Part 2: Each number is worth 3 points. Partial credit may be given. 3. Mrs. Reyes wrote 8 tenths minus 2 hundredths on the board. Sammy said the answer is 6 tenths because 8 minus 2 is 6. Is he correct? Explain.

Answer:

Question?

Step-by-step explanation:

What is the question?

Answer:

454.96

Step-by-step explanation:

Suppose that the total price of worth clothes equal : x

Rachel bought them with 12% off which means , Rachel bought them :

( x ) - ( 12x / 100 )

As the question told the above equation must equal 517$ , So :

( 100x / 100 ) - ( 12x / 100 ) = 517

100x - 12x / 100 = 517

88x / 100 = 517

multiply sides by 100

88x = 51700

Divide sides by 88

x = 587.5 $

Thus the total price is 587.5 $ .

Answer:

21.21

Step-by-step explanation:

Area of a circle is A = π r^2

Variables:

r = 18/2 = 9

θ = 30 deg

Find the area:

A = π r^2

A = π 9^2

A = 254.47

Find the area of the sector:

θ/360 * A

= 30/360 * 254.47

= 21.21

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Answer: Cost of one hosta = $11

Cost of one pot of ivy = $11

Step-by-step explanation:

Let the the cost of one hosta be represented by x.

Let the cost of one pot of ivy be represented by y.

The information given in the question can be formed into an equation as:

8x + 4y = 132 ............ i

2x + 2y = 44 ............. ii

Multiply equation i by 2

Multiply equation ii by 4

16x + 8y = 264 ........ iii

8x + 8y = 176 ........ iv

Subtract iv from iii

8x = 88

x = 88/8

x = 11

One hosta cost $11

From equation ii

2x + 2y = 44

2(11) + 2y = 44

22 + 2y = 44

2y = 44 - 22

2y = 22

y = 22/2

y = 11

One pot of ivy cost $11

The set A ∩ B = {3}

The intersection of sets, denoted as A ∩ B, refers to the set that contains elements that are common to both sets A and B. In this case, set A consists of the elements {1, 2, 3, 6}, and set B consists of the elements {3, 4, 5}.

The intersection of A and B, written as A ∩ B, represents the set of elements that appear in both sets simultaneously.

To find the intersection of sets A and B, we examine each element of set A and check if it is also present in set B. In this case, the element 3 is the only element that exists in both sets.

Therefore, the intersection of sets A and B is {3}.

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Since option b correctly represents the set LA as the set of all singletons of X, and the other options are incorrect, the correct answer is option d.

Let's break down the given options:

a) LA = {∅}:

This option represents the set LA, which is the set of all singletons of X. A singleton is a set that contains only one element. Since X is the set of integers, a singleton of X would be a set containing a single integer. However, the notation LA suggests that the singletons are related to the set A, not X. Therefore, option a is not correct.

b) LA = {{a} | a ∈ X}:

This option represents the set LA, which is the set of all singletons of X. Here, the notation {{a} | a ∈ X} denotes the set of all sets that contain a single element, where that element belongs to X. In other words, LA is the set of all possible singletons of X. This option correctly represents the set LA, so option b is correct.

c) LA = {∅, {X}}:

This option represents the set LA as a set containing two elements: the empty set (∅) and the set {X}. However, this representation does not align with the definition of LA as the set of singletons of X. The set LA should only contain sets with a single element, not the empty set or the set {X}. Therefore, option c is not correct.

d) None of the above:

Since option b correctly represents the set LA as the set of all singletons of X, and the other options are incorrect, the correct answer is option d.

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Answer:

-92  - 10 + 2(145 - 7) + 174

Step-by-step explanation:

Answer:

$85.09

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 1 , 1 )

Equation Form:

x = 1 ,   y = 1

The angles of rotation for the given conditions are:

1. π radians (180 degrees)

2. π/2 radians (90 degrees)

3. 3π/2 radians (270 degrees)

To find an angle of rotation centered at the origin that sends point P to a location with the given conditions, we can use trigonometric concepts.

1. For z > 0 and y < 0:

Since z > 0, the point P lies in the positive z-axis direction. To make y negative, we rotate the point counterclockwise by an angle of π radians (180 degrees).

2. For z < 0 and y > 0:

In this case, the point P lies in the positive y-axis direction. To make z negative, we rotate the point counterclockwise by an angle of π/2 radians (90 degrees).

3. For y < 0 and z < 0:

Here, the point P lies in the negative y-axis direction. To make both y and z negative, we rotate the point counterclockwise by an angle of 3π/2 radians (270 degrees).

In summary, the angles of rotation for the given conditions are:

1. π radians (180 degrees)

2. π/2 radians (90 degrees)

3. 3π/2 radians (270 degrees)

By rotating the point P by these angles, we can achieve the desired conditions for the (z, y) coordinates.

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The inverse of the matrix (AAB)- can be found by taking the inverse of A, the inverse of B, and the inverse of AAB.

To find the inverse of the matrix (AAB)-, we can utilize the properties of matrix inverses.

Given that A and B are invertible n x n matrices, we can express the inverse of (AAB)- as the product of the inverses of A, B, and AAB in the reverse order.

In mathematical notation, the inverse of (AAB)- can be represented as (AAB)-1 = B-1A-1(AAB)-1.

To confirm that the obtained inverse is correct, we can evaluate the expression (AAB)-1(AAB)- and verify that it equals the identity matrix.

Similarly, we can multiply (AAB)- with (AAB)-1 and check if it results in the identity matrix.

By performing these calculations and observing that the resulting product is indeed the identity matrix, we can confirm the correctness of the inverse.

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It is important to remember the definitions of binomial, continuous, discrete, interval, nominal, ordinal, and ratio variables because these are different types of data which need different methods of analysis.

Nominal variables are variables used for identification or categorization. Nominal data cannot be ranked, ordered, or compared. The gender, ethnicity, religion, and hair color of an individual are all examples of nominal variables.

Ordinal variables are variables that can be ranked or ordered, but the difference between each point on the scale is not constant. For example, we could use an ordinal variable to describe the class ranks of students: 1st, 2nd, 3rd, and so on. While there is a clear order to the data, the difference between each rank is not necessarily the same.

Interval variables have equal distances between each value, and they also have a true zero point. For example, a temperature measurement is an interval variable because the difference between 20 degrees Celsius and 30 degrees Celsius is the same as the difference between 30 degrees Celsius and 40 degrees Celsius.

Ratio variables have equal intervals between each value and have a true zero point. For example, weight is a ratio variable because a weight of zero means that there is no weight.

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Answer:

DC = 1332.95 feet

Step-by-step explanation:

From the figure attached,

Let the measure of DC = h ft

And measure of side BC = a ft

By applying tangent ratio in ΔBCD,

tan(56°) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

             = [tex]\frac{DC}{BC}[/tex]

             = [tex]\frac{h}{a}[/tex]

h = a[tan(56°)] --------(1)

By applying tangent rule in ΔACD,

tan(22°) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

tan(22°) = [tex]\frac{DC}{BC+AC}[/tex]

             = [tex]\frac{h}{a+2400}[/tex]

h = (a + 2400)tan(22°) ------- (2)

Equating the values of h from equations (1) and (2),

a[tan(56°)] = (a + 2400)tan(22°)

a[tan(56°) - tan(22°)] = 2400[tan(22°)]

1.0785a = 968.6629

a = 899.085 ft

From equation (1),

h = 899.085[tan(56°)]

h = 1332.948

h ≈  1332.95 ft

Answer:

2/5, option 4.

Step-by-step explanation:

When you are dividing 2 fractions, the first fraction stays the same, and the 2nd fraction becomes the reciprocal, and the division sign becomes a multiplication sign.

The reciprocal of 2/3 is 3/2.

Now you need to change the division sign to a multiplication sign.

The equation will now become 4/15 x 3/2.

4 times 3 is 12, and 15 times 2 is 30.

12/30 isn't an option, so you will need to simplify.

Find a common factor, then divide.

6 is a common factor, so you divide both 12 and 30 by 6, to get 2 and 5.

2/5 is what you are left with.

Option 4.

4/15 divided by 2/3 is 2/5.

Answer:

hi

Step-by-step explanation:

[tex] \frac{4}{15} \div \frac{2}{3} = \frac{4}{15} \times \frac{3}{2} = \frac{2}{5} [/tex]

have a nice day

When  we rolled a fair, 6-sided die 1000 times. out of 1,000 rolls, the actual number of even rolls may vary due to the inherent randomness of the process.

If we assume that the die is fair and unbiased, each of the six sides has an equal probability of landing face-up. Since we are interested in the number of times the die comes up even (2, 4, or 6), we need to consider that half of the possible outcomes are even numbers.

Out of the six possible outcomes (1, 2, 3, 4, 5, 6), three are even (2, 4, 6). Therefore, the probability of rolling an even number on a fair six-sided die is 3/6 or 1/2.

If we roll the die 1000 times, we can expect that the die would come up even approximately half of the time, as per the probability. Half of 1000 is 500, so we would expect the die to come up even around 500 times out of 1000 rolls.

It's important to note that this is an expected value based on probability, and in practice, the actual number of even rolls may vary due to the inherent randomness of the process.

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Answer: 3 1/3 miles

Step-by-step explanation:

The solution to the system of differential equations with the given initial condition is:

x₁(t) = (-6/17) × exp(-t) + (44/17) × exp(2t)

x₂(t) = (-15/17) × exp(-t) + (108/17) × exp(2t)

The system of differential equations

x₁'(t) = -52x₁(t) + 22x₂(t)

x₂'(t) = -110x₁(t) + 47x₂(t)

Let's find the solution X(t) = [x₁(t), x(t)] with the initial condition x₀ = [-3, -3].

To solve the system, we'll start by finding the eigenvalues and eigenvectors of the coefficient matrix.

The coefficient matrix of the system is

A = [[-52, 22], [-110, 47]]

To find the eigenvalues, we solve the characteristic equation det(A - λI) = 0, where I is the identity matrix

| -52 - λ 22 |

| -110 47 - λ | = 0

Expanding the determinant, we have

(-52 - λ)(47 - λ) - (-110)(22) = 0

Simplifying, we get

(λ + 1)(λ - 2) = 0

Solving this quadratic equation, we find two eigenvalues

λ₁ = -1

λ₂ = 2

Now let's find the corresponding eigenvectors for each eigenvalue.

For λ₁ = -1, we solve the equation (A - λ₁I)v = 0

| -51 22 | | v₁ | | 0 |

| -110 48 | | v₂ | = | 0 |

Simplifying, we get the equation

-51v₁ + 22v₂ = 0

-110v₁ + 48v₂ = 0

Solving this system of equations, we find the eigenvector v₁ = [2, 5].

For λ₂ = 2, we solve the equation (A - λ₂I)v = 0

| -54 22 | | v₁ | | 0 |

| -110 45 | | v₂ | = | 0 |

Simplifying, we get the equation

-54v₁ + 22v₂ = 0

-110v₁ + 45v₂ = 0

Solving this system of equations, we find the eigenvector v₂ = [11, 27].

Therefore, the eigenvalues in ascending order are

λ₁ = -1

λ₂ = 2

The corresponding eigenvectors are

v₁ = [2, 5]

v₂ = [11, 27]

To find the solution X(t), we can write it as a linear combination of the eigenvectors:

X(t) = c₁ × v₁ × exp(λ₁ × t) + c₂ × v₂ × exp(λ₂ × t)

Substituting the given values for x₁(t) and x₂(t) into the equation, we can find the coefficients c₁ and c₂:

x₁(t) = c₁ × 2 × exp(-t) + c₂ × 11 × exp(2t)

x₂(t) = c₁ × 5 × exp(-t) + c₂ × 27 × exp(2t)

Using the initial condition x₀ = [-3, -3], we can solve for c₁ and c₂

-3 = c₁ × 2 × exp(0) + c₂ × 11 × exp(0)

-3 = c₁ × 5 × exp(0) + c₂ × 27 × exp(0)

Simplifying, we get:

-3 = 2c₁ + 11c₂

-3 = 5c₁ + 27c₂

Solving this system of equations, we find

c₁ = -3/17

c₂ = 4/17

Substituting these values back into the solution equation, we have

x₁(t) = (-3/17) × 2 × exp(-t) + (4/17) × 11 × exp(2t)

x₂(t) = (-3/17) × 5 × exp(-t) + (4/17) × 27 × exp(2t)

Therefore, the solution to the system of differential equations with the given initial condition is:

x₁(t) = (-6/17) × exp(-t) + (44/17) × exp(2t)

x₂(t) = (-15/17) × exp(-t) + (108/17) × exp(2t)

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The question is incomplete the complete question is :

Answer:

8

Step-by-step explanation:

24/3 = 8

Answer: A. Bruno accidentally used the diameter instead of the radius to find the area of the base. B. The correct volume is 602.88

Step-by-step explanation: Area of a cylinder is (r^2)(pi)(h) not (d^2)(pi)(h)

Answer:  the answer is 9.9

Step-by-step explanation:

The approximate values of the solution to the given initial value problem at the four time steps t = 0.1, 0.2, 0.3 and 0.4 using the modified Euler formula with step sizes h = 0.05 and h = 0.001 are as follows:

Approximate solution using h = 0.05y(0.1) = 1.12116266y(0.2) = 1.25755476y(0.3) = 1.41728420y(0.4) = 1.59967883

Approximate solution using h = 0.001y(0.1) = 1.00372378y(0.2) = 1.00745820y(0.3) = 1.01119282y(0.4) = 1.01492766

The non-autonomous ordinary differential equation is given as:

dy/dt = f(t,y)......(1)

where f is a continuous function and is defined for all values of t and y. The numerical methods for non-autonomous ODEs are described below:

This method is based on the same idea as Euler's method, but the derivative is evaluated at the midpoint of the interval instead of the initial point. Consider the initial value problem (IVP) dy/dt = f(t,y), y(to) = yo, and suppose that we want to approximate the solution at tn+1 = tn + h. Then, using the improved Euler's formula, we obtain the following approximation:

Yn+1 = yn + hF(tn + h/2, yn + hF(tn,yn)/2)......(2)

Using h = 0.05

Substituting h = 0.05 in equation (2), we get

Y1 = Y0 + 0.05(F(0.025,Y0+F(0,Y0)/2))

Y2 = Y1 + 0.05(F(0.075,Y1+F(0.05,Y1)/2))

Y3 = Y2 + 0.05(F(0.125,Y2+F(0.1,Y2)/2))

Y4 = Y3 + 0.05(F(0.175,Y3+F(0.15,Y3)/2))

Using h = 0.001

Substituting h = 0.001 in equation (2), we get

Y1 = Y0 + 0.001(F(0.0005,Y0+F(0,Y0)/2))

Y2 = Y1 + 0.001(F(0.0015,Y1+F(0.001,Y1)/2))

Y3 = Y2 + 0.001(F(0.0025,Y2+F(0.002,Y2)/2))

Y4 = Y3 + 0.001(F(0.0035,Y3+F(0.003,Y3)/2))

For the given IVP, f(t,y) = 2t + ety, y(0) = 1

So, substituting f(t,y) in equation (1), we get

dy/dt = 2t + ety.....(3)

Using the modified Euler formula (equation 2), we get

Using h = 0.05

Y1 = 1 + 0.05(2(0.025) + e(0.025)Y0) = 1.12116266

Y2 = 1.12116266 + 0.05(2(0.075) + e(0.075)Y1) = 1.25755476

Y3 = 1.25755476 + 0.05(2(0.125) + e(0.125)Y2) = 1.41728420

Y4 = 1.41728420 + 0.05(2(0.175) + e(0.175)Y3) = 1.59967883

Using h = 0.001

Y1 = 1 + 0.001(2(0.0005) + e(0.0005)Y0) = 1.00372378

Y2 = 1.00372378 + 0.001(2(0.0015) + e(0.0015)Y1) = 1.00745820

Y3 = 1.00745820 + 0.001(2(0.0025) + e(0.0025)Y2) = 1.01119282

Y4 = 1.01119282 + 0.001(2(0.0035) + e(0.0035)Y3) = 1.01492766

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The graph of the transformation by of horizontally compressing g(x) by a factor of 1/2 and then reflecting across the x-axis is graph Y

The function is given as:

[tex]g(x) = 2^x[/tex]

When compressed horizontally by a factor of 1/2, the transformation rule is:

g'(x) = g(2x)

So, we have:

[tex]g(2x) = 2^{2x}[/tex]

[tex]g(2x) = 4^x[/tex]

When reflected across the x-axis, the transformation rule is:

[tex](x,y) \to (x,-y)[/tex]

So, we have:

[tex]f(x) = -4^x[/tex]

The graph represented by this is graph Y.

Hence, the graph of the transformation is graph Y

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The most expensive trailer can be purchased for $39,505.41. To determine the most expensive trailer that can be purchased at an interest rate of 3.12% compounded quarterly, we calculate the future value of the savings.

The formula for compound interest is given by the equation:

A = [tex]P(1 + r/n)^(nt)[/tex]

Where:

A is the future value of the savings,

P is the quarterly deposit amount ($1,200),

r is the interest rate per compounding period (3.12%),

n is the number of compounding periods per year (quarterly, so n = 4),

and t is the number of years (15).

Plugging the values into the formula, we have:

A =[tex]1200(1 + 0.0312/4)^(4*15)[/tex]

Calculating this expression, we find the future value of the savings after 15 years to be approximately $39,505.41.

Therefore, the most expensive trailer that can be purchased is $39,505.41 or less, as that is the maximum amount that will be saved over the 15-year period.

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To convert the hexadecimal value of the EAX register (37e11449) into binary and obtain the values of AL, AH, and EAX, we can break it down as follows:

EAX: 0011 0111 1110 0001 0001 0100 0100 1001

AH:   0011 0111

AL:    0100 1001

So, the binary representation of AL, AH, and EAX is as follows:

EAX: 0011 0111 1110 0001 0001 0100 0100 1001

AH:   0011 0111

AL:    0100 1001

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Answer:

just do 115 for 2 days come to 230

Answer:

230 pounds

Step-by-step explanation:

Since it is for 2 days, 115(2)

which gives u 230

B. More students prefer black Model C3 calculators than white Model B2 calculators.

       - Ap3x verified

The minimum sample size required is 94 to obtain a margin of error of 0.04236.

To find the minimum sample size required to obtain a margin of error of 0.04236.

we need to use the formula for sample size determination for proportions:

n = (Z² × p × (1 - p)) / E²

Where:

n = required sample size

Z = Z-score corresponding to the desired level of confidence (we'll assume a 95% confidence level, so Z ≈ 1.96)

p = estimated proportion (from the available data)

E = margin of error

Given:

Total adults in the town = 88

Adults with health insurance = 69

First, we calculate the estimated proportion (p) of adults with health insurance:

p = (69 / 88)

Next, we substitute the values into the formula and solve for n:

n = (1.96² × (69/88) × (1 - 69/88)) / (0.04236²)

n = 93.966

The minimum sample size required is 94 to obtain a margin of error of 0.04236 (or 4.236%).

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