The winding number of a closed contour C about a point zo is defined as the integral of the function 1/(z - zo) over the contour C, divided by 2πi.
The winding number, denoted as n(C, zo), measures how many times the contour C wraps around the point zo in the counterclockwise direction. It is a topological property of the contour and is an integer value.
To calculate the winding number, we evaluate the integral 1/(z - zo)dz along the contour C. The contour must be positively oriented (counterclockwise) and enclose the point zo. The integral measures the net change in the argument of the complex number z - zo as we traverse the contour.
The value of the integral divided by 2πi gives us the winding number, which represents the number of times the contour wraps around the point zo in the counterclockwise direction.
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Factor completely please. 3k^2-19k+20
Answer:
3(k*k)-3(3k)-5(2k)+2(5+5)
Step-by-step explanation:
3k²-19k+20
Just find some number that equal the terms when multiplied. ¯\_(ツ)_/¯
DOUBLE CHECK!
3(k*k)-3(3k)-5(2k)+2(5+5)
Multiply what you need to.
3k²-9k-10k+20
Combine like terms.
3k²-19k+20
---
hope it helps
prove that if limnan = a and a + 0, then there exists a positve number k and a positve integer m such that Jan> k, whenever n > m.
After considering the given data we conclude that it is proven that [tex]limnan = a (and) a + 0[/tex], and there exists a positive number k and a positive integer m such that Jan> k, whenever n > m.
To prove that if [tex]limnan = a (and) a + 0[/tex], then there exists a positive number k and a positive integer m such that Jan> k, whenever n > m, we can apply the definition of a limit.
Definition of a limit: Let assume (an) be a sequence of real numbers. We interpret that the limit of (an) as n approaches infinity is a,
denoted limnan = a, if for every ε > 0, there exists a positive integer N such that [tex]\{|an - a| < \epsilon\} whenever}\{ n > N\}[/tex].
Then lets proceed with the proof
Consider that [tex]limnan = a (and) a + 0.[/tex]
Let [tex]\epsilon = a/2[/tex]. Since a + 0, we know that a > 0, so [tex]\epsilon[/tex] > 0.
Applying the definition of a limit, there exists a positive integer [tex]N_1[/tex] such that [tex]|an - a| < \epsilon (whenever) n > N_1.[/tex]
Then [tex]k = a/\epsilon = 2[/tex]. Since [tex]\epsilon = a/2, (we have) k = 2.[/tex]
Then [tex]m = max\{N1, k\}[/tex] Hence, for n > m, we have:
[tex]n > N_1, (since) m \geq N_1[/tex].
[tex]n > k,( since) m \geq k.[/tex]
Therefore, we have:
[tex]|an - a| < \epsilon , (by the description) of N_1[/tex].
[tex]\epsilon = a/2 < a/k, (since) k = 2.[/tex]
[tex]|an - a| < a/k,[/tex] by applying substitution.
[tex]an - a < a/k[/tex], since |an - a| is positive.
[tex]an < a(1 + 1/k)[/tex], by adding a to both sides.
[tex]an < a(1 + 1/2) = 3a/2.[/tex]
Hence , we have shown that there exists a positive number k = 2 and a positive integer [tex]m = max\{N1, k\}[/tex] such that Jan> k, whenever n > m.
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Find the solution to the initial value problem y' = x² — ½, y(2) = 3.
The solution to the initial value problem using the method of separation of variables is y = (x³/3) - (1/2)x + 4/3.
To solve the initial value problem y' = x² - 1/2 with the initial condition y(2) = 3, we can use the method of separation of variables. Here are the steps:
Step 1: Separate the variables
Write the given differential equation in the form:
dy/dx = x² - 1/2
Step 2: Integrate both sides
Integrate both sides of the equation with respect to x:
∫dy = ∫(x² - 1/2) dx
Integration yields:
y = (x³/3) - (1/2)x + C
Step 3: Apply the initial condition
To find the constant C, substitute the initial condition y(2) = 3 into the equation obtained in Step 2:
3 = (2³/3) - (1/2)(2) + C
Simplifying the equation:
3 = 8/3 - 1 + C
3 = 8/3 - 3/3 + C
3 = 5/3 + C
Therefore, C = 3 - 5/3 = 9/3 - 5/3 = 4/3.
Step 4: Write the final solution
Substitute the value of C back into the equation obtained in Step 2:
y = (x³/3) - (1/2)x + 4/3
So, the solution to the initial value problem y' = x² - 1/2, y(2) = 3 is y = (x³/3) - (1/2)x + 4/3.
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evaluate ∫30(4f(t)−6g(t)) dt given that ∫150f(t) dt=−7, ∫30f(t) dt=−8, ∫150g(t) dt=4, and ∫30g(t) dt=8
The evaluation of ∫30(4f(t) - 6g(t)) dt given that ∫150f(t) dt = -7, ∫30f(t) dt = -8, ∫150g(t) dt = 4, and ∫30g(t) dt = 8 is -80.
Given that ∫150f(t) dt = -7, ∫30f(t) dt = -8, ∫150g(t) dt = 4, and ∫30g(t) dt = 8.
Let us evaluate ∫30(4f(t) - 6g(t)) dt.
Therefore,∫30(4f(t) - 6g(t)) dt = ∫30(4f(t) dt - 6g(t) dt) = 4 ∫30f(t) dt - 6 ∫30g(t) dt
Now, using the given values in the question we can say that,∫30(4f(t) - 6g(t)) dt = 4 ∫30f(t) dt - 6 ∫30g(t) dt = 4 (-8) - 6(8) = -32 - 48 = -80
Therefore, the evaluation of ∫30(4f(t) - 6g(t)) dt given that ∫150f(t) dt = -7, ∫30f(t) dt = -8, ∫150g(t) dt = 4, and ∫30g(t) dt = 8 is -80.
Note: The given integrals ∫150f(t) dt, ∫30f(t) dt, ∫150g(t) dt, and ∫30g(t) dt are only intermediate steps in order to evaluate the final integral.
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Solve the system of differential equations s = Ly' - 29x + 42y – 20x + 294 = x(0) = – 15, y(0) = == - 11 The lesser of the two eigenvalues is Its corresponding eigevector is (a, – 2). What is a? a = The greater of the two eigenvalues is Its corresponding eigevector is ( – 7,6). What is b? b = = The solution to the system is x(t) = = y(t) =
The lesser of the two eigenvalues is λ = -1. Its corresponding eigenvector is [-42 29].
The greater of the two eigenvalues is λ = 1. Its corresponding eigenvector is [42 29].
To solve the system of differential equations:
x' = -29x + 42y
y' = -20x + 29y
We can rewrite it in matrix form as follows:
X' = AX
where X = [x y] is a vector, X' represents the derivative of X with respect to time, and A is the coefficient matrix. In this case, A is given by:
A = [ -29 42 ]
[ -20 29 ]
To find the eigenvalues and eigenvectors, we need to solve the characteristic equation:
det(A - λI) = 0
where λ is the eigenvalue and I is the identity matrix. Solving this equation will give us the eigenvalues, and by substituting these eigenvalues back into the equation (A - λI)V = 0, where V is the corresponding eigenvector, we can find the eigenvectors.
Let's calculate the eigenvalues first. We have:
A - λI = [ -29 42 ]
[ -20 29 ] - λ [ 1 0 ]
[ 0 1 ]
Expanding the determinant, we get:
(-29 - λ)(29 - λ) - (42)(-20) = 0
(λ + 29)(λ - 29) + 840 = 0
λ² - 29² + 840 = 0
λ² - 841 + 840 = 0
λ² = 1
λ = ±1
So the eigenvalues are λ = 1 and λ = -1.
To find the corresponding eigenvectors, we substitute each eigenvalue back into the equation (A - λI)V = 0.
For λ = 1, we have:
[ -29 42 ] [ v₁ ] [ 0 ]
[ -20 29 ] [ v₂ ] = [ 0 ]
This gives us the following system of equations:
-29v₁ + 42v₂ = 0
-20v₁ + 29v₂ = 0
Solving this system, we find that v₁ = 42 and v₂ = 29.
Therefore, the eigenvector corresponding to the eigenvalue λ = 1 is [42 29].
For λ = -1, we have:
[ -29 42 ] [ v₁ ] [ 0 ]
[ -20 29 ] [ v₂ ] = [ 0 ]
This gives us the following system of equations:
-29v₁ + 42v₂ = 0
-20v₁ + 29v₂ = 0
Solving this system, we find that v₁ = -42 and v₂ = 29.
Therefore, the eigenvector corresponding to the eigenvalue λ = -1 is [-42 29].
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Complete Question:
Solve the system of differential equations
x' = -29x + 42y
y' = -20x + 29y
x(0) = -15, y(0) = -11
The lesser of the two eigenvalues is Its corresponding eigenvector is
The greater of the two eigenvalues is Its corresponding eigenvector is
For the following exercise, write the equation of the ellipse in standard form. Then identify the center, vertices, and foci. 9x² + 36y²-36x + 72y +36 = 0
The given equation, 9x² + 36y² - 36x + 72y + 36 = 0, represents an ellipse. In standard form, the equation can be written as (x-1)²/4 + (y+1)²/1 = 1. The center of the ellipse is at (1, -1), the vertices are located at (3, -1) and (-1, -1), and the foci are at (2, -1) and (0, -1).
To write the equation 9x² + 36y² - 36x + 72y + 36 = 0 in standard form, we need to complete the square for both the x and y terms. By rearranging the equation, we have 9x² - 36x + 36 + 36y² + 72y + 36 = 0.
Next, we can factor out a 9 from the x terms and a 36 from the y terms: 9(x² - 4x + 4) + 36(y² + 2y + 1) = 0.
Simplifying further, we have 9(x - 2)² + 36(y + 1)² = 36.
Dividing both sides by 36, we get (x - 2)²/4 + (y + 1)²/1 = 1, which is the standard form of an ellipse.
From the standard form, we can determine that the center of the ellipse is located at (1, -1), the vertices are at (3, -1) and (-1, -1), and the foci are at (2, -1) and (0, -1).
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The total weight of all the students in a class is 3,159 lb. The mean weight of the students is 117 lb. How many students are there in the class?
Answer:
27
Step-by-step explanation:
You do 3159 ÷ 27
Comes out to 27
I found 27 by just plugging in numbers.
Hope this helps
Answer:
There are 27 students in the class.
Step-by-step explanation:
Since the total weight is 3,159 and the average weight is 117lb, you can just divide 3,159 by 117, which will give you 27.
There are 35 green, 22 white, 30 purple and 14 blue gumballs in the gumball machine.
Sharee wants to get a white or green gumball.
What is the probability of getting a white or green gumball?
Answer:
The probability of getting a white or green gumball is 35.64%.
Step-by-step explanation:
1. calculate the total number of gumballs in the gumball machine
35 + 22 + 30 + 14 = 101 gumballs
2. calculate the number of white and green gumballs combined
22 + 14 = 36 w/g gumballs
3. divide the number of white and green gumballs combined by the total number of gumballs in the gumball machine
36 / 101 = 0.3564
Answer: the probability of getting a white or green gumball is 35.64% (0.3564).
Probability is the chance of occurring an event from the total possible outcomes.
The probability of getting a white or a green gumball is 57/101.
What is probability?It is the chance of occurring an event from the total possible outcomes.
We have,
Green gumballs = 35
White gumballs = 22
Purple gumballs = 30
Blue gumballs = 14
Total gumballs = 35 + 22 + 30 + 14 = 101
The combination is given by:
= [tex]^nC_{r}[/tex]
= n! / r! (n-r)!
The probability of choosing a white gumball:
= [tex]\frac{^{22}C_{1}}{^{101}C_{1} }[/tex]
= 22 / 101
The probability of choosing a green gumball:
= [tex]\frac{^{35}C_{1}}{^{101}C_{1} }[/tex]
= 35 / 101
The probability of getting a white or a green gumball:
= 22/101 + 35 / 101
= (22 +35) / 101
= 57 / 101
Thus the probability of getting a white or a green gumball is 57/101.
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The dot plots below display the pre- and post-test math scores for students in of Mr. Perez's
math classes.
The mean for the Pre-Test scores is 4.
The mean for the Post-Test scores is 10.
The mean absolute deviation of both tests is 2.
Describe the difference between the means as a multiple of the MAD.
Answer:
so one the MAD is wrong its actually 1 for both and
The multiple would be 4 and 10.
Step-by-step explanation:
4x1=4
10x1=10
find the indicated iq score. the graph depicts iq scores of adults and those scores are normally distributed with a mean of 100 and a standard deviatio of 15 the shaded are under the curve is 0.5675
The indicated IQ score, corresponding to the shaded area under the curve of 0.5675 in a normal distribution with a mean of 100 and a standard deviation of 15, is approximately 102.55.
To find the indicated IQ score, we need to determine the corresponding z-score using the given information about the normal distribution. Here's how we can calculate it step by step:
Step 1: Identify the shaded area under the curve.
The shaded area under the curve represents the cumulative probability of the IQ scores. In this case, the shaded area is 0.5675 or 56.75%.
Step 2: Convert the cumulative probability to a z-score.
To find the z-score corresponding to the shaded area, we need to find the z-score that gives us a cumulative probability of 56.75%. We can use a standard normal distribution table or a statistical calculator to find the z-score.
Step 3: Find the z-score.
Using a standard normal distribution table, we can search for the closest cumulative probability to 0.5675. The closest cumulative probability we can find in the table is 0.5681, which corresponds to a z-score of approximately 0.17.
Step 4: Convert the z-score to an IQ score.
Now that we have the z-score of 0.17, we can use the formula for transforming z-scores to raw scores:
IQ score = (z-score × standard deviation) + mean
Given that the mean is 100 and the standard deviation is 15, we can calculate the IQ score:
IQ score = (0.17 × 15) + 100
IQ score = 2.55 + 100
IQ score ≈ 102.55
Therefore, the indicated IQ score is approximately 102.55.
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: A random sample of 850 Democrats included 731 that consider protecting the environment to be a top priority. A random sample of 950 Republicans included 466 that consider protecting the environment to be a top priority. Construct a 95% confidence interval estimate of the overall difference in the percentages of Democrats and Republicans that prioritize protecting the environment. (Give your answers as percentages, rounded to the nearest tenth of a percent.)
The 95% confidence interval estimate of the overall difference in the percentages of Democrats and Republicans that prioritize protecting the environment is approximately 37.0% ± 5.0%.
Calculate the proportions for Democrats and Republicans:
Proportion of Democrats prioritizing environment = 731/850 ≈ 0.860
Proportion of Republicans prioritizing environment = 466/950 ≈ 0.490
Next, calculate the standard error (SE) of the difference between the proportions:
SE = √[(p1(1 - p1))/n1 + (p2(1 - p2))/n2]
= √[(0.860(1 - 0.860))/850 + (0.490(1 - 0.490))/950]
≈ √(0.000407 + 0.000245)
≈ √0.000652
≈ 0.0255
Now, calculate the margin of error (ME) using the critical value for a 95% confidence level (z-value):
ME = z × SE
≈ 1.96 × 0.0255
≈ 0.04998
Finally, construct the confidence interval:
Difference in proportions ± Margin of error
(0.860 - 0.490) ± 0.04998
0.370 ± 0.04998
The 95% confidence interval is approximately 37.0% ± 5.0%.
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A triangle has three angles that measure 50 degrees, 28 degrees and 3x. What is the value of x?
Answer:
57.33
Step-by-step explanation:
50+28+3x=180
78+3x=180-78
3x=172/3
x = 57.33
Solve the system with the addition method: - 8x + 5y = -33 +8.x – 4y = 28 Answer: (x, y) Preview 2 Preview y Enter your answers as integers or as reduced fraction(s) in the form A/B.
The solution to the system -8x + 5y = -33 and 8x - 4y = 28 is (x, y) = (7, -1).
To solve the given system of equations using the addition method, let's eliminate one variable by adding the two equations together. The system of equations is:
-8x + 5y = -33 (Equation 1)
8x - 4y = 28 (Equation 2)
When we add Equation 1 and Equation 2, the x terms cancel out:
(-8x + 5y) + (8x - 4y) = -33 + 28
y = -5
Now that we have the value of y, we can substitute it back into either Equation 1 or Equation 2 to solve for x. Let's use Equation 1:
-8x + 5(-5) = -33
-8x - 25 = -33
-8x = -33 + 25
-8x = -8
x = 1
Therefore, the solution to the system is (x, y) = (1, -5).
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What is the solution to the following system of equations?
x+y=5
x-y=1
(–2, 7)
(2, 3)
(3, 2)
(7, –2)
Answer:
x+y=5
×-y=1
2x/2=6/2
x=3
while x+y=5
3+y=5
y=5-3
y=2
Answer:
C
Step-by-step explanation:
(3, 2)
(A) A function is a rule that assigns (options) exactly one or one or more
output(s) to Two or more or each
input(s).
(B) The graph of a function is a set of ?
consisting of one input and the corresponding output.
(C) You can determine if a graph represents a function by using the ?
Answer:
A) A function is a rule that assigns one input into one output.
The general function is f(x) = y
Where we have one input, x, and one output, y.
But this is a really simple type of function, for example, you could define a function that calculates the volume of a box of length L, width W, and height H as:
V = f(L, W, H) = L*W*H
Then we have "3 inputs" and one output, right?
Well, not exactly, here the set (L, W, H) is called the input, so here we have a single input consisting of 3 variables.
Also we can have functions with a single input into vector-like outputs
For example:
(y, z) = f(x)
So for the input x, we got two values in the output y and z, but this is a single output defined as (y, z), then we always have a single output.
B) The graph of a function is a set of points consisting of one input and the corresponding output.
C) You can determine if a graph represents a function by using the vertical line proof.
A rule that assigns inputs into outputs is only a function if each input is assigned into only one output.
Then if we draw a vertical line that intersects our graph, it should intersect it only one time for functions.
If the line intersects the line two times this means that a single input has more than one output, then this is not a function.
Answer:
A: exactly one, each
B: ordered pairs
C: vertical line test
Step-by-step explanation:
Which graphed function is described by the given intervals? Increasing on (−∞, 0) Decreasing on (0, ∞)
A) A
B) B
C) C
D) D
Please answer correctly! I will mark you as Brainliest!
Answer:
402 in^3
Step-by-step explanation:
We know that the volume of a sphere = 4 /3 πr^3
Variables:
r = 2in
Solve for 1 toy:
4 /3 πr^3
4/3 π (2in)^3
= 33.51 cubic inches for 1 toy
For 12 toys:
33.51 in^3 * 12 toys = 402.12 in^3 of water for all the toys
Round:
402.12 in^3 ≈ 402 in^3 of water
Please mark brainliest if this helped!
Please mark brainliest if this helped!
identify the slope and y-intercept of the lins given by the equation y=2x 1.
y=Ax^2 + C/x is the general solution of the DEQ: y' + y/x = 39x. Determine A. Is the DEQ separable, exact, 1st-order linear, Bernouli?
The exact value of A in the general solution is 13
Also, the DEQ is separable
How to determine the value of A in the general solutionFrom the question, we have the following parameters that can be used in our computation:
y = Ax² + C/x
The differential equation is given as
y' + y/x = 39x
When y = Ax² + C/x is differentiated, we have
y' = 2Ax - Cx⁻²
So, we have
2Ax - Cx⁻² + y/x = 39x
Recall that
y = Ax² + C/x
So, we have
2Ax - Cx⁻² + (Ax² + C/x)/x = 39x
Evaluate
2Ax - Cx⁻² + Ax + Cx⁻² = 39x
This gives
2Ax + Ax = 39x
So, we have
3Ax = 39x
By comparing both sides of the equation, we have
3A = 39
Divide both sides by 3
A = 13
Hence, the value of A in the general solution is 13
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Evan says that plants get most of the materials they need to
grow from air and water. Use evidence/data to support and
explain his argument.
The evidence and data support Evan's argument that plants predominantly acquire the materials they need to grow from air and water .
Evan's statement is supported by evidence and data that demonstrate how plants obtain the majority of the materials they need to grow from air and water. Here are some key points to support his argument:
Carbon Dioxide (CO2) from the air: Through the process of photosynthesis, plants take in carbon dioxide from the air. They use the carbon dioxide along with water and sunlight to produce glucose and oxygen. This glucose serves as an essential energy source for plant growth and development.
Water: Plants absorb water from the soil through their root systems. Water plays a critical role in various plant processes, including nutrient uptake, transportation, and the maintenance of cell turgidity. It is a primary component of plant cells and is necessary for photosynthesis to occur.
Essential nutrients from the soil: While air and water provide the primary materials for plant growth, plants also require certain nutrients to thrive. These essential nutrients, such as nitrogen, phosphorus, and potassium, are typically obtained from the soil. However, it's important to note that these nutrients are often dissolved in water and taken up by plant roots.
Experimentation and research: Numerous scientific experiments and studies have been conducted to investigate plant nutrient uptake. These experiments have confirmed that plants can grow and develop using only air, water, and the necessary nutrients found in these sources.
The evidence and data support Evan's argument that plants predominantly acquire the materials they need to grow from air and water. While nutrients from the soil are essential, the primary sources of plant growth materials are carbon dioxide from the air and water, which are crucial for photosynthesis and various physiological processes in plants.
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A triangular pane of glass has a height of 30 inches and an area of 240 square inches. What is the length of the base of the pane?
240÷30=8
8×30=240
30 height 8 with
This hanger is in balance. There are two labeled weights of 4 grams and 12 grams. The three circles each have the same weight. What is the weight of each circle, in grams?
Answer:
8/3 gram
Step-by-step explanation:
Since the hanger is said to be in balance, then the weight on the right balances the weight on the left ;
Right hand side = Left hand side
12 = 4 + x + x + x
12 = 4 + 3x
12 - 4 = 3x
8 = 3x
8/3 = 3x / 3
x = 8/3 gram
solve the differential equation by variation of parameters. y'' y = csc(x)
The solution to the differential equation y'' + y = csc(x) using the variation of parameters method is y(x) = cos(x)ln|sin(x)| + Csin(x), where C is a constant.
To solve the differential equation by variation of parameters, we first find the complementary solution (the solution to the homogeneous equation). The homogeneous equation is y'' + y = 0, which has the solution y_c(x) = Acos(x) + Bsin(x), where A and B are constants.
Next, we find the particular solution using the variation of parameters method. We assume the particular solution is of the form y_p(x) = u(x)cos(x) + v(x)sin(x), where u(x) and v(x) are unknown functions.
We differentiate y_p(x) to find y_p' and y_p'' and substitute them into the original differential equation. After simplification, we obtain u'(x)sin(x) - v'(x)cos(x) = csc(x).
To solve this system of equations, we find the derivatives u'(x) and v'(x) and integrate them to obtain u(x) and v(x). Finally, we substitute u(x) and v(x) into the particular solution form y_p(x) = u(x)cos(x) + v(x)sin(x).
The final solution is y(x) = y_c(x) + y_p(x), which simplifies to y(x) = cos(x)ln|sin(x)| + Csin(x), where C is the constant of integration.
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Newton has just gone grocery shopping. The mean cost for each item in his bag was $3.38. He bought a total of 6 items, and the prices of 5 of those items are listed below:
$4.09, $4.03, S4.19, $2.24, $4.09
Determine the price of the 6th item in his bag.
Newton has just gone grocery shopping. The mean cost for each item in his bag was $3.38. The price of the 6th item in his bag is $1.64
To determine the price of the 6th item in Newton's bag, we can use the concept of the mean (average). We know that the mean cost for each item in his bag is $3.38, and he bought a total of 6 items.
To find the sum of all 6 item prices, we can multiply the mean cost by the total number of items:
Sum of all item prices = Mean cost * Total number of items
= $3.38 * 6
= $20.28
We also know the prices of 5 of the items, which are $4.09, $4.03, $4.19, $2.24, and $4.09.
To determine the price of the 6th item, we subtract the sum of the known prices from the sum of all item prices:
Price of the 6th item = Sum of all item prices - Sum of known prices
= $20.28 - ($4.09 + $4.03 + $4.19 + $2.24 + $4.09)
= $20.28 - $18.64
= $1.64
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For each of the following rejection regions, what is the probability that a Type I error will be made?
a. t> 2.718, where df = 11
b. t< -1.476, where df = 5
c. t< -2.060 or t > 2.060, where df = 25
a. The probability that a Type I error will be made is _____ (Round to two decimal places as needed.)
The probability of a Type I error in rejection region a is 0.01.
What is probability?We must find the area under the t-distribution curve outside the rejection region, assuming a two-tailed test in order to to determine the probability of making a Type I error in each rejection region.
for a. t > 2.718, and df = 11:
Using a t-distribution table, the probability is 0.01.
b. t < -1.476, df = 5:
Using a t-distribution table the probability is 0.05.
c. t < -2.060 or t > 2.060, df = 25:
Using a t-distribution table, the area in each tail is 0.025.
The combined probability of a Type I error in rejection region c is
0.025 + 0.025 = 0.05.
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Which angles are neither obtuse angles nor acute angles?
Answer:
Acute angles are less than 90
obtuse is more than 90
right angles are exactly 90
Step-by-step explanation:
Answer:
First option: 90 degrees
Step-by-step explanation:
Obtuse is greater than 90.
Acute is less than 90.
Right is 90.
Identify the coefficient in the following expression 6a +7
Answer:
The coefficient is 6
Step-by-step explanation:
Write a cosine function that has a midline of y=5, an amplitude of 3, a period of 1, and a horizontal shift of 1/4 to the right
The graph of this function begins at 5 and moves down to 2 and back to 5 again in a repeated pattern over one period of 1.
A cosine function is a periodic function that fluctuates about its midline and follows a predictable pattern. The formula for a cosine function with a midline of y = c, amplitude of a, and period of b is:y = a cos(bx) + cTo shift the graph of a cosine function,
you can add or subtract a value inside the parentheses of the formula, which results in a horizontal shift.
The shift is to the right if you add, and to the left if you subtract.In this instance,
the cosine function has the following characteristics:Midline = y = 5Amplitude = 3Period = 1Horizontal shift to the right = 1/4We'll have to adjust the formula to include all of these parameters.
First and foremost, let's figure out the function's frequency, which is determined by dividing 2π by the period of the cosine function. In this example, the frequency is 2π/1, which equals 2π.
y = a cos(bx) + c is the formula we'll use. We'll substitute the values given into the formula. The resulting formula is:y = 3cos(2π(x - 1/4)) + 5This is the cosine function with a midline of y = 5, an amplitude of 3, a period of 1, and a horizontal shift of 1/4 to the right.
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A triangle has a 35° angle, a 55° angle, and a side 6 centimeters in length,
Select True or False for each statement about this type of triangle.
True
False
The triangle might be an isosceles triangle.
The triangle might be an acute triangle.
The triangle must contain an angle measuring 90°.
O
Answer:
f
f
v
Step-by-step explanation:
LA Galaxy have won 35% of there soccer matches, and drawn 9 of them. If they played 40 matches, how many have they lost?
Answer:17
Step-by-step explanation:
0.35•40=14 to find how many they’ve won
14+9=23 is how many they have won or drawn
40-23=17 is how many they’ve lost