a) Therefore, the 50% confidence interval for the percentage of yellow peas in the population is approximately (0.47%, 3.93%).
b) Since the confidence interval does not contain the value of 20%, we can say that the results of the experiment do not support the expectation that 20% of the peas should be yellow.
c) The 90% confidence interval for the percentage of green peas in the population is approximately (95.87%, 99.53%).
The data given in the problem is:
Sample size (n) = 443 + 10 = 453
Number of yellow peas (x) = 10
Number of green peas (n-x) = 443
Since the sample size is very large (n > 30), we can use the normal distribution to find the confidence interval.
a) To construct a 50% confidence interval for the percentage of yellow peas in the population, we use the following formula:
Lower limit = p - z(α/2)√(p(1-p)/n)
Upper limit = p + z(α/2)√(p(1-p)/n)
where: p = x/n = 10/453 = 0.022 (proportion of yellow peas in the sample)
z(α/2) = z(0.25) = 0.674 (z-value for a 50% confidence level)
Plugging in the values, we get:
Lower limit = 0.022 - 0.674√(0.022(1-0.022)/453) ≈ 0.0047
Upper limit = 0.022 + 0.674√(0.022(1-0.022)/453) ≈ 0.0393
Therefore, the 50% confidence interval for the percentage of yellow peas in the population is approximately (0.47%, 3.93%).
b) Since the confidence interval does not contain the value of 20%, we can say that the results of the experiment do not support the expectation that 20% of the peas should be yellow.
c) To construct a 90% confidence interval for the percentage of green peas in the population, we can use the same formula as before with x = 443:
Lower limit = p - z(α/2)√(p(1-p)/n)
Upper limit = p + z(α/2)√(p(1-p)/n)where:
p = x/n = 443/453 = 0.977 (proportion of green peas in the sample)
z(α/2) = z(0.05) = 1.645 (z-value for a 90% confidence level)
Plugging in the values, we get:
Lower limit = 0.977 - 1.645√(0.977(1-0.977)/453) ≈ 0.9587
Upper limit = 0.977 + 1.645√(0.977(1-0.977)/453) ≈ 0.9953
Therefore, the 90% confidence interval for the percentage of green peas in the population is approximately (95.87%, 99.53%).
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can someone help me on this question?
Answer:
diameter 33
radius 66
area 360
Hi guys this isn’t about math but it needs to be said if you get a comment answering your question telling you a link they have has the answers DO NOT PRESS IT! Those people are either sex traffickers and trying to get your IP address or trying to get your personal information. Stay safe
Step-by-step explanation:
Dang, that's crazy! Thanks for letting us know! People be warned!
Answer:
FR
Step-by-step explanation:
don’t interact just report ☝️
Kendall bought a vase that was priced at $450. In addition, he had to pay 9% sales tax. How much did he pay for the vase?
Answer:
$436
Step-by-step explanation:
What is 980x58? I am giving 10 points I am not sure if it’s fair
Answer: 56840
A bit of long multiplication
Answer:
56840
Step-by-step explanation:
Pls help I’m very confused (will mark brainliest)
Element X decays radioactively with a half life of 11 minutes. If there are 870 grams
of Element X, how long, to the nearest tenth of a minute, would it take the element to
decay to 154 grams?
y = a(.5) t/h
Answer:
27.5 minutes
Step-by-step explanation:
Using,
R/R' = 2ᵃ/ᵇ------------------ Equation 1
From the equation,
R = mass of Element X before radioactive decay, R' = mass of element X after radioactive decay, a = Time taken, b = half life.
Given: R = 870 grams, R' = 154 grams, b = 11 minutes.
Substitute these values into equation 1
870/154 = 2ᵃ/¹¹
(870/154)¹¹ = 2ᵃ
Solve for a
2ᵃ = (5.649)¹¹
2ᵃ = 187061.26
Taking the logarithm of both side,
Log2ᵃ = Log(187061.26)
⇒ a = log(187061.26)/log2
a = 8.272/0.301
a = 27.5 minutes
Simone and Leah are playing a game with dice. What is the probability Simone rolls a 6 and then Leah rolls an odd number?
Answer:
1. 1/6
2. 1/2
Step-by-step explanation:
A dice has 6 sides. So the sample space for this question =
[1,2,3,4,5,6]
1. From the sample space we can see that 6 occurs only once in a dice
So probability of a 6
= 1/6
2. Number of odds = 3 (1,3,5)
Probability Leah rolls an odd number
= Odd/total
= 3/6
= 1/2
Can someone help me with this. Will Mark brainliest.
Answer:
3.3
Step-by-step explanation:
I would just like some solving steps or the answers.
A statistical analysis of the wait (in minutes) at the checkout line of a certain supermarket yields the probability distribution in the table. What is the probability of waiting more than 5 minute
?
The probability of waiting more than 5 minutes at the checkout line of a certain supermarket is 0.35.
This can be calculated by adding the probabilities of waiting 6 minutes (0.10) and 7 minutes (0.25).
The probability distribution table shows that the probability of waiting 0 minutes is 0.50, the probability of waiting 1 minute is 0.20, the probability of waiting 2 minutes is 0.10, and the probability of waiting 3 minutes is 0.05. The probability of waiting more than 5 minutes is the sum of the probabilities of waiting 6 minutes, 7 minutes, and so on. The probability of waiting 6 minutes is 0.10, and the probability of waiting 7 minutes is 0.25. Therefore, the probability of waiting more than 5 minutes is 0.10 + 0.25 = 0.35.
In other words, there is a 35% chance that a customer will wait more than 5 minutes at the checkout line of this supermarket.
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suppose 60% of the banks in switzerland are private organizations. if a sample of 469 banks is selected, what is the probability that the sample proportion of private banks will be greater than 65% ? round your answer to four decimal places.
The probability that the sample proportion of private banks will be greater than 65% is 0.1548.
Given that 60% of banks in Switzerland are private organizations.
If a sample of 469 banks is selected, we need to find the probability that the sample proportion of private banks will be greater than 65%.
Let p be the proportion of private banks in a sample of 469 banks.
Then
q = 1 - p
= 1 - 0.6
= 0.4 (as the percentage of private banks is given to be 60%)
Sample size, n = 469
We are to find the probability that the sample proportion of private banks will be greater than 65%.
That is, we need to find P(p > 0.65).
We use the normal distribution for finding probabilities associated with proportions.
We can use the formula as follows:
z = (p - P) / √[PQ/n],
where P is the population proportion (given as 0.6),
Q = 1 - P
= 0.4, and
n = 469
Putting all the given values in the above formula, we get;
z = (0.65 - 0.6) / √[0.6 × 0.4 / 469]
z = 1.0182
P(p > 0.65) = P(z > 1.0182)
Using the standard normal table, we get; P(z > 1.0182) = 0.1548
Therefore, the probability that the sample proportion of private banks will be greater than 65% is 0.1548 (rounded to four decimal places).
Hence, the answer is 0.1548.
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Find the area of the shaded region. Use the pin button on the calculator. Round to the nearest whole number. 14 70°
Answer:
The area is approximately [tex]588cm^2[/tex]
Step-by-step explanation:
Given
See attachment for figure
Required
The area of the shaded region
The shaded region is as follows:
A major segmentA triangleFirst, calculate the area of the major segment using:
[tex]Area = \frac{\theta}{360} * \pi r^2[/tex]
Where
[tex]r = 14[/tex]
[tex]\theta = 360 - 70 =290[/tex]
So, we have:
[tex]A_1 = \frac{290}{360} * 3.14 * 14^2[/tex]
[tex]A_1 = 495.7711[/tex]
Next, the area of the triangle using:
[tex]Area = \frac{1}{2}ab \sin C[/tex]
Where
[tex]a=b=r = 14[/tex]
[tex]C = 70^\circ[/tex]
So, we have:
[tex]A_2 = \frac{1}{2} * 14 * 14 * sin(70)[/tex]
[tex]A_2 = 92.0899[/tex]
So, the area of the shaded region is:
[tex]Area = A_1 + A_2[/tex]
[tex]Area = 495.7711 + 92.0899[/tex]
[tex]Area = 587.8610[/tex]
[tex]Area \approx 588[/tex]
how do you solve this??
Answer:
4x+50=90 being complementary
4x=90-50
x=40/4=10
value of x=10°
Answer: 10
Step-by-step explanation:
50-90= 40
40/4 = 10
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Answer:
A
I’m pretty sure it’s A
Answer:
A, sure
mark me as brainliest plz
5 cups of coffee and 2 bottles of water cost $12 4 cups of coffee and 7 bottles of water cost $15
help plss
Answer:
one cup of coffee costs $2, while one bottle of water costs $1
Step-by-step explanation:
We can represent this using two equations:
Variable x represents cups of coffee, and variable y represents bottles of water.5x + 2y = 12
4x + 7y = 15
Your answer for the value of x and y should be
x = 2
y = 1
Therefore, one cup of coffee costs $2, while one bottle of water costs $1.
which expression is equivalent to (1 cos(x))2tangent (startfraction x over 2 endfraction) )? sin(x) 1 – cos(x) 1 – cos2(x) (1 cos(x))(sin(x))
The expression (1 - cos(x))^2 * tangent(x/2) is equivalent to (1 - cos^2(x))(sin(x)).
We can simplify the expression by using the trigonometric identity: cos^2(x) + sin^2(x) = 1. Rearranging this identity, we have sin^2(x) = 1 - cos^2(x).
Substituting this identity into the expression, we get (1 - cos^2(x))(sin(x)).
Expanding the expression further, we have sin(x) - cos^2(x)sin(x).
Therefore, the expression (1 - cos(x))^2 * tangent(x/2) is equivalent to (1 - cos^2(x))(sin(x)).
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Find the unit rate. Enter your answer as a mixed number.
A fertilizer covers 2/3 square foot in 1/4 hour.
The unit rate is
square feet per hour.
what is 7 8/9 written as a decimal
find the mean of the day 10.25‚9‚4.75‚8‚2.65‚12‚2.35
Answer:
7!
Step-by-step explanation:
If you add all of those numbers together it would be 49!
Then you divide that number how many numbers there are.
There are 7 numbers and 49/7 =7!
If Sarah has $6453 Dallors of food and has $135 Dollars on her. How much will she need to pay for her food?
A. 6318
B. 233
C. 4555
D None of the Above
Answer:
It will be A
Step-by-step explanation:
6453
- 135
--------
6318 dollars needed for Sarah's food.
Hope this helps!
the measure of ∠ABD is (0.12x+68)° and the measure of ∠CBD is (0.13x+24)°. Find the value of x.
PLS HELP
ILL GIVE ALOT OF POINTS
Answer:
could you add a form?
Step-by-step explanation:
Answer:
Step-by-step explanatio
Match the correct term to its definition.
Fomite E. Portal of exit
Vector F. Zoonotic
Reservoir G. Incubation period
Portal of entry
34. _______ Site where infectious agent enters the body
35. _______ Disease transmitted through an animal bite
36. _______ Population or environment in which pathogen lives and reproduces and on which it depends on its survival
37. _______ Inanimate object covered in disease-causing agent
38. _______ Interval between exposure to pathogen and first signs and symptoms of disease
39. _______ Site where infectious agent leaves the body
40. _______ Living insect or animal involved with disease transmission
The words to fill each gap, respectively, are Portal of entry, Vector, Reservoir, Fomite, Incubation period, Portal of exit, Vector.
Diseases InfectionPortal of entry: It refers to the site or pathway through which an infectious agent enters the body of a susceptible host, allowing the agent to establish an infection.
Vector: A vector is a living organism, usually an insect or animal, that transmits disease-causing pathogens from one host to another. It serves as an intermediate carrier of the infectious agent.
Reservoir: Reservoir refers to a population or environment where a pathogen lives and multiplies, serving as a source of infection. The pathogen depends on the reservoir for its survival and can be transmitted from the reservoir to susceptible individuals.
Fomite: A fomite is an inanimate object or surface that becomes contaminated with disease-causing agents, such as bacteria or viruses. These agents can survive on fomites and potentially transmit infection if they come into contact with a susceptible individual.
Incubation period: The incubation period is the interval between exposure to a pathogen and the appearance of the first signs and symptoms of the disease. It represents the time required for the pathogen to replicate and cause noticeable illness in the infected individual.
Portal of exit: It refers to the site or pathway through which an infectious agent leaves the body of an infected individual, allowing it to be transmitted to other hosts. Examples of portals of exit include respiratory secretions, feces, blood, or skin lesions.
Vector: As mentioned earlier, a vector is a living insect or animal that plays a role in transmitting disease. It can acquire the pathogen from an infected host and transmit it to a susceptible individual, potentially causing disease in the process.
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A quality control expert at a pretzel factory took a random sample of 101010 bags from a production run of over 500500500 bags and measured the amount of pretzels in each bag in the sample. The sample data were roughly symmetric with a mean of 450, and a standard deviation of 15
Based on this sample, which of the following is a 90%, percent confidence interval for the mean amount of pretzels per bag (in grams) in this production run?
Answer:
H0:μ=440 g
Ha:μ does not equal 440 g
Step-by-step explanation:
kahn
The 90% confidence interval for the mean amount of pretzels per bag (in grams) in this production run for this case is [441.31, 458.69] approximately.
How to calculate confidence interval for population mean for small sample?If the sample size is given to be n < 30, then for finding the confidence interval for mean of population from this small sample, we use t-statistic.
Let the sample mean given as [tex]\overline{x}[/tex] andThe sample standard deviation s, andThe sample size = n, and The level of significance = [tex]\alpha[/tex]Then, we get the confidence interval in between the limits
[tex]\overline{x} \pm t_{\alpha/2}\times \dfrac{s}{\sqrt{n}}[/tex]
where [tex]t_{\alpha/2}[/tex] is the critical value of 't' that can be found online or from tabulated values of critical value for specific level of significance and degree of freedom n - 1.
For this case, we're provided;
The sample mean given as [tex]\overline{x}[/tex] = 450The sample standard deviation s = 15The sample size = n = 10The level of significance = [tex]\alpha[/tex] = 100 - 90% = 10% = 0.1The critical value of t at level of significance 0.1 iand at degree of freedom 10-1=9 is:
Thus, the confidence interval in between the limits
[tex]450 \pm 1.833 \times \dfrac{15}{\sqrt{10}}[/tex]
or
[tex]450 \pm 8.69[/tex] approximately or 441.31 to 458.69 or we write it as: [441.31, 458.69] approximately.
Thus, the 90% confidence interval for the mean amount of pretzels per bag (in grams) in this production run for this case is [441.31, 458.69] approximately.
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Answer:
I cannot see the picture
Step-by-step explanation:
Which of these is an example of qualitative data?
A how many books your classmates read this year
B. your classmates' favorite books
C. how much a book costs at the store
D. how many pages your favorite book has
i think it depends on if you have enough money to buy the books you need so C would be the answer
At a pet store, Davina counted 12 parrots out of 20 birds. Which is an equivalent ratio of parrots to birds at the pet store?
Trigonometry, please answer ASAP, Convert the radian measure to degrees.
12
Answer:
687.549 deg
Step-by-step explanation:
12 rad = 687.549 deg
Refering to #14, what is the approximate area of the lake where the resort has ownership responsibility? (Round your answer to the nearest hundredths) (Type in answer my F G F ZH = 71°.x=1.3. y = 20.0 . ZH = 71°,x= 3.0, y = 19.8 2H = 71°, x = 18.9, y 6.5 LH = 71°.x 6.5. y 18.9 14 A lakaside resort has ownership responsibility for the lako from each edge of their shoreline to the cantor of the roughly circular lake. The distance hom shore to the center of the lake is 130 meters and the central anglo respresenting the resorts Warship's 50° a What is the approudmate length of shoreline owned by the resort (Round your answer to the nearest hundredma) po in answer m)
The approximate area of the lake where the resort has ownership responsibility is 711.82 meters².
How to calculate the areaArea of sector = (central angle / 360°) * π * radius²
We know that the central angle is 50°, the radius is 130 meters, and π is approximately equal to 3.14.
Plugging these values into the formula, we get:
Area of sector = (50° / 360°) * 3.14 * 130²
Area of sector = 25/72 * 3.14 * 16900
Area of sector = 15750/22
Area of sector = 711.82 meters²
Therefore, the approximate area of the lake where the resort has ownership responsibility is 711.82 meters².
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8 x5/7 need help asap
Answer:
5.71428571429
5 7/10
Step-by-step explanation:
Hope this helps and have a great day!!!!
Answer:
40/7
Step-by-step explanation:
1/3 of your birthday cake is leftover from your party. If you eat 1/4 of the leftover cake, what fraction of the original birthday cake is left
Answer:
a twelth= 1/12
Step-by-step explanation: