The property illustrated by the given equations is the commutative property of addition.
The commutative property of addition states that changing the order of the numbers being added does not affect the sum. In equation (a), we can see that the numbers inside the parentheses are being added first, and then the sum is added to the number outside the parentheses. Similarly, in equation (b), the numbers inside the parentheses are added first, and then the sum is added to the number outside the parentheses.
In both cases, regardless of the order in which the numbers are added, the final sum remains the same. This demonstrates the commutative property of addition. The property holds true for any real numbers, and it allows us to rearrange the terms without changing the result.
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The circle radius is 12 cm. Then the circle content is
PLEASE HEEEELP
use a truth table to determine whether the symbolic form of the argument is valid or invalid ~p -> q
The symbolic argument ~p -> q is valid.
To determine the validity of the argument ~p -> q using a truth table, we need to consider all possible combinations of truth values for p and q and evaluate the truth value of the implication ~p -> q.
The symbolic form of the argument is ~p -> q, which can also be written as ¬p → q.
A truth table for this argument would have columns for p, ~p, q, and ~p -> q.
Let's construct the truth table:
| p | ~p | q | ~p -> q |
| True | False | True | True |
| True | False | False | False |
| False | True | True | True |
| False | True | False | True |
In the truth table, we consider all possible combinations of true (T) and false (F) for p and q. For ~p, we negate the value of p.
For the implication ~p -> q, it is true (T) if either ~p is false (F) or q is true (T). In all other cases, it is false (F).
Looking at the truth table, we can see that in all rows where ~p -> q is true (T), the corresponding conclusion q is true (T). Therefore, the argument ~p -> q is valid because whenever ~p is true (F), the conclusion q is also true (T).
In summary, the symbolic argument ~p -> q is valid.
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Gabriel has these cans of soup in his kitchen cabinet.
• 2 cans of tomato soup
• 3 cans of chicken soup
• 2 cans of cheese soup
• 2 cans of potato soup
• 1 can of beef soup
Gabriel will randomly choose one can of soup. Then he will put it back and randomly choose another can of soup. What is the probability that he will choose a can of tomato soup and then a can of cheese soup?
Answer:
the answer is the cheese soup has a good change of being picked but not as good as the chicken soup there would so 3:2 to 2. so if they picked the cheese soup the first time then there is not a good change of the cheese souo to be picked again i hope that helps if not let me know
solve the system using elimination. 4x+5y=2 -2x+2y=8 ( ? , ? )
Answer:
(-2,2)
Step-by-step explanation:
Hi,
4x + 5y = 2
-2x + 2y = 8
To solve using elimination, we can multiply the second equation by 2 to try and get rid of the x. So...
4x + 5y = 2
-4x + 4y = 16
Now, add...
9y = 18
Divide by 9...
y = 2
Now, let's solve for x...
4x + 5(2) = 2
4x + 10 = 2
4x = -8
x = -2
Your solution is, (-2,2)
I hope this helps :)
if -3x + 7 = -8 what does X equal
Answer:
5
Step-by-step explanation:
3x-7=8
x=5
Find the volume of the cylinder. Round your answer to the
nearest tenth.
WILL GIVE BRAINLY
Answer:
7 cm
Step-by-step explanation:
10 mm = 1cm
All you need to do is add 10mm + 6cm.
10mm = 1cm
So, 6cm + 1cm.
Therefore, it equals to 7cm.
Answer:
471.2 cm cubed
Step-by-step explanation:
The formula for the volume of a cylinder is:
π*radius squared*height
The diameter is the distance across the circle.
10 mm is the same as 1 cm
The radius is half of the diameter.
1/2=.5
Radius=.5 cm
Height=6 cm
Plug the numbers in.
.5 squared is .25
π*(.25)(6 cm)
Volume=4.71
Rounded to the nearest tenth:
Volume=4.7 cm cubed
Solve the system of differential equations x1' = – 5x1 + 0x2, X2' =– 16x1 + 3x2 x1(0) = 1, X2(0) = 5 then x1(t) = ? , x2(t) = ?
The solution of the differential equation is 1 = c₁v₁ + c₂v₂ and 5 = c₁v₁ + c₂v₂
We are given a system of two differential equations:
x₁' = – 5x₁ + 0x₂
x₂' = – 16x₁ + 3x₂
To solve this system, we can use several methods, such as substitution or matrix methods. In this explanation, we will use the substitution method.
We can write the given system of differential equations in matrix form as follows:
X' = AX
where X is the column vector [x₁, x₂], X' is the derivative of X, and A is the coefficient matrix:
A = [–5 0]
[–16 3]
To find the eigenvalues λ and eigenvectors v, we solve the characteristic equation:
|A - λI| = 0
where I is the identity matrix. Solving this equation will give us the eigenvalues and eigenvectors.
A - λI = [–5-λ 0]
[–16 3-λ]
Setting the determinant of A - λI to zero, we get:
(–5-λ)(3-λ) - (0)(–16) = 0
Simplifying, we have:
(λ + 5)(λ - 3) = 0
Solving this equation, we find two eigenvalues:
λ₁ = -5
λ₂ = 3
For each eigenvalue, we need to find its corresponding eigenvector. For λ₁ = -5, we solve the system of equations:
(A - (-5)I)v₁ = 0
Substituting the values of A and λ₁, we have:
[0 0] v₁ = 0
[–16 8]
Simplifying the equation, we get:
0v₁ + 0v₂ = 0
-16v₁ + 8v₂ = 0
From the first equation, we can see that v₁ can take any value. Let's choose v₁ = 1 for simplicity. Substituting this value into the second equation, we get:
-16(1) + 8v₂ = 0
-16 + 8v₂ = 0
8v₂ = 16
v₂ = 2
So, for λ₁ = -5, the corresponding eigenvector is v₁ = [1, 2].
Similarly, for λ₂ = 3, we solve the system of equations:
(A - 3I)v₂ = 0
Substituting the values of A and λ₂, we have:
[-8 0] v₂ = 0
[–16 0]
Simplifying the equation, we get:
-8v₁ + 0v₂ = 0
-16v₁ + 0v₂ = 0
From the first equation, we can see that v₁ can take any value. Let's choose v₁ = 1 for simplicity. Substituting this value into the second equation, we get:
-16(1) + 0v₂ = 0
-16 = 0
This equation has no solution. However, this means that v₂ can take any value. Let's choose v₂ = 1 for simplicity.
So, for λ₂ = 3, the corresponding eigenvector is v₂ = [1, 1].
The general solution of the system of differential equations can be expressed as:
X(t) = c₁e(λ₁t)v₁ + c₂e(λ₂t)v₂
where c₁ and c₂ are constants that need to be determined.
We are given the initial conditions x₁(0) = 1 and x₂(0) = 5. Substituting these values into the general solution, we get two equations:
x₁(0) = c₁e(λ₁(0))v₁ + c₂e(λ₂(0))v₂
x₂(0) = c₁e(λ₁(0))v₁ + c₂e(λ₂(0))v₂
Simplifying, we have:
1 = c₁v₁ + c₂v₂
5 = c₁v₁ + c₂v₂
Solving this system of equations, we can find the values of c₁ and c₂.
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Find the square root of -i
that graphs in the second quadrant.
The square root of -i that graphs in the second quadrant,
⇒ z = (1/2)((√(2))(cos(135°) + i sin(135°))
To find the square root of -i,
we can start by writing -i in polar form.
⇒ i = 1(cos(270°) + i sin(270°))
Now, we can find the square root by taking the square root of the magnitude and dividing the angle by 2.
⇒ √(-i) = √(1) [cos(270°/2) + i sin(270°/2)]
⇒ [tex](1)^{(1/2)}[/tex] [cos(135°) + i sin(135°)]
⇒ (1/2)(√(2)) [cos(135°) + i sin(135°)]
⇒ (1/2)(√(2)) (-√(2)/2 + i(√(2))/2)
⇒ -1/2 + ((√t(2)/2)i
Therefore,
The square root of -i that graphs in the second quadrant in the form of
z = r(cosθ + i sinθ)
Hence,
z = (1/2)((√(2))(cos(135°) + i sin(135°)).
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A fifth-grade class is earning points for a pizza party by reading books.
For every book they read, they earn 6 points. Complete the table, where b represents the number of books read. How many points will they earn if b = 24?
Answer:
144
Step-by-step explanation:
24 books at 6 points each would be 24 x 6 which equals 144
Answer:
They'll have 144 points if they read 24 books.
Step-by-step explanation:
6 x 24 = 144
The following data sets are the math and science test scores, out of 100, for a group of twelve seventh grade students
The interquartile range (IQR) of both the data sets is 8. Create a box plot for each data set Which statement correctly compares
the two data sets?
A. The majority of the math scores are greater than the median of the science scores
B. The majority of the science scores are greater than the median of the math scores
C. The medians of both data sets are equal
D. There is not enough information given to compare the data and medians of the math and science scores
Answer:
The answer and work are in the pdf
Step-by-step explanation:
Answer: A. The majority of the math scores are greater than the median of the science scores
Step-by-step explanation:
I took the test!
A student is required to solve the initial-value problem as follows:
y ' + 1x+3 y= x2 y-1 , y0= -4.
It is assumed here that x is positive. Then he/she has to find the numerical value of y 2.0, round it off to THREE figures and present the result. A student solved the problem and found that y 2.0 rounded-off to three figures was as follows :
Main Answer: The numerical value of y(2.0) rounded off to three figures is 1.279.
Supporting Explanation:
The student solved the initial-value problem and found that y(2.0) = 1.27977. The question asks to round off the value to three figures. Therefore, we have to keep only the first three digits after the decimal point, which are 279. The next digit after 9 is 7, which means we have to round up the last digit. Thus, the rounded off value of y(2.0) is 1.279.
The initial-value problem is a differential equation that has an initial condition given for a specific value of the independent variable. In this case, the initial condition is y(1) = 2. The solution of the initial-value problem gives the value of y for other values of x. Here, we are required to find the value of y for x = 2.0.
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The town of KnowWearSpatial, U.S.A. operates a rubbish waste disposal facility that is overloaded if its 4712 households discard waste with weights having a mean that exceeds 27.22 lb/wk. For many different weeks, it is found that the samples of 4712 households have weights that are normally distributed with a mean of 26.97 lb and a standard deviation of 12.29 lb. What is the proportion of weeks in which the waste disposal facility is overloaded? P(M> 27.22) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z- scores or Z-scores rounded to 3 decimal places are accepted. Is this an acceptable level, or should action be taken to correct a problem of an overloaded system? O No, this is not an acceptable level because it is not unusual for the system to be overloaded. O Yes, this is an acceptable level because it is unusual for the system to be overloaded.
The proportion of weeks in which the waste disposal facility is overloaded is approximately 0.4920. No, this is not an acceptable level because it is not unusual for the system to be overloaded.
To solve this problem, we need to find the proportion of weeks in which the waste disposal facility is overloaded, given that the weights of the samples of 4712 households are normally distributed with a mean of 26.97 lb and a standard deviation of 12.29 lb.
Let's denote X as the random variable representing the mean weight of the samples of 4712 households in a week. We want to find P(X > 27.22).
To calculate this probability, we can use the standard normal distribution. First, we need to standardize the random variable X using the z-score formula:
z = (X - μ) / σ
where μ is the mean and σ is the standard deviation.
Substituting the given values:
z = (27.22 - 26.97) / 12.29
z ≈ 0.0203
Next, we can use a standard normal distribution table or a calculator to find the proportion of weeks in which the waste disposal facility is overloaded:
P(X > 27.22) = P(Z > 0.0203)
Looking up the z-score 0.0203 in the standard normal distribution table, we find that the corresponding proportion is approximately 0.4920.
Therefore, the proportion of weeks in which the waste disposal facility is overloaded is approximately 0.4920. This means that it is not unusual for the system to be overloaded.
So the correct answer is:
No, this is not an acceptable level because it is not unusual for the system to be overloaded.
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ABCD is a quadrilateral that has a four right angle What is the most accurate way to classify this quadrilateral
Answer:
A rectangle
Step-by-step explanation:
A square can be a rectangle but a rectangle can't always be a square.
Nationwide 13.7% of employed wage and salary workers are union members. At random sample of 200 local wage and salary workers showed that 30 belonged to a union. At 0.01 level of significance, is there sufficient evidence to conclude that the proportion of union members differs from 13.7%?
There is not sufficient evidence to conclude that the proportion of union members differs from 13.7% at the 0.01 level of significance.
To determine if there is sufficient evidence to conclude that the proportion of union members differs from 13.7%, we can perform a hypothesis test using the given sample data.
Let's define the hypotheses:
Null Hypothesis (H0): The proportion of union members is equal to 13.7%.
Alternative Hypothesis (H1): The proportion of union members differs from 13.7%.
We can set up the test using the z-test for proportions. The test statistic is calculated as:
z = (p(cap) - p) / √(p × (1 - p) / n)
where p(cap) is the sample proportion, p is the hypothesized proportion, and n is the sample size.
Given that the sample size is 200 and 30 workers belonged to a union, the sample proportion is p(cap) = 30/200 = 0.15.
The hypothesized proportion is p = 0.137.
Let's calculate the test statistic:
z = (0.15 - 0.137) / √(0.137 × (1 - 0.137) / 200)
z ≈ 1.073
To determine if there is sufficient evidence to conclude that the proportion differs from 13.7%, we compare the test statistic to the critical value.
At a significance level of 0.01, the critical value for a two-tailed test is approximately ±2.576 (obtained from a standard normal distribution table).
Since |1.073| < 2.576, the test statistic does not fall in the rejection region. Therefore, we fail to reject the null hypothesis.
Conclusion: Based on the given sample data, there is not sufficient evidence to conclude that the proportion of union members differs from 13.7% at the 0.01 level of significance.
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I need help figuring out this question
Answer:
no picture
Step-by-step explanation:
El largo total de una correa transportadora debe ser de 4,5 km para poder llevar el mineral hasta la planta- Si la correa mide 3200 m ¿Cuántos Km faltan para completar el largo requerido
Answer:
Distancia restante = 1,3 kilómetroslp
Step-by-step explanation:
Dados los siguientes datos;
Distancia total = 4,5 km
Distancia recorrida = 3200 metros a kilómetros = 3200/1000 = 3,2 km
Para encontrar la distancia restante para cubrir la longitud requerida;
Distancia total = distancia recorrida + distancia a la izquierda
4.5 = 3.2 + distancia a la izquierda
Distancia a la izquierda = 4.5 - 3.2 Distancia restante = 1,3 kilómetros
The car consumes 6 liters per 100 km. How many kilometers can you drive with this car if the tank has 42 liters?
Answer:
If 100km enables consumption of 6lts
what about 42lts
42/6 multiply by 100km
42/6*100= 700km
The car will consume 42lts in 700 km.
Thank you.
Step-by-step explanation:
Rewrite the decimals as
fractions and percents
.08
Answer:
8/10 or 4/5 as a fraction. the percentage is 80%
Step-by-step explanation:
Calculate the distance between the points K = (1, -1) and P=(9.-6) in the coordinate plane.
Give an exact answer (not a decimal approximation)
Answer:
√89
Step-by-step explanation:
√(x2 - x1)² + (y2 - y1)²
√(9 - 1)² + [-6 - (-1)]²
√(8)² + (-5)²
√64 + 25
√89
HELP ASAP PLEASE!!!!
Answer:
Q' = (1, -5)
R' = (3, 1)
S' = (0, 0)
T' = (-2, -3)
Step-by-step explanation:
Look at the numbers of the current vertices and then change the signs of the y-coordinates around. For example, the original Q-coordinate was (1,5) so I changed the 5 to a -5 to reflect across the axis. Changing the y-coordinate sign reflects across the x-axis, while changing the x-coordinate sign reflects across the y-axis.
I need somebody to choose a random amount of time in either minutes or hours. Doesn't matter how long. Thanks!
Answer:
69 minutes? i don't know haha
Step-by-step explanation:
verify that the following function is a cumulative distribution function. f(x)={0x<10.51≤x<313≤x round your answers to 1 decimal place (e.g. 98.7).
The probability distribution of X is as follows:P(X = x) = 0 for x < 1P(X = x) = 0 for 1 ≤ x < 10.5P(X = x) = 1 for 10.5 ≤ x < 31P(X = x) = 0 for x ≥ 31.
Given function: f(x)={0x<10.51≤x<313≤xTo verify that the given function is a cumulative distribution function, we have to check the following conditions:1. f(x) is non-negative for all x.2. f(x) is continuous from the right for all x.3. f(x) is a non-decreasing function for all x.4. lim{x → -∞} f(x) = 0 and lim{x → ∞} f(x) = 1. Now, let's verify these conditions one by one.1. f(x) is non-negative for all x. This condition is satisfied, as the given function f(x) is defined only for x ≥ 1, and is non-negative for all x in this domain. Therefore, f(x) is non-negative for all x.2. f(x) is continuous from the right for all x. This condition is also satisfied, as the given function f(x) is defined piecewise as a continuous function for all x. Therefore, f(x) is continuous from the right for all x.3. f(x) is a non-decreasing function for all x. This condition is satisfied, as the given function f(x) is non-decreasing for all x in its domain.4. lim{x → -∞} f(x) = 0 and lim{x → ∞} f(x) = 1.
Using the definition of f(x) for x < 10, we have f(x) = 0 for x < 10. Therefore, lim{x → -∞} f(x) = 0. Using the definition of f(x) for x ≥ 31, we have f(x) = 1 for x ≥ 31. Therefore, lim{x → ∞} f(x) = 1. Hence, all four conditions are satisfied. Therefore, the given function is a cumulative distribution function. To find the probabilities of the intervals, we use the formula: P(a ≤ X ≤ b) = F(b) - F(a)where P(a ≤ X ≤ b) is the probability that X lies between a and b, and F(x) is the cumulative distribution function of X. Furthermore, the probability of the interval (a, b] is: P(a < X ≤ b) = F(b) - F(a)Therefore, the probabilities of the intervals are: P(1 < X ≤ 10.5) = F(10.5) - F(1) = 0 - 0 = 0P(10.5 < X ≤ 31) = F(31) - F(10.5) = 1 - 0 = 1P(X > 31) = F(∞) - F(31) = 1 - 1 = 0Therefore, we have: P(1 < X ≤ 10.5) = 0P(10.5 < X ≤ 31) = 1P(X > 31) = 0
Hence, the probability distribution of X is as follows: P(X = x) = 0 for x < 1P(X = x) = 0 for 1 ≤ x < 10.5P(X = x) = 1 for 10.5 ≤ x < 31P(X = x) = 0 for x ≥ 31. Therefore, the given function is a cumulative distribution function, and the probability distribution of X is as above.
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Convert:
35 pounds, 24 ounces=_ ounces
Answer:
Step-by-step explanation:
1 pound = 16 ounces
35 pounds = 560 ounces + 24 ounce = 584ounces
35 pounds,24ounces = 16 ounces
8. Jack is going to paint the ceiling and four
walls of a room that is 10 feet wide, 12 feet
long, and 10 feet from floor to ceiling. How
many square feet will he paint?
(A) 120 square feet
(B) 560 square feet
(C) 680 square feet
(D) 1,200 square feet
Answer:
D
Step-by-step explanation:
simplify (3x 2y)2 using the square of a binomial formula. question 18 options: a) 9x2 4y2 b) 9x2 5xy 4y2 c) 9x2 6xy 4y2 d) 9x2 12xy 4y2
The correct answer is option d) 9x² + 12xy + 4y². To simplify the expression (3x + 2y)² using the square of a binomial formula, we need to apply the formula (a + b)² = a² + 2ab + b². In this case, a = 3x and b = 2y.
Using the formula, we have:
(3x + 2y)² = (3x)² + 2(3x)(2y) + (2y)²
= 9x² + 12xy + 4y²
So the simplified form of (3x + 2y)² is 9x² + 12xy + 4y².
Now let's analyze the given options:
a) 9x² + 4y²: This option is incorrect because it is missing the term 12xy.
b) 9x² + 5xy + 4y²: This option is also incorrect because it contains an additional term, 5xy, which is not present in the simplified expression.
c) 9x² + 6xy + 4y²: This option is incorrect because it also contains an additional term, 6xy, which is not present in the simplified expression.
d) 9x² + 12xy + 4y²: This option is correct because it matches the simplified form we obtained using the square of a binomial formula.
Therefore, the correct answer is option d) 9x² + 12xy + 4y².
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A rabbit is carrying a dominant allele for brown hair (B) and a recessive allele for white hair (b). What is the rabbit's phenotype?
Answer:
B
Step-by-step explanation:
Its dominant because its brown hair.
Does anyone know how to do 3 & 4
Answer:
2.True
3. HGK
4. 17°
hope it helps
identifying the coefficients and constant of a quadratic function consider the quadratic function f(x) = x2 – 5x 6. what are the values of the coefficients and constant in the function? a = b = c =
For the quadratic function f(x) = x^2 - 5x + 6, the values of the coefficients and constant are:
a = 1
b = -5
c = 6.
To identify the coefficients and constant in the quadratic function f(x) = x^2 - 5x + 6, let's examine the standard form of a quadratic equation:
f(x) = ax^2 + bx + c
Comparing this with the given quadratic function, we can determine the values of the coefficients and constant:
a = 1 (coefficient of x^2 term)
b = -5 (coefficient of x term)
c = 6 (constant term)
Therefore, for the quadratic function f(x) = x^2 - 5x + 6, the values of the coefficients and constant are:
a = 1
b = -5
c = 6.
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Please help me.
Please simplify it and group it in like terms.
3a+6+2a-4+a-2=
Answer:
6a
Step-by-step explanation:
Answer:
6a
Step-by-step explanation:
3a+2a+a= 6a
6-4-2=0
6a+0=6a
A thin wire is bent into the shape of a semicircle
x^2 + y62 = 9, x ≥ 0.
If the linear density is a constant k, find the mass and center of mass of the wire.
The mass of the wire is given by the integral [tex]\int[0, R] k\sqrt{(1 + (-x/\sqrt{(9 - x^2}))^2}[/tex] dx, and the centre of mass is given by [tex]\int[0, R] x(k\sqrt{1 + (-x/\sqrt{9 - x^2})^2}[/tex] dx divided by the mass.
Find the mass and centre of mass of the wire?
To find the mass and center of mass of the wire, we need to integrate the linear density function along the curve of the wire.
The linear density function is given as a constant k, which means the mass per unit length is constant.
To find the mass of the wire, we integrate the linear density function over the length of the wire. The length of the semicircle can be found using the arc length formula:
[tex]s = \int[0, R] \sqrt{(1 + (dy/dx)^2} dx[/tex]
In this case, the equation of the semicircle is x² + y² = 9, so y = √(9 - x²). Taking the derivative with respect to x, we have dy/dx = -x/√(9 - x²).
Substituting this into the arc length formula, we have:
s = ∫[0, R] √(1 + (-x/√(9 - x²))²) dx
To find the centre of mass, we need to find the weighted average of the x-coordinate of the wire. The weight function is the linear density function, which is a constant k.
Therefore, the mass of the wire is given by the integral [tex]\int[0, R] k\sqrt{(1 + (-x/\sqrt{(9 - x^2}))^2}[/tex] dx, and the center of mass is given by [tex]\int[0, R] x(k\sqrt{1 + (-x/\sqrt{9 - x^2})^2}[/tex] dx divided by the mass.
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