Answer:
A. 0.2395 w/w %
B. 2394ppm
Explanation:
A. To find concentrationin percent by mass of the solution we need to calculate mass of glycerol and mass of water. The formula is:
Mass glycerol / Total mass * 100
Mass glycerol:
The solution is 2.6x10⁻²moles / L. As there is 1L of solution there are 2.6x10⁻² moles of glycerol. In mass (Using molar mass glycerol: 92.09g/mol):
2.6x10⁻² moles of glycerol * (92.09g / mol) = 2.394g glycerol
Mass of water:
998.9mL and density = 0.9982g/mL:
998.9mL * (0.9982g/mL) = 997.1g of water.
That means percent by mass is:
% by mass: 2.394g / (997.1g + 2.394g) * 100 = 0.2395 w/w %
B. Parts per million are mg of glycerol per L of solution. As in 1L there are 2.394g. In mg:
2.394g * (1000mg / 1g) = 2394mg:
Parts per million: 2394mg / L = 2394ppm
Considering the definition of percent by mass
A) the concentration of the glycerol solution in percent by mass is 0.2395%.
B) the concentration of the glycerol solution is 2394.34 ppm.
Concentration of the glycerol solution in percent by mass
A) The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.
The mass percentage of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.
The mass percentage is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:
[tex]mass percentage=\frac{mass of solute}{mass of solution} x100[/tex]
In this case, you have a 2.600×10⁻² M solution of glycerol (C₃H₈O₃) in water. The sample was created by dissolving a sample of C₃H₈O₃ in water and then bringing the volume up to 1.000 L.
So, being the molarity the number of moles of solute that are dissolved in a certain volume, the number of moles of glycerol can be calculated as:
number of moles of glycerol= 2.600×10⁻² M× 1 L
number of moles of glycerol= 2.600×10⁻² moles
Being the molar mass glycerol 92.09 [tex]\frac{g}{mole}[/tex], the mass of glycerol can be calculated as:
2.600×10⁻² moles×92.09 [tex]\frac{g}{mole}[/tex]= 2.39434 grams of glycerol
On the other side, the volume of water needed was 998.9 mL and the density of water at 20.0∘C is 0.9982 [tex]\frac{g}{mL}[/tex]. So, the mass of water needed can be calculated as:
998.9 mL×0.9982 [tex]\frac{g}{mL}[/tex]= 997.1 grams of water
Finally, the mass percentage of the solution can be calculated as:
[tex]mass percentage=\frac{mass of glycerol}{mass of glycerol + mass of water} x100[/tex]
Solving:
[tex]mass percentage=\frac{2.39434 grams}{2.39434 grams+ 997.1 grams} x100[/tex]
[tex]mass percentage=\frac{2.39434 grams}{999.49434 grams} x100[/tex]
mass percentaje= 0.2395 %
In summary, the concentration of the glycerol solution in percent by mass is 0.2395%.
Parts per million (ppm)B) Parts per million (ppm) is a unit of measurement of concentration that measures the number of units of substance in each million units of the whole. In this case, the concentration measurement refers to mg of glycerol per L of solution.
Being the mass of glycerol 2.39434 grams equal to 2394.34 mg (1 g=1000mg), the concentration is:
[tex]concentration=\frac{2394.34 mg}{1L}[/tex]
concentration= 2394.34 ppm
In summary, the concentration of the glycerol solution is 2394.34 ppm.
Learn more about:
mass percentage: brainly.com/question/19168984?referrer=searchResults brainly.com/question/18646836?referrer=searchResultsbrainly.com/question/24201923?referrer=searchResults brainly.com/question/9779410?referrer=searchResults brainly.com/question/17030163?referrer=searchResults ppmhttps://brainly.com/question/16727593?referrer=searchResultshttps://brainly.com/question/13565240?referrer=searchResultshrough the complete electrolysis of a sample of pure water, a student collects 14.0 grams of hydrogen gas and 112.0 grams of oxygen gas. What mass of water (in grams), if it reacted completely, was initially present? (The electrolysis of water is the use of an electric current to decompose it into its component elements.)
Answer:
126g of H₂O
Explanation:
Electrolysis of water is:
2H₂O(l) → 2H₂(g) + O₂(g).
To know mass of water that reacted, we need to find moles of hydrogen and oxygen and, by using electrolysis chemical equation, we can determine moles of water and its mass, thus:
Moles hydrogen (Molar mass: 2.01g/mol):
14.0g H₂ * (1mol / 2.01g) = 6.97 moles hydrogen
Moles Oxygen (Molar mass: 32g/mol):
112.0g O₂ * (1 mol / 32g) = 3.5 moles oxygen
As 2 moles of hydrogen and 1 mole of oxygen are produced from 2 moles of water, and 7 moles of hydrogen and 3.5 moles of oxygen were collected, moles of water that reacted were 7 moles H₂O.
As molar mass of water is 18g/mol, mass of 7 moles of H₂O is:
7 mol H₂O * (18g / mol) =
126g of H₂OThe van der Waals equation for real gases recognizes that:
A. the molecular attractions between particles of a gas decrease the pressure exerted by the gas
B. the non-zero volumes of gas particles effectively decrease the amount of "empty space" between them
C. gas particles have non-zero volumes and interact with one another
D. molar volumes of gases of different types are different
E. All of the above statements are correct
Answer:
E. All of the above statements are correct
Explanation:
The gas equation given below and which we are familiar with relates to ideal gases and not to real gases .
P V = R T
In this equation , it has been assumed that gas molecules have no mutual attraction . They do not occupy any space ie they are very small in volume . But in reality , gas molecules do have mutual attraction and also they occupy some space. . Considering these facts , a new formula was given to replace the gas equation which is written below .
(P - a / V² ) ( V - b ) = R T , a and b are constant and depend upon nature of gas involved .
This is called van der Waals equation . This is for one mole .
Here we see P of previous gas equation is replaced by P - a / V² .
That means pressure of real gas is less than the ideal gas . It is due to mutual attraction between any two gas molecules. V of previous gas equation is replaced by V - b . That means volume of empty space has been reduced . It is due to the fact that real gas molecules occupy some space . Here b is dependent on the nature of the gas.
So all the statements are correct .
The van der Waals equation for real gases recognizes that gas particles have non-zero volumes and interact with one another.
The ideal gas equation is used to describe the relation among the volume, pressure and temperature of an ideal gas. Recall that the ideal gas equation holds that there is no intermolecular interaction between gas molecules and that gas molecules occupy zero volume relative to the volume of the container.
The van der Waals equation for real gases recognizes that gas particles have non-zero volumes and interact with one another.
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3root 7
Prove that
Irrational
Walter is observing a substance that is currently a solid. What would have to
occur for the substance to become a liquid?
Answer:
Increasing the temperature
Explanation:
Solids are usually found in low-temperature conditions. Increasing the temperature increases the energy in the solids, causing the solids to turn into a liquid state. Increasing the energy between molecules in a substance reduces the attraction force between the molecules and changes them from solid to liquid state.
Which type of basin forms at divergent boundaries
Answer:
A: rift
Explanation:
Divergent boundaries within continents initially produce rifts, which produce rift valleys.
Answer:
rift just did the quiz
Science is a way of discovering what's in the natural world and how those things
A)
work today
B)
how they worked in the past
C)
how they are likely to work in the future
D)
work today, how they worked in the past, and how they are likely to work
in the future
Answer:
D
Explanation:
science shows patterns and anomalies in how the world works
An unknown element X has the following isotopes: ²⁵X (80.5% abundant) and ²⁷X (19.5% abundant). What is the Average atomic mass in amu of X?
Answer:
the average atomic mass in amu of X is 25.39 amu
Explanation:
The computation of the average atomic mass in the amu of X is shown below:
Average mass is
= Product sum + atomic mass of each and every isotope
Now the average mass
= (80.5 ÷ 100 × 25 amu) + (19.5 ÷ 100 × 27 amu)
= 20.125 + 5.265
= 25.39 amu
Hence, the average atomic mass in amu of X is 25.39 amu
The average atomic mass of X is 25.39 amu.
Atomic massIt is the quantity of matter present within an atom of an element.
Based on the given information,
• The unknown element X has the isotopes, 25X (80.5% abundant) and 27X (19.5% abundant).
Now the atomic mass of X can be calculated by using the formula,
[tex]=\frac{(M1*A1)+(M2*A2)}{A1+A2}[/tex]
Here, M1 and M2 are the atomic masses, and A1 and A2 are their abundances.
Now putting the values we get,
[tex]= \frac{(25*80.5)+(27*19.5)}{80.5+19.5} \\\\= \frac{2012.5+526.5}{100} \\= \frac{2539}{100} \\= 25.39 amu[/tex]
Thus, the average atomic mass of X is 25.39 amu.
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What reasons can you give for people to pursue discoveries in chemistry?
Answer:
cure problems
pollution
purifying water
crop production
Explanation:
The reasons for people to pursue discoveries in chemistry because it is the most important part of daily life and related to the human health too.
What is chemistry?Chemistry is a field of science which deals with the chemicals present in laboratory or in our environment o related to human body also.
Their are main 3 branches of chemistry that is organic and inorganic and physical chemistry some others are too like analytical chemistry industrial chemistry pharmaceutical chemistry.
Organic chemistry deals with the carbon compounds and hydrogen compound inorganic chemistry deals with the elements of periodic table and pharmaceutical makes medicines for human health care.
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What is the specific gravity of mercury, the liquid used in thermometers, if it has a density of
13.6 g/mL?
Answer:
13.64.
Explanation:
Hello,
In this case, since the the specific gravity is computed as the ratio of the density of the given substance by the density of water that is approximately 0.997 g/mL as shown below:
[tex]s.g=\frac{\rho}{\rho _{water}}[/tex]
In such a way, for this case, we find:
[tex]s.g=\frac{13.6g/mL}{0.997g/mL}=13.64[/tex]
Which is dimensionless due the g/mL simplification.
Best regards.
The specific gravity of mercury is 13.61
Specific gravity is defined as the ratio of the density of a substance to the density of water. Mathematically;
[tex]sg=\frac{\rho_s}{\rho_{water}}[/tex]
Given the following parameters:
[tex]\rho_{Hg}=13.6g/mL\\\rho_{H_2O}=0.9998g/mL[/tex]
Substitute the given parameters into the formula;
[tex]sg=\frac{13.6g/mL}{0.9998g/mL}\\sg=13.61[/tex]
Hence the specific gravity of mercury is 13.61
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In an ion with an unknown charge, the total mass of all the electrons was determined to be 1.640 x [tex]10^{-26}[/tex] g, the total mass of its protons was 4.015 x [tex]10^{-23}[/tex] g, and the total mass of its neutrons was 4.690 x [tex]10^{-23}[/tex] g. What is the identity, charge, and mass number of this ion? Electron one mass = 9.109 x [tex]10^{-31}[/tex] Proton one mass = 1.673 x [tex]10^{-27}[/tex] Neutron one mass = 1.675 x [tex]10^{-27}[/tex]
A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information to answer the following questions. This reaction is...
endothermic.
exothermic.
Suppose 72.8g of HgO react. Will any heat be released or absorbed?
Yes, absorbed.
Yes, released.
No.
If you said heat will be released or absorbed in the second part of this question, calculate how much heat will be released or absorbed. kJ Round your answer to 3 significant digits. ×10
Answer:
The reaction is endothermic.
Yes, absorbed
3.06x10¹kJ are absorbed
Explanation:
In the reaction:
2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ
As ΔH >0,
The reaction is endothermic
As the reaction is endothermic, when the reaction occurs,
the heat is absorbed.
Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.
72.8g are:
72.8g * (1mol / 216.59g) = 0.3361 moles HgO.
that absorb:
0.3361 moles HgO * (182kJ / 2 moles) =
3.06x10¹kJ are absorbedWhich of the following have a neutral charge. Electron, plasma, neutron, or proton
One way to represent this equilibrium is: 2 CO2(g) + 4 H2O(g)2 CH3OH(l) + 3 O2(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above. 1) CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(g) K1 = 2) 2 CH3OH(l) + 3 O2(g) 2 CO2(g) + 4 H2O(g) K2 = 3) CO2(g) + 2 H2O(g) CH3OH(l) + 3/2 O2(g)
Answer:
1) 1/√K
2) 1/K
3) √K
Explanation:
As general rules of operation of equilibrium constants:
For the reaction:
A + B ⇄ C + D; Equilibrium constant = K
C + D ⇄ A + B; K' = 1/K
2A + 2B ⇄ 2C + 2D; K'' = K²
Thus, as equilibrium constant of:
2CO2 + 4H2O ⇄ 2CH3OH + 3O2
Is K:
1) CH3OH + 3/2 O2 ⇄ CO2 + 2H2O
K' = 1 / K^(1/2) = 1/√K
2) 2CH3OH + 3O2 ⇄ 2CO2 + 4H2O
K' = 1/K
3) CO2 + 2H2O ⇄ CH3OH + 3/2 O2
K' = K^(1/2) = √K
How many atoms of zirconium are in 0.3521 mol of zirconium?
Answer:
2.12×10²³ atoms.
Explanation:
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.
Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:
1 mole of zirconium also 6.02×10²³ atoms.
Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.
Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.
There are 2.12 × 10²³ atoms of zirconium in 0.3521 mol of zirconium.
HOW TO CALCULATE NUMBER OF ATOMS:
The number of atoms of zirconium can be calculated by multiplying the number of moles in the element with Avogadro's number. That is;no. of atoms in Zirconium = no. of moles = 6.02 × 10²³According to this question, 0.3521 mol of zirconium was given. The number of atoms can be calculated as follows:no. of atoms of Zirconium = 0.3521 × 6.02 × 10²³no. of atoms of Zirconium = 2.12 × 10²³ atoms. Therefore, there are 2.12 × 10²³ atoms of zirconium in 0.3521 mol of zirconium.Learn more at: https://brainly.com/question/15488332?referrer=searchResults
Look at the image below:
Which of the following statements is true?
Group of answer choices
The figure is a molecule and a compound.
The figure is a compound, but not a molecule.
The figure is an atom and an element.
The figure is a molecule and an element.
Answer:
The figure is a molecule and a compound
Explanation:
Because it have 2 cluster molecules
5. A gas has a pressure of 1.26 atm and occupies a volume of 7.40 L. If the gas
compressed to a volume of 2.93 L, what will its pressure?
Answer:
0.499atm
Explanation:
The formula is
P1/V1 = P2/V2
so:
1.26atm/7.40L = P2/2.93L
then:
(1.26atm/7.40L)*2.93L = P2
= 0.4988918911atm
the answer must have 3 sig figs
Identify structure(s) for all constitutional isomers with the molecular formula C4H8 that have one double bond. Select all that apply.
Answer:
a) But-1-ene
b) E-But-2-ene
c) Z-But-2-ene
d) 2-Methylpropene
Explanation:
In this case, if we want to draw the isomers, we have to check the formula [tex]C_4_H8[/tex] in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain But-1-ene.
For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain Z-But-2-ene. When the methyls groups are placed on opposite sides we will obtain E-But-2-ene.
Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain 2-Methylpropene.
See figure 1 to further explanations.
I hope it helps!
In the Chocolate Chip Rock Cycle Lab,
what was represented by stirring the
melting chips with a spatula?
B. convection currents
A. weathering
C. deposition
D. erosion
A 38.6 kg marble slab is shown above. What is it’s density? Give you’re answer to the nearest tenth
Answer:
Density, [tex]d=24.68\ g/cm^3[/tex]
Explanation:
Given that,
Mass of marble slab is 38.6 kg or 38600 g
The dimensions of the slab is 23 cm × 17 cm ×4 cm
We know that the density of an object is given in terms of its mass volume as follows :
[tex]d=\dfrac{\text{mass}}{\text{volume}}\\\\d=\dfrac{38600\ g}{1564\ cm^3}\\\\d=24.68\ g/cm^3[/tex]
So, the density of the marble slab is [tex]24.68\ g/cm^3[/tex]
What causes the flame colors when salts are exposed to the flame? (hint: electrons jump
between different energy levels)
Answer:
When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.
Explanation:
How is energy transformed from one form to another? Give three examples of objects that have potential energy and kinetic energy? What does the law of convosation of energy state? .
Answer:
An energy transformation is the change of energy from one form to another. Energy transformations occur everywhere every second of the day. There are many different forms of energy such as electrical, thermal, nuclear, mechanical, electromagnetic, sound, and chemical.
Explanation:
Which of the following is a mixture? honey water gold steel
Answer:
steel because water gold and honey is not a mixture of something
Answer:
Steel
Explanation:
The total volume of seawater is 1.5 x 10²¹ L. Seawater contains approximately 3.5% sodium chloride by mass. At that high of a concentration of salt within the water, the density of water is 1.03 g/mL. Calculate the total mass of sodium chloride, in grams, contained in all the seawater in the world.
Answer:
There are [tex]5.408\times 10^{22}[/tex] grams contained in all the seawater in the world.
Explanation:
At first let is determinate the total mass of seawater ([tex]m_{sw}[/tex]), measured in grams, in the world by definition of density and considering that mass is distributed uniformly:
[tex]m_{sw} = \rho_{sw}\cdot V_{sw}[/tex]
Where:
[tex]\rho_{sw}[/tex] - Density of seawater, measured in grams per liters.
[tex]V_{sw}[/tex] - Volume of seawater, measured in liters.
If [tex]V_{sw} = 1.5\times 10^{21}\,L[/tex] and [tex]\rho_{sw} = 1030\,\frac{g}{L}[/tex], then:
[tex]m_{sw}=\left(1030\,\frac{g}{L} \right)\cdot (1.5\times 10^{21}\,L)[/tex]
[tex]m_{sw} = 1.545\times 10^{24}\,g[/tex]
The total mass of sodium chloride is determined by the following ratio:
[tex]r = \frac{m_{NaCl}}{m_{sw}}[/tex]
[tex]m_{NaCl} = r\cdot m_{sw}[/tex]
Given that [tex]m_{sw} = 1.545\times 10^{24}\,g[/tex] and [tex]r = 0.035[/tex], the total mass of sodium chloride in all the seawater in the world is:
[tex]m_{NaCl} = 0.035\cdot (1.545\times 10^{24}\,g)[/tex]
[tex]m_{NaCl} = 5.408\times 10^{22}\,g[/tex]
There are [tex]5.408\times 10^{22}[/tex] grams contained in all the seawater in the world.
Following are the calculation to the total mass of sodium chloride in grams:
Given:
Seawater volume[tex]= 1.5 \times 10^{21}\ L\\\\[/tex]
Seawater density [tex]= 1.03\ \frac{g}{mL}\\\\[/tex]
[tex]\%[/tex] of sodium chloride in seawater [tex]= 3.5\ \%[/tex]
To find:
The total mass of sodium chloride in grams=?
Solution:
The total volume of seawater [tex]= 1.5 \times 10^{21}\ L= 1.5 \times 10^{24}\ mL\\\\[/tex]
The density of seawater [tex]= 1.03 \frac{g}{mL}[/tex]
[tex]\therefore\\\\[/tex]
Seawater mass = Seawater volume [tex]\times[/tex] density
[tex]= 1.5 \times 10^{24}\times 1.03 \ g\\\\= 1.545 \times 10^{24}\ g\\\\[/tex]
[tex]\%[/tex] of sodium chloride in seawater [tex]= 3.5\ \%[/tex]
[tex]\therefore\\\\[/tex]
Calculating the sodium chloride mass in Seawater:
[tex]= 3.5\% \ \ of\ \ 1.545 \times 10^{24} \ g\\\\ =\frac{3.5}{100} \times 1.545 \times 10^{24}\ g\\\\= 5.4075 \times 10^{22} \ g\\\\[/tex]
Calculating the sodium chloride mass [tex]= 5.4075 \times 10^{22} \ g\\\\[/tex]
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If a buffer solution is 0.260 M in a weak acid (Ka=8.3×10−5) and 0.480 M in its conjugate base, what is the pH?
Answer: pH = 4.3
Explanation: The pH of a buffer solution and its conjugate base can be determine by the Henderson-Hasselbach Equation. It can be estimated because equilibrium between weak acid and its conjugate base allows the solution to not change pH when small amounts of strong acid or base are added.
pH is calculated by:
[tex]pH = pK_{a} + log(\frac{[conjugate]}{[acid]} )[/tex]
pKa is the acidic dissociation constant and it shows how much strong an acid can be. It is determined as:
[tex]pK_{a}=-log(K_{a})[/tex]
For the buffer solution:
[tex]pK_{a}=-log(8.3.10^{-5})[/tex]
[tex]pK_{a}=4.081[/tex]
Calculating pH:
[tex]pH = 4.081 + log(\frac{0.480}{0.260} )[/tex]
[tex]pH = 4.081 + log(1.846)[/tex]
pH = 4.3
For this buffer solution and its conjugate, pH = 4.3
List the 7 examples of energy sources that produce steam to turn the turbines of an electric generator.
Answer:
The fuels or energy sources used for steam turbines include biomass, coal, geothermal energy, petroleum fuels, natural gas, nuclear energy, and solar thermal energy. Most of the largest electric power plants in the United States have steam turbines.
Explanation: I hope dis help you !
C=82.76% H=17.24% Molecular formula ???
Answer:
ok
Explanation:
Element %composition Mol. mass No. of C atoms Simplest Rounding
ratio off
C 82.76 12 6.89 1× 2 2
H 17.24 1 17.24 2.5× 2 5
Number of carbon atoms present =
12
82.76
=6.89
Number of hydrogen atoms present =
1
17.24
=17.24
simplest ratio =
6.89
6.89
=1
simplest ratio =
6.89
17.24
=2.5
∴ Empirical fromula is C
2
H
5
Empirical formula mass= 2×12+5 = 29
∴ V.D. = 29
Mol. mass = 2 × V.D.
=58
n=
Empiricalformulamass
Molecularmass
=
29
58
=2
∴ Molecular formula = C
4
H
10
pls mark me as braillant
what has properties of both metals and nonmetals
Answer:
Metalloids.
Explanation:
they're between the metals and non metals in the periodic table
blance equation __CaBr2 (aq) + ___Li3PO4(aq) → ___Ca3(PO4)2(s) + ____LiBr (aq)
Answer:
3CaBr2 + 2LI3PO4 - > Ca3(PO4) 2 + 6LiBr
Explanation:
The first one I did was PO4. There are two on the right side, so I added 2 to Li3PO4 on the other side. That balanced the PO4s and then gave me 6 Lithiums so I balanced that one next on the right side. I added 6 to LiBr which balanced the Li but then gave me 6 Br, so I finished it off by adding 3 in front of CaBr2 which balanced the calcium and bromines.
Here was the process:
CaBr2+2Li3PO4 -> Ca3(PO4)2+LiBr
Balances PO4 (2on both sides)
CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr
Balances Lithiums (6 on each side)
3CaBr2+2Li3PO4 -> Ca3(PO4)2+6LiBr
Balances Calciums and Bromines (3 Calciums and 6 Bromines each side)
Hope this helped!
What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?
Answer:
17.55 g of NaCl
Explanation:
The following data were obtained from the question:
Molarity = 3 M
Volume = 100.0 mL
Mass of NaCl =..?
Next, we shall convert 100.0 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
100 mL = 100/1000
100 mL = 0.1 L
Therefore, 100 mL is equivalent to 0.1 L.
Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:
Molarity = 3 M
Volume = 0.1 L
Mole of NaCl =?
Molarity = mole /Volume
3 = mole of NaCl /0.1
Cross multiply
Mole of NaCl = 3 × 0.1
Mole of NaCl = 0.3 mole
Finally, we determine the mass of NaCl required to prepare the solution as follow:
Mole of NaCl = 0.3 mole
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl =?
Mole = mass /Molar mass
0.3 = mass of NaCl /58.5
Cross multiply
Mass of NaCl = 0.3 × 58.5
Mass of NaCl = 17.55 g
Therefore, 17.55 g of NaCl is needed to prepare the solution.
The measured quantity 0.00410 g written in scientific notation is _______. Using prefixes, the number can be written as ________.
Answer:
4.10x10⁻³g.
4.10 mg.
Explanation:
Hello,
In this case, considering the given number, we can see it has two digits after the first nonzero digit that is four (4) which is also at the third decimal place, it means that the scientific notation has a negative power as it is at the left of the given zeros, therefore it is:
4.10x10⁻³g.
Moreover, since the proper prefix for the factor x10⁻³ is milli, the number with prefix is:
4.10 mg.
Best regards.