Rework problem 29 from section 2.3 of your text, involving the selection of officers in an advisory board. Assume that you have a total of 13 people on the board: 3 out-of-state seniors, 4 in-state seniors, 1 out-of-state non-senior, and 5 in-state non-seniors. University rules require that at least one in-state student and at least one senior hold one of the three offices. Note that if individuals change offices, then a different selection exists. In how many ways can the officers be chosen while still conforming to University rules?

Answer:

400

Step-by-step explanation:

Answer:

yay

Step-by-step explanation:

yayyayyayyayyayyyayyayayayyayaya

Answer:

D. 5x2 + 28x + 21

Step-by-step explanation:

First you want to find the area of the white rectangle

Then find the area of the beings rectangle

Then subtract beings minus white.

                                     Sorry it’s +21. The first answer in your list

                                      then thats correct

...............................................................................................................................................

5x^2+28x+21 confirmed from Cortez himself

The z-score table shows that for a z-score of 15.1, the p-value is approximately zero (p < 0.0001). Hence, the p-value for this sample is p < 0.0001.

Given that the population is normally distributed and the standard deviation is σ = 5.2.

A sample of size n = 64 is obtained with the sample mean of M = 78.5.

Test statistic = (Sample mean - population mean) / (Standard error of the mean) = (78.5 - µ) / (σ /√n)

Where µ = population mean = 0σ = 5.2n = 64.

The formula for the standard error of the mean is; σM = σ/√n = 5.2/√64 = 0.65.

Substituting in the test statistic equation,

Test statistic = (78.5 - 0) / 0.65 = 121.54.

P-value is the probability of obtaining the observed sample mean or a more extreme value from the null hypothesis.

Assuming a significance level of α = 0.05 and the null hypothesis H0: µ = 0 (Population mean), we can obtain the p-value from the z-score table.z-score = (sample mean - population mean) / standard deviation = (78.5 - 0) / 5.2 = 15.1

The z-score table shows that for a z-score of 15.1, the p-value is approximately zero (p < 0.0001).Hence, the p-value for this sample is p < 0.0001.

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The y-intercept of the graph of the function f(d) would represent 7 and a reasonable domain to plot the growth function is 0 ≤ d ≤ 18 because the number of days is a whole number.

Part A: When the biologist concluded her study, the radius of the algae was approximately 13,29 mm.

What is a reasonable domain to plot the growth function?The given equation is,f(d) = 7(1.06)d

The radius of the algae was approximately 13.29 mm, which is the value of f(d).Thus, f(d) = 13.29

Substitute this value in the equation to find the value of d.13.29 = 7(1.06)dlog(13.29/7)/log(1.06) = dd = 17.19

Hence, a reasonable domain to plot the growth function is 0 ≤ d ≤ 18 because the number of days is a whole number.

Part B: What does the y-intercept of the graph of the function f(d) represent?The y-intercept of the graph of the function f(d) represents the initial value of the function when x = 0. The given function is,f(d) = 7(1.06)d

Substitute 0 in the above function and solve for f(0).f(0) = 7(1.06)0f(0) = 7

Hence, the y-intercept of the graph of the function f(d) represents 7.

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Answer:

B - Her monthly average would have increased by $19.57. ... Katie works as a waitress and records her monthly tips in the table shown below. If Katie decided not to work the month of November, how would her five month average compare to her six month ... Lisa is currently taking physics as one of her electives in school.

Step-by-step explanation:

Answer:

Nov. ✔ = Feb.

Oct. ✔ < Dec.

Jan. ✔ > Nov.

Step-by-step explanation:

Edge 2022

The mean is greater than the median, which in turn is less than the mode, in a unimodal skewed right distribution. Therefore, option c) is the correct answer.

The terms mean, median, and mode are commonly used in statistics to measure the central tendency of a set of

values or a dataset.  The mean is calculated by dividing the sum of all the numbers in a dataset by the total number of

items in the dataset. The mean is the average of the dataset. The median is the middle number in a dataset when the

data is arranged in ascending or descending order. Half of the values are higher than the median, and half are lower.

The mode is the value that appears most frequently in a dataset. If there are two values that occur with the same

frequency, the dataset is referred to as bimodal, and if there are more than two values that occur with the same

frequency, the dataset is referred to as multimodal. In a unimodal skewed right distribution, the mean is greater than

the median, which in turn is less than the mode. Therefore, the correct answer is option c) greater, less than.

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The eigenvalues of the matrix -2 0 1 1 0 -1 0 1 -1 are λ₁ = -1, λ₂ = 1, and λ₃ = -1. The corresponding eigenspaces are E₁ = span{[-1, 1, 0]}, E₂ = span{[1, 1, 1]}, and E₃ = span{[-1, 1, 2]}.

Eigenvalues and eigenvectors play a fundamental role in linear algebra, particularly in the study of matrices.

The eigenvalues of a matrix are the values λ for which the equation A = λ has nontrivial solutions, where A is the given matrix and is a non-zero vector. The eigenspace associated with an eigenvalue is the set of all eigenvectors corresponding to that eigenvalue.

To find the eigenvalues of the matrix -2 0 1 1 0 -1 0 1 -1, we need to solve the characteristic equation det(A - λI) = 0, where A is the given matrix, λ is an eigenvalue, and I is the identity matrix.

The characteristic equation in this case is (-2 - λ)(λ² + 1) + (1 - λ)(-1) = 0. Simplifying this equation yields λ³ - 2λ² - 2 = 0. This is a cubic equation, and we can use a calculator or Wolfram Alpha to find its roots, which are λ₁ = -1, λ₂ = 1, and λ₃ = -1.

Once we have the eigenvalues, we can find the corresponding eigenvectors by solving the equation (A - λ) = 0 for each eigenvalue.

For λ₁ = -1, solving (A + ) = 0 gives us the eigenvector [-1, 1, 0]. For λ₂ = 1, solving (A - ) = 0 gives us the eigenvector [1, 1, 1].

Finally, for λ₃ = -1, solving (A + ) = 0 gives us the eigenvector [-1, 1, 2]. These eigenvectors span the eigenspaces E₁, E₂, and E₃, respectively.

In summary, the eigenvalues of the matrix -2 0 1 1 0 -1 0 1 -1 are λ₁ = -1, λ₂ = 1, and λ₃ = -1. The corresponding eigenspaces are E₁ = span{[-1, 1, 0]}, E₂ = span{[1, 1, 1]}, and E₃ = span{[-1, 1, 2]}.

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Answer:

The domain of a function is the set of the possible input values of the function. For example: consider the function f(x) = cos x, the domain of the function is the set of possible values of x.

The cosine function takes x values from all real numbers.

Therefore, the domain of the cosine function is a real numbers.

Step-by-step explanation:

Answer:

the answer is d=20.5 hope this helped

Answer:

d= 20.5

Step-by-step explanation:

d/4+7/8=6

(we know that to add fractions, we have to have both denomiators the same number. We aslo know that that means 8. Using that information, we know that to top number must be 48. 48/8 = 6. We can substract)

48-7= 41

(we then need to divide by 2 as we would have had to already multiplyed 4 by 2.)

41/2 = 20.5

(a) The mgf of Y is M_Y(t) = exp (3.54t + 0.01632t²).

(b) The distribution of Y, the total weight of the three 1-kilo packs of cheese selected is Y ~ N(3.54, 0.216).

(c) The probability P(Y < W) = 0.2808.

(a) The moment generating function (mgf) of Y, the total weight of the three 1-kilo packs of cheese selected is given by:

M_Y(t) = M_X1(t) × M_X2(t) × M_X3(t)

= exp (µ_X1 t + ½ σ²_X1 t²) × exp (µ_X2 t + ½ σ²_X2 t²) × exp (µ_X3 t + ½ σ²_X3 t²)

= exp [(µ_X1 + µ_X2 + µ_X3) t + ½ (σ²_X1 + σ²_X2 + σ²_X3) t²]

Therefore, the mgf of Y is given by:

M_Y(t) = exp [(1.18 + 1.18 + 1.18) t + ½ (0.072 + 0.072 + 0.072) t²]

M_Y(t) = exp (3.54t + 0.01632t²)

(b) The total weight Y of the three 1-kilo packs of cheese is the sum of three independent and identically distributed random variables.

So, the distribution of Y is given by the following normal distribution: Y ~ N (µ_Y, σ²_Y), where µ_Y = µ_X1 + µ_X2 + µ_X3 and σ²_Y = σ²_X1 + σ²_X2 + σ²_X3.

Thus, µ_Y = 3 × 1.18

µ_Y = 3.54 and,

σ²_Y = 3 × 0.072

σ²_Y = 0.216

⇒ σ_Y = √0.216

⇒ σ_Y = 0.4649

Therefore, Y ~ N(3.54, 0.216).

(c) We need to find P(Y < W), where W is the weight of the 3-kilo pack of cheese.

Now, Y and W are independent normal random variables.

Therefore, Y - W is also a normal random variable with the following distribution: Y - W ~ N(µ_Y - µ_W, σ²_Y + σ²_W), where µ_W = 3.22 and σ²_W = 0.09².

We know that µ_Y - µ_W = 3.54 - 3.22

µ_Y - µ_W = 0.32 and,

σ²_Y + σ²_W = 0.216 + 0.09² = 0.301.

Therefore, σ_Y - W = √0.301

σ²_Y + σ²_W = 0.5486.

Now, we need to find P(Y - W < 0), which is equivalent to finding P(Z < -0.5799), where Z = (Y - W - (µ_Y - µ_W))/σ_Y - W.

Substituting the values, we get:

Z = (Y - W - 0.32)/0.5486

⇒ Y - W = -0.5799

Z = (Y - W - 0.32)/0.5486

⇒ Y - W < 0 is equivalent to Z < -0.5799.

Using a standard normal table or calculator, we get: P(Z < -0.5799) = 0.2808.

Hence P(Y < W) = P(Y - W < 0)

P(Y < W) = 0.2808.

Therefore, P(Y < W) = 0.2808, correct to four decimal places.

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To evaluate the double integral over the region in the first quadrant enclosed by a circle and lines by changing to polar coordinates, we need to express the integral limits and the integrand in terms of polar coordinates.

The region in the first quadrant enclosed by a circle and lines can be defined as follows: The circle has a radius 'r' centered at the origin, and the lines are given by the equations θ = 0 and θ = π/4, where θ represents the angle in polar coordinates.

In polar coordinates, the limits of integration for 'r' would be from 0 to the radius of the circle, and the limits of integration for θ would be from 0 to π/4.

The integrand, which represents the function being integrated, would be expressed in terms of 'r' and θ.

To evaluate the double integral, we would integrate the function over the defined region using the limits of integration and the appropriate differential element in polar coordinates, which is r dr dθ.

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Answer:

If you go to this link it'll give you a whole explanation and walk   how to get your answer:

https://www.khanacademy.org/math/arithmetic/fraction-arithmetic/arith-review-visualizing-equiv-frac/a/equivalent-fractions-common-denominator-review

Step-by-step explanation:

Hope that this helps! :)

Have a great rest of your day/night!

Answer:

what are we rounding? like what is your question?

Step-by-step explanation:

**if you answer you have my promise and i'll go back and provide an actual answer**

Answer:

True, false, true, true.

Step-by-step explanation:

The roots zeros of a quadratic function are the same as the factors of the quadratic function. This is true because your roots are your factors—>(x-3) is a factor, x=3 is the root.

The roots zeros are the spots where the quadratic function intersects with the y-axis. No! Those are called y-intercepts!

The roots zeros are the spots where the quadratic function intersects with the x-axis. True. X-intercepts are your solutions. (x-3) graphed would the (3,0). That’s a solution.

There are not always two roots/zeros of a quadratic function,​ True. No solution would be when your quadratic doesn’t intersect the x-axis. One solution would be when your vertex would be on the x-axis. Two solutions is when your quadratic intersects the x-axis twice. Can there be infinite solutions? No. It’s either 0, 1, or 2 solutions.

Answer:

The formula would be

((a+b) / 2)h = area

In this case a is one side of the base (top parralel or bottom line)

And b is the second one (top or bottom)

You can only choose one for each

You add those two up and divide that by 2

Now you multiply it by “h” or height.

Now you have the area

Answer:

I think that the answer is B , 337/5 i mean .

Good luck ^^

Answer:

= 15/20 + 1 10/20 + 4 4/20

= 5 29/20

= 6 9/20

Exact Form:

[tex]\frac{3}{4}[/tex]

Decimal Form:

6.45

Mixed Number Form:

6[tex]\frac{9}{12}[/tex]

The average cost AC when x = 90 is $1, and the derivative C'(x) when x = 90 is $0.41.

The average cost function AC and the derivative of the total cost function C'(x) can be found using the given total cost function C(x) = 0.01x + 0.4x + 50, where x represents the number of units produced and sold.

To find the average cost AC, we divide the total cost C(x) by the quantity x:

AC = C(x) / x

Substituting the given total cost function C(x) = 0.01x + 0.4x + 50, we have:

AC = (0.01x + 0.4x + 50) / x

Simplifying, we get:

AC = (0.41x + 50) / x

When x = 90, we substitute this value into the equation:

AC = (0.41 * 90 + 50) / 90

AC = (36.9 + 50) / 90

AC = 86.9 / 90

AC ≈ $0.97 ≈ $1 (rounded to two decimal places)

To find the derivative C'(x), we differentiate the total cost function C(x) with respect to x:

C'(x) = d/dx (0.01x + 0.4x + 50)

C'(x) = 0.01 + 0.4

C'(x) = 0.41

When x = 90, we substitute this value into the equation:

C'(90) = 0.41

Therefore, the derivative C'(x) when x = 90 is $0.41.

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(a) To prove that B\A = (AB)* using only the above equations and equivalences, we need to show that B\A is equivalent to (AB)*.

First, we will show that B\A is a subset of (AB)*.

Let x be an element of B\A. Then, x is in B and x is not in A. Therefore, x is in AB and not in A. This means that x is in (AB)*. Thus, we have shown that B\A is a subset of (AB)*.

Next, we will show that (AB)* is a subset of B\A.

Let x be an element of (AB)*. Then, x is in AB or x is not in AB.

If x is in AB, then x is in B and x is in A. Therefore, x is not in B\A.

If x is not in AB, then x is not in A or x is not in B. Therefore, x is not in A and x is in B. This means that x is in B\A.

Thus, we have shown that (AB)* is a subset of B\A.

Since we have shown that B\A is a subset of (AB)* and (AB)* is a subset of B\A, we can conclude that B\A = (AB)*.

(b) To prove that B* A* = (AB)*, we need to show that B* A* is a subset of (AB)* and (AB)* is a subset of B* A*.

First, we will show that B* A* is a subset of (AB)*.

Let x be an element of B* A*. Then, x is in (B*) and x is in (A*).

If x is in B*, then x is in B or x is not in B.

If x is in A*, then x is in A or x is not in A.

If x is in B and x is in A, then x is in AB.

If x is not in B and x is not in A, then x is not in AB.

If x is in B and x is not in A, then x is in B\A.

If x is not in B and x is in A, then x is in A\B.

Therefore, we have shown that x is in (AB)*.

Next

Given:

The function is:

[tex]f(x)=x^2-16[/tex]

To find:

The inverse of the function.

Solution:

We have,

[tex]f(x)=x^2-16[/tex]

Step 1: Substitute [tex]f(x)=y[/tex].

[tex]y=x^2-16[/tex]

Step 2: Interchange x and y.

[tex]x=y^2-16[/tex]

Step 3: Isolate y.

[tex]x+16=y^2[/tex]

[tex]\pm \sqrt{x+16}=y[/tex]

[tex]y=\pm \sqrt{x+16}[/tex]

Step 4: Substitute [tex]y=f^{-1}(x)[/tex].

[tex]f^{-1}(x)=\pm \sqrt{x+16}[/tex]

Therefore, the inverse function of the given function is [tex]f^{-1}(x)=\pm \sqrt{x+16}[/tex].

Answer:

11

Step-by-step explanation:

first u 90 minus 67 equals 23

and if u times 11 by 4 equal 44

minus 21 equals 23 which would make the equation true

hope this helped

Answer:

KISS THEY BESTFRIEND AND THEY BOTH WANNA CUDDLE

Step-by-step explanation:

Answer:

expressing how you feel even if it comes off wrong because sometimes we understand this based off of a boys actions for example say he gets an attitude because your talking to everyone except him at a party and he came there with you well you have to understand that it could come off as awkward because he standing around looking lonely because your not admiring his presence when he's there with you and 9 times out of 10 your his girl friend

Step-by-step explanation:

The two types of incorrect decisions in a hypothesis test and the symbol used to represent the probability of making that type of error are as follows:

A. A Type 1 error is rejecting a true null hypothesis, whose probability is denoted α.

A Type II error is not rejecting a false null hypothesis, whose probability is denoted β.

A Type I error occurs when the null hypothesis is rejected, even though it is actually true.

The probability of committing a Type I error is denoted by α (alpha), which is the significance level of the test.

A Type II error occurs when the null hypothesis is not rejected, even though it is actually false.

The probability of committing a Type II error is denoted by β (beta).

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Answer:

I think its C

Step-by-step explanation:

Answer:

it would be 64-81  than answer devide by 6.

The radius of a circle is half of its diameter so the radius of a circle with a diameter of 240 mm is 120.00 mm. Option D is the correct answer.

To find the radius of a circle with a given diameter, you can follow these steps:

Given that the diameter is 240 mm, divide it by 2 to obtain the radius. Recall that the radius is half the length of the diameter.

Radius = Diameter / 2

In this case, Radius = 240 mm / 2 = 120 mm.

Therefore, the radius of the circle with a diameter of 240 mm is 120.00 mm.

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The vertices of the ellipse are (12, -1) and (4, -1), and the co-vertices are (8, 1) and (8, -3).

To find the vertices and co-vertices of the given ellipse, we can use the equation of an ellipse in standard form:

((x-h)²/a²) + ((y-k)²/b²) = 1

Comparing this with the given equation ((x-8)²/(16)) + ((y+1)²/(4)) = 1, we can identify the values of h, k, a, and b.

From the equation, we can see that the center of the ellipse is at (h, k) = (8, -1). The value of a is the square root of the denominator of the x-term, which is 4, so a = 4. Similarly, the value of b is the square root of the denominator of the y-term, which is 2, so b = 2.

The vertices of the ellipse are located at a distance of a units from the center along the major axis, which is the x-axis. Therefore, the vertices are (8+a, -1) and (8-a, -1), which simplifies to (12, -1) and (4, -1).

The co-vertices of the ellipse are located at a distance of b units from the center along the minor axis, which is the y-axis. Therefore, the co-vertices are (8, -1+b) and (8, -1-b), which simplifies to (8, 1) and (8, -3).

Hence, the correct answer is: The vertices are (12, -1) and (4, -1). The co-vertices are (8, 1) and (8, -3).

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