The compound CH3CH2COCH2CH2CH3 is named as 3-hexanone.
The given condensed structural formula represents a ketone called 3-hexanone. In the IUPAC nomenclature, the position of the carbonyl group (C=O) is indicated by the lowest possible number, which in this case is 3. The carbon chain consists of six carbon atoms (hexane) with a carbonyl group attached to the third carbon atom.
The compound 3-hexanone can undergo both oxidation and reduction reactions. As a ketone, it contains a carbonyl group that can be oxidized to form a carboxylic acid or reduced to form an alcohol. Therefore, it is not limited to only oxidation or reduction reactions.
The statement that the compound can be reduced to form 3-hexene is incorrect. Reduction of 3-hexanone would yield 3-hexanol, not 3-hexene. Reduction adds hydrogen to the carbonyl group, converting it to a hydroxyl group (-OH).
The compound with the condensed structural formula CH3CH2COCH2CH2CH3 is named 3-hexanone. It is a ketone that can undergo both oxidation and reduction reactions. However, it cannot be directly reduced to form 3-hexene; instead, reduction of 3-hexanone would yield 3-hexanol. The compound can be formed by the oxidation of 3-hexanol, where the alcohol group is converted to a carbonyl group.
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A piece of metal of mass 23 g at 100 ◦C is
placed in a calorimeter containing 55.4 g of
water at 25◦C. The final temperature of the
mixture is 63.4
◦C. What is the specific heat
capacity of the metal? Assume that there is
no energy lost to the surroundings.
Answer in units of J
g ·
◦ C
.
Answer:
10.58 J/g-°C
Explanation:
To find the specific heat capacity of the metal, you need to know how much heat was lost when it reacted with water.
You know that there are 55.4 g of water, the initial temp. of water is 25°C, and the final temp. (the mixture's temp.) is 63.4°C.
You should also know that the specific heat capacity of water is 4.186 J/g-°C.
Plug this into the equation the q=mcΔT.
q = (55.4 g)(4.186 J/g-°C)(63.4°C - 25°C)
q = 8905.12896 J
If 8905.12896 J was gained by the water, then 8905.12896 J must have been lost from the metal.
You know that there are 23 g of the metal and that its initial temp. is 100°C.
Plug this information into q=mcΔT.
8905.12896 J = (23 g)(C)(63.4°C - 100°C)
C = 10.58 J/g-°C
*When you plug all of this into the calculator, it will result in a negative number but keep in mind that heat was LOST by the metal so 8905.12896 J is essentially negative. So the negative cancels out.*
help me help me help me
Answer:
i dont know i do this for points
Explanation:
What does the word Microbial mean?
Answer:
relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.
Explanation:
ex: "skin is a major source of microbial contamination during a surgical procedure"
◕‿↼ Hey There!
Answer → Microbial means, relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.
✨Hope This Helps!✨
Determinar el volumen de una solución en mililitros cuya concentración es 0,3 M en ácido sulfúrico y que contiene 1,5 moles del ácido
Answer:
V = 5000 mL
Explanation:
¡Hola!
En este caso, dado que la molaridad de una solution se calcula al dividir las moles por el volume de solución en litros, es posible calcular el volumen cuando se dividen las moles por la molaridad, tal y como se muestra a continuación:
[tex]M=\frac{n}{V}\\\\V=\frac{n}{M}[/tex]
Así, podemos reemplazar la molaridad y moles dadas para obtener:
[tex]V=\frac{1.5mol}{0.3mol/L}=5L[/tex]
Que en mililitros sería:
[tex]V=5L*\frac{1000mL}{1L}\\\\V=5000mL[/tex]
¡Saludos!
A solution is made by mixing 140. g of water and 91. g of methanol (CH3OH) Calculate the mole fraction of water in this solution. Be sure your answer has the correct number of significant digits.
The mole fraction of water in the solution is 0.62.
To calculate the mole fraction of water in the solution, we need to determine the moles of water and methanol present.
Mass of water = 140 g
Mass of methanol = 91 g
Molar mass of water (H2O) = 18.015 g/mol
Molar mass of methanol (CH3OH) = 32.04 g/mol
Step 1: Calculate the number of moles of water and methanol.
Moles of water = Mass of water / Molar mass of water
Moles of water = 140 g / 18.015 g/mol ≈ 7.773 mol
Moles of methanol = Mass of methanol / Molar mass of methanol
Moles of methanol = 91 g / 32.04 g/mol ≈ 2.840 mol
Step 2: Calculate the total moles of the solution.
Total moles = Moles of water + Moles of methanol
Total moles = 7.773 mol + 2.840 mol = 10.613 mol
Step 3: Calculate the mole fraction of water.
Mole fraction of water = Moles of water / Total moles
Mole fraction of water = 7.773 mol / 10.613 mol ≈ 0.732
The mole fraction of water in the solution is approximately 0.732.
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20.4 g of carbon reacts with 54.4 g of oxygen. what is the empirical formula for this compound?
To determine the empirical formula of a compound, the given masses of the elements (carbon and oxygen) are used to calculate the moles of each element. The mole ratio between the elements is then determined to find the simplest whole number ratio, which represents the empirical formula.
First, we calculate the moles of carbon and oxygen using their respective molar masses. The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of oxygen (O) is approximately 16.00 g/mol.
Moles of carbon = 20.4 g / 12.01 g/mol ≈ 1.70 mol
Moles of oxygen = 54.4 g / 16.00 g/mol ≈ 3.40 mol
Next, we determine the simplest whole number ratio by dividing the number of moles of each element by the smallest number of moles. In this case, the smallest number of moles is approximately 1.70 mol (carbon).
Carbon: 1.70 mol / 1.70 mol ≈ 1
Oxygen: 3.40 mol / 1.70 mol ≈ 2
Therefore, the empirical formula for this compound is C1O2, which can be simplified to CO2.
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hi trying this again :D What are ALWAYS the products of the complete combustion of a hydrocarbon? Check all that apply.
- oxygen
- water
- carbon dioxide
- hydrogen
- sulfur trioxide
it should be carbon dioxide and water
The heat capacity of aluminum is 0.900 J/gºC. a. How much energy is needed to raise the temperature of an 8.50 x 102g block of aluminum from 22.8°C to 94.6°C?
Recall the heat capacity equation:
q = mc∆T
We're given mass, specific heat capacity, as well as the change in temperature. All we need to do is plug the numbers into the variables and we'll have our answer!
Although this question doesn't try to trick you, more often than not questions regarding energy change will attempt to throw you off with specific heat capacity. It's extremely important to note the units of the specific heat capacity and ensure that the numbers you use are in those units. As an example, the specific heat capacity might be given to you in J/mol*K - in this case, you'd have to do some unit conversions with your given data in order to fit all the numbers. In this question, we're given the specific heat capacity in J/gºC, so we don't need to change anything since all of our data is already in these units.
Anyways, back to the actual question:
q = mc∆T
q = (8.50 * [tex]10^{2}[/tex]) * (0.900) * (94.6 - 22.8)
q = 54927 (J)
Remeber to include significant figures:
54927 = 5.49 * 10^4 (J)
The required energy is 5.49 * [tex]10^{4}[/tex] Joules, or 5.49 * [tex]10^{1}[/tex] kJ
Let me know if you need any of my work to be explained!
- Breezeツ
A drought hits the habitat of a semi-aquatic bird population. All ponds dry up, and fish populations decline. There are two groups of birds in the population that differ in leg length and diet. Long-legged birds eat fish, while short-legged birds eat insects. The drought has little effect on insect populations.
Answer:
The population of the long-legged birds decreases.
Explanation:
The population of the short-legged birds increases whereas the population of long-legged birds decreases due to availability of food in that environment. The long-legged birds feed on fish whose population decreases due to drought conditions so the population of long-legged birds also decreases while on the other hand, the population of short-legged birds increases or remain the same because they feed on the insects and the insects are available in large amount and less affected by the drought conditions.
HELP ASAP plz!:) I’ll give brainliest
Answer:
it is closer to the south pole
Explanation:
6. Calculate the molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3).
The molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3) is 180.157 g/mol.What is molecular mass Molecular mass is the sum of the masses of all the atoms in a molecule. The unit of molecular mass is grams per mole the are (g/mol).Acetylsalicylic acid molecular
mass calculation In acetylsalicylic acid, HOOC-C6H4-OOCCH3, add the mass of each atom:Oxygen (O) = 2 x 16.00 g/mol = 32.00 g/ (C) = 9 x 12.01 g/mol = 108.09 g/mol Hydrogen (H) = 8 x 1.01 g/mol = 8.08 g/molAdd the masses of all the atoms to calculate the molecular mass:32.00 g/mol + 108.09 g/mol + 8.08 g/mol = 148.17 g/molThe molecular mass of acetylsalicylic acid is 180.157 g/mol (approximately)
Molecular mass is the mass of a molecule measured in atomic mass units (amu). The molecular mass is the sum of the atomic masses of all the atoms present in the molecule.The molecular mass formula can be written as: Molecular mass = (mass of first element × number of atoms) + (mass of second element × number of atoms) + ...The molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3) can be calculated by adding the mass of each atom. Here's how to calculate the molecular mass of acetylsalicylic acid:Oxygen (O) = 2 x 16.00 g/mol = 32.00 g/molCarbon (C) = 9 x 12.01 g/mol = 108.09 g/molHydrogen (H) = 8 x 1.01 g/mol = 8.08 g/molAdd the masses of all the atoms to calculate the molecular mass:32.00 g/mol + 108.09 g/mol + 8.08 g/mol = 148.17 g/molThe molecular mass of acetylsalicylic acid is 180.157 g/mol (approximately) the formula to calculate molecular mass.
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What are cathode rays
Answer:
a beam of electrons emitted from the cathode of a high-vacuum tube.
Explanation:
Cathode rays (also known as electron beam or e-beam) are electron waves that can be used in vacuum tubes.
the formula equation of Acetylene + oxygen ----> carbon dioxide + water
Answer:
The final balanced equation is : 2C2H2+5O2→4CO2+2H2O.
Which of the following is an example of a physical property?*
the mass
ability to rust
flammability
ability to combust
Answer: The mass
Explanation: ability to rust, flammability, and ability to combust are chemical properties.
Waves made by the breeze were very different than wave created by speedboat. describe the difference
Answer:
The amplitude of the speedboat waves were larger then the Breeze waves. The frequency of the speedboats waves were lower than the breeze waves. the speedboat waves had more of an effect on the boat, which tells us the speedboat waves had more energy.
Explanation:
plz can i get brainliest:)
Answer:
speedboat waves artificail and waves by breezes natural
Explanation:
An unknown piece of metal absorbs 1350 J of heat as 55.0 g of the metal heats up from 20.0 oC to 47.0 oC
Answer:
[tex]C=0.91\frac{J}{g\°C}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it is possible to recall the equation to calculate the heat, Q, in these calorimetry problems as shown below:
[tex]Q=mC(T_f-T_i)[/tex]
Thus, given the absorbed heat, mass and temperatures, we can easily calculate the specific heat of the metal as shown below:
[tex]C=\frac{Q}{m(T_f-T_i)}[/tex]
Then, by plugging in we obtain:
[tex]C=\frac{1350J}{55.0g(47.0\°C-20.0\°C)} \\\\C=0.91\frac{J}{g\°C}[/tex]
Best regards!
Which would be the best starting question to determine
the composition of the Outer Core and the Inner Core?
A) Are the Outer Core and the Inner Core composed of
large amounts of iron?
B) How much rock do the Outer Core and the Inner Core
contain?
C) How deep in the Earth are the Outer Core and the
Inner Core?
D) Are the Outer Core and the Inner Core composed of
large amounts of metal?
What is the percentage by mass of sulphur in Al2(SO4)3[A12SO4 =
342g/mol, S = 32]
Answer: The percentage by mass of sulphur in [tex]Al_2(SO_4)_3[/tex] is 9.36%
Explanation:
Mass percent of an element is the ratio of mass of that element by the total mass expressed in terms of percentage.
[tex]{\text {Mass percentage}}=\frac{\text {mass of sulphur}}{\text {Total mass}}\times 100\%[/tex]
Given: mass of sulphur = 32 g/mol
mass of [tex]Al_2(SO_4)_3[/tex] = 342 g/mol
Putting in the values we get:
[tex]{\text {Mass percentage}}=\frac{32g/mol}{342g/mol}\times 100\%=9.36\%[/tex]
The percentage by mass of sulphur in [tex]Al_2(SO_4)_3[/tex] is 9.36%
Explain how the copper could be in the lake sample near the picnic area but not have been detected by this test.
Answer:
May be the instrument is incorrect or may be error in it.
Explanation:
The copper have not been detected by this test because the test may be not for the detection of copper, may be it is used for identification of another minerals. If there is copper in the lake sample but can't be detected in the test so it means that the instrument which is used for detection is not the right one or having error in that instrument. Every mineral has a specific type of instrument that detect its presence, if we use incorrect instrument for the mineral then we can't detect the presence of that specific mineral.
Balance the chemical equation for the following redox reaction under acidic aqueous conditions with the smallest whole-number coefficients possible using the half-reaction method. On which side does H2O(l) appear, and what is its coefficient?
MnO4^-(aq)+NH3(aq)---->Mn^2+(aq)+NO2(g)
Water ([tex]H_{2}O[/tex]) appears on the product side with a coefficient of 8. To balance the given redox reaction, we can use the half-reaction method. Let's begin by balancing the reduction half-reaction and the oxidation half-reaction separately.
Reduction half-reaction: [tex]MnO_{4}^{-aq}[/tex] + [tex]8H^{+aq}[/tex] + [tex]5e^{-}[/tex] → [tex]Mn^{2+}[/tex](aq) + [tex]4H_{2}O[/tex](l)
Oxidation half-reaction: [tex]NH_{3}[/tex](aq) → [tex]NO_{2}[/tex](g) + [tex]3H^{+}[/tex](aq) + [tex]2e^{-}[/tex]
Next, we need to balance the number of electrons transferred in both half-reactions. To do this, we multiply the oxidation half-reaction by 5 and the reduction half-reaction by 2:
[tex]2NH_{3}[/tex](aq) → [tex]2NO_{2}[/tex](g) + [tex]6H^{+}[/tex](aq) + [tex]4e^{-}[/tex]
[tex]2MnO_{4}^-[/tex](aq) + [tex]16H^{+}[/tex]+(aq) + [tex]10e^{-}[/tex] → [tex]2Mn^{2+}[/tex](aq) + [tex]8H_{2}O[/tex](l)
Now, we can combine the two half-reactions and cancel out the common species:
[tex]2MnO_{4}^-[/tex](aq) + [tex]16H^{+}[/tex](aq) + [tex]10NH_{3}[/tex](aq) → [tex]2Mn^{2+}[/tex](aq) + [tex]2NO_{2}[/tex](g) + [tex]8H_{2}O[/tex](l)
From the balanced equation, we can see that water ([tex]H_{2}O[/tex]) appears on the product side with a coefficient of 8.
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most modern catalytic converters in automobiles have a surface with a platinum-rhodium catalyst. for which of the following reactions is this catalyst used
The platinum-rhodium catalyst used in most modern catalytic converters in automobiles is primarily employed for the oxidation of harmful pollutants. It facilitates the conversion of carbon monoxide (CO) and unburned hydrocarbons (HC) into carbon dioxide (CO2) and water (H2O).
The platinum-rhodium catalyst in catalytic converters is specifically designed to promote the oxidation reactions of carbon monoxide (CO) and unburned hydrocarbons (HC). These reactions are crucial for reducing the emission of harmful pollutants from automobile exhaust gases.
Carbon monoxide (CO) is a toxic gas produced during incomplete combustion. The platinum-rhodium catalyst assists in the oxidation of CO, converting it into carbon dioxide (CO2). This reaction is represented by the equation:
2 CO + O2 → 2 CO2
Unburned hydrocarbons (HC) are volatile organic compounds (VOCs) that contribute to smog formation. The platinum-rhodium catalyst aids in their oxidation, transforming them into carbon dioxide (CO2) and water (H2O). The general reaction can be expressed as:
HC + O2 → CO2 + H2O
The platinum-rhodium catalyst is essential in facilitating these oxidation reactions, promoting more complete combustion of harmful pollutants and reducing their negative environmental impact.
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name four methods of separating mixtures
Answer:
Chromatography
Distillation
Evaporation
Filtration
Explanation:
Chromatography involves solvent separation on a solid medium.
Distillation takes advantage of differences in boiling points.
Evaporation removes a liquid from a solution to leave a solid material.
Filtration separates solids of different sizes.
Mixtures can be physically separated by using methods that use differences in physical properties to separate the components of the mixture, such as evaporation, distillation, filtration and chromatography.
Which of the following properties indicates the presence of weak intermolecular forces in a liquid: a .a high boiling point
b.a high surface tension
c.a low vapor pressure
d.a low heat of vaporization
e.none of the above.
A low vapor pressure indicates the presence of weak intermolecular forces in a liquid. The correct answer is: c.
The strength of intermolecular forces in a liquid determines the vapor pressure of the liquid. A liquid with strong intermolecular forces will have a low vapor pressure, while a liquid with weak intermolecular forces will have a high vapor pressure.
This is because the molecules in a liquid with weak intermolecular forces are more likely to escape from the surface of the liquid and enter the gas phase.
The other options are incorrect because they are all properties that indicate the presence of strong intermolecular forces in a liquid. A high boiling point indicates that a large amount of energy is required to overcome the intermolecular forces and vaporize the liquid.
A high surface tension indicates that the molecules in the liquid are strongly attracted to each other and to the surface of the liquid. A low heat of vaporization indicates that a small amount of energy is required to overcome the intermolecular forces and vaporize the liquid.
Therefore, the only property that indicates the presence of weak intermolecular forces in a liquid is a low vapor pressure.
Therefore, the correct option is C, a low vapor pressure.
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How many militias of 5.0 M H2SO4 (aq) stock silly toon are needed to prepare 100. Ml of 0.25 M H2SO4 (aq)
Answer:
5 mL
Explanation:
As this is a problem regarding dilutions, we can solve it using the following formula:
C₁V₁=C₂V₂Where subscript 1 refers to the initial concentration and volume, while 2 refers to the final C and V. Meaning that in this case:
C₁ = 5.0 MV₁ = ?C₂ = 0.25 MV₂ = 100 mLWe input the data:
5.0 M * V₁ = 0.25 M * 100 mLAnd solve for V₁:
V₁ = 5 mLAnswer:
5 mL of 5.0 M H₂SO₄ (aq) are needed to prepare 100 mL of 0.25 M H₂SO₄ (aq).
Explanation:
In chemistry, dilution is the reduction of the concentration of a chemical in a solution.
Then, dilution consists of preparing a less concentrated solution from a more concentrated one, and it consists simply by adding more solvent to the same amount of solute. That is, the amount or mass of the solute is not changed, but the volume of the solvent varies: as more solvent is added, the concentration of the solute decreases, since the volume (and weight) of the solution increases.
A dilution is calculated by the expression:
Ci*Vi = Cf*Vf
where:
Ci: initial concentration Vi: initial volume Cf: final concentration Vf: final volumeIn this case, you know:
Ci=5 MVi= ?Cf= 0.25 MVf= 100 mLReplacing:
5 M*Vi = 0.25 M* 100 mL
Solving:
[tex]Vi= \frac{0.25 M*100 mL}{5 M}[/tex]
Vi= 5 mL
5 mL of 5.0 M H₂SO₄ (aq) are needed to prepare 100 mL of 0.25 M H₂SO₄ (aq).
what is the chemical equation for
3fe(s)+4h2o(l)→fe3o4(s)+4h2(g)
Answer:
3fe s )+ 4h2o G )= fe3o4 s )+ 4h2 G
Explanation: 3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g) (i) Iron metal is getting oxidised. (ii) Water is getting reduced. (iii) Water is acting as reducing agent.
Explanation:
i make a search
Which boundary or zone adds new material to the lithosphere (the hard outer crust of the Earth)
Answer:Divergent Boundaries(or Boundary)
Explanation:took the test and got it right
How do i make observations and calculate data involving metric units?
Answer:
How to make scientific observations?
Observe something through your senses or record information using scientific tools and instruments and ask questions about your scientific observations (e.g., natural phenomena).
How to calculate data involving metric units?
To convert from one unit to another within the metric system usually means moving a decimal point (e.g., 1000000mm = 100000cm = 10000dm = 1000m = 100dkm = 10hm = 1km).
Choose all the nucleophiles.
Choose one or more:
CH3SNa
NaNH2
H3O+
CH3OH
CH3CH2CH3
NH4+
OH-
(CH3)3CLi
Answer:
CH3CH2CH3
(CH3)3CLi
CH3SNa
Explanation:
how many equivalents of mg 2 are present in a solution that contains 2.75 mol of mg 2?
There are 5.50 equivalents of Mg^2+ present in a solution containing 2.75 mol of Mg^2+.
The concept of equivalents is used to quantify the number of reactive entities or charges present in a solution. In the case of Mg^2+, each Mg^2+ ion carries two positive charges, so it is necessary to determine the number of moles of Mg^2+ and then convert it to equivalents.
Given:
Number of moles of Mg^2+ = 2.75 mol
To calculate the equivalents, we use the relationship that one mole of Mg^2+ is equal to 2 equivalents of Mg^2+ (since each Mg^2+ ion carries two positive charges):
Equivalents of Mg^2+ = Number of moles of Mg^2+ * 2
Equivalents of Mg^2+ = 2.75 mol * 2
Equivalents of Mg^2+ = 5.50 equivalents
Therefore, in a solution containing 2.75 mol of Mg^2+, there are 5.50 equivalents of Mg^2+ present.
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Determine the number of moles of Krypton contained in a 3.25 liter gas tank at 5.80 bar and 25.5 °C. If the gas were Oxygen instead of Krypton, how will the answer change? Explain.
There are approximately 0.689 moles of krypton in the gas tank.
To determine the number of moles of krypton in the gas tank, we can use the ideal gas law equation:
PV = nRT
Where:
P = pressure (in bar)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0831 L·bar/(mol·K))
T = temperature (in Kelvin)
Given:
Pressure (P) = 5.80 bar
Volume (V) = 3.25 liters
Temperature (T) = 25.5 °C = 25.5 + 273.15 = 298.65 K
Using the ideal gas law equation, we can solve for the number of moles (n):
n = PV / RT
n = (5.80 bar * 3.25 L) / (0.0831 L·bar/(mol·K) * 298.65 K)
n ≈ 0.689 moles
Therefore, there are approximately 0.689 moles of krypton in the gas tank.
If the gas in the tank were oxygen instead of krypton, the answer would change because the molar mass of oxygen is different from that of krypton. The ideal gas law equation remains the same, but the value of n (number of moles) would be different since it depends on the molar mass of the gas. Oxygen has a molar mass of approximately 32 g/mol, while krypton has a molar mass of approximately 84 g/mol. So, the number of moles of oxygen in the gas tank would be different and can be calculated using the same ideal gas law equation, but substituting the molar mass of oxygen instead of krypton.
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