If 4700 bricks each of size 25 cm x 16 cm x 10 cm are required to construct a wall
20 m long and 20 cm wide containing two windows of size 2 m X 1.5 m each, find
the height of the wall.
​

Answer:

2g   -      1

g²-g-6     g-3

2g        -  1

(g-3)(g+2)  g-3

take lcm

2g- 1(g+2)

(g-3)(g+2)

g-2

g²-g-6

Step-by-step explanation:

Step-by-step explanation:

answer is g-2/ g^2-g-6

mark this as brainliest!

Answer:

c

Step-by-step explanation:

Answer:

297/40 or 7.425

Step-by-step explanation:

Hope this helped

To find the volume you got to multiply W by H and L

Answer:

-t

Step-by-step explanation:

Additive inverse of t:

t*-1 = -t

Answer:

m=-4

(the slope is negetive 4)

Step-by-step explanation:

Answer:

[tex]-4[/tex]

Step-by-step explanation:

Start with point-slope form:

[tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Identify your values.

[tex]x_1=7\\x_2=8\\y_1=-3\\y_2=-7[/tex]

Substitute.

[tex]\frac{-7-(-3)}{8-7}[/tex]

The [tex]-3[/tex] becomes positive as it is being multiplied by a negative.

[tex]\frac{-7+3}{8-7}[/tex]

Combine like terms.

[tex]\frac{-4}{1}[/tex]

Rewrite.

[tex]-4[/tex]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

Interval                Slope  of secant lines

 [1,2]                            113.000

 [1, 1.5]                          75.000

 [1, 1.1 ]                           51.960

  [1, 1.01]                       47.482

 [1, 1.001]                       47.048

Step-by-step explanation:

From the question we are told that

   The  function is  [tex]f(x) =  16x^3 -x[/tex]

Now considering the intervals

  For  [1, 2]

The  slopes of secant lines is mathematically represented as

     [tex]\frac{ f(2) - f(1)}{2-1}  =  \frac{16(2)^3 - 2 - [16(1)^3 -1] }{2-1 }  =  113.000[/tex]

  For  [1, 1.5]

The  slopes of secant lines is mathematically represented as

     [tex]\frac{ f(1.5) - f(1)}{1.5-1}  =  \frac{16(1.5)^3 - 1.5 - [16(1)^3 -1] }{1.5-1 }  = 75.000[/tex]

  For  [1, 1.1]

The  slopes of secant lines is mathematically represented as

     [tex]\frac{ f(1.1) - f(1)}{1.1-1}  =  \frac{16(1.1)^3 - 1.1 - [16(1)^3 -1] }{1.1-1 }  = 51.960[/tex]

   For  [1, 1.01]

The  slopes of secant lines is mathematically represented as

     [tex]\frac{ f(1.01) - f(1)}{1.01-1}  =  \frac{16(1.01)^3 - 1.01 - [16(1)^3 -1] }{1.01-1 }  =47.482[/tex]

   For  [1, 1.001]

The  slopes of secant lines is mathematically represented as

     [tex]\frac{ f(1.001) - f(1)}{1.001-1}  =  \frac{16(1.01)^3 - 1.001 - [16(1)^3 -1] }{1.001-1 }  =47.048[/tex]

Answer:

85 + 86 = 171

Step-by-step explanation:

Just divide 171 by 2 = 85.5, so it pretty clear the rest is just logic.

(85.5 - 0.5) + (85.5 + 0.5) = 171

Answer:

is that i-ready

Step-by-step explanation:

Answer:

  14

Step-by-step explanation:

The objective function C=x+3y is the same as one of the constraining boundaries, x+3y≥14. Hence the minimum value of C is constrained to be 14.

91 million miles (146 million km)

Answer:

A=t+258

Step-by-step explanation:

Answer:

Step-by-step explanation:

x - 12 = 13

x = 25

y = 12

Answer:

x=25

Step-by-step explanation:

y=x-12....eq1

y=13.... eq2

Substituting eq2 in 1:-

13=x-12

x=12+13=25

Answer:

4th one

Step-by-step explanation:

The graph that represents the situation is required.

The correct option is option 2.

Here the [tex]x[/tex] axis denotes the number of hours and

[tex]y[/tex] axis denotes the pounds of ice.

The given ordered pair is

[tex](\dfrac{1}{2},1\dfrac{1}{2})=(0.5,1.5)[/tex]

At zero hours the ice produced will be zero so, the third and fourth options are incorrect.

The only graph where the line passes through [tex](0.5,1.5)[/tex] is option 2.

Learn more:

https://brainly.com/question/19837922?referrer=searchResults

Answer:

The answer is sixty million.

Answer:

0.16

Step-by-step explanation:

Answer:

-16

Step-by-step explanation:

3^2-7(3)-4

Answer: D. The data are discrete because the data can only take on specific values.

Step-by-step explanation:

Discrete data refers to data that has a specific value in a specific period and so can be counted as opposed to continuous data that cannot be counted as it goes on to infinity. An example of continuous data would be the height of students in a class. This is continuous because a person's height could be 1.02325845...... metres.

The number of car accidents on a particular stretch of highway can be counted and the data can only take on a specific value thereby making it discrete data.

In this exercise we have to use the knowledge of distance to understand which the best alternative corresponds to car accidents, in this way we find that:

Letter D. The data are discrete because the data can only take on specific values.

Discrete information in visible form refers to data that bear a distinguishing value fashionable a distinguishing period accordingly can be check in order as opposite to continuous information in visible form that cannot be deem as it continue to infinity.

An instance of constant data hopeful the height of person actively learning fashionable a class. This is constant cause a person's crest could be 1.02325845 metres.

The number of vehicle driven on streets accidents in contact a particular stretch of heavily traveled maybe have importance and the data can only oppose a particular financial worth by that making it discrete information in visible form.

See more about distance at brainly.com/question/989117

Answer:

89

Step-by-step explanation:

Given that

2 O, 2 T and 1 M

Now based on this, the following ways are there  

1

Three ways i.e. {M,T,O}

2

XX or XY

XX in 2C1 = two ways i.e. {OO or TT}

XY in 3C2 × 2! = six ways

3

XXY or XYZ

XXY in 2C1 × 2C1 × 3! ÷ 2! = twelve ways

XYZ in 3C3 × 3! = six ways

4

XXYY or XXYZ

XXYY = 4! ÷ (2! × 2!) = six ways

XXYZ in 2C1 ×  4! ÷ 2! = twenty four ways

5

= 5! ÷ (2! ×2!)

= 120 ÷ 4

= 30

Therefore, the total is

= 3 + (2 +6)+ (12 +6) + (6 +24) + 30

= 89

There are 30 different letter permutations.

The word is given as:
MOTTO

From the given word, we have the following parameters:

The number of different (d) letter permutation is then calculated as:

[tex]d = \frac{n!}{T!O!}[/tex]

This gives

[tex]d = \frac{5!}{2!2!}[/tex]

Evaluate each factorial

[tex]d = \frac{120}{2 \times 2}[/tex]

Evaluate the product of 2 and 2

[tex]d = \frac{120}{4}[/tex]

Divide 120 by 4

[tex]d = 30[/tex]

Hence, there are 30 different letter permutations.

Read more about permutations at:

https://brainly.com/question/11732255

Answer:

18 yards

Step-by-step explanation:

[tex]\sqrt{324}[/tex] = 18

Answer:

the dimensions are 81

Step-by-step explanation:

Answer:

(a) The exact value that is 33% of 2302 is 759.66.

(b) No, the result from part (a) could not be the actual number of adults who said that they play basketball.

(c) The actual number of adults who said that they play basketball is 760.

(d) 11.82% of respondents said that they only play hockey.

Step-by-step explanation:

We are given that a polling company reported that 33​% of 2302 surveyed adults said that they play basketball.

(a) The exact value that is 33% of 2302 is given by;

[tex]33\% \text{ of } 2302[/tex] = [tex]\frac{33}{100}\times 2302[/tex]

                   = 759.66

(b) No, the result from part (a) could not be the actual number of adults who said that they play basketball because the value in part (a) is in fractions or in decimals and the number of people can't be in fractions. It must be a whole number.

(c) The actual number of adults who said that they play basketball is 760. {As 759.66 rounded to one decimal point}

(d) It is given that among the 2302 respondents, 272 said that they only play hockey.

Percentage of respondents who said that they only play hockey is given by;

=  [tex]\frac{272}{2302}\times 100[/tex]  = 11.82% ≈ 12%

a) The exact value of [tex]33[/tex]% of [tex]2302[/tex] is,

[tex]=\frac{33}{100}\times 2302[/tex]

[tex]=759.66[/tex]

b) [tex]759.66[/tex] is not the actual number of adults who said that they play football as the actual number should be a whole number and not a rational number with decimal values.

c) The actual number could be a rounded one i.e. [tex]760[/tex].

d) Let [tex]272[/tex] be [tex]x[/tex]% of [tex]2302[/tex].

[tex]\Rightarrow \frac{x}{100}\times 2302=272\\\Rightarrow x=\frac{272\times 100}{2302} \\\Rightarrow x=11.8158 \ or \ 11.82[/tex]%

Therefore, [tex]11.82[/tex]% of respondents said that they only play hockey.

Learn more: brainly.com/question/1648911

Answer:

1891

Step-by-step explanation:

night 1: 4000 seats- 2950 seats= 1050 empty.

night 2: 4000 seats- 3159 seats= 841 empty.

1050+841= 1891 empty seats for the two nights.

Hope this helps! ;)

Answer:

total seats for two night= 4000*2=8000

seat occupied= 3159+2950= 6109

Total empty seat= 8000-6109=1891

Step-by-step explanation:

Answer: g -4/a

Step-by-step explanation:

Answer:

The overall group of sciences that study numbers, shapes and their relationships. An example of math is arithmetic, the study of addition, subtraction, multiplication and division.

Answer:

3

Step-by-step explanation:

30 hundreds = 30*100 which = 3000 and 3000/1000 = 3

Answer:

3

Step-by-step explanation:

30x100=3000 is the answer to solving your problem

Answer:

Step-by-step explanation:

A complex number is a number that has both real and imaginary part. An example of a complex number is z = x+iy where x is the real part and y is the imaginary part.

If z = x+iy, the conjugate of z₁ will be x-iy

adding the complex number to its conjugate will give;

P = z+z₁

P = x+iy +(x-iy)

open the parenthesis

P = x+iy+x-iy

collect like terms

P = x+x+iy-iy

P = 2x

We can see that the resulting value does not contain the imaginary number i, hence the result is a real number.

Hence the result of adding a complex number to its conjugate is a REAL NUMBER

Taking the difference;

P =  = z-z₁

P = x+iy -(x-iy)

open the parenthesis

P = x+iy-x+iy

collect like terms

P = x-x+iy+iy

P = 0+2iy

P = 2iy

We can see that the resulting value contains the imaginary number i, hence the of taking their difference is a complex number.

Hence the result of subtracting a complex number from its conjugate is an IMAGINARY NUMBER