Please help 6th grade math please please help
if you dont know the answer please do not answer this question

Answer:

x=18

Step-by-step explanation:

Answer:

x= 18

Step-by-step explanation:

To solve this equation you have to work backwards

Start by dealing with the numbers that we know:

450 + (28.75 × x) = 967.5

-450                          -450

28.75x = 967.5

(when a number and a letter in mathematics are next to each other they are multiplying)

Now divide to find the value of x:

967.5 ÷ 28.75 = 18

18 is the value of x

Answer:

C 1/9

Step-by-step explanation:

She needs to run 1/3 of a mile and is going to run/jog/walk that 1/3 mile

So she must do 1/9 of a mile running, 1/9 walking, and 1/9 jogging because 1/3 is equivalent to 3/9.

Since she is going to run/jog/walk the same amount of the 1/3 she is going to run 1/9 of the 1/3

Let me know if I'm wrong

Hope I helped :]

The equation of the red graph, g(x) is g(x) =1/3x²

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

In the graph, we can see that

This means that

g(x) = 1/3f(x)

Recall that

f(x) = x²

This means that

g(x) =1/3x²

This means that the equation of the red graph is g(x) =1/3x²

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Answer:

Value of x = 70'

Step-by-step explanation:

Given:

Given quadrilateral is a cyclic quadrilateral, in a cyclic quadrilateral sum of opposite angle is 180' .

Find:

Value of x

Computation:

x' + 110' = 180'

x' = 180' - 110'

Value of x = 70'

The matrix [T][tex]\left \{ {{B} \atop {B'}} \right.[/tex] represents the linear operator T with respect to the bases B′ and B.

The matrix representation [tex][T]\left \{ {{B} \atop {B'} \right.[/tex] of the linear operator T relative to the ordered bases B' and B, we need to determine how the basis vectors of B' are transformed under the linear operator T and express them as linear combinations of the basis vectors of B.

B′={1} and B={(0),[−1.0]} we can represent the basis vectors as column matrices

[1][tex]\left \{ {\atop {B'}} \right.[/tex] = [1]

[0][tex]\left \{ \atop {B'}} \right.[/tex] = [tex]\left[\begin{array}{ccc}0\\0\\\end{array}\right][/tex]

[-1.0][tex]\left \{ \atop B' \right.[/tex] = [tex]\left[\begin{array}{ccc}-1\\0\\\end{array}\right][/tex]

Now, we can apply the linear operator T to the basis vectors of B' and express the results in terms of the basis vectors of B.

T([1][tex]\left \{ {\atop {B'}} \right.[/tex] = [1][tex]\left \{ {\atop {B'}} \right.[/tex] = [1] = 1.[0][tex]\left \{ \atop {B'}} \right.[/tex] + 0.[-1.0][tex]\left \{ \atop B' \right.[/tex]

Therefore, we have

[T][tex]\left \{ {{B} \atop {B'}} \right.[/tex] = [tex]\left[\begin{array}{ccc}1&0\\0&0\\\end{array}\right][/tex]

The matrix [T][tex]\left \{ {{B} \atop {B'}} \right.[/tex] represents the linear operator T with respect to the bases B′ and B.

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Answer:

It might be perpendicular lines

Step-by-step explanation:

The term "TB 05-75 2/10, n/30" represents the payment terms for a transaction.

The term "TB 05-75 2/10, n/30" provides specific information regarding the payment terms for a transaction. Here's a breakdown of its components:

1. "TB": This stands for "Trade Discount" and signifies that the terms are related to a discount offered for the transaction.

2. "05-75": The numbers indicate a cash discount percentage and a payment period. In this case, "05" represents a cash discount of 5%, and "75" indicates a payment period of 75 days.

3. "2/10, n/30": These terms further elaborate on the payment conditions. "2/10" means that a 2% cash discount can be taken if the payment is made within 10 days. The "n/30" portion implies that the net payment is due within 30 days from the date of the transaction.

In summary, "TB 05-75 2/10, n/30" signifies that a trade discount is offered, a cash discount of 5% is available if payment is made within 10 days, and the net payment is due within 30 days. It provides clear guidelines for the payment terms and discounts associated with the transaction.

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Answer: b=20

Step-by-step explanation:

First for the equation 60=2b+20

We will subtract 20 from both sides to start isolating b

40=2b

Divide both sides by 2

and you get b=20

Answer:

b = 20

Hope This Helps!

Step-by-step explanation:

60 = 2b + 20

-20         -20

--------------------

40 = 2b

40/2 = 2b/2

20 = b

b = 20

To determine the components of the unit vector that points along the string, we need to break down the vector into its x and y components.

Given that the string makes an angle of 29 degrees to the vertical, we can define the unit vector as follows:

ˆr = ˆrx + ˆry

To find the x-component (ˆrx) of the unit vector, we can use the cosine of the angle:

cos(29°) = ˆrx

To find the y-component (ˆry) of the unit vector, we can use the sine of the angle:

sin(29°) = ˆry

Let's calculate the values:

ˆrx = cos(29°)

ˆry = sin(29°)

Using a calculator or mathematical software, we can find the numerical values of ˆrx and ˆry:

ˆrx ≈ 0.8829

ˆry ≈ 0.4695

Therefore, the components of the unit vector that points along the string are approximately:

ˆrx ≈ 0.8829

ˆry ≈ 0.4695

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Answer:

6

Step-by-step explanation:

8 - 2 / 2 - 1

6 / 1

6

Answer:

2.88 mi

Step-by-step explanation:

I think that i got it but at the same time not sure but the value of a+b should be 14+20

Answer:

144

Step-by-step explanation:

the area is 144 im prob wrong

Answer: The answer is g=x/16

Step-by-step explanation:

Answer:

-6

Step-by-step explanation:

g(-3) = (-3)^2 + 5(-3) [Take x value as -3]

        = 9 -15

        = -6

There is no sufficient evidence to conclude that p₁ ≠ p₂

From the question, we have the following parameters that can be used in our computation:

n₁ = 555

x₁ = 451

n₂ = 600

x₂ = 510

Calculate the pooled sample proportion using

p = sum of x/sum of n

So, we have

p = (451 + 510)/(555 + 600)

p = 0.832

Calculate the test statistic using

[tex]z = (\frac{x_1}{n_1} - \frac{x_2}{n_2}) \div (\sqrt{(p * (1 - p) / n_1) + (p * (1 - p) / n_2)}}[/tex]

So, we have

[tex]z = (\frac{451}{555} - \frac{510}{600}) \div (\sqrt{(0.832 * (1 - 0.832) / 555) + (0.832 * (1 - 0.832) / 600)}})[/tex]

When solved, we have

z = -1.699

The critical value at α = 0.05 level of significance is 1.645

The z = -1.699 is less than this value

This means that we fail to reject the null hypothesis

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Answer:

7,893,600 different combinations

Step-by-step explanation:

Answer:

We have a total.of 26 alphabets in the english language and numbers 0 to 9 will be 10.

Since there are no other limitations, we have to arrange 8 places with the 36 options we have.

It will simply be 36c8.

The answer will be 3,02,60,340.

(a) The mapping from a list of twelve students to a sequence of four groups is a k-to-1 mapping, where k is equal to 3.

Each group consists of 3 students, so when the list is divided into consecutive groups of 3, we have 4 groups in total. Therefore, each group assignment is determined by 3 students from the list, resulting in a 3-to-1 mapping.

The mapping is a 3-to-1 mapping because it assigns 3 students to each group.

(b) The mapping from a sequence of 4 groups to a group assignment is a 1-to-1 mapping.

In a group assignment, the order of the groups does not matter. As long as the students are assigned to the same groups, the assignment is considered the same. Therefore, the mapping is a 1-to-1 mapping, as there is only one possible group assignment for a given sequence of groups.
The mapping is a 1-to-1 mapping because each sequence of groups corresponds to a unique group assignment.

(c) The number of group assignments possible can be calculated by multiplying the number of ways to select 3 students from 12 for the first group, then the number of ways to select 3 students from the remaining 9 for the second group, and so on.

The number of ways to select 3 students from a group of 12 can be calculated using the combination formula "nCr," where n is the total number of students and r is the number of students to be selected. In this case, the formula becomes C(12, 3) for the first group, C(9, 3) for the second group, C(6, 3) for the third group, and C(3, 3) for the fourth group.

The total number of group assignments possible can be calculated as C(12, 3) * C(9, 3) * C(6, 3) * C(3, 3).

(d) The number of ways to break 3n students into n groups of 3 can be calculated using the multinomial coefficient formula.

The multinomial coefficient formula is used to calculate the number of ways to distribute objects into distinct groups, where the number of objects can vary in each group. In this case, we have 3n students to be distributed into n groups of 3, so the formula becomes (3n)! / (3!)^n.

The number of ways to break 3n students into n groups of 3 is (3n)! / (3!)^n.

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Answer:

I think the answer would be 65 , because :

2^4 + 7^2 = 16 + 49 = 65 .

hope it helps u ^.^

Answer:

65

Step-by-step explanation:

First you would solve the exponent and then you would add them

2 to the power of 4 = 16

7 to the power of 2 = 49

16 + 49 = 65

2 to the power of 4 + 7 to the power of 2 = 65

Answer:

x≥k   y for you y≥42 inches tall

Step-by-step explanation:

can i have brainliest if right

Answer:

22.5 miles

Step-by-step explanation:

75/60 = x/18

60x = 1350

x = 22.5

Answer:

3.375

Step-by-step explanation:

To get the volume of a cube you need to multiply length width and height since the cube is similar in length width and height you need to multiply 1.5 by itself three times.

V=l×w×h

V=1.5×1.5×1.5

V=3.375

Note:you need to multiply it to itself three times not to the number three.

Also it is only used if one number is given if three numbers are given multiply those three numbers hope this helps have a good day

Answer: 2035.8

Step-by-step explanation:

The volume of the cylinder is 2034.72 cubic ft

The volume of a cylinder is the capacity of the cylinder which calculates the amount of material quantity it can hold or we can say the volume of a cylinder is the number of unit cubes that can be fit into it. The formula for volume of cylinder is V = A × h

Assuming the given cylinder is Right Circular Cylinder

Then the formula is V = πr²h

From the question radius (r)= 6ft

                               height (h)=18ft

volume (V)= π× 6² × 18

                 =2034.72 cubic ft

Thus the volume of the cylinder is 2034.72 cubic ft

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Answer:

The answer is B. 4.4 oz.

Step-by-step explanation:

What do we know? We have the 6-pack of 12-ounce bottles and they cost $2.99, we also know that the other bottle 67.6 ounces that also costs $2.99.

Forgot the money, we're just going to be looking at the ounces.

First, we take the 6-pack and multiply by 12 because we want the size as one, rather than seperate. 6 x 12 = 72

The question is asking how many more ounces are you getting if you purchase the 6-pack. In order to do this, we take the 72 ounces that we got and subtract that 67.6 ounces of the other drink. 72 - 67.6 = 4.4

The ounces saved are 4.4 ounces.

Answer:

b, the probability that a customer buys a taco, a drink, or both is 45%

P(A or B) = 0.45 means that there is a 45% probability that a customer will buy a taco or a drink from the food truck.

In terms of this problem, P(A or B) = 0.45 represents the probability that a customer buys either a taco (event A) or a drink (event B).

When we say "P(A or B)," it refers to the probability of either event A or event B occurring. In this case, it means the probability of a customer buying a taco or a drink from the food truck.

The value of 0.45 indicates the numerical probability associated with the event A or B. It represents the likelihood that a randomly selected customer from the food truck will purchase either a taco or a drink.

Therefore, P(A or B) = 0.45 means that there is a 45% probability that a customer will buy a taco or a drink from the food truck.

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Solution :

Given : [tex]$T(x)=7-9(x-2)^2-3(x-2)^3$[/tex]

a). f(2) = T(2) = 7

    [tex]$\frac{f""(2)}{2!} =-9$[/tex]  , so f''(2) = [tex]$-18$[/tex]

b).  Yes, since f'(2) = T'(2) [tex]$=$[/tex] 0, [tex]$f$[/tex] does have the critical point at [tex]$x=2.$[/tex]

   Since f''(2) = [tex]$-18$[/tex] < 0, [tex]$f(2)$[/tex] is relative maximum value.

c).  [tex]$f(0)=T(0)=-5$[/tex]

   It is also not possible for determining if [tex]$f$[/tex] has a critical point at x = 0 because [tex]$T(x)$[/tex]   gives exact information only at [tex]$x=2.$[/tex]

d). The Lagrange [tex]$\text{error}$[/tex] bound [tex]$=\frac{6}{4!}|0-2|^4= 4$[/tex]

     [tex]$f(0) \leq T(0)+4 = -1$[/tex]

     Therefore, [tex]$f(0)$[/tex] is negative.