combine like terms: 3x^2+4y-2x^2-x^2

Answer: k = 84

Step-by-step explanation:

0.12k = 10.08

k = 84                       Divide 0.12 to both sides

Answer:

k=84

Step-by-step explanation:

Answer:

Step-by-step explanation:

x = -5

-5 < -4  and if x<-4 then  f(x) = - 2x - 8

so:

    f(-5) = - 2(-5) - 8 = 10 - 8 = 2

Step-by-step explanation:

Check the above photos...

Answer:

x = 35°, Angle 1 = 145°, Angle 2 = 35°

Step-by-step explanation:

In a trapezoid, the angles on the same leg are supplementary, meaning they add up to 180°. That means Angle 2 plus Angle 1 equals 180°. Therefore:

[tex](4x+5)+x=180^{\circ}\\5x+5=180^{\circ}\\5x=175^{\circ}\\x=35^{\circ}[/tex]

Therefore, x = 35°, Angle 2 = 35°, and Angle 1 =

[tex]4x-5^{\circ}\\4(35^{\circ})+5^{\circ}\\140^{\circ}+5^{\circ}=145^{\circ}[/tex]

To ensure our answers make sense, we verify they equal 180°:

[tex]145^{\circ}+35^{\circ}=180^{\circ}[/tex]

Answe

x = 35°, Angle 1 = 145°, Angle 2 = 35°

Step-by-step explanation:

Step-by-step explanation:

In a trapezoid, the angles on the same leg are supplementary, meaning they add up to 180°. That means Angle 2 plus Angle 1 equals 180°. Therefore:

Therefore, x = 35°, Angle 2 = 35°, and Angle 1 =

To ensure our answers make sense, we verify they equal 180°:

Answer:

(no global maxima found)

Step-by-step explanation:

Find and classify the global extrema of the following function:

f(x) = 4 x^4 - 2 x^3 + x - 5

Hint: | Global extrema of f(x) can occur only at the critical points or the endpoints of the domain.

Find the critical points of f(x):

Compute the critical points of 4 x^4 - 2 x^3 + x - 5

Hint: | To find critical points, find where f'(x) is zero or where f'(x) does not exist. First, find the derivative of 4 x^4 - 2 x^3 + x - 5.

To find all critical points, first compute f'(x):

d/( dx)(4 x^4 - 2 x^3 + x - 5) = 16 x^3 - 6 x^2 + 1:

f'(x) = 16 x^3 - 6 x^2 + 1

Hint: | Find where f'(x) is zero by solving 16 x^3 - 6 x^2 + 1 = 0.

Solving 16 x^3 - 6 x^2 + 1 = 0 yields x≈-0.303504:

x = -0.303504

Hint: | Find where f'(x) = 16 x^3 - 6 x^2 + 1 does not exist.

f'(x) exists everywhere:

16 x^3 - 6 x^2 + 1 exists everywhere

Hint: | Collect results.

The only critical point of 4 x^4 - 2 x^3 + x - 5 is at x = -0.303504:

x = -0.303504

Hint: | Determine the endpoints of the domain of f(x).

The domain of 4 x^4 - 2 x^3 + x - 5 is R:

The endpoints of R are x = -∞ and ∞

Hint: | Evaluate f(x) at the critical points and at the endpoints of the domain, taking limits if necessary.

Evaluate 4 x^4 - 2 x^3 + x - 5 at x = -∞, -0.303504 and ∞:

The open endpoints of the domain are marked in gray

x | f(x)

-∞ | ∞

-0.303504 | -5.21365

∞ | ∞

Hint: | Determine the largest and smallest values that f achieves at these points.

The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:

The open endpoints of the domain are marked in gray

x | f(x) | extrema type

-∞ | ∞ | global max

-0.303504 | -5.21365 | global min

∞ | ∞ | global max

Hint: | Finally, remove the endpoints of the domain where f(x) is not defined.

Remove the points x = -∞ and ∞ from the table

These cannot be global extrema, as the value of f(x) here is never achieved:

x | f(x) | extrema type

-0.303504 | -5.21365 | global min

Hint: | Summarize the results.

f(x) = 4 x^4 - 2 x^3 + x - 5 has one global minimum:

Answer: f(x) has a global minimum at x = -0.303504

Answer:

math

Step-by-step explanation:

Answer:

$42

Step-by-step explanation:

12*3=36+6=42

Answer: Yes [tex]\angle FDE[/tex] is one possible angle name

Another name is [tex]\angle EDF[/tex]

When it comes to naming an angle this way, all we need to worry about is the vertex point. This is where the angle hinges (think of a door or a pair of scissors). In this case, the hinge or vertex point is at point D. The vertex is always the middle letter of any three-letter sequence. The order of the other two points does not matter.

This is why saying "angle FDE" is the same as "angle EDF".

Answer: (3,4)

Step-by-step explanation:

To find the midpoint, you want to use the formula [tex]m=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )[/tex]. Since we are given the two points, we can plug them in and solve.

[tex]m=(\frac{-1+7}{2} ,\frac{9+(-1)}{2} )[/tex]            [add numerator]

[tex]m=(\frac{6}{2} ,\frac{8}{2} )[/tex]                          [divide]

[tex]m=(3,4)[/tex]

Now, we know that the midpoint is (3,4).

Answer:

2

Step-by-step explanation:

The rate of change in function f(x) from x = a to x = b is (f(b) - f(a))/(b - a).

rate of change = (7 - 3)/(2 - 0) = 4/2 = 2

Answer:

rate of change = 2 unit rise per 1 unit run

Step-by-step explanation:

The rate of change of two points on a graph is represented by the slope of a line connecting the two points.

here we are given the coordinates of the two points, hence we can simply apply the slope formula for a line given two points (see attached)

for points (0,3) and (2,7)

x₁ = 0, y₁ = 3, x₂ = 2, y₂ = 7

substituting these into the formula

rate of change

= slope, m

= (y₂-y₁) / (x₂-x₁)

= (7 - 3) / (2 - 0)

= 4 / 2

= 2

Answer:

Note that

0.16666...is equivalent to 1/6

Step-by-step explanation:

We can use the sum of fractions to write out the decimal:

For this particular question, we can see that

0.16666...is the fraction 1/6, therefore

the given decimal

2.16666...=2+1/6=13/6

Answer:

1) 5

2) 5.30..... etc

3) 4.65

4) 5

5) 5 this is the answer to all your questions

Answer:

The first, fourth, and fifth one.

Answer:

-26

Step-by-step explanation:

the answer is -26 hopefully this helps

Answer:

-88

Step-by-step explanation:

-a² + 4ab - b²

Substitute the variables with the numbers given.

-2² + 4(2×-6) - -6²

-2² + 4(-12) - -6²

-4 + 4(-12) - 36

-4 + -48 - 36

-52 - 36 =

-88

(im starting 8th grade tommorow and im doing this cause im bored and i should practice xD)

Answer:

18

Step-by-step explanation:

9+9=18 bam solved it

Answer:

x=6

Step-by-step explanation:

A midpoint is the middle point of a line segment, therefore it is equal distances from both ends of the segment.

This means that PQ and QR have the same length. So all we have to do is set each value equal to each other, and then solve for X.

[tex]3x+14=7x-10\\3x+24=7x\\24-4x\\x=6[/tex]

Answer:

x=-0.4

Step-by-step explanation:

ok you have to visualize this line

P                         Q                           R

O---------------------O-----------------------O

        3x+14                    7x-10

so to make the equation of PR you would add PQ and QR together.

3x+14+7x-10

add your like terms

10x+4

solve for x

10x+4=0

subtract 4 from each side

10x=-4

divide both sides by 10

x=-2/5       fraction

x=-0.4       decimal

Answer:

yes

Step-by-step explanation:

yes

Answer:

[tex]3m-3[/tex]

Step-by-step explanation:

So we have the expression:

[tex]-(2m+3)+5m\\[/tex]

Distribute the negative:

[tex]=-2m-3+5m[/tex]

Combine like terms:

[tex]=3m-3[/tex]

And we're done!

Answer:

AC = 23

Step-by-step explanation:

Assuming A, B, and C are on a line with B in the middle...

We know that AB + BC = AC. Travelling from A to C is the same as travelling from A to B, then B to C, as B is on the way between A and C.

Knowing this, we can set up this equation and add the 2 numbers we know:

AC = AB + BC

AC = 11 + 12

AC = 23

Answer:

Step-by-step explanation:

I'm just going to go out on a limb here and assume that those are a set of poorly made parenthesis. This, then, would be your equation:

[tex]x+\frac{x}{7}+\frac{1}{11}(x+\frac{x}{7})=60[/tex]

The first thing to do is distribute through the parenthesis to get:

[tex]x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60[/tex]

Next is to get rid of the denominators by multiplying by the LCM of 77:

[tex]77(x+\frac{x}{7}+\frac{x}{11}+\frac{x}{77}=60)[/tex] which gives you:

77x + 11x + 7x + x = 4620 and

96x = 4620 so

[tex]x=\frac{385}{8}[/tex]

Answer:

The domain of g(x) is -3 to infinity

Step-by-step explanation:

Given

[tex]g(x) = \sqrt{x + 3}[/tex]

Required

Determine the domain of g(x)

We start by expressing the content of the square root in the following form:

[tex]x + 3 \geq 0[/tex]

Subtract 3 from both sides

[tex]x + 3 -3 \geq 0 - 3[/tex]

[tex]x \geq 0 - 3[/tex]

[tex]x \geq - 3[/tex]

This can be expressed using interval notation as follows:

[tex]\{x: -3, infiniti\}[/tex]

Hence, the domain of g(x) is -3 to infinity

Answer:

All real values of x such that x ≥ −3

Step-by-step explanation:

Answer:

p(x)=x2 - 3x + 8

p(4) =(4)2 - 3(4) + 8

= 16 - 12 + 8

= 4+8

= 12

p(-2)= (-2)2 - 3(-2) + 8

= 4+6+8

=18

Answer:

100, 110, 105

Step-by-step explanation:

Answer:

100,105,110

Step-by-step explanation:

Get the two equations for the lines into slope-intercept form. ...

Set the two equations for y equal to each other.

Solve for x. ...

Use this x-coordinate and plug it into either of the original equations for the lines and solve for y.

Answer: [tex]b=13/8[/tex]

Cross multiply

[tex](13)*(1)=8*b\\13=8b[/tex]

Flip the equation

[tex]8b=13[/tex]

Divide both sides by 8

[tex]8b/8=13/8\\b=13/8[/tex]

Answer: 4 shirts x 3 pairs of pants x 4 ties = 4 x 3 x 4=48

so there are 48 possibilities (option 3)

Answer: not sure if that is a b but i beleive it is so

bh+hr=25

move all terms to the left side and set equal to 0. then set each factor equal to zero.

h= [tex]\frac{25}{b+r}[/tex]

isolate the variable by dividing each side by factors that dont

contain the variable.

r=[tex]\frac{25}{h}-b[/tex]

x=[tex]\frac{r-h}{y}[/tex]

isolate the variable by dividing each side by factors that dont

contain the variable.

h=-xy+r

solve for r by simplifieng both sides of the equation, then isolating the variable.

r=xy+h

Answer:

1A. h = 25/(b + r)

1B. r = 25/h - b

2A. h = r - xy

2B. r = xy + h

Step-by-step explanation:

1. bh + hr = 25

A. h(b + r) = 25

h = 25/(b + r)

B. h(b + r) = 25

b + r = 25/h

r = 25/h - b

2. x = (r - h)/y

A. xy = r - h

h + xy = r

h = r - xy

B. xy = r - h

r = xy + h