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We have proved that the Newton-Raphson iteration formula for solving the equation[tex]x^k e^x = 0[/tex] is given by [tex]x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.[/tex]

To prove that the Newton-Raphson method for solving the equation [tex]x^k e^x = 0[/tex], where k is a constant, is given by the formula

[tex]x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n,[/tex]

we can start by considering the iterative process of the Newton-Raphson method.

Given an initial guess [tex]x_n[/tex], we want to find a better approximation [tex]x_{n+1}[/tex]that is closer to the root of the equation [tex]x^k e^x = 0.[/tex]

The Newton-Raphson method involves the following steps:

Calculate the function value [tex]f(x_n) = x_n^k e^x_n[/tex] and its derivative [tex]f'(x_n) = k x_n^(k-1) e^x_n.[/tex]

Find the next approximation x_{n+1} by using the formula:

[tex]x_{n+1} = x_n - f(x_n) / f'(x_n)[/tex]

Let's apply these steps to our equation [tex]x^k e^x = 0[/tex]:

Calculate the function value and its derivative:

[tex]f(x_n) = x_n^k e^x_n\\f'(x_n) = k x_n^(k-1) e^x_n[/tex]

Find the next approximation x_{n+1} using the formula:

[tex]x_{n+1} = x_n - f(x_n) / f'(x_n)[/tex]

Substituting the function value and its derivative:

[tex]x_{n+1} = x_n - (x_n^k e^x_n) / (k x_n^(k-1) e^x_n)\\= x_n - (x_n^k / k)[/tex]

Simplifying the expression by combining like terms:

[tex]x_{n+1} = x_n - (x_n^k / k)\\= x_n - x_n^k / k\\= (k - 1) x_n + x_n^2 / k + x_n[/tex]

Therefore, we have proved that the Newton-Raphson iteration formula for solving the equation[tex]x^k e^x = 0[/tex] is given by [tex]x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.[/tex]

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Answer:

it will be 300 feet tall and 1000 feet wide

Step-by-step explanation:

The height and width of the arch which support of a bridge and modeled by the provided function is 1000 ft and 300 ft long respectively.

Exponential function is the function in which the function growth or decay with the power of the independent variable. The curve of the exponential function depends on the value of its variable.

The exponential function with dependent variable y and independent variable x can be written as,

[tex]y=ba^x+c[/tex]

Here, a,b and c are the real numbers.

The arch support of a bridge can be modeled by the following function,

[tex]y=-0.0012x^2+300[/tex]

Here, x and y are measured in feet.

The height and width of the arch has to be found out. First, find the x intercept of the function. As at the x intercept, the y equal to zero. Therefore,

[tex]0=-0.0012x^2+300\\0.0012x^2=300\\x=\sqrt{25000}\\x=500[/tex]

As, the graph is symmetric around the y-axis. Thus, the -500 can also be a solution. Now, the width of the arch can be given as,

[tex]w=500-(-500)\\w=1000\rm ft[/tex]

Now similarly at x equal to zero, the function will be,

[tex]y=300[/tex]

Hence, the height and width of the arch which support of a bridge and modeled by the provided function is 1000 ft and 300 ft long respectively.

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Answer:

3a-b/(x-b)=1/(x+1)Doing criss cross multiplication

3a(x+1)-b(x+1)=x-b

3ax+3a-bx-b=x-b

3ax-bx-x=b-3a-b

x(3a-b-1)=-3a

x=3a/(3a-b-1)

Answer:

it's 423.4 miles

Step-by-step explanation:

sotry for taking a while I didn't get your notification

Answer:

2

Step-by-step explanation:

Rearrange the data set in numerical order: 1, 2, 2, 3, 5 and take the number in the middle.

Answer:

12 dimes and 2 quarters

Step-by-step explanation:

12 dimes is 120 cents and 2 quarters is 50 cents that perfectly gives us 170 cents. As worded if he has 11 Dimes and the rest is quarters and we want 170 cents then it's impossible. 11 dimes is going to be 110 cents plus 2 quarters is 160 cents or plus 3 quarters is going to be 185 cents. therefore you are either short or over the money.

Answer:

9 inches ; 0.7 units ; m units

Step-by-step explanation:

The area of a square is give as :

The square of the side length of the square ; that is ;

Area of square = s² ;

Where s =! Side length of the square

Hence ;

A square with area = 81 in²

Length of its side = sqrt(81) = 9 inches

Area of square = 0.49 unit²

Length of its side = sqrt(0.49) = 0.7 units

Area of square = m² unit²

Length of its side = sqrt(m²) = m units

Answer:

The Answer is C

Step-by-step explanation:

2.00/5= C

can i have brainlist please :)

Answer:

D

Step-by-step explanation:

They are trying to see how long it takes people to complete the writing portion of the test.

Answer:

80 miles for the .9 one.

Step-by-step explanation:

Answer:

A is the correct answer .

Step-by-step explanation:

Hope this helps .

The equation that allows you to solve the given equation is (x-3)(2x+5).

Any equation of the form [tex]ax^{2} +bx+c=0[/tex] is called a quadratic equation where a is non-zero.

The given quadratic equation is:

[tex]2x^{2} -15=x[/tex]

[tex]2x^{2} -x-15=0[/tex]

[tex]2x^{2} -6x+5x-15=0[/tex]

[tex]2x(x-3)+5(x-3)=0[/tex]

[tex](x-3)(2x+5)=0[/tex].......(1)

So, the required equation is equation(1).

Hence, the equation that allows you to solve the given equation is (x-3)(2x+5).

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Answer:

The graph shows the solution set of the equality √x < -1

(No Solutions)

Answer:

19 or √145 ≈ 12.04

Step-by-step explanation:

Use the distance formula to determine the distance between the two points.

Distance  =  √ ( x ₂  −  x ₁ )²  +  ( y ₂  −  y ₁ ) ²

Substitute the actual values of the points into the distance formula.

√ ( 4  −  (  −  5 )) ²  +  ( ( − 5 ) − 3 ) ²

Simplify:  

√ 145

The result can be shown in multiple forms.

Exact Form:

√ 145

Decimal Form:

12.04159457  … ≈ 12.04

Answer:

Its D because 2×2×2 equals 8 and they are both minus and knowing - times - makes + so it becomes 8

Answer:

B.) -1/8

Step-by-step explanation:

You flip the problem because of the negative exponent

[tex]\frac{1}{-2^3}[/tex]

This makes the exponent positive

Expand the denominator

(-2) * (-2) * (-2) = 4*(-2) = -8

1/-8 = -1/8

I believe it's 4 as 32 fluid ounces is 1 quart

Answer:

ok so you said 40 points but theres only 5 points....xD anyways,

we know that 4 would be as 32 fluid ounces.

that would equal 1 quart.

hope this helps! best of luck!!!!

Answer:

12.0 units is the answer

Step-by-step explanation:

Pythagorean theorem can be written as,

[tex]d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d=\sqrt{(6-(-2))^2 + (1-(-8))^2}\\\\d=\sqrt{(8\\)^2+(9)^2} \\\\d=\sqrt{64+81} \\\\d=\sqrt{145} \\\\d=12.041...[/tex]

Rounding off,

d = 12.0 units

Answer:

because cfd eaquls a+b lllllllllll

Answer:

Step-by-step explanation:

IT is either the same as 7x+4 because it is infront of each other or you add 8x+6 and 6x+2 then you substract that from 180 to find out the remaining angle. Of course you have to subtitute the amount of x first.

Answer:

=

Step-by-step explanation:

Because |-4| is basically 4 since its the absolute value of that..

Parent functions are the base function of a family function. [tex]f(x) = \sqrt x[/tex] is the parent function of the square root function

Given that:

[tex]f(x) = \sqrt x[/tex]

The parent function of a cube root function is:

[tex]f(x) = x^3[/tex]

The parent function of a reciprocal function is:

[tex]f(x) = \frac 1x[/tex]

The parent function of an absolute function is:

[tex]f(x) = |x|[/tex]

The parent function of a square root function is:

[tex]f(x) = \sqrt x[/tex]

By comparing the above parent functions to [tex]f(x) = \sqrt x[/tex], we can conclude that [tex]f(x) = \sqrt x[/tex] is the parent function of a square root function.

Hence, (d) is true

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Answer:

b = -108

Step-by-step explanation:

Step-by-step explanation:

Given

[tex] - 6 = \frac{b}{18} \\ cross \: multiply \\ b = - 6 \times 18 \\ b = - 108[/tex]

Hope it will help :)❤

Answer:

second one

Step-by-step explanation:

Because when you try to remove the brackets then you should multiply coefficient of x and coefficient of y by 2

So it will be 2x+18y

2*9=18

Answer:

$53.70 per gram

Step-by-step explanation:

Just divide the price (123.51) by the amount of grams (2.3) to get your answer, which should be $53.70 per gram

Hopefully this helps - let me know if you have any questions!

Answer: True

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

Given:

  daily cost function c(x) = x +11

  price-demand function p(x) = -0.15x +20.8

Find:

  daily profit function

  maximum daily profit

  quantity sold for maximum profit

  price for maximum profit

Solution:

The revenue is the product of price and demand:

  x·p(x) = -0.15x^2 +20.8x

The profit is the difference between revenue and cost:

  f(x) = x·p(x) -c(x) = -0.15x^2 +20.8x -x -11

  f(x) = -0.15x^2 +19.8x -11 . . . . . daily profit function

__

The maximum profit will be had a the vertex of the curve, found where ...

  x = -(19.8)/(2(-0.15)) = 66

  f(66) = (-0.15·66 +19.8)66 -11 = 9.9·66 -11 = 642.40

The maximum profit is $642.40, when 66 gallons of ice cream are sold.

__

The price that will result in demand of 66 gallons of ice cream is ...

  p(66) = -0.15(66) +20.8 = 10.9

The price to charge per gallon to maximize profit is $10.90.

9514 1404 393

Answer:

  te, tm, (m-e), t

Step-by-step explanation:

The problem statement tells you how to interpret the expressions and their parts.

Swap the top two expressions on the right and the list will be in the appropriate order:

Answer:

Step-by-step explanation:

To address 1/3 on a number line, we split the hole among O and An into 3 equivalent parts. Leave T and Q alone the marks of division. At that point, T addresses 1/3 and Q addresses 2/3, since 2/3 methods 2 sections out of 3 equivalent parts as demonstrated beneath. By utilizing a similar system, point O addresses 0/3 and point An addresses 3/3.

Another way of saying it is:

In portrayals of divisions on a number line we can show parts on a number line. To address 1/2 on the number line, draw the number line and imprint a direct A toward address 1.  

Presently, split the hole among O and An into halves. Leave T alone the mark of division. At that point, point T addresses 1/2.  

Portrayals of Fractions on a Number Line  

To address 1/3 on a number line, we split the hole among O and An into 3 equivalent parts. Leave T and Q alone the marks of division. At that point, T addresses 1/3 and Q addresses 2/3, since 2/3 methods 2 sections out of 3 equivalent parts as demonstrated underneath.  

Portions on a Number Line  

By utilizing a similar technique, point O addresses 0/3 and point An addresses 3/3

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