Answer:
Vf = 69.56 cm/s
Explanation:
In order to find the final speed of the ramp, we will use the equations of motion. First we use second equation of motion to find out the acceleration of marble:
s = Vi t + (1/2)at²
where,
s = distance traveled = 160 cm
Vi = Initial Speed = 0 cm/s (since, marble starts from rest)
t = time interval = 4.6 s
a = acceleration = ?
Therefore,
160 cm = (0 cm/s)(4.6 s) + (1/2)(a)(4.6 s)²
a = (320 cm)/(4.6 s)²
a = 15.12 cm/s²
Now, we use first equation of motion:
Vf = Vi + at
Vf = 0 cm/s + (15.12 cm/s²)(4.6 s)
Vf = 69.56 cm/s
A beam of light has a wavelength of 620 nm in vacuum.
a. What is the speed of this light in a liquid whose index of refraction at this wavelength is 1.56? (Use 3.00×108 m/s for the speed of light in a vacuum.)
b. What is the wavelength of these waves in the liquid?
Explanation:
It is given that,
Wavelength of a beam of light in vacuum, [tex]\lambda_o=620\ nm[/tex]
(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.
We know that,
Refractive index,
[tex]n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s[/tex]
(b) The wavelength of light in material,
[tex]\lambda=\dfrac{\lambda_o}{n}[/tex]
Let [tex]\lambda_1[/tex] is the wavelength of these waves in the liquid. So,
[tex]\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m[/tex]
Hence, this is the required solution.
Given the displacement vector D = (2î − 6ĵ) m, find the displacement vector (in m) R so that D + R = −5Dĵ.
Answer:
R = (-2î − 6ĵ + 10k^)m
Explanation:
We are given;
D = (2î − 6ĵ)
Now, we want to find R such that,
D + R = −5Dĵ
Plugging in (2î − 6ĵ) for D in the R equation gives;
(2î − 6ĵ) + R = -5(2î − 6ĵ)j
(2î − 6ĵ) + R = -10k + 0
This is because in vector multiplication, i × j = k and j × j = 0
Thus;
(2î − 6ĵ) + R = -10k
Making R the subject gives;
R = -2î − 6ĵ + 10k^
Thus, the displacement vector R is;
R = (-2î − 6ĵ + 10k^)m
A girl is standing in front of a magic mirror. She finds the image of her head bigger the middle portion of her body of the same size and that of the legs smaller. The order of combinations for the magic mirror from the top is
An object travels 7.5 m/s toward the west . Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s. What is its mass?
Answer:
m = 2218.67 kg
Explanation:
It is given that,
Initial velocity, u = 7.5 m/s
Final speed of an object, v = 0 (at rest)
Force, F = 5.2 kN
Time, t = 3.2 s
We need to find the mass of the object. Force acting on an object is given by :
F = ma
m is mass, a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg[/tex]
So, the mass of the object is 2218.67 kg
The force is always equal to the product of mass and acceleration. The mass of the object is 2218.7 Kg.
An object travels 7.5 m/s toward the west.
Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s.
Now,
The initial velocity of the object is 7.5 m/s.
The final velocity of the object is 0 m/s.
The object comes to the rest position in 3.2 seconds.
The formula for finding the acceleration of the object is mentioned below:
[tex]v=u+at\\0=7.5+a \times 3.2\\a= -2.34375\;\rm m/s^2[/tex]
The formula for finding the force is mentioned below:
[tex]F=ma\\-5.2 \times 10^3=m \times 2.34375\\m=2218.7 \ \;kg[/tex]
Hence, the mass of the object is 2218.7 Kg.
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A parking lot is going to be 60 m wide and 240 m long. what dimensions could be used for a scale model of the lot?
Answer:
it is A or 20x80 cm
Explanation: DID IT ON APEX
WOO
Olivia is rolling down a hill on a skateboard and is accelerating at 2.4 m/s2. After 3 seconds, she runs into Reid at the bottom of the hill. If her initial velocity was 1.5 m/s, what was her velocity when she hit Reid?
did you ever get the answer?
Answer:
8.7
Explanation:
A=2.4m/s2 1.5m/s + (2.4m/s2)(3s)
Vi=1.5m/s 1.5m/s + 7.2
Vf=? Vf= 8.7m/s
T=3s
How much can having a lighted candle increase the temperature inside the shelter?
A lighted candle can increase the temperature inside a shelter by a few degrees Celsius.
A lighted candle produces heat by burning fuel. The heat from the candle is transferred to the air in the shelter by conduction, convection, and radiation. Conduction is the transfer of heat through direct contact. Convection is the transfer of heat through the movement of fluids. Radiation is the transfer of heat through electromagnetic waves.
The amount of heat that is transferred to the air in the shelter depends on the size of the candle, the number of candles, and the insulation of the shelter. The larger the candle, the more heat it will produce. The more candles, the more heat will be produced. The more insulation the shelter has, the less heat will be lost to the outside. In general, a lighted candle can increase the temperature inside a shelter by a few degrees Celsius.
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QUESTIONS
An ant walks eastward for 11.1 cm, then northward for 4,4 cm and finally westward for 11.1 cm. What is the magnitude of the displacement in cm Do
not include the units in your answer.
Answer:
4.4.
Explanation:
Hello,
In this considering the attached picture, we can see that the eastward movement is represented from O to A, the northward displacement from A to B and the westward displacement from B to C, which means that the resulting displacement is marked from O to C which includes the northwards movement since eastward and westward movement are the same.
In such a way, the magnitude of the displacement is simply 4.4 cm as no other dimension is taken into account due to the return to the same initial's x-axis position.
Regards-
A wooden cube of side 5cm float in water 2.0cm of its depth below the water surface and its sides are vertical calculate the density of the wood in gcm^-3. ( Density of water= 1gcm^-3)
Answer:
The density of the wooden cube is [tex]\delta= 0.4 \, \frac{g}{cm^3}[/tex]
Explanation:
Recall that the weight of the entire piece of wood that is floating must equal the weight of the displaced water in the case we have an object under flotation.
At the same time. we have a relationship between Volume (V), Weight (w) and density [tex](\delta)[/tex] given by the formula:
[tex]w=\delta\,*\,V[/tex]
Since both weights must be the same, we can write the following equation:
[tex]w_{wood} = w_{water}\\\delta *\,(5\,\,cm)^3= (\frac{1\,g}{cm^3} )\,(2\,*5^2) cm^3\\\delta= \frac{2}{5} \, \frac{g}{cm^3} \\\delta= 0.4 \, \frac{g}{cm^3}[/tex]
which statement describes a characteristics of a question that can be answered through scientific inquiry?
Answer: it is constructed in such a way that possible answers can be tested
Explanation:
The statement that describes a characteristic of a question that can be answered through scientific inquiry is it can be answered through making observations. The correct option is B.
What is scientific inquiry?The goal of scientific inquiry is to establish answers for this phenomenon by a continuous and creative process of questioning, observing and inferring, experimentation, collecting and organising data, finding evidence, drawing conclusions, and repeating the experiment numerous times.
The following phrases define scientific inquiry:
Asking and responding to questions is the process of scientific research.Investigative work and data gathering are part of scientific inquiry.Similar procedures and techniques are used in a scientific investigation.Therefore, the correct option is B. It can be answered by making observations.
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The question is incomplete. Your most probably complete question is given below:
A. It can be answered by gathering opinions.
B. It can be answered through making observations
C. It must be asked by a person who is a working scientist.
D. It must have a simple “yes or “no” answer
The_____is the division of the atmosphere where the lapse rate decreases with altitude.
Answer:
Troposphere
Explanation:
The troposphere happens to be the lowest region amongst the atmosphere. It has a length that extends from the surface to a height of about 6–10 km. And that is the lower boundary of the stratosphere among the layers of the atmosphere
The troposphere in itself is bonded on the top by a layer of air tropopause. This layer is the one which separates the troposphere from the stratosphere, and on bottom by the surface of the Earth.
Helppppppppppppppppppppppppppp
Answer:
Car 2 is travelling in a much higher speed than Car 1.But they are travelling or meeting in the same acceleration
You are standing on a street corner with your friend. You then travel 14.0 m due west across the street and into your apartment building. You travel in the elevator 22.0 m upward to your floor, walk 12.0 m north to the door of your apartment, and then walk 6.0 m due east to your balcony that overlooks the street. Your friend is standing where you left her. how far are you from your friend?
Answer:
The answer is "26.3 m".
Explanation:
The positive value from the x-axis is to the direction east side
The negative value from the x-axis is to the direction west side
The positive value from the y-axis is to the direction upwards side
The negative value from the y-axis is to the direction down words side
The positive value from the z-axis is to the direction southside
The negative value from the z-axis is to the direction north side
If the value is i, j, and k are the unit of the given vectors, which can be defined as follows:
[tex]\hat i, \hat -i, \hat j, \hat -j, \hat k, \hat -k[/tex]
The displacements values:
[tex]\underset{d_1}{\rightarrow} = -14 \ \hat i\\\\\underset{d_2}{\rightarrow} = 22\ \hat j\\\\\underset{d_3}{\rightarrow} = -12 \ \hat k\\\\\underset{d_4}{\rightarrow} = 6 \ \hat i\\\\[/tex]
calculating the final displacement that is [tex]\underset{d_5}{\rightarrow}[/tex]:
[tex]\Rightarrow \underset{d_1}{\rightarrow}+\underset{d_2}{\rightarrow}+\underset{d_3}{\rightarrow}+\underset{d_4}{\rightarrow}+\underset{d_5}{\rightarrow} =0\\\\\Rightarrow \underset{d_5}{\rightarrow} \ \ = -(\underset{d_1}{\rightarrow}+\underset{d_2}{\rightarrow}+\underset{d_3}{\rightarrow}+\underset{d_4}{\rightarrow})[/tex]
[tex]=- (-14 \hat i+ 22 \hat j -12 \hat k+ 6 \hat i)\\\\=- (-8 \hat i+ 22 \hat j -12 \hat k)\\\\=8 \hat i- 22 \hat j +12 \hat k\\[/tex]
[tex]|\underset{d_5}{\rightarrow}|=\sqrt{8^2 +(- 22)^2 +(12)^2 }\\\\[/tex]
[tex]= \sqrt{64 + 484 +144 }\\\\= \sqrt{208 + 484}\\\\= \sqrt{692}\\\\= 26.3 \ m[/tex]
What is the difference between a molecule ard
a compound ?
A car moves in a straight line at a speed of 55.4 km/h.
How long (in seconds) will it take the car to move 1.21 km at this speed?
55.4 km => 1hr (60 min) (60×60=120 sec)
1 km => 120 ÷ 55.4
1.21 km => (120 ÷ 55.4) × 1.21
= 2.6209 sec ( 5sf )
= 2.62 sec ( 3sf )
i hope you are able to understand my solution :))
The table shows chronological events in the life of our Sun, a medium-sized star. Place the missing events into the correct rows of the table.
Hello, I don't see a table, but I am guessing that you are referring to the one I attached (below).
Answer:
So, the correct order of events sorted chronologically is:
1. A nebula located in the Milky Way galaxy begins pulling nearby hydrogen atoms in its orbit.
2. The Nebula shrinks in its volume due to gravity, becoming denser and hotter. But, it's not hot enough for nuclear fusion.
3. The temperature in the core of the Nebula reaches 14 million Kelvin.
4. Hydrogen atoms begin shedding their electrons and colliding with one another.
5. The Sun enters the main sequence stage. The energy created as a result of its radiation begins nurturing life on planet such as Earth.
6. The Sun uses up all the hydrogen in its core.
7. The Sun expands greatly and cools. It is larger and redder.
8. The Sun completely runs out of hydrogen to fuse. Its outer layers are pushed away, and a cloud of ionized gas surrounds its core.
9. The Sun is a white dwarf with a dim glow.
Hope this helps!
How do very small objects behave?
a. like particles
b. like waves
c. like both waves and particles
d. like neither waves nor particles
Answer:
A) PARTICLES
Explanation:
VERY SMALL OBJECTS ARE BEHAVE LIKE A PARTICLES.
HOPE IT HELP.....❤❤unit of speed is derived unit..why??
Answer:
[tex] \boxed{ \sf{see \: below}}[/tex]
Explanation:
The unit of speed is metre per second or m / s. It clearly depends on two fundamental units ; unit of length ( metre ) and unit of time ( second ). Hence , m/s is a derived unit.
Hope I helped!
Best regards! :D
The unit of speed is m/s. The two terms metre and second are fundamental quantities.
As,m/s is derived from these two fundamental quantities. Therefore, Unit of speed is a derived unit.
The meter was originally defined so that the period of a meter-long simple pendulum would be exactly 2.00 second. (Was your measured value close to this?) Given the relationship, T^2 alpha L (T^2 is proportional to L) what would be the length of a simple pendulum, in centimeters, with a period of exactly one second?
Explanation:
Given that,
Initial length of simple pendulum, [tex]L_1=1\ m[/tex]
Initial time period, [tex]T_1=2\ s[/tex]
We need to find the length of the simple pendulum when the period is exactly 1 second.
[tex]T_2=1\ s[/tex]
We know that the time period of simple pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{L}{g}} \\\\T\propto \sqrt{L} \\\\\dfrac{T_1}{T_2}=\dfrac{L_1}{L_2}[/tex]
Put all values and find L₂
[tex]\dfrac{T_1}{T_2}=\sqrt{\dfrac{L_1}{L_2}}\\\\L_2=\dfrac{T_2^2L_1}{T_1^2}\\\\L_2=\dfrac{1^2\times 100\ cm}{2^2\ s}\\\\L_2=25\ cm[/tex]
So, the length of the pendulum with a period of exactly one second is 25 cm.
A ball is tossed up into the air with an initial speed of 5.0. How long does it take to return to the person's hand
Answer:
Explanation:
[tex]y(t) = 5t-5t^2[/tex]
When y(t) = 0, the ball is on the hand.
[tex]0=5t-5t^2\\0=5t(1-t)\\t=0,1[/tex]
It takes 1 second.
There are several different possibilities.
==> If the 5.0 means 5 miles per hour, that's 2.24 meters per second, up.
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (2.24/9.8) = 0.229 second. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 0.457 second.
==> If the 5.0 means 5 meters per second, up . . .
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (5.0/9.8) = 0.51 second. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 1.02 second.
==> If the 5.0 means 5 km/minute, that's about 83.33 meters per second, up.
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (83.33/9.8) = 8.503 seconds. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 17.01 seconds.
==> If the 5.0 means 5 furlongs per fortnight, that's about 0.00083 meters per second, up.
The acceleration of gravity is 9.8 m/s down, so the ball stops, turns around, and starts falling in (0.00083/9.8) = 0.000085 second. Then, after is starts to fall, it takes the same amount of time to the person's hand.
Total time = 0.00017 second.
This is why all of your numbers always need their units.
If an object accelerates at 40 m/s^2 in four minutes ("careful this is in minutes),
what will be the final velocity? (assume the object started from rest) *
Change in speed = (acceleration) x (time)
4 minutes = 240 seconds
Change in speed = (40 m/s²) x (240 seconds)
Change in speed = 9,600 m/s
What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.
The driver would definitely NOT get a speeding ticket, because nobody could catch him.
Also, his car would heat up and shoot flames from atmospheric friction.
(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)
Actually, I hope there's nobody in the car. His experience wouldn't be pretty.
How do you know if a boy like you?
Answer:
They cherish you
Explanation:
Answer:
They might mess with you. If you catch them looking at you they will look away quickly.
Explanation:
How is speed shown on a distance-time graph?
as the x value at the beginning of the line
as the x value at the end of the line
as the length of the line
as the slope of the line
Answer:
Divide the change in distance by the change in time.
Explanation: Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).
To my best knowledge It's D
009 10.0 points
A typical radio wave has a period of 1.5 microsecond
Express this period in seconds.
Answer in units of s.
1.5 microseconds means . . .
-- 1.5 millionths of a second
-- 1.5 x 10⁻⁶ second
-- 0.0000015 second
The Moon's center is 3.9x10 m from Earth's center. The Moon is 1.5x10^8 km from the Sun's center. If the mass of the Moon is 7.3x10^22 kg, find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon
Explanation:
It is given that The Moon's center is 3.9x10⁸ m from Earth's center. The moon 1.5x10⁸ km from the Sun's center. We need to find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon.
The gravitational force is given by :
[tex]F=\dfrac{Gm_em_m}{r^2}[/tex]
It means [tex]F\propto \dfrac{1}{r^2}[/tex]
So,
[tex]\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}[/tex]
r₁ = 3.9x10⁸ km
r₂= 1.5x10⁸ km
So,
[tex]\dfrac{F_1}{F_2}=\dfrac{1.5\times 10^8}{3.9\times 10^8}\\\\\dfrac{F_1}{F_2}=\dfrac{5}{13}[/tex]
Hence, the ratio of the gravitational forces exerted by Earth and the Sun on the Moon is 5:13.
Which is developed during the process of technology design
Answer:
solution
Explanation:
A(n) __________ is developed during the process of technological design.
A psychologist has to obtain a medical degree to diagnose and treat people with disorders.
Please select the best answer from the choices provided
T
F
Answer:
False
Explanation:
A psychologist is a person who deals with normal and abnormal mental states, emotional, and social processes and behavior of an individual in relation to one another and to their environments.
Individuals with a master's degree in psychology can work as industrial-organizational psychologists
A psychologist is not required to obtain a medical degree to diagnose and treat people with disorders.
So, the given statement is false.
Answer:
false
Explanation:
Describe how excavations are done.
Answer:
It includes earthwork, trenching, wall shafts, tunneling and underground
Explanation:
Why do you think the temperature does not change much during a phase change? If possible, discuss your answer with your classmates and teacher.
Answer:
Explanation:
The fact is that there exists no temperature change until a phase change is complete. That is to say, during a phase change, the energy that will be supplied is used only to separate the molecules. There is no part of it is used to increase the kinetic energy of the molecules. So its temperature will not rise, not really, since the kinetic energy of the molecules remains the same. Also, it should be noted that the average kinetic energy of the molecules does not change at the moment that melting occurs, thus the temperature of the molecules does not change.
To find Earth's equatorial rotation speed, we should divide the circumference of Earth by a 24 hours (1 day). To find the rotation speed at any other latitude, you need the following fact: The radial distance from Earth's axis at any latitude is equal to the equatorial radius times the cosine of the latitude. (Hint: When using the cosine (cos) function, be sure your calculator is set to recognize angles in degree mode, not in radian or gradient mode.) The radius of Earth is 6380 kilometers. Vi = 1370 km/hr
Find the rotation speed for a person at latitude 35°N.
Answer:
The value is [tex]v = 1370 km /hr [/tex]
Explanation:
From the question we are told that
The radius of the Earth is [tex]R = 6380 \ km[/tex]
The latitude is [tex]35^o N[/tex]
Generally the Earth's equatorial rotation speed is mathematically represented as
[tex]v_e = \frac{C}{t}[/tex]
Here C is the circumference which is mathematically represented as
[tex]C = 2 * \pi * R [/tex]
=> [tex]C = 2 * 3.142 * 6380 [/tex]
=> [tex]C = 40091.92 [/tex]
t is the time which is mathematically represented as
t = 24 h
So
[tex]v_e = \frac{40091.92}{24}[/tex]
=> [tex]v_e = 1670.5 \ km/h[/tex]
Generally the rotation speed for a person at latitude 35°N. is mathematically represented as
[tex]v = v_e cos (35)[/tex]
=> [tex]v = 1368 [/tex]
=> [tex] v \approx 1370 km/hr [/tex]