.The height of a cylinder whose radius is 7 cm and the curve surface area is 968 cm2 is:

Step-by-step explanation:

1/6×100%=50/3%

3/24×100%=25/4%

3/8×100%=75/2%

=>50/3%+25/4%+75/2%+x=100%

=>100%-725/12%=x

=>x=59 and 5/12

Answer:

24

Step-by-step explanation:

4/9=x/54

4/9*54=x

x=4*6

x=24

Answer:

Yep its 24

Step-by-step explanation:

Answer:

A. [tex]4x[/tex]

B. [tex]16x[/tex]

C. [tex]16x+20[/tex]

Step-by-step explanation:

A square's area will be the length of each side squared (that's why it's called squared).

Since we know the area, we can find the square root of [tex]16x^2[/tex] to find the length of each side.

We know that [tex]4^2 = 16[/tex] and [tex]x^2 = x^2[/tex], so [tex]4x\cdot 4x[/tex] should be equal to [tex]16x^2[/tex].

This means the side length is [tex]4x[/tex].

The perimeter of a square will be 4 times it's side length. We know the side length, so the perimeter is [tex]4x \cdot 4 = 16x[/tex].

If we added 5 to the length of each side, the new side length would be [tex]4x + 5[/tex]. Again, the perimeter is 4 times the side length so the perimeter would be [tex]4(4x + 5) = 16x + 20[/tex].

Hope this helped!

Answer:

23F

Step-by-step explanation:

Answer:

Step-by-step explanation:

He would put it in the thousandths digit.

0.06 = 6 hundredths

0.006 =  6 thousandths

Answer:

[tex]\boxed{\bold{\huge{\boxed{Area\ of\ Trapezium = 150\ cm\²}}}}[/tex]

Step-by-step explanation:

Using Pythagorean Theorem first to find EC

[tex]\sf CB^2 = EB^2+EC^2\\Where \ CB = 13 \ and \ EB = 5 \\13^2 = 5^2 + EC^2 \\169 - 25 = EC^2 \\EC^2 = 144\\Taking \ sqrt \ on \ both \ sides\\EC = 12 \ cm[/tex]

Given that:

AE = EC

AE = 12 cm

Now,

AB = AE + EB

AB = 12 + 5

AB = 17 cm

ABCD is a trapezoid / trapezium

So,

Area of Trapezium = [tex]\sf \frac{AB+DC}{2} (EC)[/tex]

Where AB = 17 , DC = 8 and EC = 12

Area of Trapezium = [tex]\sf \frac{17+8}{2} ( 12)[/tex]

Area of Trapezium = (25)(6)

Area of Trapezium = 150 cm²

Answer:

800

Step-by-step explanation:

the tenth is the second 9 and the 9 before it makes it round up

Thus, the second 9 rounds up also

Therefore, it changes the 7 to a 8 and the 9s are now 0s

hope it helps :)

Answer:

false

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

Calculate the length using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (- 3, - 4) and (x₂, y₂ ) = (5, 2)

d = [tex]\sqrt{(5+3)^2+(2+4)^2}[/tex]

   = [tex]\sqrt{8^2+6^2}[/tex]

   = [tex]\sqrt{64+36}[/tex]

   = [tex]\sqrt{100}[/tex] = 10

Answer:

Step-by-step explanation:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(2-2)^2+(5+1)^2}=\sqrt{0^2+5^2}=\sqrt{25}=5[/tex]

Answer:

=5/9 or 0.5

Step-by-step explanation:

Answer:

0.55

Step-by-step explanation:

8/9-1/3

8*1/9*1 - 1*3/3*3

8/9 - 3/9

8-3/9

5/9

0.55

Answer:

19 chicken wings

Step-by-step explanation:

For $39.10=23 chicken wings

For $1=23/39.10 chicken wings

For $32.30=23/39.10 x 32.30= 19 chicken wings

Answer:

Step-by-step explanation:

The segment addition theorem tells you ...

  CD +DE = CE

  x^2 +12x = 32 -2x

Subtract the right side to put this in standard form.

  x^2 +14x -32 = 0

  (x +16)(x -2) = 0

  x = -16 or 2

In order for DE to have a positive length, we must have x > 0. So ...

  CD = x^2 = 2^2 = 4

  DE = 12x = 12(2) = 24

  CE = 32 -2x = 32 -2(2) = 28

Answer:

[tex]\sqrt{65}[/tex]

Step-by-step explanation:

The magnitude of a vector < x, y > is calculated as

| < x, y > | = [tex]\sqrt{x^2+y^2}[/tex]

Thus

j + k = < - 2, 1 > + < - 5, 3 > = < - 2 - 5, 1 + 3 > = < - 7, 4 >

Then

| < - 7, 4 > | = [tex]\sqrt{(-7)^2+4^2}[/tex] = [tex]\sqrt{49+16}[/tex] = [tex]\sqrt{65}[/tex]

Answer:

Jason's camp counselor job pays a higher rate than Mia's lifeguard job.

Jason's job pays $9 a hour.

Mia's job pays $8.75 a hour.

52.50 divided by 6 equals 8.75

70.00 divided by 8 equals 8.75

43.75 divided by 5 equals 8.75

Step-by-step explanation:

Answer:

C. Jason’s camp counselor job pays a higher hourly rate than Mia’s lifeguard job.

Step-by-step explanation:

I took the quiz

Answer:

C.  pi radians

Step-by-step explanation:

got it right on edge :)

Answer:

letter c

Step-by-step explanation:

Answer:

No solution

Step-by-step explanation:

To solve this, we subtract 7x from both sides to get 2=-3. Since 2 does not equal to negative 3, there is no solution.

Answer:

9

Step-by-step explanation:

So there's 3 1's, 2 2's, 2 3's, 1 4, 2 5's, a 6, a 7, an 8, 2 0's, and no 9's.  

Answer:

20° and 70°

Step-by-step explanation:

Complementary angles sum up to 90°.

The angle = x

Its complement = x + 50

x + x + 50 = 90

2x = 40

x° = 20°

20+50=70

Answer: 70°  and 20°

Step-by-step explanation:

Complementary angles add up to 90 degrees  and we now that one angles measure is 50 degrees less than the other. So we can represent it by the expression   x = y -50    where x  and y are the two angles. We don't the value of y so it will be just y .

Now we know that if we add them,they will equation 90 degrees so we can represent it by the equation,

y + y-50 = 90  Now solve for y

2y - 50 = 90  

      +50  +50

2y = 140

y = 70  

Now we know one angles is 70 degrees and the other is 50  less than it so the other angle will be   70 - 50 = 20  

Answer:

B

Step-by-step explanation:

a-3>-7

collect like terms

a>-3-7

a>-10

Answer:

there is no choices but i can tell you some

as a decimal 0.429

6/14

12/28

multiply it by two every time

Step-by-step explanation:

Answer:

The equation of the line is,

[tex]y = - \frac{2}{5} x - 1[/tex]

Step-by-step explanation:

First, you have to write it in a form of y = mx + b :

[tex]2x + 5y = 15[/tex]

[tex]5y = 15 - 2x[/tex]

[tex]y = 3 - \frac{2}{5} x[/tex]

[tex]y = - \frac{2}{3} x + 5[/tex]

When both lines are parallel to each other, they will have to same gradient value. So the equation of the line is y = (-2/5)x + b. Next, you have to find the value of b by substutituting (-10,3) into the equation :

[tex]y = - \frac{ 2}{5}x + b [/tex]

[tex]let \: x = - 10,y = 3[/tex]

[tex]3 = - \frac{2}{5} ( - 10) + b[/tex]

[tex]3 = 4 + b[/tex]

[tex]3 - 4 = b[/tex]

[tex]b = - 1[/tex]

Answer:

the equation of a parallel line is : y=-2/5 x -1

Step-by-step explanation:

2x+5y=15

put the equation in the form of y=mx+b

2x+5y=15

5y=15-2x

y=15/5-2/5 x

y=-2/5 x+3

parallel lines has the same slope : m=-2/5

passes through point (-10,3) find b

y=-2/5 x +b

3=-2/5(-10)+b

3=20/5 +b

3=4+b

b=3-4

b=-1

the equation of a parallel line is : y=-2/5 x -1

Answer:

7

Step-by-step explanation:

Since f(x)=10 is equivalent to f(x)=2x-4, make these equations equivalent. Add 4 to both sides, and simplify to get 2x=14. Divide both sides by 2 to get 7 as your answer.

Answer:

x = 7

Step-by-step explanation:

Given

f(x) = 2x - 4 and f(x) = 10, then equating gives

2x - 4 = 10 ( add 4 to both sides )

2x = 14 ( divide both sides by 2 )

x = 7

Answer:

[tex]\large\boxed{\text{The expression is equal to 104}}[/tex]

Step-by-step explanation:

[tex]24+10 \cdot 8 \\24+80\\104[/tex]

Answer:

2y=x+16

Step-by-step explanation:

condition for a perpendicular line to the previous line is that the gradient M1=-1/M2. looking at the question above the equation of the line given y=-2x+3 that is the first M1=-2. so to get the gradient M2 of the line perpendicular, then M2=-1/-2=1/2. so M2=1/2. so the equation of the new line is y=1/2x+C. so we can find C. since the line passes through (-4,6). when x=-4, y=6, 6=1/2(-4)+C..C=6+2=8. so the equation of the new line y=1/2x+8 we can multiply via 2. so we have 2y=x+16

the equation is 2y=x+16

Answer:

3^4

Step-by-step explanation:

One of the laws of exponents is that when you are multiplying exponents with the same base, then you add their powers. So,

3^5 x 3^3 = 3^8

Another law is when dividing exponents with the same base, you can subtract the powers. So,

3^8/3^4 = 3^4

Hope this helps!

Answer:

true : 9-2=7 false:3+2=6

Step-by-step explanation:

the first equation is false because if you take 6 and minus 3 you get three not two, But with the other equation its diffrent you take 7 and add it to two you get nine.