,000
Calculating the tax liability -
Tax liability = Tax rate x Taxable gain
= 0.32 x $640,000
= $204,800
Calculating the after-tax salvage value -
After-tax salvage value = Selling price - Tax liability
= $640,000 - $204,800
= $435,200
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Figure out the x-intercept and y-intercept in given equation of the line.
6x + 2y = 12
Answer:
x intercept=2
y intercept=6
Step-by-step explanation:
to find x and y intercepts, plug in 0 for x and y
x intercept-
6x+2(0)=12
6x=12
x=2
y intercept-
6(0)+2y=12
2y=12
y=6
(50 POINTS) Express each sum using summation notation.
14. 3 + 3^2/2 + 3^3/3 ... + 3^n/n
15. 1 + 3 + 5 + 7 +... [2(12) - 1]
I'm on my school computer so the picture is blocked sorry :(
Answer:
the answer is in the photo hope it help
The 4th term of an arithmetic sequence is 24 and the 12th term is 56, what is the first term?
Answer:
First term = 12
Step-by-step explanation:
A4 = 24
A12 = 56
An = A1 + (n-1)d; this defines the formula of an arithmetic series
A4 = 24 = A1 + (4-1)d
A4 = 24 = A1 + 3d
A12 = 56 = A1 + (12-1)d
A12 = 56 = A1 + 11d
Subtract A4 from A12 to get d (distance)
(56 = A1 + 11d) - (24 = A1 +3d)
32 = 8d
d = 4
Substitute d = 4 into A4
A4 = 24 = A1 + 3(d)
24 = A1 + 3(4)
24 = A1 + 12
24 - 12 = A1
12 = A1
If c ⊥ b and a || c, what is m∠2?
Answer:
A) 90°
Step-by-step explanation:
if lines b and c are perpendicular then all 8 angles measure 90 degrees
please answer asap
i will mark brainliest
Which equation can be used to solve for in the following diagram?
Choose 1 answer:
А) 105 + (50 – 70) = 90
B) 105 + (5x – 70) = 180
C) 105 = (5x – 70)
D) 105 +90 = (5x - 70)
Answer:
C) 5x-70=105
Step-by-step explanation:
As marked in the graph, angle 105 and angle (5x-70) equal to each other because they are vertically opposite angles therefore we have equation C)
A sample of data with n = 66 observations is used to run a multiple regression with 7 independent variables.
If this data set has SST = 2326.9523 and SSR = 1632.8843, what is the value of the F-statistic for the test of overall significance of this regression relationship?
The value of the F-statistic for the test of overall significance of this regression relationship is approximately 11.245.
Given:SST = 2326.9523 SSR = 1632.8843 Independent variables = 7
Observations = 66Formula used:F = (SSR/K) / (SSE / (n-K-1))
Where SSR = Regression sum of squares SSE = Error sum of squaresK = Number of independent variables n = Number of observations
To calculate the F-statistic, we first need to calculate SSE which is given by:SSE = SST - SSR = 2326.9523 - 1632.8843 = 693.068
The degrees of freedom for the regression are K and the degrees of freedom for the error term are n - K - 1 = 66 - 7 - 1 = 58
The value of the F-statistic is given by:F = (SSR/K) / (SSE / (n-K-1))= (1632.8843/7) / (693.068 / 58)= 11.245
Therefore, the value of the F-statistic for the test of overall significance of this regression relationship is approximately 11.245.
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Assuming the profit of one airport is regulated by a rate-of-return (ROR) based regulation, the allowed ROR is 2%. The estimated airport asset that can be used as base in 2020 is about $100 million. Then, the maximum profit the airport can collect is _____.
Assuming the profit of one airport is regulated by a rate-of-return (ROR) based regulation of 2% and the estimated airport asset for 2020 is about $100 million, the maximum profit the airport can generate is $2 million.
How the maximum profit is computed:The maximum profit of the airport is a function of the multiplication of the estimated asset and the allowed maximum rate of return.
The rate of return is the percentage of total returns expressed as a quotient of the total assets multiplied by 100.
The allowed maximum rate of return = 2%
Estimated asset of the airport for 2020 = $100 million
The maximum profit = $2 million ($100 million x 2%)
Thus, the airport's maximum profit for 2020 is $2 million.
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2.07x2.4 plz help quick i need this
Answer:
2.07x2.4=4.968
Step-by-step explanation:
Answer:
4.968
Step-by-step explanation:
Find the LCM and HCF of 64 and 72 using prime factors
What is the LCM of 64 and 72?
Find the prime factorization of 64.
Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.
Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM: LCM = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3.
LCM = 576.
What is the GCF of 64 and 72?
Find the prime factorization of 64. 64 = 2 × 2 × 2 × 2 × 2 × 2.
Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.
To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 2 × 2 × 2.
GCF = 8.
Answer:
8x8 and 8x9
Step-by-step explanation:
because 8x8 is 64 and 8x9 is 72
A rectangular pool has an area of 50 square feet. What are the lengths of its sides? There is more than one possible answer. Draw a picture of the possible answers.
Answer:
10*5 or 25*2
Step-by-step explanation:
There are other answers but those involve decimals and I'm assuming they want whole numbers.
I don’t have time to do it help me please
Answer:
4=3 5=10 6= YOu would add more dots accordingly 7=4
Step-by-step explanation:
hoped this helped!