a 18 The number 21 has no composite factors. What is another number that has no composite factors? A. 27- B. 52- C. 77- D. 81-​

Answer:

8/5 < x < 12/5

Step-by-step explanation:

(2 - x)² < 4/25​

2 - x < ±2/5

2 - x < 2/5

-x < -8/5

x > 8/5

2 - x > -2/5

-x > -12/5

x < 12/5

Therefore, your answer is 8/5 < x < 12/5

Answer:

960

20 times 12 moths to get 240 then multiply that by 4 years and get 960 .

Step-by-step explanation:

sorry if wrong ]

have a good day /night

may i pleae have a branlliest .

20 x 12=240 x 4 =960

Answer:

960

Step-by-step explanation:

Answer:

Step-by-step explanation:

The winning payout for the horse is $45

To determine the winning payout for the horse, you need to use the following formula:

Odds against winning: B / (A + B)

Betting amount: X Payout: X + (X * B / A)where A is the denominator of the odds and B is the numerator of the odds.

Here, the odds against winning are 2:7.

So, the denominator (A) is 7 and the numerator (B) is 2.

The betting amount is $35.

Plugging these values into the formula:

Payout = 35 + (35 * 2 / 7)

Payout = $45.

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Answer:

Any number less than greater than or equal to 18

Step-by-step explanation:

Answer:

(0.4291, 0.4743)

Step-by-step explanation:

Using the relation :

p ± Zcritical * Sqrt[(p(1-p)) / n]

P = x / n =. 1447 / 3203 = 0.4517

1 - p = 0.5483

Zcritical at 99% = 2.575

Sqrt[(p(1-p)) / n] = sqrt(0.4517(0.5483)) / 3203) = 0.008793

p ± Zcritical * 0.008793

Lower boundary = 0.4517 - (2.575 * 0.008793) = 0.4291

Upper boundary = 0.4517 + (2.575 * 0.008793) = 0.4743

(0.4291, 0.4743)

Answer:

35% of that number is 91.

Step-by-step explanation:

we need to first find 25% of what number equals 65.

65×100÷25 = 260

Then, if you use the same method again, 60% of 260 would be 156.

We know "that" number is 260, and all we need to do is find 35% of it.

35% of 260 = 91

Hope this helped :)

Answer:

2/3

Step-by-step explanation:

Answer:

Slope = -6

Step-by-step explanation:

Answer:

Step-by-step explanation:

m<1 = 50

m<2 = 22

m<3 = 108

m<4 = 50

m<5 = 65

m<6 = 50

m<7 = 43

m<8 = 65

m<9 = 75

m<10 = 18

m<11 = 25

m<12 = 40

m<13 = 115

m<14 = 65

m15 = 115

Answer:

y = 2

Step-by-step explanation:

y = x

x = 2

Plug in the given value.

y = (2)

This is already simplified.

Therefore, when x = 2, y = 2.

Hope this helps!

Answer:

[tex]\frac{n}{5} - 6[/tex]

Step-by-step explanation:

Quotient of a number and 5 means n/5

6 less than n/5 means n/5 - 6

Answer:

the product of a triple a number and 19

Step-by-step explanation:

but i'm not 100% sure so don't quote me

Answer:

∠DAB = ∠DBA

Then AD=DB from above statement

Answer:

The absolute value of 12, is 12...

Step-by-step explanation:

Answer:

-12

Step-by-step explanation:

Step-by-step explanation:

[tex]2 \sin(90 - x) - \cos(360 - x) [/tex]

[tex]2 \cos(x) - \cos(x) [/tex]

[tex] \cos(x) [/tex]

Question:

There are 30 candies in a box, all identically shaped. 5 are filled with coconut, 10 with caramel, and 15 are solid chocolate.

You randomly select a piece of candy and eat it (so it is NOT replaced!), then select a second piece. Find the probability of each event

(a) The probability of selecting two solid chocolates in a row.

(b) The probability of selecting a caramel and then a coconut candy.

Answer:

[tex](a)[/tex] [tex]P(Chocolates) = \frac{7}{29}[/tex]

[tex](b)[/tex] [tex]P(Caramel\ and\ Coconut) = \frac{5}{87}[/tex]

Step-by-step explanation:

Given

[tex]Coconut = 5[/tex]

[tex]Caramel = 10[/tex]

[tex]Chocolate = 15[/tex]

[tex]Total = 30[/tex]

For probabilities without replacement, 1 is subtracted after the first selection.

So, we have:

Solving (a): Two solid chocolates

This is calculated as:

[tex]P(Chocolates) = P(First\ Chocolate) * P(Second\ Chocolate)[/tex]

[tex]P(Chocolates) = \frac{n(Chocolate)}{Total} * \frac{n(Chocolate) - 1}{Total - 1}[/tex]

[tex]P(Chocolates) = \frac{15}{30} * \frac{15 - 1}{30 - 1}[/tex]

[tex]P(Chocolates) = \frac{15}{30} * \frac{14}{29}[/tex]

[tex]P(Chocolates) = \frac{1}{2} * \frac{14}{29}[/tex]

[tex]P(Chocolates) = \frac{7}{29}[/tex]

Solving (a): Caramel and Coconut

This is calculated as:

[tex]P(Caramel\ and\ Coconut) = P(Caramel) * P(Coconut)[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{n(Caramel)}{Total} * \frac{n(Coconut)}{Total - 1}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{10}{30} * \frac{5}{30- 1}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{10}{30} * \frac{5}{29}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{1}{3} * \frac{5}{29}[/tex]

[tex]P(Caramel\ and\ Coconut) = \frac{5}{87}[/tex]

We have proven that ΔWXY is similar to ΔWVZ using the ASA criterion.

We have,

To prove that ΔWXY is similar to ΔWVZ, we can use the ASA (Angle-Side-Angle) criterion.

Here are the steps of the proof:

Proof:

- Given: ΔWXY is isosceles with legs WX and WY; ΔWVZ is isosceles with legs WV and WZ.

Since ΔWXY is isosceles, we have WX ≅ WY. (Given)

Since ΔWVZ is isosceles, we have WV ≅ WZ. (Given)

We also know that ΔWXY and ΔWVZ share the common side segment WZ. (Common side)

Let's consider the angles: ∠WXY and ∠WVZ. Since ΔWXY is isosceles, we have ∠WXY ≅ ∠WYX. (Isosceles triangle property)

Similarly, since ΔWVZ is isosceles, we have ∠WVZ ≅ ∠WZV. (Isosceles triangle property)

Now, we have two pairs of congruent angles: ∠WXY ≅ ∠WYX and ∠WVZ ≅ ∠WZV.

We already know that WX ≅ WY and WV ≅ WZ.

By the ASA criterion, if two pairs of corresponding angles and the included side are congruent, then the triangles are similar.

Applying the ASA criterion, we conclude that ΔWXY ~ ΔWVZ. (Angle-Side-Angle)

Therefore,

We have proven that ΔWXY is similar to ΔWVZ using the ASA criterion.

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Random samples of size 50 are taken from this population, and the number of fully vaccinated individuals in each sample, represented by the variable X, follows an approximately binomial distribution with n = 50 and p = 0.727.

(a) Using the binomial formulas, the mean (μ) of X is calculated as np, which is 50 * 0.727 = 36.4, rounded to the nearest tenth. The standard deviation (σ) is given by the square root of np(1-p), which becomes √(50 * 0.727 * 0.273) ≈ 4.1.(b) To determine the values within 3 sigma of the mean, we calculate 3 times the standard deviation (3σ) and find the range around the mean: 36.4 ± 3 * 4.1, resulting in the range of approximately 24.1 to 48.7. Therefore, the common numbers of fully vaccinated people expected in samples of this size, given the 72.7% vaccination rate, would fall within this range.(c) By using appropriate commands on a calculator or technology, the following probabilities can be determined:

The probability of one sample having exactly 35 fully vaccinated people is obtained from the binomial distribution as P(X = 35), which can be calculated using the binompdf command.

The value of P(X ≤ 25) can be found using the binomcdf command, representing the probability of having 25 or fewer fully vaccinated people in a sample. The probabilities should be reported to four decimal places for accuracy.

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Answer:

It will take her 15 weeks to have enough money for the computer.

Step-by-step explanation:

$1200 - $300 = $900

900 divided by 60 gives you 15

Therefor, it'll take Shirley 15 weeks to save $1200.

Answer:

The answer is 3,100

Step-by-step explanation:

If you subtract the 8,500 from his parents and his football scholarship you get 4,900 and then take the 1,800 from his saved money, You get what he still needs, which is 3,100.

The constant c that produces a solution satisfying the initial condition y(6) = 4 is c = 24.

To find the constant c that satisfies the given equation and the initial condition, we need to substitute the function y = x² + (c/x²) into the differential equation and solve for c. The given equation is xy' * 2y = 4x².

First, we differentiate y with respect to x to find y',

y = x² + (c/x²)

y' = 2x - (2c/x³)

Now we substitute y and y' into the differential equation,

xy' * 2y = 4x²

x(2x - (2c/x³)) * 2(x² + (c/x²)) = 4x²

Simplifying,

2x³ - 2cx + 4c = 4x²

Rearranging,

2x³ - 4x² - 2cx + 4c = 0

Now we substitute x = 6 and y = 4 (from the initial condition y(6) = 4) into the equation,

2(6)³ - 4(6)² - 2(6)c + 4c = 0

432 - 144 - 12c + 4c = 0

288 - 8c = 0

8c = 288

c = 36

Therefore, the constant c that produces a solution satisfying the initial condition y(6) = 4 is c = 36.

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Answer:

One Chilly Night, Elijah Was Sleeping but Then Woke Up. He Realized It Was 45 Degrees According To the AC Monitor, So He Changed it To 70 Degrees But The Monitor Broke And Changed to -6 DEGREES!!

Step-by-step explanation:

A situation that can be represented by the integer - 6 was envisaged.

An integer is a whole number (not a fractional number) that can be positive, negative, or zero.

One day maths teacher decided to take a random test

There were 16 questions each of 4 marks and 1 mark deduction for each wrong answer, with no penalties for non-attempt.

David was so good at guessing. He guessed all the 16 answers out of which 2 were correct and 14 were incorrect.

So, the total marks that David got = 4(2)-1(14) = 8-14 =-6

Thus, a situation that can be represented by the integer - 6 was envisaged.

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Step-by-step explanation:

feeling the compa

Como te amo mucho

Answer:

4x² + 8x - 5

= 4(3/4)² + 8(3/4) - 5

= 4 × 9/16 + 24/4 - 5

= 36/16 + 24/4 - 5

= 9/4 + 6 - 5

= 9/4 +1

= 3.25

Step-by-step explanation:

Hope it helps!!

a) The p- value is 0.0094.

b) True

c) Yes

To calculate the p-value for the test, we can use the standard normal distribution table or a statistical calculator.

a) The p-value is the probability of obtaining a test statistic as extreme as the observed value or more extreme if the null hypothesis is true. Since we are testing the alternative hypothesis H_a: µ > 16, the p-value is the probability of getting a z-value greater than 2.34.

Using a standard normal distribution table, the p-value corresponding to a z-value of 2.34 is 0.0094.

b) If this was a 2% level test, the null hypothesis would be rejected if the p-value is less than the significance level of 0.02.

Since the p-value (0.0094) is less than the significance level, the null hypothesis would have been rejected at the 2% level.

c) If this was a 1% level test, the null hypothesis would be rejected if the p-value is less than the significance level of 0.01.

Since the p-value (0.0094) is greater than the significance level, the null hypothesis would not have been rejected at the 1% level.

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Answer:

(4x+5y=7

y=3x+9

4x+5(3x+9)=7

4x+15x+45=7

19x=7-45

19x= -38

19×/19=-38/19

x= -2

whlie y=3x+9

y=3(-2)+9

y= -6+9

y=3 end solution

x= -2,y= 3

Jasmine's Z-score is 2. The number of parks per capita in the city is [tex]1.38 * 10^-4[/tex] in scientific notation.

To calculate Jasmine's Z-score, we can use the formula:

Z = (X - μ) / σ

where X is the individual score (85), μ is the mean (76), and σ is the standard deviation (4.5).

Z = (85 - 76) / 4.5

Z = 9 / 4.5

Z = 2

Since Jasmine's Z-score is 2, this tells us that her score of 85 is 2 standard deviations to the right of the mean.

Now let's calculate the probability of randomly selecting a math exam with fewer than 15 questions using the mean of 20 and a standard deviation of 2.5.

To apply the empirical rule, we need to determine how many standard deviations 15 is away from the mean.

Z = (X - μ) / σ

Z = (15 - 20) / 2.5

Z = -5 / 2.5

Z = -2

Since 15 is 2 standard deviations to the left of the mean, we can use the empirical rule to estimate the probability.

According to the empirical rule:

The data is within one standard deviation of the mean for about 68% of the time.

The data is within 2 standard deviations of the mean for about 95% of the time.

99.7% of the data are contained within a 3 standard deviation range around the mean.

Since 15 is beyond 2 standard deviations to the left, the probability of randomly selecting a math exam with fewer than 15 questions would be very close to 0. In this case, we can assume it's effectively 0%.

Now let's calculate the number of parks per capita in the city with 890,000 people and 123 parks.

Number of parks per capita = Number of parks / Population

Number of parks per capita = 123 / 890,000

To write the answer in scientific notation, we can express 890,000 as 8.9 x 10^5:

Number of parks per capita =[tex]123 / (8.9 * 10^5)[/tex]

Calculating the result:

Number of parks per capita =[tex]1.38 * 10^-4[/tex]

Therefore, the number of parks per capita in the city is[tex]1.38 * 10^-4[/tex] in scientific notation.

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Answer:

Step-by-step explanation:

Dani has only 1/2 of a cup of baking mix. She needs 3/4 of a cup for one batch of muffins. Which solution method shows how much of a batch of muffins Dani can make?

Answer:

28

Step-by-step explanation: