Consider the system of linear equations 2- y = kx - y = k (a) Reduce the augmented matrix for this system to row-echelon (or upper-triangular) form. (You do not need to make the leading nonzero entries 1.) (b) Find the values of k (if any) when the system has (a) no solutions, (b) exactly one solution (if this is possible, find the solution in terms of k), (e) infinitely many solutions (if this is possible, find the solutions).

Answer:

[tex]w = \frac{93}{40} [/tex]

Answer:

C

Step-by-step explanation:

Y= MX (The Slope which is Rise/Run) minus 2 (The Y-Intercept).

Answer:

8

Step-by-step explanation:

24/3 = 8

Answer: 3 1/3 miles

Step-by-step explanation:

The most expensive trailer can be purchased for $39,505.41. To determine the most expensive trailer that can be purchased at an interest rate of 3.12% compounded quarterly, we calculate the future value of the savings.

The formula for compound interest is given by the equation:

A = [tex]P(1 + r/n)^(nt)[/tex]

Where:

A is the future value of the savings,

P is the quarterly deposit amount ($1,200),

r is the interest rate per compounding period (3.12%),

n is the number of compounding periods per year (quarterly, so n = 4),

and t is the number of years (15).

Plugging the values into the formula, we have:

A =[tex]1200(1 + 0.0312/4)^(4*15)[/tex]

Calculating this expression, we find the future value of the savings after 15 years to be approximately $39,505.41.

Therefore, the most expensive trailer that can be purchased is $39,505.41 or less, as that is the maximum amount that will be saved over the 15-year period.

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Answer:   It is 3.>9

Step-by-step explanation:

because i dont know

4a^2+7ab-b^2

Step-by-step explanation:

Add the first two equations together:

 3a^2-ab-2b^2

+ 2a^2+5ab-3b^2

---------------------------

5a^2+4ab-5b^2

Subtract that answer from the remaining trinomial:

5a^2+4ab-5b^2

- a^2-3ab-4b^2

--------------------------

4a^2+7ab-b^2

Answer:

4a^2 + ab - 9b^2

Step-by-step explanation:

First, perform the indicated addition:

3a^2-ab-2b^2

2a^2+5ab-3b^2

------------------------

5a^2 + 4ab - 5b^2

From this sum we subtract a^2 - 3ab - 4b^2:

 5a^2 + 4ab - 5b^2

-(a^2 - 3ab - 4b^2

------------------------------

 4a^2 + ab - 9b^2

Answer:

-4m

Step-by-step explanation:

=11m-7m-(2m+6m)

=11m-7m-8m

=-4m

plz mark me as brainliest

Answer:

-4m

Step-by-step explanation:

Hey!

==================================================================

First, We should remove the Parentheses.

To remove them, we distribute the negative over (2m + 6m).

⇒ 11m - 7m - (2m + 6m)

⇒ 11m - 7m - 2m - 6m

Work the Problem from Left to Right.

⇒ 4m - 2m - 6m

⇒ 2m - 6m

⇒ -4m

==================================================================

Hope I Helped, Feel free to ask any questions to clarify :)

Have a great day!

More Love, More Peace, Less Hate.

       -Aadi x

Answer:

The front-end ratio is calculated by dividing an individual's anticipated monthly mortgage payment by his/her monthly gross income. The mortgage payment generally consists of principal, interest, taxes, and mortgage insurance (PITI). Lenders use the front-end ratio in conjunction with the back-end ratio to determine how much to lend.

Step-by-step explanation:

The time series component that exhibits a repeating pattern over successive periods, often one-year intervals, is called the seasonal component. It represents the regular and predictable variations in the data that occur due to seasonal factors, such as weather patterns, holidays, or annual events.

The seasonal component typically follows a consistent pattern, where the values tend to rise and fall in a similar manner within each season. For example, retail sales may experience higher values during the holiday season each year and lower values during other times.

Identifying and analyzing the seasonal component is crucial in many fields, including economics, finance, marketing, and forecasting. By understanding and accounting for the seasonal patterns, analysts and decision-makers can make more accurate predictions, adjust for seasonality in data, and develop strategies to optimize operations or sales during specific periods.

Methods such as seasonal decomposition or seasonal adjustment techniques are used to separate the seasonal component from other components, such as trend and irregular fluctuations, in order to better understand the underlying patterns and make informed decisions based on the data.

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Answer:

8.1

Step-by-step explanation:

Subtract 2.9 to get Y alone.

11 - 2.9 = 8.1

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 1 , 1 )

Equation Form:

x = 1 ,   y = 1

Answer:

21.21

Step-by-step explanation:

Area of a circle is A = π r^2

Variables:

r = 18/2 = 9

θ = 30 deg

Find the area:

A = π r^2

A = π 9^2

A = 254.47

Find the area of the sector:

θ/360 * A

= 30/360 * 254.47

= 21.21

Please mark brainliest if this helped!

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Respuesta:

11,80 €

Explicación paso a paso:

Dado:

Importe o coste = 16,80 €

El valor de descuento sobre la cantidad = 5 €

El precio o costo con descuento sobre el monto entregado será; la diferencia entre la cantidad dada y el valor de descuento

Importe - valor de descuento

16,80 € - 5 €

= 11,80 €

Let the number of 47-cent stamps be x, and the number of 8-cent stamps be y. So, the cost of x 47-cent stamps will be $0.47x.The cost of y 8-cent stamps will be $0.08y.Therefore, $2.99 = $0.47x + $0.08y  Multiply the entire equation by 100 to eliminate decimals. $299 = 47x + 8yEquation 1.47x + 8y = 299There are a couple of ways to solve the system of equations.

One method is substitution. We can rearrange equation 1 to solve for x:47x = 299 - 8y x = (299 - 8y)/47Substitute this expression for x into the first equation: 0.47(299 - 8y)/47 + 0.08y = 2.99 Simplifying the equation, we get: 299 - 8y + 4.76y = 299y = 299/0.76y = 393.4Hence, we cannot have fractional values of y; it must be a whole number, so Caitlyn can use 32 47-cent stamps and 15 8-cent stamps to mail a gift card to a friend.

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Answer:

7/24 i think i hope this helps and im right

The surface area of the figure is 204 sq.unit.

The surface area of a three dimensional figure is the sum of area of all its faces.

Here a three dimensional figure is given and surface area has to be calculated.

The base is a cuboid

Surface Area of a cuboid = SA= 2lw+2lh+2hw

SA = 2 * 6 * 6 +2 * 6 * 3 + 2 * 6 * 3

SA = 144 sq.units

The Surface Area of the 4 triangle surface = 4 * (1/2) * base * height

SA = 2 * 6 * 5 = 60 sq.units

The total surface area = 144 +60 = 204 sq.units

Therefore the surface area of the figure is 204 sq.unit.

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Answer:

2/5, option 4.

Step-by-step explanation:

When you are dividing 2 fractions, the first fraction stays the same, and the 2nd fraction becomes the reciprocal, and the division sign becomes a multiplication sign.

The reciprocal of 2/3 is 3/2.

Now you need to change the division sign to a multiplication sign.

The equation will now become 4/15 x 3/2.

4 times 3 is 12, and 15 times 2 is 30.

12/30 isn't an option, so you will need to simplify.

Find a common factor, then divide.

6 is a common factor, so you divide both 12 and 30 by 6, to get 2 and 5.

2/5 is what you are left with.

Option 4.

4/15 divided by 2/3 is 2/5.

Answer:

hi

Step-by-step explanation:

[tex] \frac{4}{15} \div \frac{2}{3} = \frac{4}{15} \times \frac{3}{2} = \frac{2}{5} [/tex]

have a nice day

The approximate values of the solution to the given initial value problem at the four time steps t = 0.1, 0.2, 0.3 and 0.4 using the modified Euler formula with step sizes h = 0.05 and h = 0.001 are as follows:

Approximate solution using h = 0.05y(0.1) = 1.12116266y(0.2) = 1.25755476y(0.3) = 1.41728420y(0.4) = 1.59967883

Approximate solution using h = 0.001y(0.1) = 1.00372378y(0.2) = 1.00745820y(0.3) = 1.01119282y(0.4) = 1.01492766

The non-autonomous ordinary differential equation is given as:

dy/dt = f(t,y)......(1)

where f is a continuous function and is defined for all values of t and y. The numerical methods for non-autonomous ODEs are described below:

This method is based on the same idea as Euler's method, but the derivative is evaluated at the midpoint of the interval instead of the initial point. Consider the initial value problem (IVP) dy/dt = f(t,y), y(to) = yo, and suppose that we want to approximate the solution at tn+1 = tn + h. Then, using the improved Euler's formula, we obtain the following approximation:

Yn+1 = yn + hF(tn + h/2, yn + hF(tn,yn)/2)......(2)

Using h = 0.05

Substituting h = 0.05 in equation (2), we get

Y1 = Y0 + 0.05(F(0.025,Y0+F(0,Y0)/2))

Y2 = Y1 + 0.05(F(0.075,Y1+F(0.05,Y1)/2))

Y3 = Y2 + 0.05(F(0.125,Y2+F(0.1,Y2)/2))

Y4 = Y3 + 0.05(F(0.175,Y3+F(0.15,Y3)/2))

Using h = 0.001

Substituting h = 0.001 in equation (2), we get

Y1 = Y0 + 0.001(F(0.0005,Y0+F(0,Y0)/2))

Y2 = Y1 + 0.001(F(0.0015,Y1+F(0.001,Y1)/2))

Y3 = Y2 + 0.001(F(0.0025,Y2+F(0.002,Y2)/2))

Y4 = Y3 + 0.001(F(0.0035,Y3+F(0.003,Y3)/2))

For the given IVP, f(t,y) = 2t + ety, y(0) = 1

So, substituting f(t,y) in equation (1), we get

dy/dt = 2t + ety.....(3)

Using the modified Euler formula (equation 2), we get

Using h = 0.05

Y1 = 1 + 0.05(2(0.025) + e(0.025)Y0) = 1.12116266

Y2 = 1.12116266 + 0.05(2(0.075) + e(0.075)Y1) = 1.25755476

Y3 = 1.25755476 + 0.05(2(0.125) + e(0.125)Y2) = 1.41728420

Y4 = 1.41728420 + 0.05(2(0.175) + e(0.175)Y3) = 1.59967883

Using h = 0.001

Y1 = 1 + 0.001(2(0.0005) + e(0.0005)Y0) = 1.00372378

Y2 = 1.00372378 + 0.001(2(0.0015) + e(0.0015)Y1) = 1.00745820

Y3 = 1.00745820 + 0.001(2(0.0025) + e(0.0025)Y2) = 1.01119282

Y4 = 1.01119282 + 0.001(2(0.0035) + e(0.0035)Y3) = 1.01492766

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The angles of rotation for the given conditions are:

1. π radians (180 degrees)

2. π/2 radians (90 degrees)

3. 3π/2 radians (270 degrees)

To find an angle of rotation centered at the origin that sends point P to a location with the given conditions, we can use trigonometric concepts.

1. For z > 0 and y < 0:

Since z > 0, the point P lies in the positive z-axis direction. To make y negative, we rotate the point counterclockwise by an angle of π radians (180 degrees).

2. For z < 0 and y > 0:

In this case, the point P lies in the positive y-axis direction. To make z negative, we rotate the point counterclockwise by an angle of π/2 radians (90 degrees).

3. For y < 0 and z < 0:

Here, the point P lies in the negative y-axis direction. To make both y and z negative, we rotate the point counterclockwise by an angle of 3π/2 radians (270 degrees).

In summary, the angles of rotation for the given conditions are:

1. π radians (180 degrees)

2. π/2 radians (90 degrees)

3. 3π/2 radians (270 degrees)

By rotating the point P by these angles, we can achieve the desired conditions for the (z, y) coordinates.

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Step-by-step explanation:

Factor −6 out of −6x

-6(x)+12

Factor −6 out of 12.

−6(x)−6(−2)

Factor −6 out of −6 (x)−6(−2).

-6(x-2)

It is important to remember the definitions of binomial, continuous, discrete, interval, nominal, ordinal, and ratio variables because these are different types of data which need different methods of analysis.

Nominal variables are variables used for identification or categorization. Nominal data cannot be ranked, ordered, or compared. The gender, ethnicity, religion, and hair color of an individual are all examples of nominal variables.

Ordinal variables are variables that can be ranked or ordered, but the difference between each point on the scale is not constant. For example, we could use an ordinal variable to describe the class ranks of students: 1st, 2nd, 3rd, and so on. While there is a clear order to the data, the difference between each rank is not necessarily the same.

Interval variables have equal distances between each value, and they also have a true zero point. For example, a temperature measurement is an interval variable because the difference between 20 degrees Celsius and 30 degrees Celsius is the same as the difference between 30 degrees Celsius and 40 degrees Celsius.

Ratio variables have equal intervals between each value and have a true zero point. For example, weight is a ratio variable because a weight of zero means that there is no weight.

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Answer:

y=1/9x+104

Step-by-step explanation:

I REALLY hope this helps

Sorry if im wrong

Best of luck!

To convert the hexadecimal value of the EAX register (37e11449) into binary and obtain the values of AL, AH, and EAX, we can break it down as follows:

EAX: 0011 0111 1110 0001 0001 0100 0100 1001

AH:   0011 0111

AL:    0100 1001

So, the binary representation of AL, AH, and EAX is as follows:

EAX: 0011 0111 1110 0001 0001 0100 0100 1001

AH:   0011 0111

AL:    0100 1001

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The graph of the transformation by of horizontally compressing g(x) by a factor of 1/2 and then reflecting across the x-axis is graph Y

The function is given as:

[tex]g(x) = 2^x[/tex]

When compressed horizontally by a factor of 1/2, the transformation rule is:

g'(x) = g(2x)

So, we have:

[tex]g(2x) = 2^{2x}[/tex]

[tex]g(2x) = 4^x[/tex]

When reflected across the x-axis, the transformation rule is:

[tex](x,y) \to (x,-y)[/tex]

So, we have:

[tex]f(x) = -4^x[/tex]

The graph represented by this is graph Y.

Hence, the graph of the transformation is graph Y

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Upon solving the given system of equations:

[tex]x(t) = (c_1 + e^{-t}) + (3/2) * (c_2 + e^{-t}) * cos(2t) + (1/2) * (c_1 + e^{-t}) * sin(2t),\\y(t) = (c_1 + e^{-t}) + (3/2) * (c_2 + e^{-t}) * sin(2t) - (1/4) * (c_1 + e^{-t}) * cos(2t)[/tex]

To solve the system of equations:

x' = 2x - 3y + 2sin(2t)

y' = x - 2y - 2cos(2t)

We can use the method of undetermined coefficients to find the particular solution. Assuming the particular solution takes the form:

[tex]x_p(t) = A sin(2t) + B cos(2t)\\y_p(t) = C sin(2t) + D cos(2t)[/tex]

Substituting these expressions into the original equations, we get:

2(A sin(2t) + B cos(2t)) - 3(C sin(2t) + D cos(2t)) + 2sin(2t) = 2sin(2t)

(A sin(2t) + B cos(2t)) - 2(C sin(2t) + D cos(2t)) - 2cos(2t) = cos(2t)

(2A - 3C + 2)sin(2t) + (2B - 3D)cos(2t) = 2sin(2t)

(A - 2C)sin(2t) + (B - 2D - 2)cos(2t) = cos(2t)

By comparing the coefficients of sine and cosine on both sides, we can equate them separately:

2A - 3C + 2 = 2

2B - 3D = 0

A - 2C = 0

B - 2D - 2 = 1

Solving these equations, we find:

A = 1

B = 3/2

C = 1/2

D = -1/4

So the particular solution is:

[tex]x_p(t)[/tex] = sin(2t) + (3/2)cos(2t)

[tex]y_p(t)[/tex] = (1/2)sin(2t) - (1/4)cos(2t)

To find the complementary solution, we solve the homogeneous system:

x' = 2x - 3y

y' = x - 2y

We can rewrite this system as a matrix equation:

X' = AX

where [tex]X = [x, y]^T[/tex] and

[tex]A = \left[\begin{array}{ccc}2&-3\\1&-2\end{array}\right][/tex]

The characteristic equation is:

det(A - λI) = 0, where I is the identity matrix. Solving this equation, we find the eigenvalues:

[tex]\lambda_1 = -1\\\lambda_2 = -1[/tex]

For each eigenvalue, we solve the corresponding eigenvector equation:

(A - λI)V = 0

For [tex]\lambda_1 = -1[/tex], we have:

[tex]\left[\begin{array}{ccc}3&-3\\1&-1\end{array}\right] * V_1 = 0[/tex]

Solving this system, we find the eigenvector:

[tex]V_1 = [1\ \ 1][/tex]

For [tex]\lambda_2 = -1[/tex], we have:

[tex]\left[\begin{array}{ccc}3&-3\\1&-1\end{array}\right] * V_2= 0[/tex]

Solving this system, we find the eigenvector:

[tex]V_2 = [3\ \ 1][/tex]

So the complementary solution is:

[tex]x_c(t) = c_1 * e^{-t} * [1\ \ 1]^T + c_2 * e^{-t} * [3\ \ 1]^T\\y_c(t) = c_1 * e^{-t} * [1\ \1]^T + c_2 * e^{-t} * [3\ \ 1]^T[/tex]

where

[tex]c_1\ and\ c_2[/tex] are arbitrary constants.

The general solution is the sum of the particular and complementary solutions:

[tex]x(t) = x_p(t) + x_c(t)\\y(t) = y_p(t) + y_c(t)[/tex]

Simplifying and combining terms, we get:

[tex]x(t) = (c_1 + e^{-t}) + (3/2) * (c_2 + e^{-t}) * cos(2t) + (1/2) * (c_1 + e^{-t}) * sin(2t)\\y(t) = (c_1 + e^{-t}) + (3/2) * (c_2 + e^{-t}) * sin(2t) - (1/4) * (c_1 + e^{-t}) * cos(2t)[/tex]

where [tex]c_1\ and\ c_2[/tex] are arbitrary constants.

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B. More students prefer black Model C3 calculators than white Model B2 calculators.

       - Ap3x verified

Answer:

ok so i can have i insteaof f too

Step-by-step explanation: